# chapter 5: thermally activated processes & diffusion me 2105 dr. r. lindeke

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Chapter 5: Thermally Activated Processes & Diffusion ME 2105 Dr. R. Lindeke Slide 2 DIFFUSION is observed to occur: IN LIQUIDS: ink in water, etc. and IN SOLIDS IN GASES: swamp gas in air, exhaust fumes into Smog, etc. Carburization Surface coating Slide 3 Case Hardening: Diffuse carbon atoms into the host iron atoms at the surface. Example of interstitial diffusion to produce a surface (case) hardened gear. The carbon atoms (interstitially) diffuse from a carbon rich atmosphere into the steel thru the surface. Result: The presence of C atoms makes the iron (steel) surface harder. Processing Using Diffusion Courtesy of Surface Division, Midland-Ross. Slide 4 Typical Arrhenius plot of data compared with Equation 5.2. This behavior controls most molecular movement driven behavior (like vacancy formation or diffusion). The slope equals Q/R, and the intercept (at 1/T = 0) is ln(C) Note: this is a Semi-log plot Slide 5 Process path showing how an atom must overcome an activation energy, q, to move from one stable position to a similar adjacent position. And it is this Activation Energy barrier which we can model as in Ex. 5.1 that determines the Rate Limiting Step in any process Slide 6 The overall thermal expansion (L/L) of aluminum is measurably greater than the lattice parameter expansion (a/a) at high temperatures because vacancies are produced by thermal agitation(a). A semilog (Arrhenius-type) plot of ln(vacancy concentration) (b) versus 1/T based on the data of part (a). The slope of the plot (E v /k) indicates that 0.76 eV of energy is required to create a single vacancy in the aluminum crystal structure. (From P. G. Shewmon, Diffusion in Solids, McGraw-Hill Book Company, New York, 1963.) Slide 7 Atomic migration (Diffusion) occurs by a mechanism of vacancy migration. Note that the overall direction of material flow (the atom) is opposite to the direction of vacancy flow. So diffusion is faster at higher temperature since more vacancies will exist in the lattice! Slide 8 Diffusion by an interstitialcy mechanism illustrates the random- walk nature of atomic migration (which is quicker as temperature increases) Diffusion of importance to material engineers is observed to occur by both mechanisms vacancy migration and random moving interstitials Slide 9 The interdiffusion of materials A and B. Although any given A or B atom is equally likely to walk in any random direction (see Figure 5.6), the concentration gradients of the two materials can result in a net flow of A atoms into the B material, and vice versa. (From W. D. Kingery, H. K. Bowen, and D. R. Uhlmann, Introduction to Ceramics, 2nd ed., John Wiley & Sons, Inc., New York, 1976.) Slide 10 The interdiffusion of materials on an atomic scale was illustrated in Figure 5.7. This interdiffusion of copper and nickel is a comparable example on the microscopic scale. Slide 11 Quantifying Diffusion: Ficks First Law (Equation 5.8) is a statement of Material Flux across a Barrier We will consider this model as a Steady State Diffusion system Slide 12 Quantifying Diffusion: Ficks Second Law (Equation 5.10) is a statement of Concentration Variation over time across a Barrier Solution to Ficks second law (Equation 5.10) for the case of a semi- infinite solid, constant surface concentration of the diffusing species c s, initial bulk concentration c 0, and a constant diffusion coefficient, D. We will consider this model as a Non-Steady State (transient) Diffusion system Slide 13 One practically important solution is for a semi-infinite solid (as illustrated in the previous graph) in which the surface concentration is held constant. Frequently source of the diffusing species is a gas phase, which is maintained at a constant pressure value. The following assumptions are implied for a good solution: 1.Before diffusion, any of the diffusing solute atoms in the solid are uniformly distributed with concentration of C 0. 2.The value of x (position in the solid) is taken as zero at the surface and increases with distance into the solid. 3.The time is taken to be zero the instant before the diffusion process begins. A bar of length l is considered to be semi-infinite when: Slide 14 Non-steady State Diffusion Adapted from Fig. 5.5, Callister 7e. at t = 0, C = C o for 0 x at t > 0, C = C S for x = 0 (const. surf. conc.) C = C o for x = Copper diffuses into a bar of aluminum. pre-existing conc., C o of copper atoms Surface conc., C of Cu atoms bar s C s Boundary Conditions: Notice: the concentration decreases at increasing x (from surface) while it increases at a given x as time increases! Slide 15 Master plot summarizing all of the diffusion results of Figure 5.10 on a single curve. Slide 16 Mathematical Solution: C(x,t) = Conc. at point x at time t erf (z) = error function erf(z) values are given in Table 5.1 (see next slide!) CSCS CoCo C(x,t)C(x,t) Slide 17 Slide 18 Similar