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Pearson Edexcel Level 3 Advanced GCE in Physics Sample Assessment Materials – Issue 1 – October 2014 © Pearson Education Limited 2014
133
Pa
per
3 M
ark
sche
me
Que
stio
n nu
mbe
r
A
ccep
tabl
e an
swer
s
Add
ition
al g
uida
nce
Mar
k
1(a)
A
n ex
plan
atio
n th
at m
akes
refe
renc
e to
the
follo
win
g po
ints
: •
Com
men
t on
the
data
(1)
• C
orre
ct c
onse
quen
t con
clus
ion
(1)
4.43
is a
n an
omal
ous v
alue
So
the
mea
n va
lue
is to
o lo
w
Acc
ept
data
is c
onco
rdan
t so
mea
n va
lue
is c
orre
ct
2
1(b)
A
n ex
plan
atio
n th
at m
akes
refe
renc
e to
the
follo
win
g po
ints
: •
Ligh
t gat
es c
an re
cord
shor
t tim
es a
ccur
atel
y (1
) O
R w
ith sm
alle
r unc
erta
inty
(1)
• B
ecau
se h
uman
reac
tion
time
is n
ot in
volv
ed (1
)
2 (T
otal
for
Que
stio
n 1
= 4
mar
ks)
Pearson Edexcel Level 3 Advanced GCE in Physics Sample Assessment Materials – Issue 1 – October 2014 © Pearson Education Limited 2014
134
Que
stio
n nu
mbe
r
A
ccep
tabl
e an
swer
s
Add
ition
al g
uida
nce
Mar
k
2 •
Sens
ible
est
imat
e of
unc
erta
intie
s fro
m re
adin
gs g
iven
(1)
• A
dds p
erce
ntag
e un
certa
intie
s (1)
•
Hen
ce c
alcu
late
s unc
erta
inty
in sp
eed
(1)
• C
andi
date
’s c
oncl
usio
n m
ust b
e su
ppor
ted
by th
eir e
stim
ate
of th
e un
certa
intie
s (1)
Exam
ple
of c
alcu
latio
n:
%U
in L
is (0
.1/2
5.6)
x 1
00 %
= 0
.4 %
%U
in F
is (1
/320
) x 1
00 %
= 0
.3 %
%
U in
spee
d is
0.7
%
328
x 0.
007
= 2
Spee
d =
328
± 2
All
thre
e re
sults
are
with
in th
e ca
lcul
ated
un
certa
inty
so c
oncl
udes
stud
ent B
is c
orre
ct
4
(Tot
al fo
r Q
uest
ion
2 =
4 m
arks
)
Pearson Edexcel Level 3 Advanced GCE in Physics Sample Assessment Materials – Issue 1 – October 2014 © Pearson Education Limited 2014
135
Que
stio
n nu
mbe
r
A
ccep
tabl
e an
swer
s
Add
ition
al g
uida
nce
Mar
k
3 (a
)(i)
A d
escr
iptio
n th
at m
akes
refe
renc
e to
the
follo
win
g po
ints
: C
ircui
t dia
gram
show
ing:
• C
ell,
varia
ble
resi
stor
and
am
met
er in
serie
s and
vol
tmet
er
in p
aral
lel w
ith c
ell (
1)
• R
ecor
ding
pai
rs o
f rea
ding
s of t
erm
inal
p.d
. and
cur
rent
(1)
•
Use
the
varia
ble
resi
stor
to o
btai
n 5
othe
r pai
rs o
f rea
ding
s (1
)
Shou
ld b
e be
twee
n 5
and
10 o
ther
pai
rs
3 3
(a)(
ii)
A d
escr
iptio
n th
at m
akes
refe
renc
e to
the
follo
win
g po
ints
: •
Plot
a g
raph
of t
erm
inal
pot
entia
l diff
eren
ce o
n th
e y-
axis
an
d cu
rren
t on
the
x-ax
is (1
) •
Inte
rcep
t on
the
y-ax
is e
qual
s e.m
.f. (1
) •
And
gra
dien
t = -r
(1)
3
3(b)
•
From
gra
ph: a
fter 5
00 c
harg
ing
cycl
es in
tern
al re
sist
ance
of c
ell
is 3
27 mΩ
(1)
• U
se o
f V =
ε -
Ir (1
)
• U
se o
f %
100
0500×
VV
%99.6
%100
0500
=×
VV
(1)
• So
man
ufac
ture
r’s c
laim
is c
orre
ct (1
)
Exam
ple
of c
alcu
latio
n:
V3.352
V0.248
V3.6
Ω0.310
A0.800
V3.6
0
=−
=
×−
=V
V3.338
V0.262
V3.6
Ω0.327
A0.800
V3.6
500
=−
=
×−
=V
%99.6
%100
V3.352V
3.338
%100
0500
=×
=×
VV
Th
is la
st m
ark
is a
war
ded
only
if th
e co
nclu
sion
is
corr
ectly
supp
orte
d by
the
calc
ulat
ion.
