Download - Plotting a Graph

Transcript
Page 1: Plotting a Graph

Plotting a Graph

x y y coordinate

0

1

2

3

4

Remember coordinates

are plotted ( , )x y

We can work out points to plot a line

y=2x+3The value of y depends on x

For example:If x=1 then y=2(1)+3 =5

35

7

9

11

2(0)+3

2(1)+3

2(4)+3

2(3)+3

2(2)+3

(0,3)

(1,5)(2,7)

(3,9)

(4,11)

Page 2: Plotting a Graph

y

x

1

1

2

2

3

3

4

4

5

5

6

6

7

7

8

8

9

9

10

10

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

– 6

– 6

– 7

– 7

– 8

– 8

– 9

– 9

– 10

– 10

1

1

2

2

3

3

4

4

5

5

6

6

7

7

8

8

9

9

10

10

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

– 6

– 6

– 7

– 7

– 8

– 8

– 9

– 9

– 10

– 10

2 3y x

x y

0 3

1 5

2 7

3 9

4 11

Page 3: Plotting a Graph

Gradients

Gradient=slope =rate of change =how steep the line is =rise run

y

x

2

2

4

4

6

6

8

8

10

10

– 2

– 2

– 4

– 4

– 6

– 6

– 8

– 8

– 10

– 10

2

2

4

4

6

6

8

8

10

10

– 2

– 2

– 4

– 4

– 6

– 6

– 8

– 8

– 10

– 10

m= 5 2

Page 4: Plotting a Graph

To read a gradient: we start on the line and go up or down first and then back to the line

y

x

1

1

2

2

3

3

4

4

5

5

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

1

1

2

2

3

3

4

4

5

5

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

y

x

1

1

2

2

3

3

4

4

5

5

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

1

1

2

2

3

3

4

4

5

5

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

y

x

1

1

2

2

3

3

4

4

5

5

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

1

1

2

2

3

3

4

4

5

5

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

m= 2/3m= 3/1

m= 3

How’s this graph different from the other 2 graphs?

m= 3/4 ??

m= - 3/4

Page 5: Plotting a Graph

Draw lines with the following gradients

2/3 3 -1/2 -2

1) Decide which way the line goes by the 1) Decide which way the line goes by the + , – sign+ , – sign

2) Count rise and run2) Count rise and run

Page 6: Plotting a Graph
Page 7: Plotting a Graph

Jonathan Climbs a hill. The gradient is 3/2 when he goes uphill, the gradient is -2/5 when he goes downhill. Draw the hill Jonathan climbs. (Assume that it’s a very pointy hill)

Page 8: Plotting a Graph

y

x

1

1

2

2

3

3

4

4

5

5

6

6

7

7

8

8

9

9

10

10

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

– 6

– 6

– 7

– 7

– 8

– 8

– 9

– 9

– 10

– 10

1

1

2

2

3

3

4

4

5

5

6

6

7

7

8

8

9

9

10

10

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

– 6

– 6

– 7

– 7

– 8

– 8

– 9

– 9

– 10

– 10

y= 3x-2y= -x+5y=1/2x+2y= 4-x

Page 9: Plotting a Graph

Gradient Intercept Method

gradient y intercept

y

x

1

1

2

2

3

3

4

4

5

5

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

1

1

2

2

3

3

4

4

5

5

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

y

x

1

1

2

2

3

3

4

4

5

5

6

6

7

7

– 1

– 1

– 2

– 2

– 3

– 3

1

1

2

2

3

3

4

4

5

5

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

3 2y x 2

13

y x

2 points determine a line!!!!!2 points determine a line!!!!!(you need 2 points to draw a line)(you need 2 points to draw a line)