F.S.L. Diffusion Studies have been documented for other than Semi-Infinite Solids: The parameter c m is the average concentration of diffusing species within the sample. Again, the surface concentration, c s, and diffusion coefficient, D, are assumed to be constant. (From W. D. Kingery, H. K. Bowen, and D. R. Uhlmann, Introduction to Ceramics, 2nd ed., John Wiley & Sons, Inc., New York, 1976.) Slide 19 Non-steady State Diffusion Sample Problem: An FCC iron-carbon alloy initially containing 0.20 wt% C is carburized at an elevated temperature and in an atmosphere that gives a surface carbon concentration (C s ) constant at 1.0 wt%. If after 49.5 h the concentration of carbon is 0.35 wt% at a position 4.0 mm below the surface, determine the temperature at which the treatment was carried out. Solution: use Eqn. 5.11 Slide 20 The solution requires the use of the erf function which was developed to model conduction along a semi-infinite rod Slide 21 Solution (cont.): t = 49.5 h x = 4 x 10 -3 m C x = 0.35 wt%C s = 1.0 wt% C o = 0.20 wt% erf(z) = 0.8125 Slide 22 Solution (cont.): We must now determine from Table 5.1 the value of z for which the error function is 0.8125. An interpolation is necessary as follows zerf(z) 0.900.7970 z0.8125 0.950.8209 z 0.93 And now solve for D: Now By LINEAR Interpolation: Slide 23 Diffusion and Temperature The Diffusion coefficient seen in Ficks Laws increases with increasing T and, along with vacancy formation, is a Classic Arrhenius Model: D DoDo exp QdQd RT = pre-exponential [m 2 /s] = diffusion coefficient [m 2 /s] = activation energy for diffusion [J/mol or eV/atom] = gas constant [8.314 J/mol-K] = absolute temperature [K] D DoDo QdQd R T So, using this model, we should be able to back out the temperature at which this process took place! Slide 24 Arrhenius plot of the diffusivity of carbon in -iron over a range of temperatures. Note also related Figures 4.4 and 5.6 and other metallic diffusion data in Figure 5.14. Slide 25 Arrhenius plot of diffusivity data for a number of metallic systems. (From L. H. Van Vlack, Elements of Materials Science and Engineering, 4th ed., Addison-Wesley Publishing Co., Inc., Reading, MA, 1980.) Slide 26 In a computationally simpler form (to read!): Slide 27 Similar Data also exists for Ionic (and Organic) Compounds: From P. Kofstad, Nonstoichiometry, Diffusion, and Electrical Conductivity in Binary Metal Oxides, John Wiley & Sons, Inc., NY, 1972; and S. M. Hu in Atomic Diffusion in Semiconductors, D. Shaw, Ed., Plenum Press, New York, 1973. Slide 28 And in a Tabular Form: Slide 29 To solve for the temperature at which D has above value, we use a rearranged the D (Arrhenius) Equation: Now, Returning to the Solution to our Carburizing problem: Slide 30 Following Up: In industry one may wish to speed up this process This can be accomplished by increasing: Temperature of the process Surface concentration of the diffusing species If we choose to increase the temperature, determine how long it will take to reach the same concentration at the same depth as in the previous study ? Slide 31 Diffusion time calculation: Given target X (depth of case) and concentration are equal: Here we known that D*t is a constant for the diffusion process (where D is a function of temperature) D 1260 was 2.6x10 -11 m 2 /s at 987 C while the process took 49.5 hours How long will it take if the temperature is increased to 1250 C? Slide 32 Considering a First Law or Steady-State Diffusion Case C1C1 C2C2 x C1C1 C2C2 x1x1 x2x2 D is the diffusion coefficient Here, The Rate of diffusion is independent of time Flux is proportional to concentration gradient = Note, steady state diffusion concentration gradient ( dC/dx) is linear Slide 33 F.F.L. Example: Chemical Protective Clothing (CPC) Methylene chloride is a common ingredient in paint removers. Besides being an irritant, it also may be absorbed through skin. When using this paint remover, protective gloves should be worn. If butyl rubber gloves (0.04 cm thick) are used, what is the diffusive flux of methylene chloride through the glove? Data: diffusion coefficient of MeChl in butyl rubber: D = 110 x10 -8 cm 2 /s surface concentrations: C 2 = 0.02 g/cm 3 (inside surface) C 1 = 0.44 g/cm 3 (outside surface) Slide 34 Example (cont). glove C1C1 C2C2 skin paint remover x1x1 x2x2 D = 110 x 10 -8 cm 2 /s C 2 = 0.02 g/cm 3 C 1 = 0.44 g/cm 3 x 2 x 1 = X = 0.04 cm Data: Slide 35 What happens to a Worker? If a person is in contact with the irritant and more than about 0.5 gm of the irritant is deposited on their skin they need to take a wash break If 25 cm 2 of glove is in the paint thinner can, How Long will it take before they must take a wash break? Slide 36 Another Example: Chemical Protective Clothing (CPC) If butyl rubber gloves (0.04 cm thick) are used, what is the breakthrough time (t b ), i.e., how long could the gloves be used before methylene chloride reaches the hand (at all)? Data: diffusion coefficient of Me-C

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