chapter 19 radioactivity and nuclear chemistry

112
Copyright 2011 Pearson Education, I Chapter 19 Radioactivi ty and Nuclear Chemistry Roy Kennedy Massachusetts Bay Community College Wellesley Hills, MA Chemistry: A Molecular Approach, 2nd Ed. Nivaldo Tro

Upload: taline

Post on 11-Jan-2016

47 views

Category:

Documents


9 download

DESCRIPTION

Chemistry: A Molecular Approach , 2nd Ed. Nivaldo Tro. Chapter 19 Radioactivity and Nuclear Chemistry. Roy Kennedy Massachusetts Bay Community College Wellesley Hills, MA. Nuclear Medicine. Changes in the structure of the nucleus are used in many ways in medicine - PowerPoint PPT Presentation

TRANSCRIPT

Page 1: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Chapter 19Radioactivity and Nuclear Chemistry

Roy KennedyMassachusetts Bay Community College

Wellesley Hills, MA

Chemistry: A Molecular Approach, 2nd Ed.Nivaldo Tro

Page 2: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Nuclear Medicine

• Changes in the structure of the nucleus are used in many ways in medicine

• Nuclear radiation can be used to visualize or test structures in your body to see if they are operating properlye.g. labeling atoms so their intake and output can

be monitored

• Nuclear radiation can also be used to treat diseases because the radiation is ionizing, allowing it to attack unhealthy tissue

Tro: Chemistry: A Molecular Approach 2

Page 3: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

The Discovery of Radioactivity• Antoine-Henri Becquerel

designed an experiment to determine if phosphorescent minerals also gave off X-raysphosphorescence is the long-lived

emission of light by atoms or molecules that sometimes occurs after they absorb light

X-rays are detected by their ability to penetrate matter and expose a photographic plate

3Tro: Chemistry: A Molecular Approach

Page 4: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

The Discovery of Radioactivity

4Tro: Chemistry: A Molecular Approach

• Becquerel discovered that certain minerals were constantly producing energy rays that could penetrate matter

• Becquerel determined that 1. all the minerals that produced these rays contained

uranium2. the rays were produced even though the mineral was not

exposed to outside energy• He called them uranic rays because they were

emitted from minerals that contained uranium like X-rays but not related to phosphorescence

• Energy apparently being produced without energy input??

Page 5: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

The Curies

5Tro: Chemistry: A Molecular Approach

• Marie Curie broke down these minerals and used an electroscope to detect where the uranic rays were coming from

• She discovered the rays were emitted from specific elements

• She also discovered new elements by detecting their rays radium named for its green

phosphorescence polonium named for her homeland

• Because these rays were no longer just a property of uranium, she renamed it radioactivity

Page 6: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Electroscope++

+ +++

When charged, the metalfoils spread apart due to

like charge repulsion

When exposed to ionizing radiation, the

radiation knocks electrons off the

air molecules, which jump onto the foils

and discharge them, allowing them to

drop down

6Tro: Chemistry: A Molecular Approach

Page 7: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Other Properties of Radioactivity

7Tro: Chemistry: A Molecular Approach

• Radioactive rays can ionize mattercause uncharged matter to become chargedbasis of Geiger Counter and electroscope

• Radioactive rays have high energy• Radioactive rays can penetrate matter• Radioactive rays cause phosphorescent

chemicals to glowbasis of scintillation counter

Page 8: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

What Is Radioactivity?

• Radioactivity is the release of tiny, high-energy particles or gamma rays from an atom

• Particles are ejected from the nucleus

8Tro: Chemistry: A Molecular Approach

Page 9: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Types of Radioactive Decay

9Tro: Chemistry: A Molecular Approach

• Rutherford discovered three types of raysalpha (a) rays

have a charge of +2 c.u. and a mass of 4 amuwhat we now know to be helium nucleus

beta (b) rayshave a charge of −1 c.u. and negligible masselectron-like

gamma ( ) g raysform of light energy (not a particle like a and b)

• In addition, some unstable nuclei emit positrons like a positively charged electron

• Some unstable nuclei will undergo electron capturea low energy electron is pulled into the nucleus

Page 10: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Rutherford’s Experiment

++++++++++++

--------------a

gb

10Tro: Chemistry: A Molecular Approach

Page 11: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Penetrating Ability of Radioactive Rays

ab g

0.01 mm 1 mm 100 mm

Pieces of Lead

11Tro: Chemistry: A Molecular Approach

Page 12: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Facts About the Nucleus