The equation is in the form of y=mx+c

Page 10: Plotting a Graph

y

x

2

2

4

4

6

6

8

8

10

10

– 2

– 2

– 4

– 4

– 6

– 6

– 8

– 8

– 10

– 10

2

2

4

4

6

6

8

8

10

10

– 2

– 2

– 4

– 4

– 6

– 6

– 8

– 8

– 10

– 10

y=3x-2

y=-x+5

y=3 x + 6 5

y=4 - 1x 2

Page 11: Plotting a Graph

Application of linear graphs

Page 12: Plotting a Graph

Applications of GraphsGradient

The gradient is the rate of change of the graph

It is the change in y over the change in x

We can describe it in y units per x unit

Cost$

Timehours

Cost$

Weighttonnes

WaterLevellitres

Time miniutescost

gradienttime

$

hr

charge per hour

costgradient

weight

$

tonne

charge per tonne

water levelgradient

time

litres

minute

water lost per minute

=flow rate

Page 13: Plotting a Graph

meter

days

Water level of a reservoir

Cooking time

hours

kg

Temperature of an item in the freezertemp

minutes

Interpreting Gradient

Gradient=m/day How many meters the water level drops per day

Gradient=hour/kgHow many hours does it take to cook 1 kg of food.

Gradient=temp/min How much the temp dropsper minute

3

4

5

4

5

2

2

5

7

6.5

5

If the equation of the line is y= -x+5How long would it take before the reservoir is empty?

y

x

Page 14: Plotting a Graph

The pizzeria Italiano specializes in selling large size PizzasThe relationship between x ( the number of pizzas they sell) andy (their daily costs) is given by the equation y=10x+50.

a) Draw a graph showing the number of pizzas on the x-axis, and the daily costs on the y x-axis.

b) What are their costs if they sell 8 pizzas?

c) If their costs are $100, how many pizzas did they sell.

d) What’s the y-intercept, What does it represent?

e) Give the gradient. What does it represent?

Page 15: Plotting a Graph

.The time it takes for a block of ice to melt can be represented by a straight-line graph.

x=time (hours)y=volume of the block of ice (litres)

There are two blocks of ice, A and B. The equation for block A is y=6-1/2x. The equation of block B is y=8-xa) Draw the lines for the two blocks of iceb) How large is block A to start with?c) Explain what the y-intercept for block B graph represents?d) When are the two blocks the same volume?e) What do the x-intercepts for the 2 lines tell you?

Page 16: Plotting a Graph

Linear graph revision

Page 17: Plotting a Graph

y

x

2

2

4

4

6

6

8

8

10

10

– 2

– 2

– 4

– 4

– 6

– 6

– 8

– 8

– 10

– 10

2

2

4

4

6

6

8

8

10

10

– 2

– 2

– 4

– 4

– 6

– 6

– 8

– 8

– 10

– 10

Page 18: Plotting a Graph

y

x

2

2

4

4

6

6

8

8

10

10

– 2

– 2

– 4

– 4

– 6

– 6

– 8

– 8

– 10

– 10

2

2

4

4

6

6

8

8

10

10

– 2

– 2

– 4

– 4

– 6

– 6

– 8

– 8

– 10

– 10

Page 19: Plotting a Graph

y

x

2

2

4

4

6

6

8

8

10

10

– 2

– 2

– 4

– 4

– 6

– 6

– 8

– 8

– 10

– 10

2

2

4

4

6

6

8

8

10

10

– 2

– 2

– 4

– 4

– 6

– 6

– 8

– 8

– 10

– 10

Page 20: Plotting a Graph

Parabola factorised form

Page 21: Plotting a Graph

Draw the following parabola

y=3x2

y=(x+2)2 – 4

y=-x2 + 5

y= -(x+3)2 + 2

y

x

1

1

2

2

3

3

4

4

5

5

6

6

7

7

8

8

9

9

10

10

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

– 6

– 6

– 7

– 7

– 8

– 8

– 9

– 9

– 10

– 10

1

1

2

2

3

3

4

4

5

5

6

6

7

7

8

8

9

9

10

10

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

– 6

– 6

– 7

– 7

– 8

– 8

– 9

– 9

– 10

– 10

Page 22: Plotting a Graph

y=(x-2)(x-3)y=(x-2)(x-3)Is it a parabola???Is it a parabola???

