chapter 4 nuclear chemistry: the heart of matter

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Chapter 4 Nuclear Chemistry: The Heart of Matter

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Chapter 4 Nuclear Chemistry: The Heart of Matter. Radioisotopes. Radioactive decay – Many isotopes are unstable Nuclei that undergo radioactive decay May produce one or more types of radiation. Natural Radioactivity. Background radiation What occurs from natural sources - PowerPoint PPT Presentation

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Page 1: Chapter 4  Nuclear Chemistry: The Heart of Matter

Chapter 4

Nuclear Chemistry: The Heart of Matter

Page 2: Chapter 4  Nuclear Chemistry: The Heart of Matter

Radioisotopes

• Radioactive decay – Many isotopes are unstable

– Nuclei that undergo radioactive decay

– May produce one or more types of radiation

Page 3: Chapter 4  Nuclear Chemistry: The Heart of Matter

Natural Radioactivity• Background

radiation– What occurs from

natural sources– Accounts for >80%

of radioactivity exposure

Page 4: Chapter 4  Nuclear Chemistry: The Heart of Matter

Types of Radiation

• Ionizing radiation – knocks electrons out of atoms or groups of atoms

– Produces charged species – ions– Charged species that cause damage

Page 5: Chapter 4  Nuclear Chemistry: The Heart of Matter

Alpha Decay

• Nucleus loses particle– Mass decreases by 4 and atomic number decreases by 2

He42

Page 6: Chapter 4  Nuclear Chemistry: The Heart of Matter

Beta Decay• Nucleus loses particle

– No change in mass but atomic number increases

e01

Positron Emission• Loses a positron

– Equal mass but opposite charge of an electron– Decrease in atomic number and no change in mass +

Page 7: Chapter 4  Nuclear Chemistry: The Heart of Matter

Electron Capture• Nucleus absorbs an

electron and then releases an X-ray

• Mass number stays the same and atomic number decreases

Gamma Radiation

• Release of high-energy photon

• Typically occurs after another radioactive decay• No change in mass number or atomic number

Page 8: Chapter 4  Nuclear Chemistry: The Heart of Matter

Nuclear Equations

• Elements may change in nuclear reactions• Total mass and sum of atomic numbers must be

the same• MUST specify isotope

Po He Rn 21884

42

22286

Page 9: Chapter 4  Nuclear Chemistry: The Heart of Matter

Differences Between Chemical and Nuclear Reactions

Page 10: Chapter 4  Nuclear Chemistry: The Heart of Matter

Example 4.1  Balancing Nuclear Equations

Write balanced nuclear equations for each of the following processes. In each case, indicate what new element is formed.a. Plutonium-239 emits an alpha particle when it decays.b. Protactinium-234 undergoes beta decay.c. Carbon-11 emits a positron when it decays.d. Carbon-11 undergoes electron capture.

Solutiona. We start by writing the symbol for plutonium-239 and a partial equation showing that one of the products is an alpha particle (helium nucleus):

23994 Pu 4

2 He + ?

Mass and charge are conserved. The new element must have a mass of 239 – 4 = 235 and a charge of 94 – 2 = 92. The nuclear charge (atomic number) of 92 identifies the element as uranium (U):

23994 Pu 4

2 He + 23592 U

Page 11: Chapter 4  Nuclear Chemistry: The Heart of Matter

Half-Life• Period for one-half of the

original elements to undergo radioactive decay

• Characteristic for each isotope

• Fraction remaining =

n = number of half-lives

n21

Page 12: Chapter 4  Nuclear Chemistry: The Heart of Matter

You obtain a new sample of cobalt-60, half-life 5.25 years, with a mass of 400 mg. How much cobalt-60 remains after 15.75 years (three half-lives)?

Example 4.2  Half-Lives

SolutionThe fraction remaining after three half-lives is

1

2n1

23

1

2 x 2 x 2

1

8===

The amount of cobalt-60 remaining is ( ) (400 mg) = 50 mg.1

8

You have 1.224 mg of freshly prepared gold-189, half-life 30 min. How much of the gold-189 sample remains after five half-lives?

Exercise 4.2A

What percentage of the original radioactivity remains after five half-lives?

Exercise 4.2B

Page 13: Chapter 4  Nuclear Chemistry: The Heart of Matter

You obtain a 20.0-mg sample of mercury-190, half-life 20 min. How much of the mercury-190 sample remains after 2 hr?

Example 4.3  

There are 120 min in 2 hr. There are ( ) = 6 half-lives in 2 hr. The fraction remainingafter six half-lives is

The amount of mercury-190 remaining is ( ) (20.0 mg) = 0.313 mg.

Solution

1

2n1

26

1

2 x 2 x 2 x 2 x 2 x 2

1

64===

164

12020

A sample of 16.0 mg of nickel-57, half-life 36.0 hr, is produced in a nuclear reactor. How much of the nickel-57 sample remains after 7.5 days?

Exercise 4.3A

Tc-99 decays to Ru-99 with a half-life of 210,000 years. Starting with 1.0 mg of Tc-99, how long will it take for 0.75 mg of Ru-99 to form?