• Very small volume compared to volume of the atom

• Essentially entire mass of atom• Very dense• Composed of protons and neutrons that are

tightly held togetherthe particles that make up the nucleus are called

nucleons

12Tro: Chemistry: A Molecular Approach

Page 13: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Facts About the Nucleus

• Every atom of an element has the same number of protonsatomic number (Z)

• Atoms of the same elements can have different numbers of neutronsisotopesdifferent atomic masses

• Isotopes are identified by their mass number (A)mass number = number of protons + neutrons

13Tro: Chemistry: A Molecular Approach

Page 14: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Facts About the Nucleus

• The number of neutrons is calculated by subtracting the atomic number from the mass number

• The nucleus of an isotope is called a nuclideless than 10% of the known nuclides are non-

radioactive, most are radionuclides• Each nuclide is identified by a symbol

Element – Mass Number = X – A

14Tro: Chemistry: A Molecular Approach

Page 15: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Radioactivity

• Radioactive nuclei spontaneously decompose into smaller nuclei radioactive decaywe say that radioactive nuclei are unstabledecomposing involves the nuclide emitting a particle

and/or energy

• The parent nuclide is the nucleus that is undergoing radioactive decay

• The daughter nuclide is the new nucleus that is made

• All nuclides with 84 or more protons are radioactive

15Tro: Chemistry: A Molecular Approach

Page 16: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Important Atomic Symbols

16Tro: Chemistry: A Molecular Approach

Page 17: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Transmutation

17Tro: Chemistry: A Molecular Approach

• Rutherford discovered that during the radioactive process, atoms of one element are changed into atoms of a different element – transmutationshowing that statement 3 of Dalton’s Atomic Theory is not

valid all the time, only for chemical reactions

• For one element to change into another, the number of protons in the nucleus must change!

Page 18: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Chemical Processes vs. Nuclear Processes

• Chemical reactions involve changes in the electronic structure of the atomatoms gain, lose, or share electronsno change in the nuclei occurs

• Nuclear reactions involve changes in the structure of the nucleuswhen the number of protons in the nucleus

changes, the atom becomes a different element

18Tro: Chemistry: A Molecular Approach

Page 19: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Nuclear Equations

• We describe nuclear processes with nuclear equations

• Use the symbol of the nuclide to represent the nucleus

• Atomic numbers and mass numbers are conserveduse this fact to predict the daughter nuclide if you know

parent and emitted particle

19Tro: Chemistry: A Molecular Approach

Page 20: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Alpha Emission

20Tro: Chemistry: A Molecular Approach

88222Ra

24He

86218Rn

• An particle contains 2 protons and 2 neutronshelium nucleus

• Most ionizing, but least penetrating of the types of radioactivity

• Loss of an alpha particle meansatomic number decreases by 2mass number decreases by 4

Page 21: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.21Tro: Chemistry: A Molecular Approach

Page 22: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Beta Emission

22Tro: Chemistry: A Molecular Approach

• A particle is like an electronmoving much fasterproduced from the nucleus

• About 10 times more penetrating than a, but only about half the ionizing ability

• When an atom loses a particle itsatomic number increases by 1mass number remains the same

• In beta decay, a neutron changes into a proton

Page 23: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.23Tro: Chemistry: A Molecular Approach

Page 24: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Gamma Emission

24Tro: Chemistry: A Molecular Approach

• Gamma (g) rays are high energy photons of light

• No loss of particles from the nucleus• No change in the composition of the nucleus

same atomic number and mass number• Least ionizing, but most penetrating• Generally occurs after the nucleus undergoes

some other type of decay and the remaining particles rearrange

Page 25: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Positron Emission

25Tro: Chemistry: A Molecular Approach

• Positron has a charge of +1 c.u. and negligible massanti-electron

• Similar to beta particles in their ionizing and penetrating ability

• When an atom loses a positron from the nucleus, itsmass number remains the sameatomic number decreases by 1

• Positrons result from a proton changing into a neutron

Page 26: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.26Tro: Chemistry: A Molecular Approach

Page 27: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Electron Capture

27Tro: Chemistry: A Molecular Approach

• Occurs when an inner orbital electron is pulled into the nucleus

• No particle emission, but atom changessame result as positron emission

• Proton combines with the electron to make a neutronmass number stays the sameatomic number decreases by one

Page 28: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Particle Changes

28Tro: Chemistry: A Molecular Approach

Page 29: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.29Tro: Chemistry: A Molecular Approach

Page 30: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

What Kind of Decay and How Many Protons and Neutrons Are in the Daughter?

