do an dialux (ok)

N MN HC 1

GVHD : TRN THANH SN

LI NHN XT CA GIO VIN ............................................................................................. ............................................................................................. ............................................................................................. ............................................................................................. ............................................................................................. ............................................................................................. ............................................................................................. ............................................................................................. ............................................................................................. ............................................................................................. ............................................................................................. ............................................................................................. ............................................................................................. ............................................................................................. ............................................................................................. ............................................................................................. ............................................................................................. ............................................................................................. ............................................................................................. ............................................................................................. ............................................................................................. ............................................................................................. .............................................................................................TP.HCM, thng 01 nm 2010 Ging vin hng dn. K tn:

N MN HC 1

GVHD : TRN THANH SN

MC LCLi m u.............................................................................................................Trang 1. Li nhn xt ca gio vin.....................................................................................Trang 2. Mc lc...................................................................................................................Trang 3. Chong I: Xc nh tm ph ti tnh ton. ..........................................................Trang 4. Chong II: Tnh ton chiu sng........................................................................ Trang 8. Chong III: Xc nh ph ti tnh ton............................................................... Trang 23. Chong IV: Tnh ton chn my bin p. ...........................................................Trang 38. Chong V: Chn dy dn v thit b bo v........................................................ Trang 40. Chong VI: Kim tra st p cho cc thit b tiu th in.................................. Trang 63. Chong VII: Tnh ton ngn mch cho phn xng........................................... Trang 70. Chong VIII: Chn t b cho phn xng. ........................................................Trang 75.

N MN HC 1

GVHD : TRN THANH SN

Chng I Xc nh tm ph tiI. Xc nh tm ph ti cho t ng lc

1. Mc ch Vic t t ng lc tm ph ti nhm cung cp in p v tn hao cng sut nh nht v chi ph kim loi mu hp l 2. Xc nh tm ph ti t ng lc: Ta tm ph ti c th xc nh theo cng thc sau:Xo =

Pdmi X ii =1 n

n

Pi =1

; Yo =

Pi =1 n i =1

n

dmi i

Y

dmi

P

dmi

Vi : X i : Ta ca thit b th i theo trc honh.Yi : Ta ca thit b th i theo truc tung. X o : Ta ca t ng lc th n theo trc honh. Yo : Ta ca t ng lc th n theo trc tung.

Xc nh tm ph ti ca phn xng bao gm vic xc nh tm ph ti ca tng nhm thit b chn ni t t ng lc, xc nh tm ph ti ca ton phn xng chn ni t t phn phi. Nhm I K hiu S Cng sut Tn thit b X(m) Y(m) mt bng lng (KW) 1.1 My phay rng 1 4.5 203 162 1.2 My phay rng 1 4.5 203 155 2.1 My phay rng 1 4.5 202 148 2.2 My phay rng 1 4.5 215 148 3.1 My xc 1 2.8 214 162 3.2 My xc 1 2.8 214 156 4.1 My bo ngang 1 4.5 223 162 4.2 My bo ngang 1 4.5 223 162 5 My bo ngang 1 4.5 192 153 6 My mi trn vn nng 1 4.5 183 186 7 My mi th 1 2.3 169 160 9.3 My khoan ng 1 4.5 168 170 13 My tin ren 1 20 191 177

N MN HC 1

GVHD : TRN THANH SN

14

My tin ren Tng nhm 2

1 14Y

20 88.4

201

176

X1 =

Pdmi X ii =1 14

14

Pi =1

= 198 ; Y1 =

Pi =1 14 i =1

14

dmi i

dmi

P

= 167

dmi

Ta di tm t ng lc cho ph hp vi mt bng : Vy ta ca t th nht l P1(159,167) Nhm II K hiu mt bng 9.1 9.2 10 11 12 15 16 17 Tn thit b My khoan ng My khoan ng My ca kiu i My phay vn nng My phay vn nng My tin ren My tin ren My tin ren Tng nhm 1 S lng 1 1 1 1 1 1 1 1 8Y

Cng sut X(m) (KW) 4.5 167 4.5 183 1 168 7 186 7 181 20 198 20 208 20 221 84

Y(m) 186 186 203 203 177 201 203 189

X2 =

Pdmi X ii =1 8

8

Pi =1

= 200 ; Y2 =

Pi =1 8 i =1

8

dmi i

dmi

P

= 195

dmi

Ta di tm t ng lc cho ph hp vi mt bng : Vy ta ca t th nht l P2(158,195) Nhm 3 K hiu Tn thit b mt bng 18 20.1 20.2 20.3 21 23 19 26 My tin ren My co My co My co Cu trc B du tng nhit My mi th My khoan bn S ln g 1 1 1 1 1 1 1 1 Cng sut X(m) (KW) 20 1 1 1 24.2 8.5 2.8 0.85 269 245 254 266 250 261 254 277 Y(m) 218 203 199 204 220 220 206 218

N MN HC 1

GVHD : TRN THANH SN

30

My mi ph Tng nhm 39

1 9

2.8 62.15

266

195

X3 =

Pdmi X ii =1 9

Pi =1

= 259 ; Y3 =

Pi =1 9 i =1

9

dmi i

Y

dmi

P

= 216

dmi

Ta di tm t ng lc cho ph hp vi mt bng : Vy ta ca t th nht l P3(259,225) Nhm 4 K hiu mt bng 27 31 32.1 32.2 32.3 33.1 33.2 34 35 36 37 38 39.1 39.2 40 Tn thit b My hn in My khoan ng My khoan ng My khoan ng My khoan ng My ct ren lin hp My ct ren lin hp Qut l rn My cun dy My cun dy B ngm c tng nhit B ngm c tng nhit B ngm dung dch kim B ngm dung dch kim T sy Tng nhm 4= 290 ; Y4 =

S lng 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 15

Cng sut X(m) (KW) 25 280 4.5 297 4.5 297 4.5 302 4.5 289 1.7 310 1.7 310 1.5 305 1.2 307 1.2 302 4 300 4 294 3 289 3 289 3 290 67.3

Y(m) 211 206 196 206 202 207 197 213 221 220 220 219 195 218 209

X4 =

Pdmi X ii =1 15

15

Pi =1 15 i =1

15

dmi i

Y

Pi =1

dmi

P

= 209

dmi

Ta di tm t ng lc cho ph hp vi mt bng : Vy ta ca t th nht l P4(290,225) II. XC NH TM PH TI CHO T PHN PHI CHNH: STT1 2 3 4

TN THIT B T ng lc I T ng lc II T ng lc III T ng lc IV

Pm (kw)84 88.4 62.15 67.3

X(m)200 198 259 290

Y(m)195 167 216 209

N MN HC 1

GVHD : TRN THANH SN

TngX=

301.85

Pi =1 4 i =1

4

dmi

Xi

P

= 231 ; Y =

Pi =1 4 i =1

4

dmi i

Y

dmi

P

= 194

dmi

Ta di tm t phn phi cho ph hp vi mt bng : v pha tng v c ta mi Vy ta ca t phn phi chnh l : P (231;235) Bng tng kt v tr t t phn phi v t ng lc STT1 2 3 4

5

TN THIT B T ng lc I T ng lc II T ng lc III T ng lc IV T phn phi

Pm (kw)84 88.4 62.15 67.3

X(m)200 198 259 290

Y(m)195 167 216 209

301.85

231

235

N MN HC 1

GVHD : TRN THANH SN

CHNG II : TNH TON CHIU SNG THC TI. TNH TON BNG CNG THC 1. Kch thc chiu di : a = 40m chiu rng : b = 25m chiu cao : c = 4m din tch : S=a .b = 40 . 25 = 1000m 2 2. Mu sn Trn : mu trng => h s phn x Ptrn = 0.75 Tng : vng nht =>h s phn x Ptng = 0.5 Nn : xi mng =>h s phn x Pnn = 0.3 3. ri yu cu Etc = 300lux 4. Chn h chiu sng : chung u 5. Chn khong nhit mu : Theo ng cong kruithof, ta chn Tm = 3000 ( 0 K ) 6. Chn bng n : Loi bng n hunh quang. Tm = 3000 ( 0 K ) Ra = 85 ; P = 36w; = 2500(lm) 7. Chn b n Loi RI 202 Cp b n : RI - GT Cp hiu sut : 0.81E S n/1 b = 1 cc bng/1 b : 2500 x 2 = 2500 (lm) Ldc max = 1,6 . htt ; Lngang max = 2 . htt 8. Phn b cc b n Cch trn : h = 0m B mt lm vic : 0.8m Chiu cao treo n so vi b mt lm vic : h tt = 4-(0.8+0)=3.2(m) 9. Ch s a imk= a.b 40 25 = = 4.8 htt 3.2 (40 + 25)

N MN HC 1 10. Tinh h s bu -

GVHD : TRN THANH SN

Chon h s suy giam quang thng 1 = 0.8 Chon h s suy giam do bam bui 2 = 0.9 H s bu :d= 1 1 = = 1.4 1 + 2 0.8 0.9

-

11. Ti s treoj= h' 0 = =0 h '+ h tt 0 + 3.2

12. H s s dung U=0.81 1.05 = 0.85 13. Quang thng tng tong =Etc .S .d 300.1000.1, 4 = = 494117 U 0.85 494117 = 98.8 (b) 5000

