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 Name ___________________________________ Student ID ____________  Score  _______  last first VECTORDERTVATIVES Cunesian. i +./r +./.ii lr =dr.l\.1. <tt ^ 0t^ itt ^ /;rL. Ll,, \ ^ /af. nr- \ (^ ;/'*(a , , ^ / rrr', iJr. \ ^ Y-t. . " / ' S p h c r i c a f . r1f d/i+ rdHA+r\int)lO6t .lr =.1s;n|bnsd6 t;,nJ.rr. v , n'i-t'i d - '.0'6 , t r JH r \rna 4 Q /r,p.$c,,c .r- -1.I .,,.,, ' '-',,n,,,-,. I " ' ' / {n i,q | \|nH ;|o tttt. v.,- I f ",""",,,-''l, / \,n L.re da l I J I a'-' ,lo ' f-',.,..,- ' ' l ;  ' |,.o n t - u,'''' , I Ldr i., ) L*td,nu, ,,, ;; ( , I)-.,G",:(*"j,1)-;]","1, a 2 (D c _ u - F : o_ o t:), ( . : r.i_) tt-l {'..: C lindricsl. .ll =.tsi. s OA +.l.it ttr=\ts.tbd. - i ' I ilr I r t ^ vr= {+ 9+ 2 df r r@ rr: l a [*r''",-[]'  

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PHYS 322

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  • Name ___________________________________Student ID ____________ Score_______ last first

    VECTOR DERTVATIVES

    Cunesian. i +. / r !+. / . i i l r =dr. l \ .1.

  • Name ___________________________________Student ID ____________ Score_______ last first

    , l \ t t ( s rL-T.DA \ I ENT-{L CO \ST{ \TS

    .:N8ar lorrCr, \ r r r

    / i : l r IO \ Al

    ( =.1 l | r . l l l 'nr \

    . = 1.6{) , l (J L"C

    ' , : ( r l l , l ( l lg

    iPennr l l i \ i l \ of l rcc \ t r ! ( |

    rpcrnrr ihr | r \ ( i f i i .c \ f ! ( ( l

    rchrrg. o l the elecrron)

    rmi\ \ o l the ele.rro l

    SPHERICAL AND CYLI\DRICAL COORI)INATESSphc cal

    t '= ' i i l 'n \oIr=/nn"!od,

    l ' : , ' , r , , r - :t " : ' , " ,1, , , ; .1Ilo=lun i \ t r

    ( rlindrical

    i : . in i r .o.d i - .os ' .*ar i .1" o ii : \ in, \ ,n @i-.o\ , \ ;n r , r i - corodt : c,r , i . rn" P.f .

    ll i : s in r ! {^or i -sLn ! \urdi +co\di{ : e," ' , .^o i - .o." ' ! r ( ' , i \ in

    p i0 = \u 'o i - .o 'o i

    i : cosdG nn OCr" : \ rn p\ + .osp9i :2

    s^ : e,"oi - ' 'n o iC: \ rndi-eo.dii : i

    l ,=. \ , - \ ;I

    F = 140qQr2 r Coulombs Law

    F =QE Force on charge Q due to electric field

    E = 140 !r( )r2 r d ! Electric field from continuous charge distribution

  • Name ___________________________________Student ID ____________ Score_______ last first

    Eda =10Qencl Gauss Law (integral), andE =

    10

    Gauss Law (differential)

    E dl = 0 and E = 0

    V r( ) = Ed l

    r

    Electrostatic potential, and E = V

    2V = 0

    Poissons equation, and 2V = 0 Laplaces equation (regions of no charge)

    V (r) = 140qr and V r( ) =

    140

    !r( )r d ! (setting reference point at infinity)

    Eabove Ebelow =0n and

    Vaboven

    Vbelown =

    10 boundary conditions

    V b( )V a( ) =WQ

    W = 12 qii=1

    n

    V ri( ) and W = 12 V d and W =02 E

    2 d

    P = 02 E2

    Electrostatic pressure

    Q =CV Capacitor