electricity magnetism lecture 1: coulomb’s la lecture 01 - coulomb's l… · electricity...

Electricity & Magnetism Lecture 1: Coulomb’s Law

Today’sConcepts:

A)Coulomb’sLaw

B)Superposi5on

Electricity&Magne5smLecture1,Slide1

Ifyouhaven'tdonePrelecture1yet,pleasedosolatertoday

Theforceonachargeduetoanotherchargeispropor5onaltotheproductofthechargesandinverselypropor5onaltothesepara5onsquared.

r

Theforceisalwaysparalleltoalineconnec5ngthecharges,butthedirec5ondependsonthesignsofthecharges:

q2

q2 q1

q1

Likesignsrepel

Coulomb’s Law:

q2 q1

OppositesignsaMractq2 q1


Taketwoballoonsandrubthembothwithapieceofcloth.A8eryourubthemtheywill:

A)A<racteach-otherB)Repeleach-otherC)Either–itdependsonthematerialofthecloth

Clicker Question: Balloons


Balloons

Ifthesamethingisdonetobothballoonstheywillacquirethesamesigncharge.

Theywillrepel!

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Text

We can only be sure about this if the balloons are made out of the same material.

Comment

Whatdoestherwithahatmean?Isitliketheunitvectorsi-hat,j-hatandk-hat,ordoesitmeansomethingelse?Thevideodidn'treallyexplainitthatwell.

Coulomb’s Law


Examples: Ifthechargeshavethesamesign,theforcebycharge1oncharge2wouldbeinthedirec5onofr12(totheright).

q2q1

Ifthechargeshaveoppositesign,theforcebycharge1oncharge2wouldbeoppositethedirec5onofr12(leT).

q1 q2

Ournota5on:

istheforceby1on2(think“by-on”)

istheunitvectorthatpointsfrom1to2.

Clicker Question: Coulomb Force

Whatwillthedirec5onoftheforcebe?

A)AMrac5ve B)Repulsive

k = 9 x 109 N m2 / C2

electroncharge= 1.6 x 10−19 Coulombs

NA = 6.02 x 1023

Twopaperclipsareseparatedby10meters.Thenyouremove1electronfromeachatomonthefirstpaperclipandplaceitonthesecondone.


Clicker Question: Coulomb Force

Whichweightisclosesttotheapproximateforcebetweenthosepaperclips(recallthatweight=mg,g=9.8m/s2)?

A)Paperclip(1 g x g)B)Textbook(1 kg x g)C)Truck(104 kg x g)D)AircraNcarrier(108 kg x g)

E)Mt.Everest(1014 kg x g)

k = 9 x 109 N m2 / C2

electroncharge= 1.6 x 10−19 Coulombs

NA = 6.02 x 1023

Twopaperclipsareseparatedby10meters.Thenyouremove1electronfromeachatomonthefirstpaperclipandplaceitonthesecondone.


CheckPoint: Forces on Two Charges


Two charges q = + 1 µC and Q = +10 µC are placed near each other as shown in the figure.Which of the following diagrams best depicts the forces acting on the charges:

CheckPoint Results: Forces on Two Charges


“Thebiggerchargewillpushthesmallerchargeharderthanthesmallerwillpushthelarger.“

“Theybothrepeleachother,andaccordingtotheF=kQq/r^2andnewton'sthirdlaw,theforceshavetobethesame.”

“Theforcesoftwoobjectsarealwaysequalandopposite.bothequasionsinvolvethechargeofbothparYclesinthesamemanner,thereforetheyarethesame..”

Two charges q = + 1 µC and Q = +10 µC are placed near each other as shown in the figure.Which of the following diagrams best depicts the forces acting on the charges:

q1

q2

q3

q4

Iftherearemorethantwochargespresent,thetotalforceonanygivenchargeisjustthevectorsumoftheforcesduetoeachoftheothercharges:

F2,1

F3,1

F4,1

F1

Superposition


F2,1

F3,1

F4,1

F1

WhathappenstoForceonq1ifitssignischanged?