4
(Tot
al fo
r Q
uest
ion
3 =
10 m
arks
)
Pearson Edexcel Level 3 Advanced GCE in Physics Sample Assessment Materials – Issue 1 – October 2014 © Pearson Education Limited 2014
136
Que
stio
n nu
mbe
r
A
ccep
tabl
e an
swer
s
Add
ition
al g
uida
nce
Mar
k
4 (a
)
Any
thre
e fr
om:
• In
cons
iste
nt p
reci
sion
for e
xten
sion
(1)
• La
ck o
f pre
cisi
on o
n m
ass,
shou
ld b
e sh
own
to 3
DP
(1)
• N
o ev
iden
ce o
f rep
eat r
eadi
ngs
(1) O
R th
ere
shou
ld b
e m
ore
read
ings
to c
ompe
nsat
e fo
r rep
eat r
eadi
ngs b
eing
inap
prop
riate
(1
) •
Inco
nsis
tent
inte
rval
s bet
wee
n re
adin
gs (1
)
Unc
erta
inty
sugg
este
d by
1 sf
is fa
r gre
ater
than
that
ex
pect
ed in
pra
ctic
e
3 4
(b)
A d
escr
iptio
n th
at m
akes
refe
renc
e to
two
of th
e fo
llow
ing
poin
ts:
• us
e of
fici
dual
mar
k (1
) •
eye
clos
e to
liqu
oric
e la
ce to
avo
id p
aral
lax
erro
rs (1
) •
Fixe
d m
etre
rule
clo
se to
lace
(1)
• U
se o
f set
squa
re to
ens
ure
rule
ver
tical
(1)
2
(Tot
al fo
r Q
uest
ion
4 =
5 m
arks
)
Pearson Edexcel Level 3 Advanced GCE in Physics Sample Assessment Materials – Issue 1 – October 2014 © Pearson Education Limited 2014
137
Que
stio
n nu
mbe
r
A
ccep
tabl
e an
swer
s
Add
ition
al g
uida
nce
Mar
k
5 •
Dia
met
er is
onl
y ha
lf a
divi
sion
on
the
scal
e (1
) OR
dia
met
er is
m
easu
red
to o
nly
1 sf
(1)
• H
ence
ther
e is
a la
rge
perc
enta
ge u
ncer
tain
ty in
mea
sure
men
t of
diam
eter
of o
il dr
op (1
) •
Sinc
e th
e vo
lum
e of
the
drop
is c
alcu
late
d by
taki
ng (d
iam
eter
)3 , th
e pe
rcen
tage
unc
erta
inty
in v
olum
e be
com
es v
ery
larg
e (3
× %
un
certa
inty
in d
iam
eter
) (1)
•
Sugg
estio
n fo
r im
prov
emen
t: us
e a
larg
er o
il dr
op, u
se a
(v
erni
er) s
cale
cap
able
of r
eadi
ng to
nea
rest
0.1
mm
, pro
ject
im
age
of d
ropl
et to
larg
er si
ze (1
) •
Dro
p w
ill n
ot sp
read
out
as a
n ex
actly
circ
ular
are
a, so
dia
met
er
read
ing
may
be
inac
cura
te (1
) •
Sugg
estio
n fo
r im
prov
emen
t: th
e di
amet
er o
f spr
ead-
out o
il dr
op
shou
ld b
e ta
ken
a nu
mbe
r of t
imes
acr
oss a
num
ber o
f diff
eren
t di
rect
ions
and
a m
ean
calc
ulat
ed (1
)
Allo
w fo
r ide
ntifi
catio
n of
any
oth
er v
alid
pro
blem
s an
d im
prov
emen
ts b
ased
on
good
phy
sics
, for
ex
ampl
e pl
ace
met
re ru
le a
cros
s tra
y so
that
it is
cl
ose
to th
e su
rfac
e.
