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    The total internal resistance = nr (since the internal resistances come in series)

    The total resistance in the circuit = nr+R

    The total emf = nE (since the emfs add up in series circuit)

    Therefore, the current in the circuit;

    PARALLEL COMBINATION OF CELLS

    Consider m identical cells of emf E and internal resistance connected in parallel across an external resistor of resistance R.

    The total emf in circuit = E (Since each cell has the same emf and they are in parallel)

    The net internal resistance = r/m (since the cells are in parallel, their resistances are also in parallel. If m identical resistances are in parallel, the effective resistance

    is r/m)

    The total resistance in circuit = R + r/m

    Therefore, the current in circuit;

    MIXED COMBINATION OF CELLS

    Consider a combination of m rows of n cells each. The emf of each cell is E and the internal resistance of each cell is r. This combination is connected across and

    external resistance R.

    The total EMF = nE

    The net internal resistance = nr/m

    The total resistance in circuit = R + nr/m

    The current in circuit;

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    2 comments- What do you think? Posted by admin - February 15, 2011 at 2:41 pm

    Categories: Current Electricity Tags: answer, cell, combination of cells, derivation, emfs, external resistor, internal resistance,parallel combination, singh,

    treatment

    2 Responses to DERIVATION OF CELLS IN SERIES AND PARALLEL

    1. jaipreetsays:

    February 16, 2011 at 4:28 pm

    thank u very much for clearing my doubt..

    Log in to Reply

    2. bhagyashrisays:

    August 3, 2011 at 10:09 pm

    thnks..!! dis also heplped me..!!!

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