chapter 29: nuclear physics
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Chapter 29: Nuclear Physics. The Nucleus Binding Energy Radioactivity Half-life Biological Effects of Radiation Induced Nuclear Reactions Fission and Fusion. §29.1 Nuclear Structure. The atomic nucleus is composed of neutrons and protons. These particles are called nucleons. - PowerPoint PPT PresentationTRANSCRIPT
Chapter 29: Nuclear Physics
1
•The Nucleus
•Binding Energy
•Radioactivity
•Half-life
•Biological Effects of Radiation
•Induced Nuclear Reactions
•Fission and Fusion
§29.1 Nuclear Structure
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The atomic nucleus is composed of neutrons and protons. These particles are called nucleons.
The atom’s atomic number (Z) gives the number of protons in its nucleus. It is the atomic number that determines an atom’s identity.
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The nucleon number or mass number is A = Z+N, where N is the number of neutrons.
Masses of atoms are sometimes give in terms of atomic mass units. 1u = 1.66053910-27 kg.
4
The mass quoted for an atom in the periodic table is a weighted average over all of the natural isotopes of that element. The weight factors are determined by using the relative abundance on Earth of each isotope.
Atoms of the same element with differing numbers of neutrons are known as isotopes.
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For an atomic nucleus .AV
Am
This implies the density of an atomic nucleus is independent of A.
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3
3
4
Ar
ArV
As an equality 31
0Arr
where r0=1.210-15 m = 1.2 fm
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Example (text problem 29.2): Calculate the mass density of nuclear matter.
m 102.1 150
31 Arr
Consider a nucleus with one nucleon (A = 1).
The density is
.kg/m 103.2
m 102.134
kg 1066.1
34
317
315
27
3
r
m
7
Example (text problem 29.9): Find the radius and
volume of the nucleus.
m. 1070.5107m 102.1 151/3151/30
Arr
.m 107.73
4 3433 rV
The radius is
The volume is
Tc10743
§29.2 Binding Energy
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A nucleus is held together by the strong nuclear force. This force only acts over distances of a few fermis.
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The binding energy (EB) of a nucleus is the energy that must be supplied to separate it into individual protons and neutrons.
EB = Total energy of Z protons and N neutrons – total energy of nucleus.
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Total energy of Z protons and N neutrons = (mass of Z protons and N neutrons)c2.
Total energy of nucleus= (mass of nucleus)c2.
These can be used to define the mass defect m = (mass of Z protons and N neutrons) - (mass of nucleus) so that
.2mcEB
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Nucleons also obey the Pauli Exclusion Principle such that only two protons (neutrons) can occupy each proton (neutron) energy level.
Like an atom, a nucleus can be put into an excited state if it absorbs a photon of the correct energy. The nucleus can then emit a photon to go to a lower energy state.
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Example (text problem 29.14): (a) Find the binding energy of the 16O nucleus.
u1370046.0
u9949146.15u0086649.1 1.00782508
atom Oneutral of mass
neutrons 8 of mass atoms H 8 of massm16
MeV 8.1272 mcEB
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(b) What is the average binding energy per nucleon?
Example continued:
n.MeV/nucleo 986.7
nucleons ofnumber nucleonper energy Binding
BE
§29.3 Radioactivity
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Some nuclei are unstable and decay. These nuclei are radioactive. A nucleus can emit an alpha ray, beta ray, or a gamma ray during its decay.
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During nuclear reactions:
1. Charge is conserved.
2. The total number of nucleons is constant.
3. Energy is conserved.
Define: disintegration energy = binding energy of radioactive nucleus – total binding energy of products. This is the rest mass energy that can be converted into other forms of energy.
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Alpha rays have been identified as helium nuclei.
The reaction for alpha decay is
42
42
DP AZ
AZ
Parent nucleus
Daughter nucleus
Alpha particle
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Example (text problem 29.28): Show that the spontaneous alpha decay of 19O is not possible.
.CO 42
156
198 The reaction is
The mass of the products (including electrons) is 19.01320250u.
The mass of 19O is 19.0035787u.
The mass of the products is larger than the reactant, so this reaction cannot occur spontaneously.
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Beta rays have been identified as either electrons (-) or positrons (+).
The reaction for beta-minus decay is
.e 00
011 DP A
ZAZ
The reaction for beta-plus decay is
.e 00
011 DP A
ZAZ
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The neutrino and antineutrino have no charge and are nearly massless. They do not readily interact with matter.
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During beta-minus decays, a neutron is converted into a proton.
00
01
11
10 epn
During beta-plus decays, a proton is converted into a neutron.
00
01
10
11 enp
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Example (text problem 29.29): Calculate the maximum kinetic energy of the beta particle when decays via - decay.
.eCaK 00
01
4020
4019 The reaction is
The maximum kinetic energy of the electron is given by the disintegration energy.
K4019
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u. 00140750.0
1920
KCa
eKeCa
MM
mMmmMm e
Example continued:
The difference between the mass of the products and the reactant is
The disintegration energy and the maximum KE of the electron is
MeV. 31.12 cmEB
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During inverse beta decay (electron capture) a proton in a nucleus captures an electron. The reaction is
.npe 00
10
11
01
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Gamma rays were determined to be high energy photons.
A gamma ray will be emitted when a nucleus is an excited state when making a transition to a lower energy level. For example,
.TlTl 20881
*20881
When a nucleus has experienced alpha or beta decay, it is not always left in the ground state.
§29.4 Radioactive Decay Rates and Half-Lives
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The half-life of a sample of unstable nuclei is the time it takes for one-half of the sample to decay. The decay process is quantum mechanical and is based on probability.