6 (T
otal
for
Que
stio
n 5
= 6
mar
ks)
Pearson Edexcel Level 3 Advanced GCE in Physics Sample Assessment Materials – Issue 1 – October 2014 © Pearson Education Limited 2014
138
Que
stio
n nu
mbe
r
A
ccep
tabl
e an
swer
s
Add
ition
al g
uida
nce
Mar
k
6 (a
)
An
expl
anat
ion
that
mak
es re
fere
nce
to th
e fo
llow
ing
poin
ts:
• Th
e cu
rren
t pro
duce
s a m
agne
tic fi
eld
arou
nd th
e al
umin
ium
rin
g (1
) •
The
dire
ctio
n of
the
ring
field
opp
oses
the
chan
ge p
rodu
cing
it
(1)
• Th
e fie
lds r
epel
, pro
duci
ng a
forc
e (1
) •
The
elec
trom
agne
tic fo
rce
is e
qual
and
opp
osite
to th
e w
eigh
t of
the
ring
so it
rem
ains
in p
ositi
on sh
own
(1)
4
6 (b
)(i)
•
Use
of ½
mv2 =
mgh
(1)
• v
= 2.
43 m
s-1 (1
) Ex
ampl
e of
cal
cula
tion:
v
= 2𝑔𝑔ℎ
= 2×9.81×0.30
= 2
.43
m s-1
2
6 (b
)(ii)
•
Use
of i
mpu
lse
= ch
ange
in m
omen
tum
(1)
• R
ecog
nise
s ini
tial v
eloc
ity is
zer
o (1
) •
Hen
ce F
= 0
.923
N (1
) •
Use
of l
= π
d (1
) •
Equa
tes c
alcu
late
d va
lue
of F
with
BIl
(1)
• H
ence
I =
191
A (1
)
Exam
ple
of c
alcu
latio
n:
Ft =
mv
– m
u w
here
u =
0
So F
= (0
.019
kg ×
2.43
m s-1
)/0.0
5 s =
0.9
23 N
l =
π ×
0.0
48 m
= 0
.151
m
I = 0
.923
N/(0
.032
T ×
0.1
51 m
) = 1
91 A
6 (T
otal
for
Que
stio
n 6
= 12
mar
ks)
Pearson Edexcel Level 3 Advanced GCE in Physics Sample Assessment Materials – Issue 1 – October 2014 © Pearson Education Limited 2014
139
Que
stio
n nu
mbe
r
A
ccep
tabl
e an
swer
s
Add
ition
al g
uida
nce
Mar
k
7 (a
)(i)
A d
escr
iptio
n th
at m
akes
refe
renc
e to
the
follo
win
g po
ints
: •
Rec
ord
nT (w
here
n is
at l
east
5) (
1)
• D
ivid
e m
easu
rem
ent b
y n
(1)
2
7 (a
)(ii)
•
Ano
mal
ies c
an b
e sp
otte
d (1
) •
Red
uce
the
effe
ct o
f ran
dom
err
or (1
)
2
7 (b
)(i)
• B
FL is
smoo
th a
nd th
in w
ith a
def
inite
min
imum
an
d m
inim
um is
in ra
nge
0.26
m –
0.2
8 m
(1)
1
7 (b
)(ii)
•
Val
ues r
ead
corr
ectly
from
can
dida
te’s
line
(1)
• h
to 3
sig
fig a
nd T
to 4
sf (1
) V
alue
s fro
m th
eir c
urve
to w
ithin
1 sm
all s
quar
e w
ith
no u
nit p
enal
ty.