A)|F1| increases

B)|F1| remainsthesame

C)|F1| decreases

D)NeedmoreinformaYontodetermine

Clicker Question: Superposition

q1

q2

q3

q4


Thedirec5onofallforceschangesby180o–themagnitudesstaythesame:

F2,1

F3,1

F4,1

F1

F2,1

F3,1

F4,1

F1

F2,1

F3,1

F4,1

F1

q1

q2

q3

q4

F2,1

F3,1

F4,1

F1

q1

q2

q3

q4



qq

−Q +Q

+Q+Q

Case 1 Case 2

Comparethemagnitudeofthenetforceonqinthetwocases.

A)|F1| > |F2|

B)|F1|= |F2|

C)|F1|< |F2|

D)Dependsonsignofq

F1F2 = 0

Incaseone,bothoftheforcesareworkinginthesamedirecYon(thedownwarddirecYon)resulYnginagreaternetforceasopposedtocasetwowheretherepellingforcesareworkinginoppositedirecYonsinturncancelingeachotheroutBothcaseshaveachargedplacedequidistantfromchargesofthesamemagnitudessonoma[erchargeqhastheforcesatthisinstantarethesame.Themagnitudeofchargeofanelectronisthesameasthemagnitudeofaproton.So,whilethedistanceisthesame,themagnitudeofForcebetweenbothcaseswillbethesame.

CheckPoint: Compare Forces

CheckPoint: Compare Forces

qq

−Q +Q

+Q+Q

Case 1 Case 2

Comparethemagnitudeofthenetforceonqinthetwocases.

A)|F1| > |F2|

B)|F1|= |F2|

C)|F1|< |F2|

D)Dependsonsignofq

F1F2 = 0

Incaseone,bothoftheforcesareworkinginthesamedirecYon(thedownwarddirecYon)resulYnginagreaternetforceasopposedtocasetwowheretherepellingforcesareworkinginoppositedirecYonsinturncancelingeachotherout

Bothcaseshaveachargedplacedequidistantfromchargesofthesamemagnitudessonoma[erchargeqhastheforcesatthisinstantarethesame.Thereisnowaytotelliftheforcesonthecenterchargearerepulsiveora[racYvewithoutknowingthesignofthecentercharge.


Force from Four Charges

Fourchargedpar5clesareplacedasshown.Apar5clewithcharge+Qisplaced1/2waybetweenthemiddle+qontheleTandthe+3qontheright

Whatisthedirec5onofhorizontalforceonQ?

A)leftwardB)noneC)rightward

x

y

3qq

q

q

Q


CheckPoint Results: Force from Four Charges

Fourchargedpar5clesareplacedonacircularringwithradius3masshownbelow.Apar5clewithchargeQisplacedinthecenterofthering

Whatisthedirec5onofhorizontalforceonQ?

A)Fx>0B)Fx=0C)Fx<0

x

y

3q

q qq

Q


Clicker Question: Force from Four Charges

Fourchargedpar5clesareplacedonacircularringwithradius3masshownbelow.Apar5clewithchargeQisplacedinthecenterofthering

Whatisthever&calforceonQ?

A)Fy>0B)Fy= 0 C)Fy<0

Fywouldequal0ifall3ofthebo[omchargeswereontopofeachother,butbecausetheyarepullingatanangle,theywillnotequaltheforceofthe3qchargethatispullingonlyinthe+YdirecYon.

They-direcYoncomponentsalsocanceleachotheroutsincethereisachargeorforceof3QpoinYngbothupwardanddownward.

ThetwoqchargesonthesidealsohaveanxcomponentsotheirFyisnotasgreatthusthesumoftheforcefromthebo[omchargesinsmallerthanthetopcharge.TheforcesarerepulsivesothechargewillhaveanegaYveFy.

x

y


3q

qq

Q

q

electricity magnetism lecture 1: coulomb’s la lecture 01 - coulomb's l… · electricity...

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