derivation of cells in series and parallel - free help in physics - plustwophysics.pdf
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The total internal resistance = nr (since the internal resistances come in series)
The total resistance in the circuit = nr+R
The total emf = nE (since the emfs add up in series circuit)
Therefore, the current in the circuit;
PARALLEL COMBINATION OF CELLS
Consider m identical cells of emf E and internal resistance connected in parallel across an external resistor of resistance R.
The total emf in circuit = E (Since each cell has the same emf and they are in parallel)
The net internal resistance = r/m (since the cells are in parallel, their resistances are also in parallel. If m identical resistances are in parallel, the effective resistance
is r/m)
The total resistance in circuit = R + r/m
Therefore, the current in circuit;
MIXED COMBINATION OF CELLS
Consider a combination of m rows of n cells each. The emf of each cell is E and the internal resistance of each cell is r. This combination is connected across and
external resistance R.
The total EMF = nE
The net internal resistance = nr/m
The total resistance in circuit = R + nr/m
The current in circuit;
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2 comments- What do you think? Posted by admin - February 15, 2011 at 2:41 pm
Categories: Current Electricity Tags: answer, cell, combination of cells, derivation, emfs, external resistor, internal resistance,parallel combination, singh,
treatment
2 Responses to DERIVATION OF CELLS IN SERIES AND PARALLEL
1. jaipreetsays:
February 16, 2011 at 4:28 pm
thank u very much for clearing my doubt..
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2. bhagyashrisays:
August 3, 2011 at 10:09 pm
thnks..!! dis also heplped me..!!!
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