2
7 (c
) A
des
crip
tion
that
mak
es re
fere
nce
to th
e fo
llow
ing
poin
ts:
• Pl
ot T
2 h
agai
nst h
2 (1)
• C
is in
terc
ept o
n T2
h ax
is (
1)
OR
C is
the
valu
e of
T2 h
whe
n h2 is
zer
o (1
) •
Uni
t is m
s2 (1)
3
(Tot
al fo
r Q
uest
ion
7 =
10 m
arks
)
Pearson Edexcel Level 3 Advanced GCE in Physics Sample Assessment Materials – Issue 1 – October 2014 © Pearson Education Limited 2014
140
Que
stio
n nu
mbe
r
A
ccep
tabl
e an
swer
s
Add
ition
al g
uida
nce
Mar
k
8 (a
) A
n ex
plan
atio
n th
at th
e st
uden
t’s c
oncl
usio
n is
inco
rrec
t bec
ause
: •
The
popp
er re
turn
s to
its o
rigin
al sh
ape,
eve
n th
ough
ther
e is
a
time
dela
y (1
) •
Elas
tic m
ater
ial r
etur
ns to
its o
rigin
al sh
ape
whe
n th
e de
form
ing
forc
e is
rem
oved
(1)
• B
ut a
pla
stic
mat
eria
l wou
ld su
ffer
a p
erm
anen
t def
orm
atio
n (1
)
3
8 (b
) A
des
crip
tion
that
mak
es re
fere
nce
to th
e fo
llow
ing
poin
ts:
• R
efer
to v
2 = u
2 + 2
as (1
) •
Whe
re s
is h
eigh
t rea
ched
, v is
zer
o, a
= -g
(1)
• So
u =
√2g
s (1)
Allo
w a
rgum
ent ½
mv2 =
mgh
to g
et th
e sa
me
resu
lts.
3 8
(b)(
ii)
• A
ir re
sist
ance
will
act
on
the
popp
er…
(1)
• …
As a
dec
eler
atin
g fo
rce
(1) O
R…
dis
sipa
ting
ener
gy (1
) •
So th
e in
itial
spee
d w
ill b
e lo
wer
than
in th
e ab
senc
e of
air
resi
stan
ce, s
o th
e su
gges
tion
is n
ot c
orre
ct (1
)
3 (T
otal
for
Que
stio
n 8
= 9
mar
ks)
Pearson Edexcel Level 3 Advanced GCE in Physics Sample Assessment Materials – Issue 1 – October 2014 © Pearson Education Limited 2014
141
Que
stio
n nu
mbe
r
A
ccep
tabl
e an
swer
s
Add
ition
al g
uida
nce
Mar
k
9 (a
) •
Use
s wei
ght o
f dis
plac
ed a
ir = ρV
g (1
) •
Find
s res
ulta
nt fo
rce
= up
thru
st –
wei
ght (
1)
• U
ses F
= m
a to
find
acc
eler
atio
n (1
) •
Acc
eler
atio
n =
0.16
1 m
s−2 (1
)
Exam
ple
of c
alcu
latio
n:
Wei
ght o
f air
disp
lace
d = ρV
g =
1.20
kg
m−3×2
880
m3 ×
9.8
1m s−
2 = 3
3 90
3N
Res
ulta
nt u
pwar
d fo
rce
= 33
903
N –
(340
0 kg
×
9.81
m s−
2 ) = 5
49 N
A
ccel
erat
ion
= 54
9 N
/340
0 kg
= 0
.161
m s−
2
4 9
(b)*
Th
is q
uest
ion
asse
sses
a st
uden
t’s a
bilit
y to
show
a c
oher
ent
and
logi
cally
stru
ctur
ed a
nsw
er w
ith li
nkag
es a
nd fu
lly-
sust
aine
d re
ason
ing.
Mar
ks a
re a
war
ded
for i
ndic
ativ
e co
nten
t and
for h
ow th
e an
swer
is st
ruct
ured
and
show
s lin
es o
f rea
soni
ng.
The
follo
win
g ta
ble
show
s how
the
mar
ks sh
ould
be
awar
ded
for i
ndic
ativ
e co
nten
t. N
umbe
r of
indi
cativ
e m
arki
ng
poin
ts se
en in
an
swer
Num
ber o
f m
arks
aw
arde
d fo
r ind
icat
ive
mar
king
poi
nts
6 4
5–4
3 3–
2 2
1 1
0 0
Gui
danc
e on
how
the
mar
k sc
hem
e sh
ould
be
appl
ied:
The
mar
k fo
r ind
icat
ive
cont
ent s
houl
d be
add
ed to
th
e m
ark
for l
ines
of r
easo
ning
. Fo
r exa
mpl
e, a
n an
swer
with
five
indi
cativ
e m
arki
ng p
oint
s whi
ch is
pa
rtial
ly st
ruct
ured
with
som
e lin
kage
s and
line
s of
reas
onin
g sc
ores
4 m
arks
(3 m
arks
for i
ndic
ativ
e co
nten
t and
1 m
ark
for p
artia
l stru
ctur
e an
d so
me
linka
ges a
nd li
nes o
f rea
soni
ng).
