current electricity applied physics and chemistry circuits lecture 1

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Current Electricity Applied Physics and Chemistry Circuits Lecture 1

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Page 1: Current Electricity Applied Physics and Chemistry Circuits Lecture 1

Current Electricity

Applied Physics and Chemistry Circuits Lecture 1

Page 2: Current Electricity Applied Physics and Chemistry Circuits Lecture 1

Electric Current

Current is flow of charges There must be a complete loop (closed) for flow

to occur Flow from high potential to low potential

As potential decreases, work is done by charges Conventional current is flow of positive charges Do positive charges actually flow?

Page 3: Current Electricity Applied Physics and Chemistry Circuits Lecture 1

Electric Current

Current may be direct or alternating Direct current: flows in one direction Alternating current: flows back and forth

Page 4: Current Electricity Applied Physics and Chemistry Circuits Lecture 1

Electric Circuit

Required for current electricity Closed loop or conducting path from high to low

potential Must have four parts:

Source of charges (area of high potential) Path for charges Device that reduces potential energy Sink (area of low potential)

Page 5: Current Electricity Applied Physics and Chemistry Circuits Lecture 1

Electric Circuit Energy is conserved in the circuit Charge is conserved in the circuit Energy carried by current depends on charge

and potential difference ΔE = qV Remember, V is the potential difference

1 V = 1 J/C

Page 6: Current Electricity Applied Physics and Chemistry Circuits Lecture 1

Electric Current

Current is rate of flow of electric charge Measured in Coulombs / sec 1 C/s = 1 A (Ampere) Symbol for current is I

Page 7: Current Electricity Applied Physics and Chemistry Circuits Lecture 1

Electric Power

Rate of energy transfer Measured in Watts 1W = 1 J/s

Page 8: Current Electricity Applied Physics and Chemistry Circuits Lecture 1

Electric Power

Since P = E/t And E = qV And q= It Then P = VI Power is current times the potential difference.

Page 9: Current Electricity Applied Physics and Chemistry Circuits Lecture 1

Equation for Amber

• In a circle!

Page 10: Current Electricity Applied Physics and Chemistry Circuits Lecture 1

Electric Power

If the current through a motor is 3 A and the potential difference is 120 V, what is the power of the motor?

Known: I=3A V=120 V Equation: P=IV P=(3A)(120V)=360 W

Page 11: Current Electricity Applied Physics and Chemistry Circuits Lecture 1

Electric Power Problem 2A 6 V battery delivers 0.5 A of current to an electric

motor. What is the power rating of this motor?

What we know:

V = 6V I = 0.5 A

Equation:

P = IV

Substitute:

P = (0.5 A)(6 V)

Solve!

P = 3 W

Page 12: Current Electricity Applied Physics and Chemistry Circuits Lecture 1

Electric Power Problem 2 Contd.How much energy does the motor use in 5.0

minutes?

What we know:

P = 3 W t = 5.0 min = 300 s

Equation:

P = W/t which means P = E/t and E = Pt

Substitute:

E = (3 W)(300 s)

Solve!

E = 300 J