honors algebra 1 chapter 5 review

8
Honors Algebra 1 Chapter 5 Review

Upload: brett-stevenson

Post on 31-Dec-2015

25 views

Category:

Documents


1 download

DESCRIPTION

Honors Algebra 1 Chapter 5 Review. 1 ) Simplify completely:. 2) Find the quotient:. 3 ) Given the functions and find: (a) (b). - PowerPoint PPT Presentation

TRANSCRIPT

Page 1: Honors Algebra 1  Chapter 5 Review

Honors Algebra 1 Chapter 5 Review

Page 2: Honors Algebra 1  Chapter 5 Review

1) Simplify completely:

5 3 7 5 3 3 712 18 30 8 14 11a b a b a b ab a b

5 3 7 5 3 3 76 2 3 5 8 14 11a b a b a b ab a b

5 3 7 5 3 3 712 18 30 8 14 11a b a b a b ab a b

5 3 7 34 19 14 41a b a b ab

Page 3: Honors Algebra 1  Chapter 5 Review

2) Find the quotient:

3 6 20 2 10 3 6 20 2 10

18 6 24

6 2 8 14

2 146 2 8

3x x

x

3 26 20 2 10

3

x x x

x

Page 4: Honors Algebra 1  Chapter 5 Review

3) Given the functions andfind: (a) (b)

2( ) 5 6f x x x ( ) 3g x x ( )( 2)f g ( )( )f g x

(a) ( )( 2) 2 2f g f g 22 5 2 6 2 3

20 5 25

2(b) ( )( ) 5 6 3f g x x x x

3 2 23 5 15 6 18x x x x x 3 28 21 18x x x

Page 5: Honors Algebra 1  Chapter 5 Review

4) The number of diagonals that can be drawn inside a polygon is given by the formula:

where D is the number of diagonals and n is the number of sides. If a polygon has 65 diagonals, how many sides does it have?

( 3)

2

n nD

( 3)65

2

n n

( 3)65

22 2

n n

130 ( 3)n n 2130 3n n 20 3 130n n

0 13 10n n

13 and 10n

The polygon has 13 sides.

Page 6: Honors Algebra 1  Chapter 5 Review

5) Factor the following polynomials:

7 2 3 2 10( ) 64 72 8a k y k k y

2( ) 2 128b y

4( ) 16c h

2 5 2 108 8 9k k y k y

22 64y 2 8 8y y

PRIME!

Page 7: Honors Algebra 1  Chapter 5 Review

6) Find the zeros of the function , then find the x-intercepts of the graph of the function.

2( ) 49 28 4f m m m

20 49 28 4m m

20 7 2m

7 2 0m 7 2m

2

7m

2, The x-intercept is ,0

7

Page 8: Honors Algebra 1  Chapter 5 Review

7) Find the equation of the line passing through the points . 2, 9 and 4, 11

11 9 20 10

1) Find the slope:4 2 6 3

m

1 12) Use point-slope form: y y m x x

x y

109 2

3y x

10 209

3 3y x

10 7

3 3y x