Alpha emission giving a daughter nuclide withnine protons and seven neutrons

11 p+

9 n0

30Tro: Chemistry: A Molecular Approach

= proton

= neutron

? +

Page 31: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

? +

What Kind of Decay and How Many Protons and Neutrons Are in the Daughter?, Continued

Beta emission giving a daughter nuclide with10 protons and 11 neutrons

9 p+

12 n0

31Tro: Chemistry: A Molecular Approach

= proton

= neutron

= electron

Page 32: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

What Kind of Decay and How Many Protons and Neutrons Are in the Daughter?, Continued

Positron emission giving a daughter nuclide withfour protons and five neutrons

5 p+

4 n0

32Tro: Chemistry: A Molecular Approach

? +

= proton

= neutron

= positron

Page 33: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Nuclear Equations

33Tro: Chemistry: A Molecular Approach

• In the nuclear equation, mass numbers and atomic numbers are conserved

• We can use this fact to determine the identity of a daughter nuclide if we know the parent and mode of decay

Page 34: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Example 19.2b: Write the nuclear equation for positron emission from K–40

1. Write the nuclide symbols for both the starting radionuclide and the particle

34Tro: Chemistry: A Molecular Approach

Page 35: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Examle 19.2b: Write the nuclear equation for positron emission from K–40

2. Set up the equation• emitted particles are products• captured particles are reactants

35Tro: Chemistry: A Molecular Approach

Page 36: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Example 19.2b: Write the nuclear equation for positron emission from K–40

3. Determine the mass number and atomic number of the missing nuclide• mass and atomic numbers are conserved

36Tro: Chemistry: A Molecular Approach

Page 37: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Example 19.2b: Write the nuclear equation for positron emission from K–40

4. Identify and determine the symbol of the element from the atomic number

37Tro: Chemistry: A Molecular Approach

Page 38: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Practice – Write a nuclear equation for each of the following

Tro: Chemistry: A Molecular Approach 38

alpha emission from U–238

beta emission from Ne–24

positron emission from N–13

electron capture by Be–7

Page 39: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

What Causes Nuclei to Decompose?

• The particles in the nucleus are held together by a very strong attractive force only found in the nucleus called the strong forceacts only over very short distances

• The neutrons play an important role in stabilizing the nucleus, as they add to the strong force, but don’t repel each other like the protons do

39Tro: Chemistry: A Molecular Approach

Page 40: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

N/Z Ratio

• The ratio of neutrons : protons is an important measure of the stability of the nucleus

• If the N/Z ratio is too high, neutrons are converted to protons via b decay

• If the N/Z ratio is too low, protons are converted to neutrons via positron emission or electron captureor via a decay – though not as efficiently

40Tro: Chemistry: A Molecular Approach

Page 41: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Valley of Stability

for Z = 1 20, stable N/Z ≈ 1

for Z = 20 40, stable N/Z approaches 1.25

for Z = 40 80, stable N/Z approaches 1.5

for Z > 83, there are no stable nuclei

41Tro: Chemistry: A Molecular Approach

Page 42: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Example 19.3b: Predict the kind of radioactive decay that Mg−22 undergoes

• Mg–22Z = 12N = 22 – 12 = 10

• N/Z = 10/12 = 0.83• From Z = 1 20, stable

nuclei have N/Z ≈ 1• Because Mg–22 N/Z is

low, it should convert p+ into n0, therefore it will undergo positron emission or electron capture

42Tro: Chemistry: A Molecular Approach

Page 43: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Practice – Predict whether Kr–85 is stable or radioactive. If radioactive, predict the mode of

radioactive decay and the daughter nuclide.

43Tro: Chemistry: A Molecular Approach

Page 44: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Practice – Predict whether Kr–85 is stable or radioactive. If radioactive, predict the mode of

radioactive decay and the daughter nuclide.