14. Xac inh s b en N ben =

cacbong /1ben

=

Chon s b en : N ben = 99 15. Kim tra sai s quang thng: N ben cacbong /1b en = 99 5000 494117 = 1.7 103 = 494117 => % = 1,57 % Kt lun : s b en thoa ( nm trong khoang -10% 20%) 16. Kim tra roi trung binh cua b mt lam vic N ben cacbong /1b en U 99 5000 0.85Etb = S d = 1000 1.4

= 300.5(lux)

Nhn xet : E tb >E tc =300 lux, thoa man yu cu v roi 17. Phn b cac b en Theo cp b en a chon ta co :L 1,5 => L < 1,5 htt = 1,5 3, 2 = 4.8m htt

Chon khoang cach cac en theo chiu doc la : Ld = 3.6m

N MN HC 1 Ld L 2.2 2.2 N a d Na 3 2 3 2

GVHD : TRN THANH SN

Khoang cach t en n tng thoa man :

Chon N a =1(m) Tng t ta chon khoang cach cac en theo chiu ngang la : Ln = 2.7 Khoang cach t en n tng b thoa manLn L 2.8 2.8 N a n Nb 3 2 3 2

Chon Nb = 1.3(m) Ta chia thanh 9 day en theo chiu ngang va 11 day en theo chiu doc 18. Cng sut chiu sang cua cac en - Cng sut tac dungPcs = N P (Kw)

Vi N : s bong en => Pcs =99 2 36 = 7128W= 7.128(KW) - Cng sut phan khang Qcs = Pcs tg (KVAR) Vi cos =0.8=> tg =0.75 => Qcs = 7.128 0.75 = 5.346 (KVAR) - Cng sut biu kin2 S = Pcs + Qcs 2 = 7.1282 + 5.3462 = 8.91 (KW)

TNH TON BNG PHN MM DIALUX B1 : khi ng dialuxII.

Vao startdialuxall programedialuxdialux 4.7

N MN HC 1

GVHD : TRN THANH SN

Hnh 2.1 B2 : chon new iteritor project

Hnh 2.2 B4 : Nhp kich thc cho ban ve

N MN HC 1

GVHD : TRN THANH SN

Hnh 2.3 B5 : tao ca ra vao - Ta vao objectwindow and doorchon biu tng ca ra vao - nhp toa thch hp

Hnh 2.4 - vo position/size thay i kch thc ca cho ph hp

N MN HC 1

GVHD : TRN THANH SN

Hnh 2.5 Bc 6 : To ca s - Ta vao objoctwindow and doorchon biu tng ca s - nhp toa thch hp

Hnh 2.6 - vo position/size thay i kch thc ca cho ph hp

N MN HC 1

GVHD : TRN THANH SN

Hnh 2.7 Bc 6 : thm cac i tng lam vic. y ta ly ban lam tng trng-

vao objectindoorfurniturtable Chon loai ban thich hp theo y chung ta

-

Hnh 2.8 Nhp kich thc va toa cho phu hp vi yu cu lam vic thc t

N MN HC 1

GVHD : TRN THANH SN

Hnh 2.9 Bc 6 : chon loai bong en s dung chiu sang Vao luminairedialux catalogclause

Hnh 2.10-

Vi la phn xng c khi nn ta chon loai en chiu sang trong cng nghip, ta chon industrial lightingChon loai en RI, 1052093- 36w

N MN HC 1

GVHD : TRN THANH SN

-

Sau khi a chon loai en se s ta click chut vao use in dialux

Hnh 2.11 Bc 7 : chon kiu phn b chiu sang-

Ta chon kiu phn b chung u : Vao pasteluminaire arrangemantfield arrangemant

-

Hnh 2.12 Trong mc luminous ta nhp quang thng l 5000 Lm Trong mc power ta cng sut b n l 72 W

N MN HC 1

GVHD : TRN THANH SN

Hnh 2.13 - th Mounting, ti mc Rough calculation ta chn ri tiu chun l 300 lux. Sau ta chn insert lp t n

H2.14 - Hnh nh sau khi lp t n

N MN HC 1

GVHD : TRN THANH SN

H2.15 - mun n sng hay tt ta chn 3D light distribution dislay

Hnh 2.16 Bc 8 : tinh toan

N MN HC 1

GVHD : TRN THANH SN

Ta vao outputstart calculation

-

Hinh 2.17 ta chn all tnh ton tt c

Hnh 2.18

N MN HC 1

GVHD : TRN THANH SN

- Chn ok v ch cho my tnh ton

Hinh 2.19 Bc 9 : xut kt qua Ta vao outputproject 1 la chn nhng bng s liu cn thit xut

Hinh 2.20

N MN HC 1

GVHD : TRN THANH SN

Luminaire data sheet (a) : thng s ca b n

Hnh 2.21 Luminaire data sheet (b)

Hnh 2.22

N MN HC 1

GVHD : TRN THANH SN

Summary : cho ta bit s b n, quang thng tng v tng cng sut cc b n

Hinh 2.23 Luminaire parts list : thng s ca mt b n

H2.24

N MN HC 1

GVHD : TRN THANH SN

Khong cch gia cc b n

H2.25 Luminaires (coordinates list : s mt bng v ta ca tng bng n

Hinh 2.26

N MN HC 1

GVHD : TRN THANH SN

- Coordinates lists : s mt bng v to ca cc i tng lam vic trong phn xng

H2.27 Bng so snh kt qu gia tnh ton bng tay v bng phn mm dialux Tnh ton bng tay 99 494117 300.5 lux Tnh ton bng dialux 99 49500 300 lux

S b n Quang thng ri trung bnh

N MN HC 1

GVHD : TRN THANH SN

CHNG III : XC NH PH TI TNH TONI. MC CH Xc nh ph ti tnh ton lm c s gip ta la chn dy dn v cc thit b trong li mt cch hiu qu nht. gim thiu ti a hao ph cng nh nng cao tnh kinh t ca h thng III. XC NH PH TI TNH TON A. i vi t ng lc 1 K hiu 1.1 1.2 2.1 2.2 3.1 3.2 4.1 4.2 5 6 7 9.3 13 14 THIT B My phay rng My phay rng My phay rng My phay rng My xc My xc My bo ngang My bo ngang My bo ngang My mi trn vn nng My mi th My khoan ng My tin ren My tin ren Tng nhm 2 1 . Cng sut t nhm 1:Pdat nh1 = 8

S Lng 1 1 1 1 1 1 1 1 1 1 1 1 1 1 14

Pm (kw) 4.5 4.5 4.5 4.5 2.8 2.8 4.5 4.5 4.5 4.5 2.3 4.5 20 20 88.4

0.8 0.8 0.8 0.8 0.8 0.8 0.8 0.8 0.8 0.8 0.8 0.8 0.8 0.8

Pt 1tb (kw) 5.625 5.625 5.625 5.625 3.5 3.5 5.625 5.625 5.625 5.625 2.875 5.625 25 25 110.5

Pt tng tb (kw) 5.625 5.625 5.625 5.625 3.5 3.5 5.625 5.625 5.625 5.625 2.875 5.625 25 25 110.5

Ksd 0.2 0.2 0.2 0.2 0.2 0.2 0.2 0.2 0.2 0.2 0.2 0.2 0.2 0.2

cos 0.75 0.75 0.75 0.75 0.75 0.75 0.75 0.75 0.75 0.75 0.75 0.75 0.78 0.78

i =1

Pdati =5.625+5.625+5.625+5.625+3.5+3.5+5.625+5.625

+5.625+5.625+2.875+5.625+25+25 = 110.5 (kw) 2. Dng in nh mc ca cc thit b trong nhm 1: Um=380 (v) - Dng in nh mc ca mi my 1.1: Im=Pdat 5.625 103 = = 11.4 (A) 3 U dm cos 3 380 0.75

- Dng in nh mc ca mi my 1.2:

N MN HC 1

GVHD : TRN THANH SN

Im=

Pdat 5.625 103 = = 11.4 (A) 3 U dm cos 3 380 0.75 Pdat 5.625 103 = = 11.4 (A) 3 U dm cos 3 380 0.75 Pdat 5.625 103 = = 11.4 (A) 3 U dm cos 3 380 0.75 Pdat 3.5 103 = = 7 (A) 3 U dm cos 3 380 0.75 Pdat 3.5 103 = = 7 (A) 3 U dm cos 3 380 0.75 Pdat 5.625 103 = = 11.4 (A) 3 U dm cos 3 380 0.75 Pdat 5.625 103 = = 11.4 (A) 3 U dm cos 3 380 0.75 Pdat 5.625 103 = = 11.4 (A) 3 U dm cos 3 380 0.75 Pdat 5.625 103 = = 11.4 (A) 3 U dm cos 3 380 0.75 Pdat 2.875 103 = = 5.82 (A) 3 U dm cos 3 380 0.78 Pdat 5.625 103 = = 11.4 (A) 3 U dm cos 3 380 0.75

- Dng in nh mc ca mi my 2.1: Im=






- Dng in nh mc ca mi my 5: Im=




- Dng in nh mc ca mi my 13:

N MN HC 1

GVHD : TRN THANH SN

Im=

Pdat 25 103 = = 50 (A) 3 U dm cos 3 380 0.75 Pdat 25 103 = = 50 (A) 3 U dm cos 3 380 0.75

- Dng in nh mc ca mi my 14: Im=3. H s s dng nhm 1: k sd nh1 =

ki =1

14

sdi

Pdatidati

Pi =1

14

=

22.1 = 0.2 110.5

4. S thit b hiu qu ca nhm 1 : nhqnh1 = ( Pdati ) 2i =1 14 14

Pi =1

=

2 dati

12210.25 = 7.7 1567.531

5. H s cng sut nhm 1 : cos =

(Pi =1

14

dat i

cosi )dati

Pi =1

14

=

84.375 = 0.76 110.5

tg = 0.85

6. Cng sut trung bnh ca nhm 1: a. Cng sut tc dng trung bnh ca nhm 1:

Ptb nh2= Ksd nh2 Pdt nh2= 0.2 110.5 =22.1 (KW) b. Cng sut phn khng trung bnh ca nhm 1: Qtb nh2 = tg nh2 Ptb nh2 =0.85 22.1 =17.875 (KVar)7. Ph ti tnh ton ca nhm 1 : a. Cng sut tnh ton ca nhm 1:

Do nhq nh1 =7.7 > 4 v s thit b thc t ln hn 6 nn ta tnh ton nh sau : Vi Ksd =0.2 v nhq nh1 = 7.7 tra bng A.2 trang 9 (Sch HD n Mn Hc Thit K Cung Cp in) ta c : Kmax = 2.1Ptt = kmax ksd nh1 P = 2.1 0.2 110.5 = 46.41 (Kw) dmii =1 14

N MN HC 1

GVHD : TRN THANH SN

b. Cng sut phn khng tnh ton ca nhm 1:

Qtt nh1 =Ptt tg nh1 =46.41 0.85 =39.5 (KVar)c. Cng sut biu kin tnh ton ca nhm 1: Stt = P 2 + Q 2 = 46.412 + 39.52 = 60.9 (KVA) 8. Dng in tnh ton ca nhm 1 : Stt 60.9 103 I tt = = = 92.5 (A) 3 U dm 3 380 9. Dng in nh nhn ca nhm 1 :

Chon k mm =4.5 In = Itt + Ikmax Ksd Im M = Itt + (Kmm Ksd ) Im M = 92.5 + 4.5 50 = 317.5 (A) i vi t ng lc 2 Pt 1tb Pt tng tb S Pm THIT B Ksd Lng (kw) (kw) (kw) My khoan ng 1 4.5 0.8 5.625 5.625 0.2 My khoan ng 1 4.5 0.8 5.625 5.625 0.2 My ca kiu i 1 1 0.8 1.25 1.25 0.2 My phay vn nng 1 7 0.8 8.75 8.75 0.2 My phay vn nng 1 7 0.8 8.75 8.75 0.2 My tin ren 1 20 0.8 25 25 0.2 My tin ren 1 20 0.8 25 25 0.2 My tin ren 1 20 0.8 25 25 0.2 Tng nhm 1 8 84 105 105 1. Cng sut t nhm 2:Pdat nh2 = 8

B.

K hiu 9.1 9.2 10 11 12 15 16 17

cos 0.75 0.75 0.75 0.75 0.75 0.78 0.78 0.78

i =1

Pdati =5.625+5.625+1.25+8.75+8.75+25+25+25 = 105 (kw)

2. Dng in nh mc ca cc thit b trong nhm 2:

Um=380 (v) - Dng in nh mc ca mi my 9.1: Im=Pdat 5.625 103 = = 11.4 (A) 3 U dm cos 3 380 0.75

- Dng in nh mc ca mi my 9.2:

N MN HC 1

GVHD : TRN THANH SN

Im=

Pdat 5.625 103 = = 11.4 (A) 3 U dm cos 3 380 0.75 Pdat 1.25 103 = = 2.53 (A) 3 U dm cos 3 380 0.75 Pdat 25 103 = = 50 (A) 3 U dm cos 3 380 0.75 Pdat 8.75 103 = = 17.7 (A) 3 U dm cos 3 380 0.75 Pdat 8.75 103 = = 17.7 (A) 3 U dm cos 3 380 0.75 Pdat 20 103 = = 48.7 (A) 3 U dm cos 3 380 0.78 Pdat 20 103 = = 48.7 (A) 3 U dm cos 3 380 0.78 Pdat 20 103 = = 48.7 (A) 3 U dm cos 3 380 0.78








3. H s s dng nhm 2: k sd nh 2 =

ki =1

8

sdi

Pdatidati

Pi =1 8

8

=

21 = 0.2 105

4. S thit b hiu qu ca nhm 2 : nhqnh 2 = ( Pdati )2i =1 8

Pi =1

= 5.2

2 dati

5. H s cng sut nhm 2 :

N MN HC 1

GVHD : TRN THANH SN

cos =

(Pi =1

8

dat i

cosi )dati

Pi =1

16

= 0.77

tg = 0.82

6. Cng sut trung bnh ca nhm 2 :

a. Cng sut tc dng trung bnh ca nhm : Ptb nh1= Ksd nh1 Pdt nh1= 0.2 105 =21 (KW) b. Cng sut phn khng trung bnh ca nhm 1: Qtb nh1 = tg nh1 Ptb nh1 =0.82 21 =17.22 (KVar)7. Ph ti tnh ton ca nhm 2: a. Cng sut tnh ton ca nhm 2:

Do nhq nh2 =5.2 > 4 v s thit b thc t ln hn 6 nn ta tnh ton nh sau : Vi Ksd =0.2 v nhq nh2 = 5.2 tra bng A.2 trang 9 (Sch HD n Mn Hc Thit K Cung Cp in) ta c : Kmax = 2.42Ptt = kmax ksd nh 2 P = 2.42 0.2 105 = 50.82 (Kw) dmii =1 8

b. Cng sut phn khng tnh ton ca nhm 2: Qtt nh2 =Ptt tg nh2 =50.82 0.82 =41.6 (KVar) c. Cng sut biu kin tnh ton ca nhm 2:Stt = P 2 + Q 2 = 50.822 + 41.62 = 65.6 (KVA) 8. Dng in tnh ton ca nhm 2 : I tt = Stt 65.6 103 = = 99.6 (A) 3 U dm 3 380

9. Dng in nh nhn ca nhm 2 :

Chon k mm =4.5 In = Itt + Ikmax Ksd Im M = Itt + (Kmm Ksd ) Im M = = 99.6 + 4.5 50 = 324.6 (A) C. i vi t ng lc 3 K Hiu THIT B S P (kw) Lng m Pt 1tb (kw) Pt tng tb (kw) Ksd cos

N MN HC 1

GVHD : TRN THANH SN

18 19 20 20 20 21 23 26 30

My tin ren My mi th My co My co My co Cu trc B du tng nhit My khoan bn My mi ph Tng nhm 1 1. Cng sut t nhm 3:Pdat nh1 = 9

1 1 1 1 1 1 1 1 1 9

20 2.8 1 1 1 24.2 8.5 0.85 2.8 62.2

0.8 0.8 0.8 0.8 0.8 0.8 0.8 0.8 0.8

25 3.5 1.25 1.25 1.25 30.3 10.6 1.06 3.5 77.6

25 3.5 1.3 1.3 1.3 30 11 1.1 3.5 78

0.2 0.2 0.2 0.2 0.2 0.2 0.2 0.2 0.2

0.78 0.75 0.75 0.75 0.75 0.78 0.75 0.75 0.75

i =1

Pdati =25+3.5+1.25+1.25+1.25+30.25+10.625+1.0625+3.5=105 (kw)

2. Dng in nh mc ca cc thit b trong nhm 3:

Um=380 (v) - Dng in nh mc ca mi my 18: Im=Pdat 25 103 = = 48.6 (A) 3 U dm cos 3 380 0.78 Pdat 3.5 103 = = 7.1 (A) 3 U dm cos 3 380 0.75 Pdat 1.25 103 = = 2.53 (A) 3 U dm cos 3 380 0.75 Pdat 1.25 103 = = 2.53 (A) 3 U dm cos 3 380 0.75 Pdat 1.25 103 = = 2.53 (A) 3 U dm cos 3 380 0.75 Pdat 30.25 103 = = 59 (A) 3 U dm cos 3 380 0.78






- Dng in nh mc ca mi my 23:

N MN HC 1

GVHD : TRN THANH SN

Im=

Pdat 10.625 103 = = 21.5 (A) 3 U dm cos 3 380 0.75 Pdat 1.0625 103 = = 2.15 (A) 3 U dm cos 3 380 0.75 Pdat 3.5 103 = = 7.1 (A) 3 U dm cos 3 380 0.75