Page 23: Plotting a Graph

y

x

1

1

2

2

3

3

4

4

5

5

6

6

7

7

8

8

9

9

10

10

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

– 6

– 6

– 7

– 7

– 8

– 8

– 9

– 9

– 10

– 10

1

1

2

2

3

3

4

4

5

5

6

6

7

7

8

8

9

9

10

10

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

– 6

– 6

– 7

– 7

– 8

– 8

– 9

– 9

– 10

– 10

y=(x-1)(x-5) Step a Find the two x interceptsPut y=0 (x-1)(x-5)=0 x=1 and x=5

Step bFind the y interceptPut x=0y=(0-1)(0-5)y= 5

Step cFind the line of symmetryMid-way between 1 and 5x=(1+5)÷2=3

Step dFind the turning pointSubstitute x=3 into y=(x-1)(x-5) y=(3-1)(3-5) y=2×-2 y=-4Turning point (3,-4)

Page 24: Plotting a Graph

Step (a)Find the x- and y-intercepts by putting y = 0 and x = 0.Step (b) Find the axis of symmetrymidway between the two x-intercepts.Step (c) Find the coordinates of turning point.Substitute the mid-point of two X-intercepts in to the equation to get y

Page 25: Plotting a Graph

This gives the x coordinate, sub it back into

the original equation to find the y coordinate

( 3 1)( 3 5)

( 2)(2)

4 Vertex ( 3, 4)

y

y

x

1

1

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

– 6

– 6

– 7

– 7

– 8

– 8

1

1

2

2

3

3

4

4

5

5

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

2) Cuts axis 0

(0 1)(0 5)

1 5

5

y x

y

y

y

Parabolas in factorised form

1) Cuts axis 0

( 1)( 5) 0

1 0, 5 0

1, 5

x y

x x

x x

x x

y

x

1

1

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

– 6

– 6

– 7

– 7

– 8

– 8

1

1

2

2

3

3

4

4

5

5

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

3) To find the vertex.

This must be half way between the x intercepts

-5 -1 63

2 2x x x

( 1)( 5)y x x

To find the symmetry

Page 26: Plotting a Graph

y

x

1

1

2

2

3

3

4

4

5

5

6

6

7

7

8

8

9

9

10

10

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

– 6

– 6

– 7

– 7

– 8

– 8

– 9

– 9

– 10

– 10

1

1

2

2

3

3

4

4

5

5

6

6

7

7

8

8

9

9

10

10

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

– 6

– 6

– 7

– 7

– 8

– 8

– 9

– 9

– 10

– 10

y=(x-4)(x+2) Step (a)Find the x-intercepts by putting y = 0 Step Step (b) Find the y-intercept by putting x=0Step (c)Find the axis of symmetrymidway between the two x-intercepts.Step (d) Find the coordinates of turning point.( , )Substitute the mid-point of two X-intercepts in to the equation to get y

Page 27: Plotting a Graph

y

x

1

1

2

2

3

3

4

4

5

5

6

6

7

7

8

8

9

9

10

10

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

– 6

– 6

– 7

– 7

– 8

– 8

– 9

– 9

– 10

– 10

1

1

2

2

3

3

4

4

5

5

6

6

7

7

8

8

9

9

10

10

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

– 6

– 6

– 7

– 7

– 8

– 8

– 9

– 9

– 10

– 10

y=(x-4)(x+2) Step a Find the two x interceptsPut y=0 (x-4)(x+2)=0 x=4 and x=-2

Step bFind the y interceptPut x=0y=(0-4)(0+2)y= -8

Step cFind the line of symmetryMid-way between 2 and -3x=(4+-2)÷2=1

Step dFind the turning pointSubstitute x=1 into y=(x-4)(x+2) y=(1-4)(1+2) y=-3×3 y=-9Turning point (1,-9)