Kr–85 has Z = 36 and N = (85 − 36) = 49

Because the N/Z ratio of Kr–85 is greater than 1.25, it has too many neutrons and will undergo b decay to reduce them

Because most stable isotopes with Z between 20 and 40 have N/Z ratios between 1 and 1.25, we expect Kr–85 to be radioactive

(Kr–85 is a byproduct of nuclear fission and was released into the atmosphere when atom bombs were tested in the 1940’s to 1960’s)

44Tro: Chemistry: A Molecular Approach

Page 45: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Magic Numbers• Besides the N/Z ratio, the actual numbers of protons and

neutrons affects stability• Most stable nuclei have even numbers of protons and

neutrons• Only a few have odd numbers of protons and neutrons• If the total number of nucleons adds to a magic number,

the nucleus is more stable same principle as stability of the

noble gas electron configuration most stable when N or Z = 2, 8,

20, 28, 50, 82; or N = 126

45Tro: Chemistry: A Molecular Approach

Page 46: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Decay Series

46Tro: Chemistry: A Molecular Approach

• In nature, often one radioactive nuclide changes into another radioactive nuclide i.e. the daughter nuclide is also radioactive

• All of the radioactive nuclides that are produced one after the other until a stable nuclide is made is called a decay series

• To determine the stable nuclide at the end of the series without writing it all out

1. count the number of a and b decays

2. from the mass no. subtract 4 for each a decay

3. from the atomic no. subtract 2 for each a decay and add 1 for each b

Page 47: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

U-238 Decay Series

a b b a a a

a

bababba

or ababbab

or other combinations

47Tro: Chemistry: A Molecular Approach

Page 48: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Detecting Radioactivity

To detect something, you need to identify what it does• Radioactive rays can expose light-protected

photographic film• We may use photographic film to detect the

presence of radioactive rays – film badge dosimeters

48Tro: Chemistry: A Molecular Approach

Page 49: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Detecting Radioactivity• Radioactive rays cause air to become ionized• An electroscope detects radiation by its ability

to penetrate the flask and ionize the air inside• A Geiger-Müller counter works by counting

electrons generated when Ar gas atoms are ionized by radioactive rays

49Tro: Chemistry: A Molecular Approach

Page 50: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Detecting Radioactivity

• Radioactive rays cause certain chemicals to give off a flash of light when they strike the chemical

• A scintillation counter is able to count the number of flashes per minute

50Tro: Chemistry: A Molecular Approach

Page 51: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Natural Radioactivity

• There are small amounts of radioactive minerals in the air, ground, and water

• Even in the food you eat!• The radiation you are exposed to from natural

sources is called background radiation

51Tro: Chemistry: A Molecular Approach

Page 52: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Rate of Radioactive Decay

52Tro: Chemistry: A Molecular Approach

• It was discovered that the rate of change in the amount of radioactivity was constant, and different for each radioactive “isotope”change in radioactivity measured with Geiger counter

counts per minute• Each radionuclide had a particular length of time

it required to lose half its radioactivity a constant half-lifewe know that processes with a constant half-life follow

first order kinetic rate laws• The rate of radioactive change was not affected

by temperaturemeaning radioactivity is not a chemical reaction!

Page 53: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Kinetics of Radioactive Decay

• Rate = kNN = number of radioactive nuclei

• t1/2 = 0.693/k

• the shorter the half-life, the more nuclei decay every second – we say the sample is hotter

53Tro: Chemistry: A Molecular Approach

Page 54: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Half-Lives of Various Nuclides

Nuclide Half-Life Type of Decay

Th–232 1.4 x 1010 yr alpha

U–238 4.5 x 109 yr alpha

C–14 5730 yr beta

Rn–220 55.6 sec alpha

Th–219 1.05 x 10–6 sec alpha

54Tro: Chemistry: A Molecular Approach

Page 55: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Half-Life

Half of the radioactive atoms decay each half-life

55Tro: Chemistry: A Molecular Approach

Page 56: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Pattern for Radioactive Decay

56Tro: Chemistry: A Molecular Approach

Page 57: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.57Tro: Chemistry: A Molecular Approach

Page 58: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Example19.4: If you have a 1.35 mg sample of Pu–236, calculate the mass that will remain after 5.00 years

Tro: Chemistry: A Molecular Approach 58

units are correct, the magnitude makes because since it is less than ½ the original mass for longer than 1 half-life

Check:

Solve:

Conceptual Plan:

Relationships:

mass Pu–236 = 1.35 mg, t = 5.00 yr, t1/2 = 2.86 yr

mass remaining, mg

Given:

Find:

t1/2 k m0, t mt+

Page 59: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Practice—Radon–222 is a gas that is suspected of causing lung cancer as it leaks into houses. It is

produced by uranium decay. Assuming no loss or gain from leakage, if there is 10.24 g of Rn–222 in the house

today, how much will there be in 5.4 weeks? ( Rn–222 half-life is 3.8 Days)

59Tro: Chemistry: A Molecular Approach

Page 60: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Practice – If there is 10.24 g of Rn–222 in the house today, how much will there be in 5.4 weeks?

units are correct, the magnitude makes sense because the length of time is 10 half-lives

Check:

Solve:

Conceptual Plan:

Relationships:

mass Rn–222 = 10.24 g, t = 5.4 wks, t1/2 = 3.8 d

mass remaining, g

Given:

Find:

t1/2 k m0, t mt+

60Tro: Chemistry: A Molecular Approach

Page 61: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Radiometric Dating

61Tro: Chemistry: A Molecular Approach

• The change in the amount of radioactivity of a particular radionuclide is predictable and not affected by environmental factors

• By measuring and comparing the amount of a parent radioactive isotope and its stable daughter we can determine the age of the objectby using the half-life and the previous equations

• Mineral (geological) datingcompare the amount of U-238 to Pb-206 in volcanic

rocks and meteoritesdates the Earth to between 4.0 and 4.5 billion yrs. old

compare amount of K-40 to Ar-40

Page 62: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Radiocarbon Dating

62Tro: Chemistry: A Molecular Approach

• All things that are alive or were once alive contain carbon

• Three isotopes of carbon exist in nature, one of which, C–14, is radioactiveC–14 radioactive with half-life = 5730 yrs

• We would normally expect a radioisotope with this relatively short half-life to have disappeared long ago, but atmospheric chemistry keeps producing C–14 at nearly the same rate it decays

Page 63: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Radiocarbon Dating

63Tro: Chemistry: A Molecular Approach

• While still living, C–14/C–12 is constant because the organism replenishes its supply of carbonCO2 in air ultimate source of all C in organism

• Once the organism dies the C–14/C–12 ratio decreases

• By measuring the C–14/C–12 ratio in a once living artifact and comparing it to the C–14/C–12 ratio in a living organism, we can tell how long ago the organism was alive

• The limit for this technique is 50,000 years oldabout 9 half-lives, after which radioactivity from C–14

will be below the background radiation

Page 64: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Radiocarbon Dating% C-14 (compared to living

organism)Object’s Age (in years)

100% 0

90% 870

80% 1850

60% 4220

50% 5730

40% 7580

25% 11,500

10% 19,000

5% 24,800

1% 38,100

64Tro: Chemistry: A Molecular Approach

Page 65: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Example 19.5: An ancient skull gives 4.50 dis/min∙gC. If a living organism gives 15.3 dis/min∙gC, how old is the skull?

Tro: Chemistry: A Molecular Approach 65

units are correct, the magnitude makes sense because it is less than 2 half-lives

Check:

Solve:

Conceptual Plan:

Relationships:

ratet1/2 = 4.50 dis/min∙gC, ratet1/2 = 15.3 dis/min∙gC

time, yr

Given:

Find:

t1/2 k rate0, ratet t+

Page 66: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Practice – Archeologists have dated a civilization to 15,600 yrs ago. If a living sample gives 20.0 counts per minute per gram C, what would be the number of counts per minute per gram C for a rice grain found at the site?

66Tro: Chemistry: A Molecular Approach

Page 67: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Practice – What would be the number of counts per minute per gram for a rice grain found at the site?

