crystalball in new product development

04/08/2023R Balisnomo 1

Name: Ramon (Ray) BalisnomoTitle/Position: Design for Six Sigma Instructor/Engr.Company: Ingersoll Rand Securities Technologies

CONTACT INFORMATION:

E-mail: [email protected]@gmail.com

Telephone: 719-896-3604

04/08/2023R Balisnomo

ANALYZING TEST LAB DATAEXERCISE 1 OF 3

Establishing Product Performance Targets

1

D-bolt


Right-click your mouse button


40.5 41.0 41.5 42.0 42.5 43.0 43.53950

4000

4050

4100

4150

4200

4250

f(x) = − 113.2296879306 x² + 9510.080581804 x − 195485.7849684R² = 0.891471798557738

ROCKWELL HARDNESS C

PULL

STR

ENG

TH (

FT-L

BS)


Strength Frame machine was used for measuring the pull strength.

Objectives:

1.How hard should the face plate be for maximum strength?

2.What is certainty that the deadbolt will tolerate 4,150 ft-lbs of force?


40.5 41.0 41.5 42.0 42.5 43.0 43.53950

4000

4050

4100

4150

4200

4250

f(x) = − 113.229687930558 x² + 9510.08058180449 x − 195485.78496844R² = 0.891471798557738

ROCKWELL HARDNESS C

PULL

STR

ENG

TH (

FT-L

BS)


Let:T = Target Value for HardnessT = Min + AdjustmentAdjustment < RangeY = predicted pull strength @ T

Then, Y = -113.23T2 + 9510.1T - 195486


40.5 41.0 41.5 42.0 42.5 43.0 43.53950

4000

4050

4100

4150

4200

4250

f(x) = − 113.229687930558 x² + 9510.08058180449 x − 195485.78496844R² = 0.891471798557738

ROCKWELL HARDNESS C

PULL

STR

ENG

TH (

FT-L

BS)

40.9

4065


40.5 41.0 41.5 42.0 42.5 43.0 43.53950

4000

4050

4100

4150

4200

4250

f(x) = − 113.229687930558 x² + 9510.08058180449 x − 195485.78496844R² = 0.891471798557738

ROCKWELL HARDNESS C

PULL

STR

ENG

TH (

FT-L

BS)

Min X Max X


40.5 41.0 41.5 42.0 42.5 43.0 43.53950

4000

4050

4100

4150

4200

4250

ROCKWELL HARDNESS C

PULL

STR

ENG

TH (

FT-L

BS)

Min X Max X

Optimal Y

Target Value

Adjustment <[Max-Min]


40.5 41.0 41.5 42.0 42.5 43.0 43.53950

4000

4050

4100

4150

4200

4250

ROCKWELL HARDNESS C

PULL

STR

ENG

TH (

FT-L

BS)

Min X Max X

Optimal Y

Adjustment <[Max-Min]

Target Value

Performance Goal


Strength Frame machine was used for measuring the pull strength.

Answers:1. How hard should the face plate be for maximum

strength? 42.0 Rockwell C for an expected pull strength of 4,200 ft-lbs.

2. What is certainty that the deadbolt will tolerate 4,150 ft-lbs of force? 99.84% @ 42.0 Rockwell C


ORACLE Crystal Ball is needed in new product development because:

1. Errors are inherent in all predictive models (e.g., Linear Regression or Design of Experiments). We need a tool for modeling them (risks) so that our new products perform as expected.

2. Often times we are searching for that “Sweet Spot” or Optimal Point that lets our product perform at its peak best.

3. We want to know the probability of success (or failure) associated with our design or performance goals.


LINEAR STATISTICAL STACK-UPSEXERCISE 2 OF 3

Robust Tolerance Design

2

ND lock


Schlage ND-Series Heavy Duty Commercial Cylindrical Lever Lock

Based on the survey response of 107 customers in July 2009

04/08/2023R Balisnomo 30+40 interdependent critical dimensions in the ND Lock


TechnicalDefinitionof Wobble

USL = 0

USL = 0.02

Vertical



USL = 0

Vertical

HorizontalUSL = 0.02



USL = 0

Vertical

Horizontal

AxialUSL = 0.03


USL = 0

USL = 0.02

VerticalTechnicalDefinitionof Wobble

Use Copy & Paste for Horizontal & Axial, but don’t forget to change USL=0.03 for Axial


USL = 0

USL = 0.02



USL = 0




USL = 0


Horizontal

AxialUSL = 0.03


Financial Analysis of Wobble Problem


USL = 0

USL = 0.02


Before After OptQuest2% improvement


USL = 0





USL = 0


Horizontal

AxialUSL = 0.03



Financial Analysis of Wobble Problem


Optional Step: If you only want to run 1 out of 4 possible Forecast (Outputs)


99% @ $394

95% @ $634

88% @ $900

82% @ $106290% @

$835

86% @ $957

A

B

C

D

E

F

WhichHorseWould

YouBet On?

-$380


99% Certain we can save at least $394K by changing the nominal drawing dimensions.


ORACLE Crystal Ball® is needed in new product development because:

1. When it comes to tolerance stack-ups1 there is no better tool for optimizing fit and function. Humans typically cannot simultaneously adjust +40 interdependent variables at the same time.

2. It’s exponentially easier to fix the problem in the Design Phase then it is to fix the problem once the product has launched.

3. It’s a good tool for translating quality and engineering terms into language finance and management can understand.

1. note: Cartesian -- not GD&T


EFFICIENT FRONTIEREXERCISE 3 OF 3

Cost Versus Quality3

Rekey


3. Extract Current Security Control Key 2. Rotate 30 Degrees CCW

4. Insert New Security Control Key

NE

W

5. Rotate back to home position

1. Insert Current Security Control Key

NE

W

The New Way to Rekey a Lock


E

B

A

D C


1 = choose this supplier to make this part

0 = do NOT choose this supplierKey:


“Best” SupplierCpk = 1.75 (99.99%)Unit Cost = $3.49

“Cheap” SupplierCpk = 0.59 (60.64%)Unit Cost = $0.99


Objective:

1. If the requirement is 0.5<Cpk < 0.9, find the lowest cost supplier(s)



4. If the requirement is Cpk > 1.7, find the lowest cost supplier(s)


The model does not know that only one of the four suppliers can produce each part. We have to specify this constraint into the analysis.


This constraint only allows one supplier out of four to produce each part.


Due to time constraints, we may be running the optimization for a much-less time (only 3-5 minutes); thus, your actual results may vary from this presentation.


1,135 simulations @ 10,000 runs per simulation (11,350,000 data points) in 10 minutes, or 18,917 data points per second.


(0.59, $0.99)

(0.92, $1.62)

(1.35, $2.55)

(1.72, $3.44)

Trade-off Curve between Quality and Unit Cost.

Due to a shorter number of runs, your results may vary from what is being shown here.


ORACLE Crystal Ball® is needed in new product development because:

1. The trade-offs between RISK and REWARD are difficult to quantify. Efficient Frontiers is a tool that specializes in the above.

2. Simple YES/NO or GO/STOP decisions become complex in the face of so many combinations and permutations. Sometimes it’s better to let the a Computer make the long-term business decisions.

3. We can make a lot of money by solving big and difficult problems in a short amount of time.


Name: Ramon (Ray) BalisnomoTitle/Position: Design for Six Sigma Instructor/Engr.Company: Ingersoll Rand Securities Technologies

CONTACT INFORMATION:

E-mail: [email protected]@gmail.com

Telephone: 719-896-3604

The EndDo you have any questions?

crystalball in new product development

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