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  • given

    y 1 exp 0.011 Ms Ti( )[ ]=

    find Ti( ) Ms 90.909090909090909091 ln 1. y 1.( )

    Ms 314

    Ti y( ) Ms 90.909090909090909091ln 1 y( )

    1yTi y( )lim

    0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8 2400

    320

    240

    160

    80

    0

    80

    160

    240

    320

    400

    Ti y( )

    y


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