Tro: Chemistry: A Molecular Approach 67

units are correct, the magnitude makes sense because it is between 10 and 25% of the original activity

Check:

Solve:

Conceptual Plan:

Relationships:

t = 15,600 yr, rate0 = 20.0 counts/min∙gC

ratet, counts/min∙gC

Given:

Find:

t1/2 k rate0, t ratet+

Page 68: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Nonradioactive Nuclear Changes

Lise Meitner

68Tro: Chemistry: A Molecular Approach

• A few nuclei are so unstable that if their nucleus is hit just right by a neutron, the large nucleus splits into two smaller nuclei — this is called fission

• Small nuclei can be accelerated to such a degree that they overcome their charge repulsion and smash together to make a larger nucleus - this is called fusion

• Both fission and fusion release enormous amounts of energy fusion releases more energy per gram

than fission

Page 69: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.69Tro: Chemistry: A Molecular Approach

Page 70: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Fission Chain Reaction

70Tro: Chemistry: A Molecular Approach

• A chain reaction occurs when a reactant in the process is also a product of the processin the fission process it is the neutronsso you only need a small amount of neutrons to start

the chain• Many of the neutrons produced in fission are

either ejected from the uranium before they hit another U-235 or are absorbed by the surrounding U-238

• Minimum amount of fissionable isotope needed to sustain the chain reaction is called the critical mass

Page 71: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.71Tro: Chemistry: A Molecular Approach

Page 72: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.72Tro: Chemistry: A Molecular Approach

Page 73: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Fissionable Material

73Tro: Chemistry: A Molecular Approach

• Fissionable isotopes include U–235, Pu–239, and Pu–240

• Natural uranium is less than 1% U–235rest mostly U–238not enough U–235 to sustain chain reaction

• To produce fissionable uranium, the natural uranium must be enriched in U–235to about 7% for “weapons grade”to about 3% for reactor grade

Page 74: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Nuclear Power

• Nuclear reactors use fission to generate electricityabout 20% of U.S. electricityuses the fission of U–235 to produce heat

• The heat boils water, turning it to steam• The steam turns a turbine, generating

electricity

74Tro: Chemistry: A Molecular Approach

Page 75: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Nuclear Power Plants vs. Coal-Burning Power Plants

• Use about 50 kg of fuel to generate enough electricity for 1 million people

• No air pollution

• Use about 2 million kg of fuel to generate enough electricity for 1 million people

• Produce NO2 and SOx that add to acid rain

• Produce CO2 that adds to the greenhouse effect

75Tro: Chemistry: A Molecular Approach

Page 76: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Nuclear Power Plants - Core

76Tro: Chemistry: A Molecular Approach

• The fissionable material is stored in long tubes, called fuel rods, arranged in a matrixsubcritical

• Between the fuel rods are control rods made of neutron-absorbing materialB and/or Cdneutrons needed to sustain the chain reaction

• The rods are placed in a material to slow down the ejected neutrons, called a moderatorallows chain reaction to occur below critical mass

Page 77: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Pressurized Light Water Reactor

77Tro: Chemistry: A Molecular Approach

• Design used in United States (GE, Westinghouse)

• Water is both the coolant and moderator• Water in core kept under pressure to keep it

from boiling• Fuel is enriched uranium

subcritical

• Containment dome of concrete

Page 78: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.78Tro: Chemistry: A Molecular Approach

Page 79: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

PLWR

Core

ContainmentBuilding

Turbine

Condenser

ColdWater

Boiler

79Tro: Chemistry: A Molecular Approach

Page 80: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.80

PLWR - Core

ColdWater

FuelRods

HotWaterControl

Rods

The control rods are made of neutron absorbing material. This allows the rate of neutron flow through the reactor to be controlled. Because the neutrons are required to continue the chain reaction, the control rods control the rate of nuclear fission

Tro: Chemistry: A Molecular Approach

Page 81: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Concerns about Nuclear Power

81Tro: Chemistry: A Molecular Approach

• Core melt-downwater loss from core, heat melts coreChina SyndromeChernobyl

• Waste disposalwaste highly radioactive reprocessing, underground storage?Federal High Level Radioactive Waste

Storage Facility at Yucca Mountain, Nevada • Transporting waste• How do we deal with nuclear power

plants that are no longer safe to operate?Yankee Rowe in Massachusetts

Page 82: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Where Does the Energy fromFission Come from?