3. H s s dng nhm 3: k sd nh1 =

ki =1

9

sdi

Pdatidati

Pi =1

9

=

13.5375 = 0.2 77.6

4. S thit b hiu qu ca nhm 3 : nhqnh 3 = ( Pdati ) 2i =1 9 9

Pi =1

= 3.5

2 dati

5. H s cng sut nhm 3 : cos =

(Pi =1

9

dat i 9

cosi )dati

Pi =1

=

59.9 = 0.77 77.6

tg = 0.82

6. Cng sut trung bnh ca nhm 3 : a. Cng sut tc dng trung bnh ca nhm : Ptb nh3= Ksd nh3 Pdt nh3= 0.2 77.6 =15.52 (KW) b. Cng sut phn khng trung bnh ca nhm 3: Qtb nh3 = tg nh3 Ptb nh3 =0.82 15.52 = 12.7 (KVar)7. Ph ti tnh ton ca nhm 3 : a. Cng sut tnh ton ca nhm 3: Do nhq nh1 =3.5 4 v s thit b thc t ln hn 4 nn ta tnh ton nh

sau : Vi Ksd =0.2 v nhq nh1 = 4 tra bng A.2 trang 9 (Sch HD n Mn Hc Thit K Cung Cp in) ta c : Kmax = 2.64Ptt = kmax ksd nh1 P = 2.64 0.2 77.6 = 40.9 (Kw) dmii =1 9

N MN HC 1

GVHD : TRN THANH SN

b. Cng sut phn khng tnh ton ca nhm 3:

Qtt nh3 =Ptt tg nh3 =40.9 0.82 =33.5 (KVar)c. Cng sut biu kin tnh ton ca nhm 3: Stt = P 2 + Q 2 = 40.92 + 33.52 = 52.8 (KVA) 8. Dng in tnh ton ca nhm 3 : Stt 52.8 103 I tt = = = 80.3 (A) 3 U dm 3 380 9. Dng in nh nhn ca nhm 3 :

Chon k mm =4.5 In = Itt + Ikmax Ksd K Hiu 27 31 32.1 32.2 32.3 33.1 33.2 34 35 36 S Lng 1 1 1 1 1 1 1 1 1 1

Im M = Itt + (Kmm Ksd ) Im M = 80.3 + 4.5 48.6 = 299 (A) Pm (kw) 25 4.5 4.5 4.5 4.5 1.7 1.7 1.5 1.2 1.2 0.8 0.8 0.8 0.8 0.8 0.8 0.8 0.8 0.8 0.8 Pt 1tb (kw) 31.25 5.625 5.625 5.625 5.625 2.125 2.125 1.875 1.5 1.5 Pt tng tb (kw) 31.25 5.625 5.625 5.625 5.625 2.125 2.125 1.875 1.5 1.5 Ksd cos 0.2 0.2 0.2 0.2 0.2 0.2 0.2 0.2 0.2 0.2 0.78 0.75 0.75 0.75 0.75 0.75 0.75 0.75 0.75 0.75

THIT B My hn in My khoan ng My khoan ng My khoan ng My khoan ng My ct ren lin hp My ct ren lin hp Qut l rn My cun dy My cun dy

D. i vi t ng lc 4 1. Cng sut t nhm 4:Pdat nh4 = 15

i =1

Pdati = 31.25+5.625+5.625+5.625+5.625+2.125+2.125+1.875+1.5

+1.5+5+5 +3.75+3.75+3.75 = 84.125 (kw) 2. Dng in nh mc ca cc thit b trong nhm 4: Um=380 (v) - Dng in nh mc ca mi my 27:

N MN HC 1

GVHD : TRN THANH SN

Im=

Pdat 31.25 103 = = 60 (A) 3 U dm cos 3 380 0.75 Pdat 5.625 103 = = 11.4 (A) 3 U dm cos 3 380 0.75


- Dng in nh mc ca mi my 32.1: Im=Pdat 5.625 103 = = 11.4 (A) 3 U dm cos 3 380 0.75 Pdat 5.625 103 = = 11.4 (A) 3 U dm cos 3 380 0.75


- Dng in nh mc ca mi my 33.3: Im=Pdat 5.625 103 = = 11.4 (A) 3 U dm cos 3 380 0.75 Pdat 2.125 103 = = 4.3 (A) 3 U dm cos 3 380 0.75 Pdat 2.125 103 = = 4.3 (A) 3 U dm cos 3 380 0.75 Pdat 1.875 103 = = 3.7 (A) 3 U dm cos 3 380 0.75 Pdat 1.5 103 = = 3 (A) 3 U dm cos 3 380 0.75 Pdat 1.5 103 = = 3 (A) 3 U dm cos 3 380 0.75 Pdat 5 103 = = 10 (A) 3 U dm cos 3 380 0.78







N MN HC 1

GVHD : TRN THANH SN Pdat 5 103 = = 10 (A) 3 U dm cos 3 380 0.78


- Dng in nh mc ca mi my 39.1: Im=Pdat 3.75 103 = = 7.6 (A) 3 U dm cos 3 380 0.75 Pdat 3.75 103 = = 7.6 (A) 3 U dm cos 3 380 0.75 Pdat 3.75 103 = = 7.6 (A) 3 U dm cos 3 380 0.75



3. H s s dng nhm 4:k sd nh 4 =

ki =1

15

sdi

Pdatidati

Pi =1

15

=

16.825 = 0.2 84.125

4. S thit b hiu qu ca nhm 4 :nhqnh 4 = ( Pdati ) 2i =1 15 15

Pi =1

=

2 dati

7077.016 = 5.8 1212.36

5. H s cng sut nhm 4 :cos =

(Pi =1

14

dat i

cosi )dati

Pi =1

14

=

84.375 = 0.76 110.5

tg = 0.85

6. Cng sut trung bnh ca nhm 4 : a. Cng sut tc dng trung bnh ca nhm : Ptb nh4= Ksd nh4 Pdt nh4= 0.2 84.125 =16.825 (KW) b. Cng sut phn khng trung bnh ca nhm 2:

N MN HC 1

GVHD : TRN THANH SN

Qtb nh4 = tg nh4 Ptb nh4 =0.85 16.825 =14.3 (KVar) 7. Ph ti tnh ton ca nhm 4: a. Cng sut tnh ton ca nhm 4: Do nhq nh2 =5.8> 4 v s thit b thc t ln hn 5 nn ta tnh ton nh sau : Vi Ksd =0.2 v nhq nh2 = 5.8 tra bng A.2 trang 9 (Sch HD n Mn Hc Thit K Cung Cp in) ta c : Kmax = 2.42Ptt = kmax ksd nh 2 P = 2.42 0.2 84.125 = 40.7 (Kw) dmii =1 14

b. Cng sut phn khng tnh ton ca nhm 4: Qtt nh4 =Ptt tg nh4 =40.7 0.85 =34.6 (KVar) c. Cng sut biu kin tnh ton ca nhm 4:Stt = P 2 + Q 2 = 40.72 + 34.62 = 53.4 (KVA) 8. Dng in tnh ton ca nhm 4 : I tt = Stt 53.4 103 = = 81.1 (A) 3 U dm 3 380

9. Dng in nh nhn ca nhm 4 :

Chon k mm =4.5 In = Itt + Ikmax Ksd Im M = Itt + (Kmm Ksd ) Im M = = 81.1 + 4.5 60 = 351.1 (A) BANG TNG KT S LIU TINH TOAN CUA CAC NHOMA.> i vi nhom 1 : (Tu ng lc 1)

Thit Bi My phay rng My phay rng

S Ki Hiu P m Lng 1 1.1 4.5 1 1.2 4.5

I m 11.4 11.4

n hq K m

P tt

Q tt

S tt

I tt

I n

B.> i vi nhom 2 : (Tu ng lc 2)

Thit Bi

SL

Ki Hiu

P m

I m

n hq

Km

P tt

Q tt

S tt

I tt

I n

N MN HC 1

GVHD : TRN THANH SN

My khoan ng My khoan ng My ca kiu i My phay vn nng My phay vn nng My tin ren My tin ren My tin ren Tinh theo nhom

1 1 1 1 1 1 1 1 8

9.1 9.2 10 11 12 15 16 17

4.5 4.5 1 7 7 20 20 20 84

11.4 11.4 50 17.7 17.7 48.7 48.7 48.7 254

5.2

2.4

50.8

42

66

99.6

324.6

C.> i vi nhom 3 : (Tu ng lc 3)

S Lng My tin ren 1 My mi th 1 My co 1 My co 1 My co 1 Cu trc 1 B du tng 1 nhit My khoan bn 1 My mi ph 1 Tnh theo 9 nhm Thit Bi

Ki Hiu 18 19 20.1 20.2 20.3 21 23 26 30

P m 20 2.8 1 1 1 24.2 8.5 0.85 2.8 62.1

I m 48.6 7.1 2.53 2.53 2.53 59 21.5 21.5 7.1 172.4

n hq

Km

P tt

Q tt

S tt

I tt

I n

4

2.6

40.9

33.5

52.8

80

299

D.> i vi nhom 4 : (Tu ng lc 4)

Thit Bi My hn in My khoan ng My khoan ng My khoan ng My khoan ng My ct ren lin hp My ct ren lin hp

SL 1 1 1 1 1 1 1

Ki P m Hiu 27 25 31 4.5 32.1 4.5 32.2 4.5 32.3 4.5 33.1 1.7 33.2 1.7

I m 60 11.4 11.4 11.4 11.4 4.3 4.3

n hq

Km

P tt

Q tt

S tt

I tt

I n

N MN HC 1

GVHD : TRN THANH SN

Qut l rn 1 My cun dy 1 My cun dy 1 B ngm c tng nhit 1 B ngm c tng nhit 1 B ngm dung dch kim 1 B ngm dung dch kim 1 T sy 1 Tnh Theo Nhm 15