Page 28: Plotting a Graph

y

x

1

1

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

– 6

– 6

– 7

– 7

– 8

– 8

1

1

2

2

3

3

4

4

5

5

6

6

7

7

8

8

9

9

– 1

– 1

2

1) Cuts axis 0

( 3) 0

3 0

3

x y

x

x

x

2( 3)y x

2

2) Cuts axis 0

(0 3)

3

9

y x

y

y

y

y

x

1

1

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

– 6

– 6

– 7

– 7

– 8

– 8

1

1

2

2

3

3

4

4

5

5

6

6

7

7

8

8

9

9

– 1

– 1

4) Turning point is at (-3,0)

3) Line of symmetry is at y=-3

Page 29: Plotting a Graph

P259

14.3

Q1 and Q5

Page 30: Plotting a Graph
Page 31: Plotting a Graph

The sketch shows the functiony = x(x - 2)

(a) What are the coordinates of A?(b) What are the coordinates of B?(c) What is the equation of m?(d) What are the coordinates of the turning point of the curve?(e) What is the minimum value of the function? 

The sketch shows the functiony = (x-2)(x+3)

(a) What are the coordinates of A?(b) What are the coordinates of B?(c) What is the equation of D?(d) What are the coordinates of the turning point of the curve?(e) What is the minimum value of the function? 

Page 32: Plotting a Graph

Match up each of the graphs with the following functions

(a) y = x2 - 2

(b) y - 2 = (x + 1)2

(c) y = (x + 2)(x - 1)

(i)                         (ii)                        

(iii)

                        (iv)                        

(v)                         (vi)                        

(d) y = (x - 2)(x + 1)

(e) y = - x2 + 2

(f) y = x2 + 2

Page 33: Plotting a Graph

y

x

1

1

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

– 6

– 6

– 7

– 7

– 8

– 8

1

1

2

2

3

3

4

4

5

5

6

6

7

7

8

8

9

9

– 1

– 1

2

1) Cuts axis 0

( 3) 0

3 0

3

x y

x

x

x

2( 3)y x

2

2) Cuts axis 0

(0 3)

3

9

y x

y

y

y

y

x

1

1

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

– 6

– 6

– 7

– 7

– 8

– 8

1

1

2

2

3

3

4

4

5

5

6

6

7

7

8

8

9

9

– 1

– 1

4) Turning point is at (-3,0)

3) Line of symmetry is at y=-3

Page 34: Plotting a Graph

Parabola applications

Page 35: Plotting a Graph

x-intercept:(0,0)Y-intercept:NoneVertex:(0,0)

x-intercept:(-4,0) (0,0)y-intercept:(0,0)Vertex:(-2, -4)

y

x

1

1

2

2

3

3

4

4

5

5

6

6

7

7

8

8

9

9

10

10

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

– 6

– 6

– 7

– 7

– 8

– 8

– 9

– 9

– 10

– 10

1

1

2

2

3

3

4

4

5

5

6

6

7

7

8

8

9

9

10

10

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

– 6

– 6

– 7

– 7

– 8

– 8

– 9

– 9

– 10

– 10

X-intercpet:(-3,0) (3,0)Y-intercpet:(0,5)Vertex:(5,0)

Alternatively Draw parabola:y= x2 + 2x - 8

Find

1) X intercepts2) Y intercept3) Vertex (turning point)

Page 36: Plotting a Graph

For the helicopter to fly above the rainbow parabola, how high must the helicopter fly? (In other words what is the maximum value of the parabola)

Page 37: Plotting a Graph

Problem 2) Nick threw a ball out of a window that is 4 units high. The position of the ball is determined by the parabola y = -x² + 4.At how many feet from the building does the ball hit the ground?