• During nuclear fission, some of the mass of the nucleus is converted into energyE = mc2

• Each mole of U–235 that fissions produces about 1.7 x 1013 J of energya very exothermic chemical reaction produces 106 J

per mole

82Tro: Chemistry: A Molecular Approach

Page 83: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Mass Defect and Binding Energy

• When a nucleus forms, some of the mass of the separate nucleons is converted into energy

• The difference in mass between the separate nucleons and the combined nucleus is called the mass defect

• The energy that is released when the nucleus forms is called the binding energy1 MeV = 1.602 x 10−13 J 1 amu of mass defect = 931.5 MeV the greater the binding energy per nucleon, the more

stable the nucleus is

83Tro: Chemistry: A Molecular Approach

Page 84: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.84Tro: Chemistry: A Molecular Approach

Page 85: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Example19.7: Calculate the mass defect and nuclear binding energy per nucleon (in MeV) for C–16, a radioactive isotope of

carbon with a mass of 16.014701 amu

Solve:

Conceptual Plan:

Relationships:

mass C-16 = 16.01470 amu, mass p+ = 1.00783 amu,mass n0 = 1.00866 amu mass defect in amu, binding energy per nucleon in MeV

Given:

Find:

mp+, mn0, mC-16massdefect

binding energy

85Tro: Chemistry: A Molecular Approach

Page 86: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Practice – Calculate the binding energy per nucleon in Fe–56

86Tro: Chemistry: A Molecular Approach

Page 87: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Practice – Calculate the binding energy per nucleon in Fe–56 (mass 55.93494 amu)

Solve:

Conceptual Plan:

Relationships:

mass Fe-56 = 55.93494 amu, mass p+ = 1.00783 amu,mass n0 = 1.00866 amu binding energy per nucleon in MeV

Given:

Find:

mp+, mn0, mC-16massdefect

binding energy

87Tro: Chemistry: A Molecular Approach

Page 88: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Nuclear Fusion• Fusion is the combining of light nuclei to make a

heavier, more stable nuclide• The Sun uses the fusion of hydrogen isotopes to

make helium as a power source• Requires high input of energy to initiate the

processbecause need to overcome repulsion of positive nuclei

• Produces 10x the energy per gram as fission• No radioactive byproducts• Unfortunately, the only currently working

application is the H-bomb

88Tro: Chemistry: A Molecular Approach

Page 89: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Fusion

89Tro: Chemistry: A Molecular Approach

Page 90: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Tokamak Fusion Reactor

90Tro: Chemistry: A Molecular Approach

Page 91: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Making New Elements:Artificial Transmutation

Tro: Chemistry: A Molecular Approach 91

• High energy particles can be smashed into target nuclei, resulting in the production of new nuclei

• The particles may be radiation from another radionuclide, or charged particles that are accelerated Rutherford made O–17 bombarding N–14 with alpha

rays from radium

Cf–244 is made by bombarding U–238 with C–12 in a particle accelerator

Page 92: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.92

Artificial Transmutation

Tro: Chemistry: A Molecular Approach

• Bombardment of one nucleus with another causing new atoms to be madecan also bombard with neutrons

• Reaction done in a particle acceleratorlinearcyclotron

Tc-97 is made by bombarding Mo-96 with deuterium, releasing a neutron

Page 93: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.Nuclear Chemsity 93

Linear Accelerator

target

- + - + - + - + - + - + - + - + - + - + - + -

source

+

+ - + - + - + - + - + - + - + - + - + - + - +

+ +

Page 94: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Cyclotron

source

target

94Tro: Chemistry: A Molecular Approach

Page 95: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Practice – Predict the other daughter nuclide and write a nuclear equation for each of the

following

Tro: Chemistry: A Molecular Approach 95

bombarding Ni–60 with a proton to make Co–57

bombarding N–14 with a neutron to make C–12

bombarding Cf–250 with B–11 producing 4 neutrons

Page 96: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.96

Practice – Predict the other daughter nuclide and write a nuclear equation for each of the

following

Tro: Chemistry: A Molecular Approach

bombarding Ni–60 with a proton to make Co–57

bombarding N–14 with a neutron to make C–12

bombarding Cf–250 with B–11 producing 4 neutrons

Page 97: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Biological Effects of Radiation

• Radiation has high energy, energy enough to knock electrons from molecules and break bondsionizing radiation

• Energy transferred to cells can damage biological molecules and cause malfunction of the cell

97Tro: Chemistry: A Molecular Approach

Page 98: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Acute Effects of Radiation

• High levels of radiation over a short period of time kill large numbers of cellsfrom a nuclear blast or exposed reactor core

• Causes weakened immune system and lower ability to absorb nutrients from foodmay result in death, usually from infection

98Tro: Chemistry: A Molecular Approach

Page 99: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Chronic Effects

• Low doses of radiation over a period of time show an increased risk for the development of cancerradiation damages DNA that may not get repaired

properly

• Low doses over time may damage reproductive organs, which may lead to sterilization