If th
ere
are
no li
nkag
es b
etw
een
poin
ts, t
he sa
me
five
indi
cativ
e m
arki
ng p
oint
s wou
ld y
ield
an
over
all
scor
e of
3 m
arks
(3 m
arks
for i
ndic
ativ
e co
nten
t and
no
mar
ks fo
r lin
kage
s).
6
Pearson Edexcel Level 3 Advanced GCE in Physics Sample Assessment Materials – Issue 1 – October 2014 © Pearson Education Limited 2014
142
Que
stio
n nu
mbe
r
A
ccep
tabl
e an
swer
s
Add
ition
al g
uida
nce
Mar
k
9 (b
)*
(con
tinue
d)
The
follo
win
g ta
ble
show
s how
the
mar
ks sh
ould
be
aw
arde
d fo
r stru
ctur
e an
d lin
es o
f rea
soni
ng.
N
umbe
r of
mar
ks
awar
ded
for
stru
ctur
e of
an
swer
and
su
stai
ned
line
of
reas
onin
g
Ans
wer
show
s a c
oher
ent a
nd
logi
cal s
truct
ure
with
link
ages
an
d fu
lly su
stai
ned
lines
of
reas
onin
g de
mon
stra
ted
thro
ugho
ut
2
Ans
wer
is p
artia
lly st
ruct
ured
w
ith so
me
linka
ges a
nd li
nes o
f re
ason
ing
1
Ans
wer
has
no
linka
ges
betw
een
poin
ts a
nd is
un
stru
ctur
ed
0
Pearson Edexcel Level 3 Advanced GCE in Physics Sample Assessment Materials – Issue 1 – October 2014 © Pearson Education Limited 2014
143
Que
stio
n nu
mbe
r
A
ccep
tabl
e an
swer
s
Add
ition
al g
uida
nce
Mar
k
9 (b
)*
(con
tinue
d)
Indi
cativ
e co
nten
t •
As p
arac
hute
ope
ns (a
t B) t
he u
pwar
ds fo
rce
incr
ease
s •
Alo
ng B
C th
e ve
loci
ty is
dec
reas
ing
at a
no
n-co
nsta
nt ra
te
• Th
e dr
ag is
gre
ater
than
wei
ght (
nega
tive
grad
ient
) •
The
drag
is d
ecre
asin
g (c
urve
d lin
e)
• Ev
entu
ally
the
drag
forc
e ba
lanc
es th
e w
eigh
t •
No
acce
lera
tion
so li
ne is
hor
izon
tal
(Tot
al fo
r Q
uest
ion
9 =
10 m
arks
)
Pearson Edexcel Level 3 Advanced GCE in Physics Sample Assessment Materials – Issue 1 – October 2014 © Pearson Education Limited 2014
144
Que
stio
n nu
mbe
r
A
ccep
tabl
e an
swer
s
Add
ition
al g
uida
nce
Mar
k
10 (a
) A
des
crip
tion
that
mak
es re
fere
nce
to th
e fo
llow
ing
poin
ts:
• g
is d
irect
ly p
ropo
rtion
al to
r up
to R
0 (1)
•
and
then
g d
ecre
ases
with
incr
easi
ng r
(1)
• w
here
g is
pro
porti
onal
to th
e in
vers
e of
the
squa
re o
f r (1
)
3
10 (b
) •
Forc
e on
obj
ect =
mg
(loca
l g) (
1)
• Fo
rce
is p
ropo
rtion
al to
dis
plac
emen
t (1)
•
Forc
e ac
ts in
the
oppo
site
dire
ctio
n to
the
disp
lace
men
t (1)
•
Ther
efor
e w
e ca
n sa
y F
= -k
x, so
the
cond
ition
for S
HM
is m
et
and
the
pred
ictio
n is
cor
rect
(1)
4
10 (c
)(i)
Eith
er
• W
hen
x =
R0,
F =
GM
m/R
02 (1)
• F
= G
Mm
R0/R
03 so k
= mω
2 = G
Mm
/R03 (1
) •
Use
of T
=2π/ω
(1)
• T2 =
4π2 /ω
2 = 4π2 R
03 /GM
So
𝑇𝑇=2𝜋𝜋√(𝑅𝑅 !! /𝐺𝐺𝐺𝐺
) (1)
OR
• Fr
om g
raph
F=-
(g/R
o)r (
1)
• Fr
om w
hich
ω =√(𝑔𝑔/𝑅𝑅 !
