gus omer randy hurd. determining the most economic method for heating diesel fuel in a reservoir...
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![Page 1: Gus Omer Randy Hurd. Determining the most economic method for heating diesel fuel in a reservoir from 20 to 100 °C in under 90 minutes. PROBLEM](https://reader035.vdocuments.mx/reader035/viewer/2022070410/56649ee75503460f94bf785b/html5/thumbnails/1.jpg)
Gus Omer • Randy Hurd
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Determining the most economic
method
for heating diesel fuel in a reservoir
from 20 to 100 °C in under 90
minutes.
PROBLEM
![Page 3: Gus Omer Randy Hurd. Determining the most economic method for heating diesel fuel in a reservoir from 20 to 100 °C in under 90 minutes. PROBLEM](https://reader035.vdocuments.mx/reader035/viewer/2022070410/56649ee75503460f94bf785b/html5/thumbnails/3.jpg)
• Three different power heaters are available from the
chosen manufacturer: 1500 W, 2500 W and 3750 W.
• The 3750 W heater will obviously heat the fuel the fastest,
but because our target heat-up time is 90 minutes it may
make more sense economically to choose a smaller heater
that will cost less to purchase and run long-term.
INITIAL THOUGHT
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• Steel tank filled with diesel fuel
• Wall thickness = 0.003038m
• k = 50 W/m∙K
RESERVOIR
0.2413m
0.6604m
0.4064m
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• Uniform heating
• Bottom of tank is insulated (q=0)
• Thin walled tank (fuel and reservoir at same temperature)
• Quiescent air (no forced convection)
• Lumped capacitance for natural convection
ASSUMPTIONS
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• Mild Steel
• k = 50 W/m • k
• C = 500 J/kg • K
• ρ = 7,850 kg / m3
• Diesel Fuel
• C = 1,800 J/kg • K
• ρ = 875 kg / m3
Mathematic Model Material Properties
APPROACH
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• The coefficient h was calculated assuming all heat transfer
through convection was due to natural convection in quiescent air.
• Separate Rayleigh, Nusselt, and h values were calculated for the
top of the fuel reservoir and the sides.
• The weighted average is h ≈ 7
• The total heat transfer q was then calculated:
− q = Ash(Ts – T∞ )
CONVECTION
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RADIATION
• Properties:
− ε = 0.08
• Heat Transfer:
− q = Asεσ(Ts4 - Tsur
4)
• The calculated heat transfer through radiation was comparatively
small and could safely be considered insignificant in calculating
temperature increase with respect to time.
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RESULTS
90
100
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• Assuming the fuel reservoir heater was run for 16 hours a
day, 300 days per year at a cost of 8.51¢/kWh, the annual
cost to run one unit would be:
− 1500 W: $612.72
− 2500 W: $1021.20
− 3750 W: $1531.80
• In addition, smaller power heaters require a smaller initial
investment.
FINANCES
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• According to our calculation only the 2500W and 3750 W
heaters were capable of accomplishing the proposed task.
The initial cost of the heaters is relatively insignificant when
compared to energy costs over long periods of time. When
energy costs are considered the 2500W heater proves ideal
because it performs the proposed task for the cheapest
energy cost.
CONCLUSION
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QUESTIONS