34 35 36 37 38 39.1 39.2 40

1.5 3.7 1.2 3 1.2 3 4 10 4 10 3 7.6 3 7.6 3 7.6 67.3 166.7 5.8 2.42 40.7 34.6 53.4 81.1 351.1

PHU TAI TINH TOAN CHO TU PHN PHI a. Cng sut inh mc cua tu phn phi :Pm TPP = Pm nhi = 84 + 84.4 + 62.15 + 67.3 = 297.85 (Kw)1 4

b. Dong in inh mc cua tu phn phi :I m TPP = I m nhi = 254.3 + 222.42 + 172.39 + 166.7 = 815.41 (A)1 4

C. Cng sut trung binh cua tu phn phiPTB TPP = P nhi = 21 + 22.1 + 15.52 + 16.825 = 74.445 (Kw) TB QTB TPP = QTB nhi = 17.22 + 17.875 + 12.7 + 14.7 = 62.495 (Kvar)1 1 4 4

d. Cng sut tinh toan cua tu phn phi :Ptt TPP = Ptt nhi = 50.82 + 46.41 + 40.9 + 40.7 = 178.83 (Kw) Qtt TPP = Qtt nhi = 41.6 + 39.5 + 53.5 + 34.6 = 169.2 (Kvar) Stt TPP = Stt nhi = 65.6 + 60.9 + 52.8 + 53.4 = 232.7 (KVA)1 1 4 1 4 4

e. Dong in tinh toan cua phn xng :I tt TPP = Stt TPP 3 U = 232.7 103 = 353.5 (A) 3 380

N MN HC 1

GVHD : TRN THANH SN

CHNG 4 : TNH TON CHN MY BIN PMC CH My bin p l mt phn t quan trng trng h thng in. N ng vai tr bin i in p cp trung th v h th cung cp cho phn xng. Vic chn my bin p cn m bo tnh k thut, tnh cung cp in lin tc v tnh kinh t. Khi chn my bin p cng cn kho v yu cu cung cp in trong tng li II. TNH TON PH Ti TNH TON TON NH MY : Ta xem ph ti tnh ton ng lc v ph ti tnh ton chiu sng l ng thi => K dt = 1 Ta c I.

N MN HC 1 Pttcs = P = 7128 (W) ttcs1 1

GVHD : TRN THANH SN

Qttcs = Qttcs = 5346 (VAR)1 2 2 Sttcs = Pttcs + Qttcs = 71282 + 53262 = 8910 (W) = 8.91 (KW)

1

=> PttcsNM = Kdt ( PttDL +P ) = 1 (178.83 + 7.128) = 186 (KW) ttcs => QttcsNM = K dt (QttDL +Qttcs ) = 1 (169.2 + 5.346) = 174.5 (KVAR)2 2 2 SttcsNM = P 2 ttcsNM + QttcsNM = 186 + 174.5 = 255 (KVA)

I ttNM = Cos =

SttNM 255 103 = = 387 (A) 3 U d 3 380 PttNM 186 = = 0.73 SttNM 255

CHN MY BIN P CHO NH MY Kh chn dung lng ca MBA, ta phi lu n kh nng qu ti thng xuyn ca MBA. Vic cn phi theo cc bc sau: - Xc th ph ti ca trm - Xc nh cc h s K1, K2 theo cc cng sut ng tr (nhit). - Xc nh nhit ng tr mi trng Cng sut ph ti ln nht ca phn xng :S max = Stt NM = 255 (KVA)

Cng sut pht ti nh nht ca phn xng :S min = 0.6 Stt NM = 0.6 255 = 153 (KVA)

V phn xng c cng suy tiu th khng ln lm nn ta ch cn mt MBA. y ta dng loi MBA ngoi tri, lm mt bng du, ba pha. MBA c chn phi c cng sut nh mc S dmB nm trong khongS min < S dmB < Smax . Tra bng (sch HNG DN N MN HC Phan Th Thanh

Bnh Dng Lan Hng v Phan Th Thu Vn) (trang 59), ta thy c MBA c cng sut nh mc SB p ng yu cu trn l 250 KVA Thi gia qu ti thng xuyn l 4h. chn MBA thc hp nht, ta xt kh nng qu ti thng xuyn ca n : MBA loi 250 KVA Trc tin ta tnh h s non ti K1 :

N MN HC 1 K1 = Smin 153 = = 0.61 S dmB 250 S max 253 = = 1.012 SdmB 250

GVHD : TRN THANH SN

H s qu ti K 2 ca MBA l :K2 =

i chiu vi bng ng cong qu ti ta thy :K 2 cp = 1.4 > K2 = 1.012

Vy MBA 250 KVA t yu cu ` Ta chn MBA c cng sut nh mc S dmB = 250 KVA ci cc thng s : - in p nh mc : U dmB = 0.4 (Kv) - Tn tht in p P0 = 750 (W) - Tn tht ngn mch PN = 4000 (W) - in p ngn mch U % = 5%

CHNG 5 : CHN DY DN V THIT B BO VI . NGHA 1. Dy dn m bo iu kin lm vic bnh thng ca dy theo iu kin pht nng, ta cn phi la chn tit din dy dn v dy cp theo dng in cho php tha mn iu kin :I cp , Ilvmax I lv max k

Vi

, I cp =

Trong I cp : dng cho php ca dy dn (A)

N MN HC 1, Chn dy dn theo cng thc sau : I cp I cp =

GVHD : TRN THANH SN I lv max k

Vi : * I lv max =I tt : i vi nhm thit b I dm : i vi 1 thit b

I

dm

: i vi cc my lin thng

* K : h s hiu chnh K = K1 K 2 K3 K4 - K 4 = 1 : theo kiu lp t (chn trong t) - K 5 = 0.84 : theo cc hng cp t gn nhau trong t - K 6 = 1 : theo nh hng ca t chn cp (t kh) - K 7 = 0.89 : cch in bng PVC, nhit ca t 300 C => K = K 4 K 5 K 6 K7 = 1 0.84 1 0.89 = 0.7476 * I cp : dng in cho php ca dy dn 2. Thit B Bo V iu kin chn CB l :U dmCB U dmluoi I dmCB Ilv max3 I catCB I N

Vi : + U dmCB : in p nh mc ca CB (V) + U dmluoi = 400V : in p nh mc ca li in + I dmCB : dng in nh mc ca CB (A)(3) + I N : dng ngn mch 3 pha ca dy dn (KA)

Sau khi chn CB xong, ta phi chnh dng nhit in ca CB sao cho :' I nhCB K I cp

Vi

' - I cp : dng in cho php ca dy dn sau khi hiu chnh

-

K : h s cho php ca dy dn

II. TNH TON CHN DY DN V THIT B BO V : a. T MBA n t phn phi Ta phi chn theo kiu pht nng :

N MN HC 1 I cp I lv max K1 K 2 K 3

GVHD : TRN THANH SN

Cc h s K1 , K 2 , K 3 c chn nh sau (ng dy trn khng)K1 = 1 K 2 = 0.84 K 3 = 0.96 (Nhit mi trng l 35 0 C

T MBA n t phn phi c + H s K = K1 K 2 K3 = 1 0.84 0.96 = 0.8064 + I lv max = I tt px =' + I cp =

Stt px 3 U

=

232.7 103 = 353.5 (A) 3 380

I lv max K

=

353.5 = 438.4 (A) 0.8064

Tra bng ph lc 8.3 : Cp ng h p 3,4 li cch in PVC do lens ch tao. (sch hng dn n mn hc Phan Th Thanh Bnh Dng Lan Hng Phan Th Thu Vn). Ta chn cp ng h p 4 li 4G185 c I cp = 484( trong nh) v 450 (ngoi tri) Kim tra bng iu kin pht nng cho php : K. I cp = 0.8064 484 = 390 (A) > I lv max = 353.5 (A) ( I cp l thng s dy dn mi tnh ton). Vy dy dn ta chn tha mn iu kin pht nng cho php. Chn CB : Ta c :I dm CB I lv max = 353.5 (A)

Tra bng catalogue ca hng mitsubishi ta chn c CB 3 cc m : NF400-CW c I dmCB = 400 (A) ; Kh nng ct I cat CB = 36 (KA)U dm CB = 400 (V)

b. T t phn phi n t ng lc

T ng lc 1 H s K = K 4 K5 K 6 K7 = 1 0.84 1 0.89 = 0.7476 (K l chn theo cp ngm)I lv max = I ttTDL 2 = 92.5 (A)' I cp =

I lv max K

=

92.5 = 123.7 (A) 0.7476

N MN HC 1

GVHD : TRN THANH SN

Tra bng ph lc 8.4 (trang 45 sch hng dn n mn hc Phan Th Thanh Bnh Dng Lan Hng Phan Th Thu Vn) ta chn loi cp ng 4 li 4G25 c I cp = 144 (A) Kim tra iu kin pht nng cho php :K I cp = 0.7476 144 = 107.6 (A) > I lv max = 92.5 (A)