) (1
) •
Use
of T
=2π/ω
(1)
• So
𝑇𝑇=2𝜋𝜋√(𝑅𝑅 !
/𝑔𝑔) (
1)
4
Pearson Edexcel Level 3 Advanced GCE in Physics Sample Assessment Materials – Issue 1 – October 2014 © Pearson Education Limited 2014
145
Que
stio
n nu
mbe
r
A
ccep
tabl
e an
swer
s
Add
ition
al g
uida
nce
Mar
k
10 (c
)(ii)
Eith
er
Cen
tripe
tal f
orce
= m
v2 /R0 =
GM
m/R
02 (1)
• 4π
2 R02 / T
2 R0 =
GM
/R02 (1
) •
T2 = 4π2 /ω
2 = 4π2 R
03 /GM
So 𝑇𝑇=2𝜋𝜋√(𝑅𝑅 !! /𝐺𝐺𝐺𝐺
) (1)
O
R
• m
g =
mv2 /R
0 =
m ω
2 R0 (
1)
• So
ω =
√(𝑔𝑔/𝑅𝑅
!) (1
) •
T =
2π/ω
= 2𝜋𝜋√(𝑅𝑅
!/𝑔𝑔)
(1)
3
(Tot
al fo
r Q
uest
ion
10 =
14
mar
ks)
Pearson Edexcel Level 3 Advanced GCE in Physics Sample Assessment Materials – Issue 1 – October 2014 © Pearson Education Limited 2014
146
Que
stio
n nu
mbe
r
A
ccep
tabl
e an
swer
s
Add
ition
al g
uida
nce
Mar
k
11 (a
) A
n ex
plan
atio
n th
at m
akes
refe
renc
e to
the
follo
win
g po
ints
: •
Res
ista
nce
incr
ease
s with
dec
reas
ing
inte
nsity
(1)
• A
s dis
tanc
e in
crea
ses l
ight
inte
nsity
dec
reas
es so
resi
stan
ce
incr
ease
s (1)
2
11 (b
) A
n ex
plan
atio
n th
at m
akes
refe
renc
e to
the
follo
win
g po
ints
: •
Show
s exp
ansi
on ln
R =
p ln
(d) +
ln(k
) (1
) •
Com
pare
s with
y =
mx+
c a
nd st
ates
that
the
grad
ient
is p
whi
ch
is c
onst
ant (
1)
2
11 (c
)(i)
•
Ln v
alue
s cor
rect
and
to 3
or 4
SF
(1)
d/m
R
/kΩ
ln
(d/m
) ln
(R/kΩ
)
1.00
1.
79
0.00
0 0.
582
1.20
2.
24
0.18
2 0.
806
1.60
3.
32
0.47
0 1.
200
2.00
4.
04
0.69
3 1.
396
2.20
4.
70
0.78
8 1.
548
2.60
5.
50
0.95
6 1.
