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Finding Limits Algebraically.notebook 1 April 29, 2014 Warm-Up: 1. Sketch a graph of the function and use the table to find the lim 3x 2 x 5 2. fix your evaluation from Friday

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Page 1: Finding Limits Algebraically.notebookmisssahadypshsclasswebsite.weebly.com/uploads/5/1/3/0/... · 2018. 9. 6. · Finding Limits Algebraically.notebook 4 April 29, 2014 Target Agenda

Finding Limits Algebraically.notebook

1

April 29, 2014

Warm-Up:

1. Sketch a graph of the function and use the table to find the 

lim  3x2 x⇒­5

2. fix your evaluation from Friday

Page 2: Finding Limits Algebraically.notebookmisssahadypshsclasswebsite.weebly.com/uploads/5/1/3/0/... · 2018. 9. 6. · Finding Limits Algebraically.notebook 4 April 29, 2014 Target Agenda

Finding Limits Algebraically.notebook

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April 29, 2014

Page 3: Finding Limits Algebraically.notebookmisssahadypshsclasswebsite.weebly.com/uploads/5/1/3/0/... · 2018. 9. 6. · Finding Limits Algebraically.notebook 4 April 29, 2014 Target Agenda

Finding Limits Algebraically.notebook

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April 29, 2014

finding limits algibraically

Ch.12      Lesson 2

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Finding Limits Algebraically.notebook

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April 29, 2014

Target

Agenda

Purpose

Evaluation

TSWBAT: Find the limit of a function given Limit Laws.

Find the limit using Factoring, Simplifying and Rationalizing

Warm-Up

Lesson

BAT: Get ready for calculus. Extend knowledge functions, make connections, apply knowledge to new situations

3-2-1

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Finding Limits Algebraically.notebook

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April 29, 2014

This is CRAZY!

What is the lim  3x2 ­ 4x + 2?

What is the limit   x4 + x2 ­ 2 ?4­4x

x⇒­5

x⇒1

Page 6: Finding Limits Algebraically.notebookmisssahadypshsclasswebsite.weebly.com/uploads/5/1/3/0/... · 2018. 9. 6. · Finding Limits Algebraically.notebook 4 April 29, 2014 Target Agenda

Finding Limits Algebraically.notebook

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April 29, 2014

Limit Laws

lim  [f(x) + g(x)] =  M + Lx ⇒ a

Let c be a constant

lim f(x) = M  and    lim g(x) = Lx ⇒ a x ⇒ a

lim  [f(x) ­ g(x)] =  M ­ Lx ⇒ a

lim  c f(x) =  c Mx ⇒ a

lim  [f(x) g(x)] =  M Lx ⇒ a

lim  x ⇒ a g(x)

 f(x)     M L= 

1.

2. 

3. 

4. 

5.

lim  f(x)k =  Mkx ⇒ a

6. 

lim  √f(x) = √Mx ⇒ a

7.  k k

lim g(x)≠0

k > 0

a,k > 0

Page 7: Finding Limits Algebraically.notebookmisssahadypshsclasswebsite.weebly.com/uploads/5/1/3/0/... · 2018. 9. 6. · Finding Limits Algebraically.notebook 4 April 29, 2014 Target Agenda

Finding Limits Algebraically.notebook

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April 29, 2014

Combining Limit Laws Example

lim (t + 3)8 (t2 ­ 6)x⇒­4

Page 8: Finding Limits Algebraically.notebookmisssahadypshsclasswebsite.weebly.com/uploads/5/1/3/0/... · 2018. 9. 6. · Finding Limits Algebraically.notebook 4 April 29, 2014 Target Agenda

Finding Limits Algebraically.notebook

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April 29, 2014

Cool Extra yet Necessary Rules

Finding the Limit Algebraically

lim C = C

lim x = a

lim xk = ak

lim √x = √akk

x⇒a

x⇒a

x⇒a

x⇒a

Page 9: Finding Limits Algebraically.notebookmisssahadypshsclasswebsite.weebly.com/uploads/5/1/3/0/... · 2018. 9. 6. · Finding Limits Algebraically.notebook 4 April 29, 2014 Target Agenda

Finding Limits Algebraically.notebook

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April 29, 2014

lim C = C

lim x = a

lim xk = ak

lim √x = √akk

x⇒a

x⇒a

x⇒a

x⇒a

Finding the Limit Algebraically

ex.   lim 5  = x⇒16

ex.   lim x  = x⇒16

ex.   lim (x4)  = x⇒16

ex.   lim   x  = x  16

Which rule did they use? Match them!

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Finding Limits Algebraically.notebook

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April 29, 2014

Finding the Limit Algebraically

Substitute a in for x, that's the limit!

lim f(x) = f(a)   a  Domain of fx    a

ex.  lim  (3x2 ­ 4x + 2)x    6

**If this is true for all points in the function, then it is continuous!

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Finding Limits Algebraically.notebook

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April 29, 2014

Canceling Common Factors

Use this tool when dividing by 0

Because: Law 5 Quotient and direct substitution cant be used to find the limits because we would be dividing by 0

ex. lim x ­ 2 x2 ­ 4x  2

Page 12: Finding Limits Algebraically.notebookmisssahadypshsclasswebsite.weebly.com/uploads/5/1/3/0/... · 2018. 9. 6. · Finding Limits Algebraically.notebook 4 April 29, 2014 Target Agenda

Finding Limits Algebraically.notebook

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April 29, 2014

Finding the Limit by SimplifyingUse when the numerator is not simplified or if you can cancel out the denominator completely

Because: Law 5 Quotient and direct substitution cant be used to find the limits because we would be dividing by 0 

ex. lim (6+2x)2 ­ 36  2xx  0

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Finding Limits Algebraically.notebook

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April 29, 2014

Finding the Limit by RationalizingUse when the numerator has a radical with the denominator being 0

Because: Law 5 Quotient and direct substitution cant be used to find the limits because we would be dividing by 0 

ex. lim √m2+25 ­ 5  m2x  0

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April 29, 2014

SummarizingTIME!

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Finding Limits Algebraically.notebook

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April 29, 2014

Evaluation:

1.Practice! pg.897  # 1­23 

lim f(x) =x  ­4

(x2+5x + 6)(x+4)  x2+6x+8

f(x) =

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April 29, 2014

Finding the Limit by Finding:

Left and Right hand limits separately

Use when there is a piecewise function or absolute values in the function

Because:

ex. lim |x ­ 3|x  3

x  0lim (             ) 1  

2x  1  |2x|

+ex.

Page 17: Finding Limits Algebraically.notebookmisssahadypshsclasswebsite.weebly.com/uploads/5/1/3/0/... · 2018. 9. 6. · Finding Limits Algebraically.notebook 4 April 29, 2014 Target Agenda

Finding Limits Algebraically.notebook

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April 29, 2014

Finding the Limit by Finding:

Left and Right hand limits separately

Use when there is a piecewise function or absolute values in the function

Because:{ 3x     if  x < 0

x3 if 0 < x < 4

6­x if x > 4

lim p(x)

p(x) =

x  0+ 

lim p(x)x  0­ 

lim p(x)x  0 

lim p(x)x  4+ 

lim p(x)x  4 

lim p(x)x  3 

lim p(x)x  4­ 

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April 29, 2014

Evaluation:

1.

Practice! pg.897  # 27­34

lim f(x) =

x  ­4

 |x+4|    x2­16

f(x) =

2. lim f(x) =x  ­5