You need to draw a parabola

There are two solutions. 2 and − 2.

This picture assumes that Nick threw the ball to the rightso that the balls lands at 2 feet away from the building.

Page 38: Plotting a Graph

Problem 4) A ball is dropped from a height of 36 feet. The quadratic equation d = -t² + 36 provides the distance, d, of the ball, after t seconds. After how many seconds, does the ball hit the ground?

d

t

d = -t² + 36

When the ball hits the groundd=0So we are looking for X intercpt

0= -t² + 36t= ±6

t=-6 is not a sensible answerSo t=6After 6 seconds

?

Page 39: Plotting a Graph

The stream of water from a fountain can be modelled by a parabola with equation:

H=(2 -d)( 1+d ) H is the height of the water

stream above the ground and d is the distance from the wall (both in meters)

a) Calculate the height of the fountain’s spout.

b) How far from the wall does the water stream hit the ground?

c) Blake stands 1.3m from the wall. He is 1.7m tall. Will he get wet ?

H

d

Wall

ground1.3

Page 40: Plotting a Graph

Equation for parabola

Page 41: Plotting a Graph

In an instantWhat do you know about the

following three parabola?

y=(x-3)(x-4) y=(x-2)2 + 3y=x2

Page 42: Plotting a Graph

Write an equation for a parabola There are 2 forms of parabola

y=(x+a)(x+b) y=(x+1)(x-3)

When you know x-intercepts

y=(x-a)2 + by=(x-4)2 + 1

When you know the turning point

3-1

4

1(4,1)

Page 43: Plotting a Graph

a cb

g

3-3

-3 1

e f

h i

d

-3

1

-3

3-13

3

1

-3 -1

Page 44: Plotting a Graph

j

-3 -1

k

3

1

l

3

m

3

n

-3

Page 45: Plotting a Graph

End of the year revision

Page 46: Plotting a Graph

0 1 2 3 4 5 6 7 8 9 10-9 -8 -7 -6 -5 -4 -3 -2 -1-10 x

y

1

2

3

4

5

6

7

8

9

10

-1

-2

-3

-4

-5

-6

-7

-8

-9

-10

y = x

y = 2x

Drawing Straight Line Graphs

y = -2/3x+4

y = 7

x=-7

Page 47: Plotting a Graph

0 1 2 3 4 5 6 7 8 9 10-9 -8 -7 -6 -5 -4 -3 -2 -1-10 x

y

1

2

3

4

5

6

7

8

9

10

-1

-2

-3

-4

-5

-6

-7

-8

-9

-10

3y-2x=12Intercept Method

2y+4x=8

Page 48: Plotting a Graph

741 2 3 5 6 8 100

1

2

3

4

5

6

7

8

9

10

9 x

All straight lines have the equation of the form

y = ax + b

GradientWhere linemeets y-axis

y

ww

w.m

ath

srevis

ion

.com

Straight Line Equation

Find the equations of the following lines

y = x y = x+4

Line are parallel same

gradient

y = 4x+2 y = -2x+2

Page 49: Plotting a Graph

10 20 30 400

10

20

30

40

50

50 E

CQ1. Find the connection between

cost (C) and electricity used (E)

Since line passes through 15 on the y-axis b =15

Gradient a =35 15 20 1

40 0 40 2

y

x

Equation is

ww

w.m

ath

srevis

ion

.com

GeneralStraight Line Equation

115

2C E

Page 50: Plotting a Graph

10 20 30 400

10

20

30

40

50

50 T

WQ2. The graph shows the

connection between water flowing out of a tank (W)and time (T)