Vy dy chn tha mn iu kin pht nng cho php. Chn CB : Ta c :I dm CB I lv max = 92.5 (A)

Tra bng catalogue ca hng mitsubishi ta chn c CB 3 cc m : NF125 -CW c I dmCB = 100 (A) ; Kh nng ct I cat CB = 10 (KA)U dm CB = 400 (V)

Kim tra s phi hp gia Cb v dy dn :' I dmCB = 100 (A) I cp = 123.7(A)

Vy vic chn trn l ph hp T ng lc 2

H s K = K 4 K5 K 6 K7 = 1 0.84 1 0.89 = 0.7476 (K l chn theo cp ngm)I lv max = I ttTDL1 = 99.6 (A)' I cp =

I lv max K

=

99.6 = 133.2 (A) 0.7476



Tra bng catalogue ca hng mitsubishi ta chn c CB 3 cc m : NF125 -CW c : I dmCB = 100 (A) ; Kh nng ct I cat CB = 10 (KA)U dm CB = 400 (V)

Kim tra s phi hp gia Cb v dy dn :

N MN HC 1' I dmCB = 100 (A) I cp =133.2 (A)

GVHD : TRN THANH SN

Vy vic chn trn l ph hp

T ng lc 3: H s K = K 4 K5 K 6 K7 = 1 0.84 1 0.89 = 0.7476 (K l chn theo cp ngm)I lv max = I ttTDL 3 = 80.3 (A)' I cp =

I lv max K

=

80.3 = 107.4 (A) 0.7476






T ng lc 4: H s K = K 4 K5 K 6 K7 = 1 0.84 1 0.89 = 0.7476 (K l chn theo cp ngm)I lv max = I ttTDL 3 = 81.1 (A)' I cp =

I lv max K

=

81.1 = 108.4 (A) 0.7476

Tra bng ph lc 8.4 (trang 45 sch hng dn n mn hc Phan Th Thanh Bnh Dng Lan Hng Phan Th Thu Vn) ta chn loi : cp ng 4 li 4G15 c I cp = 113 (A) Kim tra iu kin pht nng cho php :K I cp = 0.7476 113 = 84.5 (A) > I lv max = 81.1 (A)

N MN HC 1

GVHD : TRN THANH SN

Vy dy chn tha mn iu kin pht nng cho php. Chn CB :I dm CB I lv max = 81.1 (A)



Vy vic chn trn l ph hp c. T t ng lc n cc thit b: . i vi t ng lc 2 My phay rng ( s 1.1, 1.2, 2.1 v 2.2) : H s K = K 4 K5 K 6 K7 = 1 0.84 1 0.89 = 0.7476I lv max = I dm = 11.4 (A)' I cp =

I lv max K

=

11.4 = 15.2 (A) 0.7476

Tra bng ph lc 8.2 (trang 53 sch hng dn n mn hc Phan Th Thanh Bnh Dng Lan Hng Phan Th Thu Vn) ta chn loi cp nhm 4 li : m hiu AVV-4, tit din 4 mm 2 c I cp = 18 (A) Kim tra iu kin pht nng cho php :K I cp = 0.7476 18 = 13.5 (A) > I lv max = 11.4 (A)

Vy dy chn tha mn iu kin pht nng cho php. Chn CB : Ta c :I dm CB I lv max = 11.4(A)

Tra bng catalogue ca hng mitsubishi ta chn c CB 3 cc m : NF30 -CS c I dmCB = 15 (A) ; Kh nng ct I cat CB = 1.5 (KA)U dm CB = 400 (V)

Kim tra s phi hp gia Cb v dy dn :' I dmCB = 15 (A) I cp = 52(A)


My xc ( s 3.1 v 3.2) :

H s K = K 4 K5 K 6 K7 = 1 0.84 1 0.89 = 0.7476

N MN HC 1 I lv max = I dm = 7 (A)' I cp =

GVHD : TRN THANH SN

I lv max K

=

7 = 9.4 (A) 0.7476


Vy dy chn tha mn iu kin pht nng cho php. Chn CB : Ta c :I dm CB I lv max = 7(A)




My bo ngang ( s 4.1, 4.2 v 5) :

H s K = K 4 K5 K 6 K7 = 1 0.84 1 0.89 = 0.7476I lv max = I dm = 11.4 (A)' I cp =

I lv max K

=

11.4 = 15.2 (A) 0.7476



Tra bng catalogue ca hng mitsubishi ta chn c CB 3 cc m : NF30 -CS c I dmCB = 15 (A) ; Kh nng ct I cat CB = 1.5 (KA)

N MN HC 1 U dm CB = 400 (V)

GVHD : TRN THANH SN



My mi trn vn nng ( s 6) :


I lv max K

=

11.4 = 15.2 (A) 0.7476






My mi th ( s 7) :


I lv max K

=

5.28 = 7.1 (A) 0.7476

Tra bng ph lc 8.2 (trang 53 sch hng dn n mn hc Phan Th Thanh Bnh Dng Lan Hng Phan Th Thu Vn) ta chn loi cp nhm 4 li : m hiu AVV-4, tit din 4 mm 2 c I cp = 18 (A) Kim tra iu kin pht nng cho php :

N MN HC 1

GVHD : TRN THANH SN

K I cp = 0.7476 18 = 13.5 (A) > I lv max = 5.28 (A)





My khoan ng ( s 9.3) :


I lv max K

=

11.4 = 15.2 (A) 0.7476






My tin ren ( s 13 v 14) :

H s K = K 4 K5 K 6 K7 = 1 0.84 1 0.89 = 0.7476

N MN HC 1 I lv max = I dm = 48.6 (A)' I cp =

GVHD : TRN THANH SN

I lv max K

=

48.6 = 65 (A) 0.7476





Vy vic chn trn l ph hp . i vi t ng lc 2 My khoan ng ( 9.1 v 9.2) : H s K = K 4 K5 K 6 K7 = 1 0.84 1 0.89 = 0.7476I lv max = I dm = 11.4 (A)' I cp =

I lv max K

=

11.4 = 15.2 (A) 0.7476



Tra bng catalogue ca hng mitsubishi ta chn c CB 3 cc m : NF30 -CS

N MN HC 1

GVHD : TRN THANH SN

c I dmCB = 15 (A) ; Kh nng ct I cat CB = 1.5 (KA)U dm CB = 400 (V)


Vy vic chn trn l ph hp My ca kiu i ( s 10) : H s K = K 4 K5 K 6 K7 = 1 0.84 1 0.89 = 0.7476I lv max = I dm = 2.53 (A)' I cp =

I lv max K

=

2.53 = 3.4 (A) 0.7476





Vy vic chn trn l ph hp My phay vn nng ( s 11 v 12) : H s K = K 4 K5 K 6 K7 = 1 0.84 1 0.89 = 0.7476I lv max = I dm = 17.7 (A)' I cp =

I lv max K

=

17.7 = 23.6 (A) 0.7476

Tra bng ph lc 8.2 (trang 53 sch hng dn n mn hc Phan Th Thanh Bnh Dng Lan Hng Phan Th Thu Vn) ta chn loi cp nhm 4 li : m hiu AVV-4, tit din 8 mm 2 c I cp = 27 (A)

N MN HC 1

GVHD : TRN THANH SN

Kim tra iu kin pht nng cho php :K I cp = 0.7476 27 = 20.2 (A) > I lv max = 17.7 (A)




Vy vic chn trn l ph hp My tin ren ( s 15,16 v 17) : H s K = K 4 K5 K 6 K7 = 1 0.84 1 0.89 = 0.7476I lv max = I dm = 39 (A)' I cp =

I lv max K

=

39 = 52 (A) 0.7476

Tra bng ph lc 8.2 (trang 53 sch hng dn n mn hc Phan Th Thanh Bnh Dng Lan Hng Phan Th Thu Vn) ta chn loi cp nhm 4 li : m hiu AVV-4, tit din 22 mm 2 c I cp = 53 (A) Kim tra iu kin pht nng cho php :K I cp = 0.7476 53 = 39.6 (A) > I lv max = 39 (A)




Vy vic chn trn l ph hp . i vi t ng lc 3

My tin ren ( s 18) :

N MN HC 1

GVHD : TRN THANH SN


I lv max K

=

48.6 = 65 (A) 0.7476






My mi th ( s 19) :


I lv max K

=

7.1 = 9.5 (A) 0.7476



N MN HC 1

GVHD : TRN THANH SN




My co ( s 20.1, 20.2 v 20.3) :


I lv max K

=

2.53 = 3.4 (A) 0.7476






My cn trc ( s 21) :

H s K = K 4 K5 K 6 K7 = 1 0.84 1 0.89 = 0.7476I lv max = I dm = 59 (A)' I cp =

I lv max K

=

59 = 79 (A) 0.7476

Tra bng ph lc 8.2 (trang 53 sch hng dn n mn hc Phan Th Thanh Bnh Dng Lan Hng Phan Th Thu Vn) ta chn loi cp nhm 4 li :

N MN HC 1

GVHD : TRN THANH SN

m hiu AVV-4, tit din 38 mm 2 c I cp = 83 (A) Kim tra iu kin pht nng cho php :K I cp = 0.7476 83 = 62 (A) > I lv max = 59 (A)