705
•
Labe
ls a
nd u
nit (
1)
• Sc
ales
(1)
• Pl
ots (
1)
• Li
ne o
f bes
t fit
(1)
See
mar
king
gui
danc
e fo
r gra
ph p
lotti
ng
5
Pearson Edexcel Level 3 Advanced GCE in Physics Sample Assessment Materials – Issue 1 – October 2014 © Pearson Education Limited 2014
147
Que
stio
n nu
mbe
r
A
ccep
tabl
e an
swer
s
Add
ition
al g
uida
nce
Mar
k
11 (c
)(i)
(con
tinue
d)
11 (c
) (ii)
•
Find
s gra
dien
t with
larg
e tri
angl
e –
at le
ast h
alf t
he p
lotte
d le
ngth
(1
) •
1.13
< p
< 1
.23
to 2
/3 S
F an
d no
uni
ts (1
) •
Obt
ains
k =
1.8
(1)
• St
ates
rela
tions
hip
betw
een
R an
d d
(1)
4
(Tot
al fo
r Q
uest
ion
11 =
13
mar
ks)
Pearson Edexcel Level 3 Advanced GCE in Physics Sample Assessment Materials – Issue 1 – October 2014 © Pearson Education Limited 2014
148
Que
stio
n nu
mbe
r
Acc
epta
ble
answ
ers
Add
ition
al g
uida
nce
Mar
k
12 (a
)(i)
•
use
of F
= Q
1Q2/4πε
0r2 (1
) •
use
of F
= G
m1m
2/r2 (1
) •
Expr
esse
s for
ces a
s a ra
tio (1
) OR
cal
cula
tes t
he in
divi
dual
fo
rces
Fe=
8.1
x 10
-8 N
Fg =
3.6
x 1
0-47 N
(1)
• R
atio
= 2
x 1
039 o
r 5 x
10-4
0 and
iden
tifie
s gra
vita
tiona
l for
ce a
s in
sign
ifica
nt (1
)
4
12 (a
)(ii)
•
use
of F
= m
v2 /r a
nd F
= Q
1Q2/4πε
0r2 (1
)
• to
der
ive 𝑣𝑣 =
! !! !
!!! !!"
(1)
• ve
loci
ty =
2.2×
106 m
s-1 (1
)
Exam
ple
of c
alcu
latio
n:
v =
! !! !
!!! !!"
v =
!.! ×!"
!!" C×!.! ×!"
!!" C
!!×!.!"
!!" F!!! ×!.! ×!"
!!!m×!.!×!"
!!" kg
v =
2.1
85 ×
106 m
s-1
3
12 (b
) •
Cal
cula
tes w
avel
engt
h λ
(circ
umfe
renc
e) (1
) •
Use
of p
= h
/λ (1
) •
v =
2.2 ×
106 m
s-1 (1
)
Exam
ple
of c
alcu
latio
n:
λ =
2πr =
2π ×
5.3 ×
10-1
1 m =
3.3
3 ×
10-1
0 m
λ =
h/m
v so
v =
h/m
. v
= 6.
63×1
0-34 J
s/(9
.1×1
0-31 k
g×3.
33×1
0-10
m)
v =
2.18
8 ×
106 m
s-1
3
(Tot
al fo
r Q
uest
ion
12 =
10
mar
ks)
Pearson Edexcel Level 3 Advanced GCE in Physics Sample Assessment Materials – Issue 1 – October 2014 © Pearson Education Limited 2014
149
Que
stio
n nu
mbe
r
A
ccep
tabl
e an
swer
s
Add
ition
al g
uida
nce
Mar
k
13 (a
)
An
expl
anat
ion
that
mak
es re
fere
nce
to th
e fo
llow
ing
poin
ts:
• R
eson
ance
is o
ccur
ring…
(1)
• …
whe
n th
e dr
ivin
g fr
eque
ncy/
forc
ed v
ibra
tion
(at w
alki
ng
freq
uenc
y) m
atch
es th
e na
tura
l fre
quen
cy …
(1)
• …
ener
gy tr
ansf
er is
max
imum
(1)
• Su
ppor
ting
the
obse
rvat
ion
that
the
ampl
itude
rapi
dly
incr
ease
s (1
)
4
13 (b
)(i)*
Th
is q
uest
ion
asse
sses
a st
uden
t’s a
bilit
y to
show
a c
oher
ent
and
logi
cally
stru
ctur
ed a
nsw
er w
ith li
nkag
es a
nd fu
lly-
sust
aine
d re
ason
ing.
Mar
ks a
re a
war
ded
for i
ndic
ativ
e co
nten
t and
for h
ow th
e an
swer
is st
ruct
ured
and
show
s lin
es o
f rea
soni
ng.