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Each radioactive nucleus has a probability per second that it will decay, called the decay constant.
unit time
decay ofy probabilitconstant decay
The number of nuclei that decay in a short time interval is
.tNN
There are statistical fluctuations in the number of decays that occur. These fluctuations are of order .N
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The decay rate or activity is the number of radioactive decays that occur in a sample per unit time.
Nt
NR
unit time
decays ofnumber
The unit of activity is the bequerel. 1 Bq = 1 decay/sec. Another common unit is the curie. 1 Ci = 3.71010 Bq.
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The number of nuclei remaining in a sample having N0 nuclei at t=0 is
./0
teNtN
is the mean lifetime of a nucleus.
1
Note: the above expression for N(t) is a way to determine the number of remaining nuclei only. It does not tell us which nuclei have decayed.
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It is common to write the expressions for N(t) and R(t) in terms of half-life (T1/2).
2ln2/1 T 2/12/1
2
12 00
Tt
Tt
NNtN
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Example (text problem 29.37): Some bones discovered in a crypt in Guatemala are carbon dated. The 14C activity is measured to be 0.242 Bq per gram of carbon. Approximately how old are the bones?
/0
teRtR
Solve for t:
years270
m0.25bq/gra
bq/gram 242.0ln
2ln
years 5730ln
2ln
ln
0
1/2
0
R
tRT
R
tRt
§29.5 Biological Effects of Radiation
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The absorbed dose of ionizing radiation is the amount of radiation energy absorbed per unit mass of tissue. Ionizing radiation is radiation with enough energy to ionize an atom or molecule.
The SI unit of absorbed dose is the Gray. 1 Gy = 1 J/kg. Another common unit is the rad (radiation absorbed dose). 1 rad = 0.01 Gy.
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Different radiation causes different amounts of biological damage. The biologically equivalent dose measures the amount of damage caused by radiation exposure.
Equivalent dose (in sieverts) = absorbed dose (in grays)* QF.
Equivalent dose (in rem) = absorbed dose (in rads)* QF.
QF is a quality factor that is a relative measure of biological damage (200 keV x-rays have QF = 1).
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Alpha, beta, and gamma radiation penetrates to different depths in biological materials.
•Alpha rays are stopped by a few cm of air or about 0.02 mm of aluminum.
•Beta-minus can penetrate a few cm into biological tissue.
•Gamma ray absorption is based on probability so they can penetrate to varying depths.
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Example (text problem 29.45): An alpha particle produced in radioactive alpha decay has a kinetic energy of typically about 6 MeV. When an alpha particle passes through matter, it makes ionizing collisions with molecules, giving up some of its kinetic energy to supply the binding energy of the electron that is removed. If a typical ionization energy for a molecule in the body is around 20 eV, roughly how many molecules can the alpha particle ionize before coming to rest?
sionization 105eV 20
MeV 6
ionizationper lost energy
particle alpha ofenergy totalsionization ofnumber
5
§29.6 Induced Nuclear Reactions
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An unstable nucleus decays in a spontaneous nuclear reaction. An induced nuclear reaction only takes place because it is caused by a collision between a nucleus and another particle.
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For example, p.CNn 1414
The above reaction is induced by the absorption of a neutron. This process is called neutron activation.
A spontaneous nuclear reaction will always release energy. In an induced nuclear reaction, some of the kinetic energy of the reactants is converted into rest mass of the products.
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An exoergic reaction releases energy.
An endoergic reaction is one that requires energy to make it proceed.
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Example (text problem 29.49): A certain nuclide absorbs a neutron. It then emits an electron, and then breaks up into two alpha particles. (a) Identify the original nucleus and the two intermediate nuclei (after absorbing the neutron and after emitting the electron).
The reactions are
.
en
42
423
01321
10
X
XXXe
f
e
f
c
d
a
b
Since the number of nucleons is conserved e = 4 + 4 = 8. Charge is conserved so f = 2 + 2 = 4. Identify X3 as Be.
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Example continued:
In the second step of the first reaction c= e+0 = 8 and d = f - 1. This gives d = 3. Identify X2 as Li.
In the first step of the reaction a + 1 = c so a = 7 and b + 0 = d = 3. Identify X1 as Li.
The nuclei involved are
Be. Li; Li; 843
832
731 XXX
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(b) Would any (anti)neutrino(s) be emitted? Explain.
Example continued:
In the second reaction (the beta decay of 8Li) will also involve the emission of one antineutrino.
§29.7 Fission
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Fission is when a large nucleus splits into two smaller, more tightly bound nuclei. This process releases energy.
Fission can either occur spontaneously when the nucleus is very large, or it can be induced. When fission occurs by the capture of slow moving neutrons, a chain reaction can occur.
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The process of fusion is the energy production mechanism in cores of stars. Stars on the main sequence (like the Sun) turn hydrogen into helium in their cores. This occurs by the proton-proton cycle and by the CNO (carbon) cycle.
Overall, this process take four protons and turn them into a helium nucleus and energy.
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Example (text problem 29.57): Consider the fusion reaction between a proton and a deuteron (shown below). (a) Identify the reaction product X.
XHH 21
11
The product must have 3 nucleons and a charge (atomic number) of 2. The element is He.
He32
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Example continued:
(b) The binding energy of the deuteron is about 1.1 MeV per nucleon and the binding energy of “X” is about 2.6 MeV per nucleon. Approximately how much energy (in MeV) is released in this fusion reaction?
The binding energies are: 0 MeV for 1H; 2.2 MeV for 2H; and 7.8 MeV for 3He.
Energy released = difference in binding energy between the products and reactants = 7.8 MeV – 2.2 MeV = 5.6 MeV.
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(c) Why is this reaction unlikely to occur at room temperature?
Example continued:
At room temperature the reactants will not have enough kinetic energy to overcome the Coulomb repulsion between them to get close enough to fuse.