• Damage to reproductive cells may lead to genetic defects in offspring

99Tro: Chemistry: A Molecular Approach

Page 100: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Measuring Radiation Exposure• The curie (Ci) is an exposure of 3.7 x 1010 events per

second no matter the kind of radiation

• The gray (Gy) measures the amount of energy absorbed by body tissue from radiation 1 Gy = 1 J/kg body tissue

• The rad also measures the amount of energy absorbed by body tissue from radiation 1 rad = 0.01 Gy

• A correction factor is used to account for a number of factors that affect the result of the exposure – this biological effectiveness factor is the RBE, and the result is the dose in rems rads x RBE = rems rem = roentgen equivalent man

100Tro: Chemistry: A Molecular Approach

Page 101: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Factors that Determine theBiological Effects of Radiation

1. The more energy the radiation has, the larger its effect can be

2. The better the ionizing radiation penetrates human tissue, the deeper effect it can have Gamma >> Beta > Alpha

3. The more ionizing the radiation, the larger the effect of the radiation Alpha > Beta > Gamma

4. The radioactive half-life of the radionuclide5. The biological half-life of the element6. The physical state of the radioactive material

101Tro: Chemistry: A Molecular Approach

Page 102: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.102Tro: Chemistry: A Molecular Approach

Page 103: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Biological Effects of Radiation

• The amount of danger to humans of radiation is measured in the unit rems

Dose (rems) Probable Outcome

20-100 decreased white blood cell count; possible increased cancer risk

100-400 radiation sickness; increased cancer risk

500+ death

103Tro: Chemistry: A Molecular Approach

Page 104: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Medical Uses of Radioisotopes,Diagnosis

104Tro: Chemistry: A Molecular Approach

• Radiotracerscertain organs absorb most or all of a particular

elementyou can measure the amount absorbed by using

tagged isotopes of the element and a Geiger countertagged = radioisotope that can then be detected

and measureduse radioisotope with a short half-lifeuse radioisotope that is low ionizing

beta or gamma

Page 105: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.105Tro: Chemistry: A Molecular Approach

Page 106: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Bone Scans

106Tro: Chemistry: A Molecular Approach

Page 107: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Medical Uses of Radioisotopes,Diagnosis

107Tro: Chemistry: A Molecular Approach

• PET scanpositron emission tomographyF–18 tagged glucose

F–18 is a positron emitterbrain scan and function

Page 108: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Medical Uses of Radioisotopes,Treatment – Radiotherapy

108Tro: Chemistry: A Molecular Approach

• Cancer treatmentcancer cells more sensitive to radiation than healthy

cells – use radiation to kill cancer cells without doing significant damage

brachytherapyplace radioisotope directly at site of cancer

teletherapyuse gamma radiation from Co–60 outside to penetrate inside IMRT

radiopharmaceutical therapyuse radioisotopes that concentrate in one area of the body

Page 109: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.

Gamma Ray Treatment

109Tro: Chemistry: A Molecular Approach

Page 110: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.110

Nonmedical Uses of Radioactive Isotopes

Tro: Chemistry: A Molecular Approach

• Smoke detectorsAm–241smoke blocks ionized air, breaks

circuit• Insect control

sterilize males• Food preservation• Radioactive tracers

follow progress of a “tagged” atom in a reaction

• Chemical analysisneutron activation analysis

Page 111: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.111

Nonmedical Uses of Radioactive Isotopes

Tro: Chemistry: A Molecular Approach

• Authenticating art object many older pigments and ceramics were made

from minerals with small amounts of radioisotopes

• Crime scene investigation• Measure thickness or condition of industrial

materialscorrosion track flow through processgauges in high temp processes weld defects in pipelines road thickness

Page 112: Chapter 19 Radioactivity and Nuclear Chemistry

Copyright 2011 Pearson Education, Inc.112

Nonmedical Uses of Radioactive Isotopes

Tro: Chemistry: A Molecular Approach

• Agribusinessdevelop disease-resistant crops trace fertilizer use

• Treat computer disks to enhance data integrity• Nonstick pan coatings

initiates polymerization

• Photocopiers to help keep paper from jamming• Sterilize cosmetics, hair products and contact lens

solutions and other personal hygiene products