Since line passes through 40 on the y-axis b = 40

Gradient a =40

140

y

x

Equation is

ww

w.m

ath

srevis

ion

.com

GeneralStraight Line Equation

40W T

Downward slope

Page 51: Plotting a Graph

If we add a number in the brackets graph is shifted horizontallyIf we add a number at the end, the graph is shifted vertically

y

x

1

1

2

2

3

3

4

4

5

5

6

6

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

– 6

– 6

– 7

– 7

– 8

– 8

1

1

2

2

3

3

4

4

5

5

6

6

7

7

8

8

9

9

10

10

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

2( 3) 4y x

2( 2) 5y x

2( 1) 2y x

y

x

y

x

y

x

y

x

Page 52: Plotting a Graph

y

x

1

1

2

2

3

3

4

4

5

5

6

6

7

7

8

8

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

– 6

– 6

1

1

2

2

3

3

4

4

5

5

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

– 6

– 6

– 7

– 7

– 8

– 8

– 9

– 9

– 10

– 10

We can also translate the reflected graphs

2 4y x

2( 2) 3y x

y

x

y

x

y

x

Page 53: Plotting a Graph

y=3x2

y=-1/2x2

y

x

1

1

2

2

3

3

4

4

5

5

6

6

7

7

8

8

9

9

10

10

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

– 6

– 6

– 7

– 7

– 8

– 8

– 9

– 9

– 10

– 10

1

1

2

2

3

3

4

4

5

5

6

6

7

7

8

8

9

9

10

10

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

– 6

– 6

– 7

– 7

– 8

– 8

– 9

– 9

– 10

– 10

Page 54: Plotting a Graph

y

x

1

1

2

2

3

3

4

4

5

5

6

6

7

7

8

8

9

9

10

10

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

– 6

– 6

– 7

– 7

– 8

– 8

– 9

– 9

– 10

– 10

1

1

2

2

3

3

4

4

5

5

6

6

7

7

8

8

9

9

10

10

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

– 6

– 6

– 7

– 7

– 8

– 8

– 9

– 9

– 10

– 10

y=(x-4)(x+2) Step (a)Find the x-intercepts by putting y = 0 Step Step (b) Find the y-intercept by putting x=0Step (c)Find the axis of symmetrymidway between the two x-intercepts.Step (d) Find the coordinates of turning point.( , )Substitute the mid-point of two X-intercepts in to the equation to get y

Page 55: Plotting a Graph

y

x

1

1

2

2

3

3

4

4

5

5

6

6

7

7

8

8

9

9

10

10

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

– 6

– 6

– 7

– 7

– 8

– 8

– 9

– 9

– 10

– 10

1

1

2

2

3

3

4

4

5

5

6

6

7

7

8

8

9

9

10

10

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

– 6

– 6

– 7

– 7

– 8

– 8

– 9

– 9

– 10

– 10

y=(x-4)(x+2) Step a Find the two x interceptsPut y=0 (x-4)(x+2)=0 x=4 and x=-2

Step bFind the y interceptPut x=0y=(0-4)(0+2)y= -8

Step cFind the line of symmetryMid-way between 2 and -3x=(4+-2)÷2=1

Step dFind the turning pointSubstitute x=1 into y=(x-4)(x+2) y=(1-4)(1+2) y=-3×3 y=-9Turning point (1,-9)

Page 56: Plotting a Graph

y

x

1

1

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

– 6

– 6

– 7

– 7

– 8

– 8

1

1

2

2

3

3

4

4

5

5

6

6

7

7

8

8

9

9

– 1

– 1

2

1) Cuts axis 0

( 3) 0

3 0

3

x y

x

x

x

2( 3)y x

2

2) Cuts axis 0

(0 3)

3

9

y x

y

y

y

y

x

1

1

– 1

– 1

– 2

– 2

– 3

– 3

– 4

– 4

– 5

– 5

– 6

– 6

– 7

– 7

– 8

– 8

1

1

2

2

3

3

4

4

5

5

6

6

7

7

8

8

9

9

– 1

– 1

4) Turning point is at (-3,0)

Page 57: Plotting a Graph
Page 58: Plotting a Graph
Page 59: Plotting a Graph
Page 60: Plotting a Graph

Top Related