B du to nhit ( s 23) :


I lv max K

=

21.5 = 29 (A) 0.7476

Tra bng ph lc 8.2 (trang 53 sch hng dn n mn hc Phan Th Thanh Bnh Dng Lan Hng Phan Th Thu Vn) ta chn loi cp nhm 4 li : m hiu AVV-4, tit din 10 mm 2 c I cp = 32 (A) Kim tra iu kin pht nng cho php :K I cp = 0.7476 32 = 24 (A) > I lv max = 21.5 (A)





My khoan bn ( s 26) :

N MN HC 1

GVHD : TRN THANH SN


I lv max K

=

2.15 = 2.9 (A) 0.7476






My mi ph ( s 30) :


I lv max K

=

7.1 = 9.5 (A) 0.7476



Tra bng catalogue ca hng mitsubishi ta chn c CB 3 cc m : NF30 -CS

N MN HC 1

GVHD : TRN THANH SN

c I dmCB = 10 (A) ; Kh nng ct I cat CB = 1.5 (KA)U dm CB = 400 (V)


Vy vic chn trn l ph hp . i vi t ng lc 4

My hn in ( s 27) :


I lv max K

=

60 = 80 (A) 0.7476

Tra bng ph lc 8.2 (trang 53 sch hng dn n mn hc Phan Th Thanh Bnh Dng Lan Hng Phan Th Thu Vn) ta chn loi cp nhm 4 li : m hiu AVV-4, tit din 38 mm 2 c I cp = 83 (A) Kim tra iu kin pht nng cho php :K I cp = 0.7476 83 = 62 (A) > I lv max = 60 (A)





My khon ng ( s 31, 32.1, 32.2 v 32.3) :


I lv max K

=

11.4 = 15.2 (A) 0.7476


N MN HC 1

GVHD : TRN THANH SN

m hiu AVV-4, tit din 4 mm 2 c I cp = 18 (A) Kim tra iu kin pht nng cho php :K I cp = 0.7476 18 = 13.5 (A) > I lv max = 11.4 (A)





My ct ren lin hp ( s 33.1 v 33.2) :


I lv max K

=

4.3 = 5.8 (A) 0.7476






N MN HC 1

GVHD : TRN THANH SN

Qut l rn ( s 34) :


I lv max K

=

3.7 = 5 (A) 0.7476




Kim tra s phi hp gia Cb v dy dn :' I dmCB = 5 (A) I cp = 5 (A)


My cun dy ( s 35 v 36) :


I lv max K

=

3 = 4 (A) 0.7476


Vy dy chn tha mn iu kin pht nng cho php. Chn CB : Ta c :I dm CB I lv max = 3 (A)

N MN HC 1

GVHD : TRN THANH SN




B ngm c tng nhit ( s 37 v 38) :


I lv max K

=

5 = 6.7 (A) 0.7476


Vy dy chn tha mn iu kin pht nng cho php. Chn CB : Ta c :I dm CB I lv max = 5 (A)


Kim tra s phi hp gia Cb v dy dn :' I dmCB = 6 (A) I cp = 6.7 (A)


B ngm dung dch kim ( s 39.1 v 39.2) :


I lv max K

=

7.6 = 10 (A) 0.7476


N MN HC 1

GVHD : TRN THANH SN

m hiu AVV-4, tit din 4 mm 2 c I cp = 18 (A) Kim tra iu kin pht nng cho php :K I cp = 0.7476 18 = 13.5 (A) > I lv max = 7.6 (A)





T sy ( s 40) :


I lv max K

=

7.6 = 10 (A) 0.7476





Vy vic chn trn l ph hp . i vi t chiu sng

N MN HC 1

GVHD : TRN THANH SN

H s K = K 4 K5 K 6 K7 = 1 0.84 1 0.89 = 0.7476I lv max' I cp =

Sttcs 8.96 103 = = = 40.7 (A) U dm 220 I lv max K = 40.7 = 54.4 (A) 0.7476




Kim tra s phi hp gia Cb v dy dn :' I dmCB = 50 (A) I cp = 54.4 (A)

Vy vic chn trn l ph hp III. BNG TNG KT DY DN V THIT B BO V T my bin p n t phn phi STT K Hiu 1 2. Tu Thit B T phn phi Dy Dn PVC Lens 185mm2 CB MITSUBISHI NF400-CW

1.

T t phn phi n t ng lc STT 1 2 Thit b T ng lc 1 T ng lc 2 Dy Dn PVC lens 4G25 25mm2 PVC lens 4G25 25mm2 CB MITSUBISHI NF125 - CW MITSUBISHI NF125 - CW

N MN HC 1

GVHD : TRN THANH SN

3 4 3. A.

T ng lc 3 T ng lc 4

PVC lens 4G15 15mm2 PVC lens 4G15 15mm2

MITSUBISHI NF125 - CW MITSUBISHI NF125 - CW

T t ng lc n tng thit b T ng lc 1 STT K hiu 1 1.1 2 3 4 5 6 7 8 9 10 11 12 13 14 1.2 2.1 2.2 3.1 3.2 4.1 4.2 5 6 7 9.3 13 14 Tn thit b My phay rng My phay rng My phay rng My phay rng My xc My xc My bo ngang My bo ngang My bo ngang Dy dn CB 2 PVC AVV4 - 4mm MITSUBISHI NF30-CS PVC AVV4 - 4mm2 MITSUBISHI NF30-CS PVC AVV4 - 4mm2 MITSUBISHI NF30-CS PVC AVV4 - 4mm2 MITSUBISHI NF30-CS PVC AVV4 - 4mm2 MITSUBISHI NF30-CS PVC AVV4 - 4mm2 MITSUBISHI NF30-CS PVC AVV4 - 4mm2 MITSUBISHI NF30-CS PVC AVV4 - 4mm2 MITSUBISHI NF30-CS PVC AVV4 - 4mm2 MITSUBISHI NF30-CS

My mi trn vn nng PVC AVV4 - 4mm2 MITSUBISHI NF30-CS My mi th My khoan ng My tin ren My tin ren PVC AVV4 - 4mm2 MITSUBISHI NF63-CW PVC AVV4 - 4mm2 MITSUBISHI NF30-CS PVC AVV4 - 30mm2 MITSUBISHI NF63-CW PVC AVV4 - 30mm2 MITSUBISHI NF63-CW

B. STT K hiu 1 9.1 2 3 4 5 9.2 10 11 12

t ng lc 2 Thit b My khoan ng My khoan ng My ca kiu i Dy dn CB 2 PVC AVV4 4mm MITSUBISHI NF30-CS PVC AVV4 4mm2 MITSUBISHI NF30-CS PVC AVV4 - 4mm2 MITSUBISHI NF30-CS PVC AVV4 8mm2 MITSUBISHI NF30-CS PVC AVV4 8mm2 MITSUBISHI NF30-CS

My phay vn nng My phay vn nng

N MN HC 1

GVHD : TRN THANH SN

6 7 8

15 16 17

My tin ren My tin ren My tin ren

PVC AVV4 22mm2 PVC AVV4 22mm2 PVC AVV4 22mm2

MITSUBISHI NF63-CW MITSUBISHI NF63-CW MITSUBISHI NF63-CW

C. T ng lc 3 STT K hiu 1 2 3 4 5 6 18 19 20.1 20.2 20.3 21 Tn thit b My tin ren My mi th My co My co My co Cu trc Dy dn CB PVC AVV4 - 30mm2 MITSUBISHI NF63-CW PVC AVV4 - 4mm2 MITSUBISHI NF30-CS PVC AVV4 - 4mm2 MITSUBISHI NF30-CS PVC AVV4 - 4mm2 MITSUBISHI NF30-CS PVC AVV4 - 4mm2 MITSUBISHI NF30-CS PVC AVV4 - 38mm2 MITSUBISHI NF63-CW

7 8 9

23 26 30

B du tng nhit My khoan bn My mi ph C. T ng lc 4

PVC AVV4 - 10mm2 MITSUBISHI NF63-CW PVC AVV4 - 4mm2 PVC AVV4 - 4mm2 MITSUBISHI NF30-CS MITSUBISHI NF30-CS

STT K Hiu 1 27 2 3 4 5 6 31 32.1 32.2 32.3 33.1

Tn Thit B My hn in My khoan ng My khoan ng My khoan ng My khoan ng My ct ren lin hp

Dy Dn CB PVC AVV4 - 38mm2 MITSUBISHI NF63-CW PVC AVV4 - 4mm2 MITSUBISHI NF30-CS PVC AVV4 - 4mm2 MITSUBISHI NF30-CS PVC AVV4 - 4mm2 MITSUBISHI NF30-CS PVC AVV4 - 4mm2 MITSUBISHI NF30-CS PVC AVV4 - 4mm2 MITSUBISHI NF30-CS

