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Page 1: Doc1 - 阿超數學、國中數學 · 2017-07-05 · 79 : aabc ac bc 12 ; hijaabc ? 109 80 , aabc , d f def ? 81 aabc , zb=900 bc ac , ? -28- : ' i ' ab ac 17.3c tac ; ? 092 : Ãaaabc#

Page 2: Doc1 - 阿超數學、國中數學 · 2017-07-05 · 79 : aabc ac bc 12 ; hijaabc ? 109 80 , aabc , d f def ? 81 aabc , zb=900 bc ac , ? -28- : ' i ' ab ac 17.3c tac ; ? 092 : Ãaaabc#

Page 3: Doc1 - 阿超數學、國中數學 · 2017-07-05 · 79 : aabc ac bc 12 ; hijaabc ? 109 80 , aabc , d f def ? 81 aabc , zb=900 bc ac , ? -28- : ' i ' ab ac 17.3c tac ; ? 092 : Ãaaabc#

Page 4: Doc1 - 阿超數學、國中數學 · 2017-07-05 · 79 : aabc ac bc 12 ; hijaabc ? 109 80 , aabc , d f def ? 81 aabc , zb=900 bc ac , ? -28- : ' i ' ab ac 17.3c tac ; ? 092 : Ãaaabc#

Page 5: Doc1 - 阿超數學、國中數學 · 2017-07-05 · 79 : aabc ac bc 12 ; hijaabc ? 109 80 , aabc , d f def ? 81 aabc , zb=900 bc ac , ? -28- : ' i ' ab ac 17.3c tac ; ? 092 : Ãaaabc#

Page 6: Doc1 - 阿超數學、國中數學 · 2017-07-05 · 79 : aabc ac bc 12 ; hijaabc ? 109 80 , aabc , d f def ? 81 aabc , zb=900 bc ac , ? -28- : ' i ' ab ac 17.3c tac ; ? 092 : Ãaaabc#

Doc1 - mp3ktv.huhu.tw · 105 : , , zb>oo aabcá9 ac < bcu, zi>zb z2 3 z4 : +Ãiihi ab bc z , Äljzbpc (a) 55 (b) 600 (c) 80 (d) 130 550 : aabc#s ab < ac , (b) zc (c) Ža75q0

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Doc1 · 2017. 7. 5. · (1) (2) (3) (1) (2) (3) (4) ab//cd//ef//gh cd gh ab cda ef gh adef aabc ph b bc , lb—300 zc=900 ab —12 16 12 105 : , aabc ac 3 00 4 450 eau bc' + ect =

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阿超數學、國中數學 - Doc1mp3ktv.huhu.tw/all t cool/4-3-3/questiom/Doc2.pdf · 109. )110. )111. )112. )113. )115. ) 116. )117. )118. AABC ' A > Z B > LC ' ? (A) (B)

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Doc1 - mp3ktv.huhu.tw · ad —1 2m zbac—900 ; ab + bc cd 4m. z bac-=900 ; 68 : , aabc# , zbaf= zcae lac , —12 ac —16 , 69 : Ãaaabc ac=6 ; : 061 -25- be—cf de—df , +

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medmateiasi.files.wordpress.com · 2015-10-08 · Construiÿi un triunghi ascutitunghic AABC cu AB = 8 cm si AC — 12 cm. Media- toarea laturii [BC] intersecteazä [ACJ în D. Calculati

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Doc1 - mp3ktv.huhu.tw · 131 : ' aabc 0 aic' —16 , . (2) aabc 132 : , aa b 'c o ab —12 ' ' hijaa 'b 'c ? ac —15 133: cd o ab 0b =2y-3 oc =y+3 01) — 10x+2 cd —16 ?

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