index laws tutorial intermediate
DESCRIPTION
This is a quick tutorial for students seeking to use the first, second and third index law at a more intermediate level.TRANSCRIPT
![Page 1: Index laws tutorial intermediate](https://reader033.vdocuments.mx/reader033/viewer/2022052600/55848bfbd8b42a043a8b4cd8/html5/thumbnails/1.jpg)
![Page 2: Index laws tutorial intermediate](https://reader033.vdocuments.mx/reader033/viewer/2022052600/55848bfbd8b42a043a8b4cd8/html5/thumbnails/2.jpg)
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59 x 53
53
= 512
53
76 x 77
74
= 713
74
= 59
= 79
![Page 5: Index laws tutorial intermediate](https://reader033.vdocuments.mx/reader033/viewer/2022052600/55848bfbd8b42a043a8b4cd8/html5/thumbnails/5.jpg)
a6 x a4 = a10
b5 x b7 = b12
a5 x a3
a4 x a6
= a8
a10
= a-2
c5 x c3
c4
= c8
c4
= c4
![Page 6: Index laws tutorial intermediate](https://reader033.vdocuments.mx/reader033/viewer/2022052600/55848bfbd8b42a043a8b4cd8/html5/thumbnails/6.jpg)
How could you get an answer of 30?
35 ÷ 35 = 35-5 = 30
30 = 1 General Rule
a0 = 1
![Page 7: Index laws tutorial intermediate](https://reader033.vdocuments.mx/reader033/viewer/2022052600/55848bfbd8b42a043a8b4cd8/html5/thumbnails/7.jpg)
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2a3 x 3a4 = 6a7= 2 x 3 x a3 x a4
8a6 ÷ 4a4 = 2a2= (8 ÷ 4) x (a6 ÷ a4)
8a6 4a4
2 2
![Page 9: Index laws tutorial intermediate](https://reader033.vdocuments.mx/reader033/viewer/2022052600/55848bfbd8b42a043a8b4cd8/html5/thumbnails/9.jpg)
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This can be for the next tutorial.
Something to look forward to.