chapter 16 – vector calculus
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Chapter 16 – Vector Calculus. 16.3 The Fundamental Theorem for Line Integrals. Objectives: Understand The Fundamental Theorem for line integrals Determine conservative vector fields. FTC – Part 2. - PowerPoint PPT PresentationTRANSCRIPT
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Chapter 16 – Vector Calculus16.3 The Fundamental Theorem for Line Integrals
16.3 The Fundamental Theorem for Line Integrals
Objectives: Understand The
Fundamental Theorem for line integrals
Determine conservative vector fields
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16.3 The Fundamental Theorem for Line Integrals
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FTC – Part 2Recall from Section 5.3 that Part 2 of the
Fundamental Theorem of Calculus (FTC2) can be written as:
where F′ is continuous on [a, b].
'( ) ( ) ( )b
aF x dx F b F a
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16.3 The Fundamental Theorem for Line Integrals
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Fundamental Theorem for Line IntegralsLet C be a smooth curve given by the vector
function r(t), a ≤ t ≤ b.Let f be a differentiable function of two or
three variables whose gradient vector is continuous on C.
Then,
Cf d f b f a r r r
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16.3 The Fundamental Theorem for Line Integrals
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NoteTheorem 2 says that we can evaluate the
line integral of a conservative vector field (the gradient vector field of the potential function f) simply by knowing the value of f at the endpoints of C.◦ In fact, it says that the line integral of f is
the net change in f.
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16.3 The Fundamental Theorem for Line Integrals
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Note: If f is a function of two variables and C is a
plane curve with initial point A(x1, y1) and terminal point B(x2, y2), Theorem 2 becomes:
2 2 1 1, ,Cf d f x y f x y r
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Note: If f is a function of three variables and C is a
space curve joining the point A(x1, y1, z1) to the point B(x2, y2, z2), we have:
2 2 2 1 1 1, , , ,Cf d f x y z f x y z r
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PathsSuppose C1 and C2 are two piecewise-smooth
curves (which are called paths) that have the same initial point A and terminal point B.
We know from Example 4 in Section 16.2 that, in general,
1 2C Cd d F r F r
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16.3 The Fundamental Theorem for Line Integrals
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Conservative Vector FieldHowever, one implication of
Theorem 2 is that
whenever f is continuous.
◦That is, the line integral of a conservative vector field depends only on the initial point and terminal point of a curve.
1 2C Cf d f d r r
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16.3 The Fundamental Theorem for Line Integrals
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Independence of a Path In general, if F is a continuous vector field
with domain D, we say that the line integral is independent of path if
for any two paths C1 and C2 in D that have the same initial and terminal points.
◦ This means that line integrals of conservative vector fields are independent of path.
CdF r
1 2C Cd d F r F r
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Closed CurveA curve is called closed if its terminal point
coincides with its initial point, that is, r(b) = r(a)
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Theorem 3 is independent of path
in D if and only if:
for every closed path C in D.
CdF r
0C
d F r
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Physical InterpretationThe physical interpretation is that:
◦ The work done by a conservative force field (such as the gravitational or electric field in Section 16.1) as it moves an object around a closed path is 0.
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Theorem 4Suppose F is a vector field that is continuous
on an open, connected region D.
If is independent of path in D, then F is a conservative vector field on D.
◦ That is, there exists a function f such that f=F.
CdF r
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Determining Conservative Vector FieldsThe question remains:
◦ How is it possible to determine whether or not a vector field is conservative?
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Theorem 5 If F(x, y) = P(x, y) i + Q(x, y) j is a conservative
vector field, where P and Q have continuous first-order partial derivatives on a domain D, then, throughout D, we have:
P Q
y x
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Conservative Vector FieldsThe converse of Theorem 5 is
true only for a special type of region, specifically simply-connected region.
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Simply Connected RegionA simply-connected region in the plane is a
connected region D such that every simple closed curve in D encloses only points in D.
Intuitively, it contains no hole and can’t consist of two separate pieces.
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Theorem 6Let F = P i + Q j be a vector field on an open
simply-connected region D.
Suppose that P and Q have continuous first-order derivatives and throughout D.
◦ Then, F is conservative.
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Example 1 – pg. 1106Determine whether or not F is a conservative
vector field. If it is, find a function f such that F = f.
2
3. ( , ) 2 3 3 4 8
4. ( , ) cos sin
( , ) cos sin cos
x x
x y x y x y
x y e y e y
x y xy xy xy x xy
F i j
F i j
F i j
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Example 2a) Find a function f such that F=f.
b) Use part (a) to evaluate along the given curve C.
CdF r
2 2 2
2
( , , ) 2 2 3 ,
: , 1, 2 1, 0 1
x y z xz y xy x z
C x t y t z t t
F i j k
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Example 3 – pg. 1107 # 24Find the work done by the force
field F in moving an object from P to Q.( , ) ; (0,1), (2,0)y yx y e xe P Q F i j
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Example 4Determine whether or not the given set is
a) open,
b) connected,
c) and simply-connected.
( , ) | 0x y x
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Example 5 – pg. 1106 # 12a) Find a function f such that F=f.
b) Use part (a) to evaluate along the given curve C.
CdF r
2 2
2
( , ) ,
is the arc of the parabola 2
from 1,2 to 2,8
x y x y
C y x
F i j
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Example 6 – pg. 1107 # 16a) Find a function f such that F=f.
b) Use part (a) to evaluate along the given curve C.
CdF r
2 2 2 2
2
( , , ) 2 2 2 ,
: , 1, , 0 1
x y z y z xz xyz xy x z
C x t y t z t t
F i j k
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Example 7 – pg. 1107 # 17a) Find a function f such that F=f.
b) Use part (a) to evaluate along the given curve C.
CdF r
2 2 2
( , , ) ,
: 1 1 2 , 0 2
xz xz xzx y z yze e xye
C t t t t t t
F i j k
r i j k
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Example 8 – pg. 1107 # 18a) Find a function f such that F=f.
b) Use part (a) to evaluate along the given curve C.
CdF r
( , , ) sin cos cos sin ,
: sin 2 , 0 2
x y z y x y z y z
C t t t t t
F i j k
r i j k