Find the perimeter of each shape to 1dp –all arcs are either

semicircles, quarter circles or three-quarter circles

a)

3m

10m

5m

4cm

5m

4m

6cm

12cm

10cm

13cm

17cm

7cm 31cm

7cm

12cm11cm

1.5cm2.3cm 17m

20m

15m

12m

1m

4m

4m

10m

12m

14m

b)

c)

i)

e)

f)

g)

h)

d)

j) k)

l)

Find the perimeter of each shape to 1dp –all arcs are either

semicircles, quarter circles or three-quarter circles

m)

13m

97m

37m20m 30m

29m

4m

5m

12m15m

16m

4m

20m

10m 10m

22m

40m

24m

6m

p)

n) o)

q)

r) The shape below is made of 10

congruent triangles surrounding a

rectangles)

55m

5m

84m

Worktops* These solutions may not

be the most

elegant or efficientsolutions ,

but are

rather ones that can be followed .

* The diagrams in the questionsare not

sketched accurately

-

Are ⇒ 8xxf = ⇐onK

r si= It424cm I = 32

× = 532 am

Perimeter = +6T) cm =245#

Blue are ⇒ 6Iz = 3km"

Yellow are ⇒ x'tx= 622x'= 36I = 18x.= 518

⇒ ZF8E x4 = I it = 20.0#-

Blue length ⇒ 1.5cm Gadivs)

① i. ssE= I -5't 0.82I = 2.89

0.8 × = 1.7×

Yellow are ⇒ fatPerimeter = t.tt 2.3 tat =6.%mUdp)_-

←

Yellow are ⇒ = fit

of ⇒

D; : %/ 6 of = 100

It = 10

Perimeter = lot lot6I=38.8mdd#

All yellow lines are equal to theradius of the quarter circle

172=157×2← Blue line ⇒ ⑤ is zpq = 225 tx64 = ×'

x 8 =×

Perimeter = 17H5T 6IT 20thRadius = 20-8 = km/ = 70.8in Cup)Green are⇒2 = 6T =

-

°

Yellow are ⇒ tTxgI= 18T

µ

Blue triangle ⇒ E- 127122I = 288

1145=5Perimeter= Hit + fbf 121 ty2=288

= 69.5cm Gdp) y' = 167

- y= F67-

Blue are⇒ 10¥ = Sit

Yellow are ⇒ 2¥ = HIT

Green length ⇒ It 122=132x x = 5

Perimeter= 5ft Htt 5+13= p)

Yellow are ⇒ = It

sn

,

Blue triangle ⇒ 5=44×23 =×

Perimeter = 3t9tIzI=K9mGdp-

×

At yellow lines are the radius

r Green arc⇒ 25ft8 4

Blue triangle ⇒ 18=84×26=2

Perimeter = 25¥ + 10+6+5+3 = 43.6mGd-

MY Yellow are⇒ 144×4 = 2¥

7in✓

Blue triangle ⇒ 72+24=57cm 25=2

Perimeter= 25T I7T 2II×

= 78.1 Gdp)-

All green lines are the radius

< Yellow are ⇒ Ktx£= 27

Bbq Blue triangle ⇒ ① a E- 447'

× =25

7

Perimeter = 25+3It 2¥ = 607cmGdp

-

×

Green lines give us a radius of 4m

c

'

Yellow are⇒ 8 it =4t8 -2

Blue triangle ⇒E-get 8'

I = 80× = 580

③angle lines gives us final length 5Perimeter =4ttFot It2+5+2+10

= 41.5M Gdp)-

q, Orange arcs ⇒ kIt3I H5T

" s Blue triangle ⇒ a xD3

40

I=9't 402

Perimeter = 15kt 41+41 I =8lt 1600= 129 . Im Gdp) of = 1681- × = 41

-

Yellow are⇒ 26¥ = 13€×

[ Blue triangle ⇒ I = 84+132

④zm

"= 85

84

Perimeter = 37+97+37 t t 85 = 276.fm/ld#-

2=>5 Yellow are ⇒ 101T

( = >

Bketnayk ⇒%x

29 t 2022

Green line = A

perimeter = 911-30+30429+104=161.4map)-

zYellow are -_ 2T

Green lines give us f- 6is

Blue triangle ⇒⑤102=64×2Orange lines give 8=x 6

↳ Z=4perimeter lot20+2*+10+4=50.3mcldp)-

Yellow are = = It•

,

is

Blue triangle ⇒ ④ 12

I 152=12459 =p ×

Orange lines =I6 .

'

. y=4m

Perimeter -_ I5T 16+5+4 that +9= 48.7M Gdp)-

÷:*"+= 29

,

perimeter= (10×29)+(8×20)to= 490M

-

Orange are = HIT

× Blue triangle ⇒ sf

I= 12752x.= 13

Perimeter = 5tBt5t5t HIT= 62.6M Gdp)-