7 8 9

33.2 34 35

My ct ren lin hp Qut l rn My cun dy

PVC AVV4 - 4mm2 MITSUBISHI NF30-CS PVC AVV4 - 4mm2 MITSUBISHI NF30-CS PVC AVV4 - 4mm2 MITSUBISHI NF30-CS

N MN HC 1

GVHD : TRN THANH SN

10 11 12 13 14 15

36 37 38 39.1 39.2 40

My cun dy B ngm c tng nhit B ngm c tng nhit

PVC AVV4 - 4mm2 MITSUBISHI NF30-CS PVC AVV4 - 4mm2 MITSUBISHI NF30-CS PVC AVV4 - 4mm2 MITSUBISHI NF30-CS

B ngm dung dch kim PVC AVV4 - 4mm2 MITSUBISHI NF30-CS B ngm dung dch kim PVC AVV4 - 4mm2 MITSUBISHI NF30-CS T sy PVC AVV4 - 4mm2 MITSUBISHI NF30-CS

CHNG 6 : KIM TRA ST P CHO CC THIT B TIU TH IN I. Mch ch :Trong thc t, khng th gi c in p c nh m ch c th m bo c tr s in p trong mt phm vi nht nh cho php, thng l 5%. V Vy t cn phi tnh st p nhm kim tra xem vic chn dy dn thch hp cha c nhng iu chnh cho ph hp nhm hn ch ti a tn hao. II. Tnh ton st p Cng sut tnh st p l : U % PR + QX .100% U dm

R= r 0 .1 : in tr ng dy ( ) X=0, 09 : in khng ng dy ( ) m

r 0 : tra bng theo tit din dy dn. m : s cp i song song trong cng mt thit b Q : cng sut phn khng ca thit b ln ng dy tng ng (KVar) U % : st p % Nu U % % th tit din dy dn t yu cu Nu U % > % th tit din dy dn khng t yu cu, phi chn

li dy dn.

N MN HC 1

GVHD : TRN THANH SN

TNH TON ST P T NG LC 1 on 1 : t t phn phi n my bin p : F = 185mm2,Ptt = 191.07 (kw) r 0 = 0.0991 ( /km) I cp

= 484 (A)

Qtt = 178.38 (Kvar)

chn l = 20m = 0.02 (km)R = r0 l = 0.0991 0.02 = 1.982 103 ( )

V F = 185mm2 > 50mm2 nn ta chn X 0 = 0.08( )X dd = x0 l = 0.08 0.02 = 0.0016 ( ) U1 = P [ KW ] R [ ] + Q [ KVar ] X [ ] U dm [ KV ] U1 1.67 = 100 = 0, 4 (%) Z 2 = R22 + X 22 = 1242 + 02 =124 ( m )

N MN HC 1 Z 32 = Z + Z dd3 + Z 2 = 80.6 + 40 + 124 = 244.6 ( m )(3) I N 3 2 =

GVHD : TRN THANH SN

Vy tng tr t t ng lc 2 n my co s 20.2 :U dm 400 = = 0.944 (KA) 3 Z 3 2 3 244.6

T ng lc 4 33.2R1 = 200 ( m ) X 1 = 0 ( m )

Ngn mch t t ng lc 4 n my ct ren lin hp s

=> Z1 = R12 + X 12 = 2002 + 02 =200 ( m ) Vy tng tr t t ng lc 4 n my ct ren lin hp s 33.2 :Z 41 = Z + Z dd4 + Z1 = 80.6 + 80 + 160 = 320.6 ( m )(3) I N 41 =

U dm 400 = = 0.72 (KA) 3 Z 41 3 320.6

33.1R2 = 138 ( m )

Ngn mch t t ng lc 4 n my my ct ren lin hpX 2 = 0 ( m )

=> Z 2 = R22 + X 22 = 1382 + 02 =138 ( m ) Vy tng tr t t ng lc 4 n my co s 33.1 :Z 4 2 = Z + Z dd4 + Z 2 = 80.6 + 80 + 138 = 298.6 ( m )(3) I N 42 =

U dm 400 = = 0.773 (KA) 3 Z 4 2 3 298.6

Bng tng kt tnh ton ngn mch cho phn xng(3) 1. Dng ngn mch t MBA n t phn phi k : I N = 2.78 (KA)

2. Dng ngn mch t t phn phi n t ng lc - T ng lc 1 : 1.56 (KA) - T ng lc 2 : 1.43 (KA) - T ng lc 3 : 1.91 (KA) - T ng lc 4 : 1.43 (KA) 3. Dng ngn mch t t ng lc n mt s thit b a. t ng lc 1 - My tin ren (17) : 1.13 (KA) - My tin ren (16) : 1.19 (KA) b. T ng lc 2

N MN HC 1

GVHD : TRN THANH SN

- My bo ngang (4.2) : 0.46(KA) - My phy rng (2.2) : 0.47 (KA) c. T ng lc 3 - My ph (30) : 0.82(KA) - My co (20.2) : 0.94(KA) d. T ng lc 4 : - My ct ren lin hp (33.1) : 0.72(KA) - My ct ren lien hp (33.2) : 0.77(KA)

CHNG 8 TNH V CHN T B CHO PHN XNGI. Mc ch : Trong h thng in, t in c s dng vo nhiu mc ch khc nhau: b kinh t, b k thut, b thng s ca ng dy ti in y ta ch xt n vn la chn cng sut ca b t in t ti ci trm bin p phn phi hoc ti cc t phn phi hoc ti cc t ng lc ca cao c nhm mc ch nng cao h s cos hay gi l b cos. Ngi ta ch to t in b cos vi nhiu kch c, chng loi vi cng sut b t vi KVar n vi trm KVar vi in p t 1,22 KV n 24 KV, 1 pha v 3 pha. C loi t in ri, c loi lp t sn thnh t t b. T in b cos c th t pha cao p hay h p ca trm bin p phn phi, c th t chung cho c cao c hay t ring ti ci nt. t t b ti v tr no vi cng sut bao nhiu l li gii ca bi ton kinh t ph thuc vo nhiu yu t: Gi tin 1 KVar t b cao p, h p, kt cu li h p, gi tin tn tht in nng, tnh cht lm vic ca ph ti V tr t t b : 1.B tp trung : p dng khi ti n nh v lin tc

Nguyn l :

N MN HC 1

GVHD : TRN THANH SN

B t u vo thanh gp h p ca t phn phi chnh v c ng trong thi gian ti hot ng. u im : - Gim tin pht do vn tiu th cng sut phn khng. - Gim cng sut biu kin yu cu. - Lm nh ti cho my bin p, do lm tng thm kh nng pht trin ph ti khi cn thit. Nhc im : - Dng in phn khng tip tc i vo tt c cc l ra t phn phi chnh. - V l do trn kch c ca dy dn, cng sut tn hao trong dy khng c ci thin vi ch b tp trung. 2.B nhm : B nhm nn s dng khi mng in qu ln v khi ch ti tiu th theo thi gian ca cc phn on thay i khc nhau. Nguyn l : B t c u vo t phn phi khu vc. Hiu qu do b nhm mang li cho cc dy dn xut pht t t phn phi chnh n cc t phn phi khu vc c t t c th hin r nht.

u im :

- Gim tin pht do vn tiu th cng sut phn khng. - Gim cng sut biu kin yu cu. - Kch thc dy cp i n t phn phi khu vc s gim i hoc vi cng dy cp trn c th tng thm ph ti cho t phn phi khu vc. - Tn hao trn cng dy cp s gim. Nhc im : - Dng in phn khng tip tc i vo tt c dy dn xut pht t t phn phi khu vc. - V l do trn kch thc v cng sut tn hao trong dy dn ni trn khng c ci thin vi ch b nhm. - Khi c s thay i ng k v ti, lun lun tn ti nguy c b d v km theo hin tng qu in p. 3.B ring : B ring nn c xt n khi cng sut ng c ng k so vi cng sut mng in.

Nguyn l :

N MN HC 1

GVHD : TRN THANH SN

B t ni trc tip vo u dy ni ca thit b dng in c tnh cm. B ring nn c xt n khi cng sut ca ng c l ng k so vi cng sut mng in. B t nh mc ln n khong 25% gi tr cng sut ng c. B b sung ti u ngun in cng c th mang li hiu qu tt u im : - Gim tin pht do vn tiu th cng sut phn khng. - Gim cng sut biu kin yu cu. - Gim kch thc v tn hao dy dn i vi tt c dy dn. - Cc dng in phn khng c gi tr ln s khng cn tn ti trong mng. II. Tnh ton chn t b : Cng sut tnh ton cho ton phn xng trc khi c t b :SttNM = 255 (KVA)

Cng sut b t cn t nng h s cng sut b t 0.73 ln 0.95 l : Qb = PttNM (tag1 tag 2 ) = 186(0.93 0.32) = 113.5 (KVAR) Cng sut tnh ton ton phn xng khi c t b :SttNM = PttNM 186 = = 195.8 (KVA) cos 2 0.95

Da vo bng 8.18 (thng s k thut ca t b do Lin X ch to ) trang 57 sch Hng dn n mt hc Thit K Cung Cp in ca Phan Th Thanh Bnh Dng Lan Hng Phan Th Thu Vn . Ta c : Chn 2 t in b loai

KC2 0.38 50 - 3Y3 c cc thng s sau : - in p nh mc : 0.38 (KV) - Cng sut nh mc : 50 (KVAR) - in dung : 1102 ( F) - Chiu cao : 725(mm) - Khi lng : 60 (KG)

do an dialux (ok)

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