The
follo
win
g ta
ble
show
s how
the
mar
ks sh
ould
be
awar
ded
for i
ndic
ativ
e co
nten
t. N
umbe
r of
indi
cativ
e m
arki
ng
poin
ts se
en in
an
swer
Num
ber o
f m
arks
aw
arde
d fo
r ind
icat
ive
mar
king
poi
nts
6 4
5–4
3 3–
2 2
1 1
0 0
Gui
danc
e on
how
the
mar
k sc
hem
e sh
ould
be
appl
ied:
The
mar
k fo
r ind
icat
ive
cont
ent s
houl
d be
add
ed to
th
e m
ark
for l
ines
of r
easo
ning
. Fo
r exa
mpl
e, a
n an
swer
with
five
indi
cativ
e m
arki
ng p
oint
s whi
ch is
pa
rtial
ly st
ruct
ured
with
som
e lin
kage
s and
line
s of
reas
onin
g sc
ores
4 m
arks
(3 m
arks
for i
ndic
ativ
e co
nten
t and
1 m
ark
for p
artia
l stru
ctur
e an
d so
me
linka
ges a
nd li
nes o
f rea
soni
ng).
If th
ere
are
no li
nkag
es b
etw
een
poin
ts, t
he sa
me
five
indi
cativ
e m
arki
ng p
oint
s wou
ld y
ield
an
over
all
scor
e of
3 m
arks
(3 m
arks
for i
ndic
ativ
e co
nten
t and
no
mar
ks fo
r lin
kage
s).
6
Pearson Edexcel Level 3 Advanced GCE in Physics Sample Assessment Materials – Issue 1 – October 2014 © Pearson Education Limited 2014
150
Que
stio
n nu
mbe
r
A
ccep
tabl
e an
swer
s
Add
ition
al g
uida
nce
Mar
k
13 (b
)(i)*
(c
ontin
ued)
Th
e fo
llow
ing
tabl
e sh
ows h
ow th
e m
arks
shou
ld
be a
war
ded
for s
truct
ure
and
lines
of r
easo
ning
.
N
umbe
r of
mar
ks
awar
ded
for
stru
ctur
e of
an
swer
and
su
stai
ned
line
of
reas
onin
g
Ans
wer
show
s a c
oher
ent a
nd
logi
cal s
truct
ure
with
link
ages
an
d fu
lly su
stai
ned
lines
of
reas
onin
g de
mon
stra
ted
thro
ugho
ut
2
Ans
wer
is p
artia
lly st
ruct
ured
w
ith so
me
linka
ges a
nd li
nes o
f re
ason
ing
1
Ans
wer
has
no
linka
ges
betw
een
poin
ts a
nd is
un
stru
ctur
ed
0
Pearson Edexcel Level 3 Advanced GCE in Physics Sample Assessment Materials – Issue 1 – October 2014 © Pearson Education Limited 2014
151
Que
stio
n nu
mbe
r
A
ccep
tabl
e an
swer
s
Add
ition
al g
uida
nce
Mar
k
13 (b
)(i)*
(c
ontin
ued)
In
dica
tive
cont
ent
• D
eter
min
e th
e na
tura
l fre
quen
cy b
y di
spla
cing
the
tea
in th
e cu
p an
d m
easu
ring
the
time
for o
scill
atio
ns
• Ti
me
(5 to
10
or ‘s
uita
ble
num
ber’
if te
st ru
n m
entio
ned)
full
osci
llatio
ns a
nd d
ivid
e by
the
num
ber
• C
arry
the
tea
for a
kno
wn
volu
me
of te
a fo
r fix
ed n
umbe
r of
step
s at a
stea
dy p
ace
• D
eter
min
e th
e fr
eque
ncy
of th
e ga
it •
Mea
sure
the
quan
tity
of te
a re
mai
ning
•
Rep
eat f
or o
ther
wal
king
pac
es
13 (b
)(ii)
A d
escr
iptio
n th
at m
akes
refe
renc
e to
the
follo
win
g po
ints
: •
Plot
vol
ume
of re
mai
ning
tea
agai
nst w
alki
ng fr
eque
ncy
(1)
• D
eter
min
e w
heth
er th
ere
is a
rela
tions
hip
betw
een
step
fr
eque
ncy
and
spill
age
(1)
• If
ther
e is
, det
erm
ine
whe
ther
max
imum
spill
age
occu
rs a
t or
near
the
natu
ral f
requ
ency
(1)
3
(Tot
al fo
r Q
uest
ion
13 =
13
mar
ks)