Exercise 4.3B

Page 14: Chapter 4  Nuclear Chemistry: The Heart of Matter

Radioisotopic Dating• Use certain isotopes to estimate the age of various

items• 235U half-life = 4.5 billion years

– Determine age of rock• 3H half-life = 12.3 years

– Used to date aged wines

Carbon-14 Dating• 98.9% 12C• Produce 14C in upper atmosphere• Half-life of 5730 years• ~50,000 y maximum age for dating

H Cn N 11

146

10

147

Page 15: Chapter 4  Nuclear Chemistry: The Heart of Matter

A piece of fossilized wood has carbon-14 activity one-eighth that of new wood. How old is the artifact? The half-life of carbon-14 is 5730 years.

Example 4.4  

SolutionThe carbon-14 has gone through three half-lives:

It is therefore about 3 x 5730 = 17,190 years old.

1

8==

1

2

1

2x

1

2x( )1

2

3

How old is a piece of cloth that has carbon-14 activity that of new cloth fibers? The half-life of carbon-14 is 5730 years.

Exercise 4.41

16

Page 16: Chapter 4  Nuclear Chemistry: The Heart of Matter

Shroud of Turin• Alleged burial shroud of Jesus Christ

– Contains faint human likeness– First documented in Middle Ages

• Carbon-14 dating done in 1988– Three separate labs– Shroud ~800 years old– Unlikely to be burial shroud

Artificial Transmutation• Transmutation changes one element into another

– Middle Ages: change lead to gold• In 1919 Rutherford established protons as fundamental particles

– Basic building blocks of nuclei

H O He N 11

178

42

147

Page 17: Chapter 4  Nuclear Chemistry: The Heart of Matter

Uses of Radioisotopes• Tracers

– Easy to detect– Different isotopes have similar chemical and physical properties– Physical, chemical, or biological processes

• Agriculture– Induce heritable genetic alterations – mutations– Preservative

– Destroys microorganisms with little change to taste or appearance of the food

Nuclear Medicine• Used for two purposes• Therapeutic – treat or cure disease using radiation• Diagnostic – obtain information about patient’s health

Page 18: Chapter 4  Nuclear Chemistry: The Heart of Matter

Radiation Therapy• Radiation most lethal to dividing cells• Makes some forms of cancer susceptible• Try to destroy cancer cells before too much damage to healthy cells

– Direct radiation at cancer cells– Gives rise to side effects

Diagnostic Uses• Many different isotopes used

– See Table 4.6• Can measure specific things

– Iodine-131 to locate tumors in thyroid– Selenium-75 to look at pancreas– Gadolinium-153 to determine bone mineralization

Page 19: Chapter 4  Nuclear Chemistry: The Heart of Matter

Imaging• Positron emission tomography (PET)• Uses an isotope that emits a positron• Observe amount of radiation released

e B C 01

115

116

Penetrating Power of Radiation• The more mass the particle has, the less penetrating it is• The faster the particle is, the more penetrating it is

Page 20: Chapter 4  Nuclear Chemistry: The Heart of Matter

Prevent Radiation Damage• To minimize

damage – Stay a distance

from radioactive sources

– Use shielding; need more with more penetrating forms of radiation

Page 21: Chapter 4  Nuclear Chemistry: The Heart of Matter

Example 4.6

One of the isotopes used for PET scans is oxygen-15, a positron emitter. What new element is formed when oxygen-15 decays?

Phosphorus-30 is a positron-emitting radioisotope suitable for use in PET scans. What new element is formed when phosphorus-30 decays?

Exercise 4.6

SolutionFirst write the nuclear equation

0+1 e + ?15

8O

The nucleon number does not change, but the atomic number becomes 8 – 1, or 7; and sothe new product is nitrogen-15:

0+1 e +15

8O 157N

Page 22: Chapter 4  Nuclear Chemistry: The Heart of Matter

Energy from Nucleus• E = mc2

• Lose mass, gain energy– For chemical

reactions, mass changes are not measurable

– For nuclear reactions, mass changes may be measurable

Page 23: Chapter 4  Nuclear Chemistry: The Heart of Matter

Binding Energy• Holds protons and neutrons together in

the nucleus• The higher the binding energy, the more

stable the element

Page 24: Chapter 4  Nuclear Chemistry: The Heart of Matter

Nuclear Fission• “Splitting the atom”• Break a large

nucleus into smaller nuclei

Page 25: Chapter 4  Nuclear Chemistry: The Heart of Matter

Nuclear Chain Reaction• Neutrons from one

fission event split further atoms

• Only certain isotopes, fissile isotopes, undergo nuclear chain reactions

Page 26: Chapter 4  Nuclear Chemistry: The Heart of Matter

Manhattan Project• How to sustain the nuclear reaction?• How to enrich uranium to >90% 235U?

– Only 0.7% natural abundance• How to make 239Pu (another fissile isotope)?• How to make a nuclear fission bomb?

Radioactive Fallout

• Nuclear bomb detonated; radioactive materials may rain down miles away and days later– Some may be unreacted U or Pu– Radioactive isotopes produced during the explosion

Page 27: Chapter 4  Nuclear Chemistry: The Heart of Matter

Nuclear Power Plants• Provide ~20% U.S. electricity

– France >70% • Slow controlled release of energy• Need 2.5–3.5% 235U• Problem with disposal of radioactive waste

Nuclear Fusion• Reaction takes smaller nuclei and builds larger ones

– Also called thermonuclear reactions

e2 He H4 01

42

11

• Releases tremendous amounts of energy–1 g of H would release same as 20 tons of coal