chapter 12 solutions copyright © 2008 by pearson education, inc. publishing as benjamin cummings

Chapter 12 Solutions

Copyright © 2008 by Pearson Education, Inc.Publishing as Benjamin Cummings

Chapter 12 Slide 2 of 39

Solute and Solvent

Solutions• Are

homogeneous mixtures of two or more substances.

• Consist of a solvent and one or more solutes. Copyright © 2008 by Pearson Education, Inc.

Publishing as Benjamin Cummings


Solutes• Spread evenly

throughout the solution.

• Cannot be separated by filtration.

• Can be separated by evaporation.

• Are not visible, but can give a color to the solution.

Nature of Solutes in Solutions



Examples of SolutionsThe solute and solvent can be a solid, liquid, and/ora gas. Table 12.3

Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings


WaterWater• Is the most common solvent.• Is a polar molecule.• Forms hydrogen bonds between the

hydrogen atom in one molecule and the oxygen atom in a different water molecule.



Formation of a Solution

Na+ and Cl- ions• On the surface of a

NaCl crystal are attracted to polar water molecules.

• In solution are hydrated as several H2O molecules surround each.



When NaCl(s) dissolves in water, the process can be written as:

H2O

NaCl(s) Na+(aq) + Cl- (aq)

solid separation of ions

The Na+ ions are attracted to the oxygen atom ( -) of water.

The Cl- ions are attracted to the hydrogen atom (+) of water.

Equations for Solution Formation


Two substances form a solution • When there is an attraction between the

particles of the solute and solvent.

• When a polar solvent such as water dissolves polar solutes such as sugar and ionic solutes such as NaCl.

• When a nonpolar solvent such as hexane (C6H14) dissolves nonpolar solutes such as oil or grease.

Like Dissolves Like


Water and a Polar Solute



Like Dissolves Like

Solvents Solutes

Water (polar) Ni(NO3)2

CH2Cl2(nonpolar) (polar)

I2 (nonpolar)Copyright © 2008 by Pearson Education, Inc.Publishing as Benjamin Cummings


Electrolytes and Nonelectrolytes




In water, • Strong electrolytes produce ions and conduct an

electric current. • Weak electrolytes produce a few ions. • Nonelectrolytes do not produce ions.

Solutes and Ionic Charge



Strong electrolytes • Dissociate in water producing positive and negative

ions.• Conduct an electric current in water.• In equations show the formation of ions in aqueous (aq)

solutions.

H2O 100% ions

NaCl(s) Na+(aq) + Cl− (aq)

H2O

CaBr2(s) Ca2+(aq) + 2Br− (aq)

Strong Electrolytes


A weak electrolyte• Dissociates only slightly in water.• In water forms a solution of only a few ions and

mostly undissociated molecules.

HF(g) + H2O(l) H3O+(aq) + F- (aq)

NH3(g) + H2O(l) NH4+(aq) + OH- (aq)

Note: Unequal lengths of the arrows

Weak Electrolytes


Nonelectrolytes

Nonelectrolytes • Dissolve as

molecules in water. • Do not produce ions

in water.• Do not conduct an

electric current.




Solubility



Solubility • Is the maximum amount of solute that dissolves

in a specific amount of solvent. • Can be expressed as grams of solute in 100

grams of solvent, usually water.

g of solute

100 g water

Solubility


Effect of Temperature on Solubility

Solubility• Depends on

temperature.• Of most solids

increases as temperature increases.

• Of gases decreases as temperature increases.



Unsaturated Solutions

Unsaturated solutions • Contain less than the

maximum amount of solute.

• Can dissolve more solute. Dissolved

solute



Saturated Solutions

Saturated solutions • Contain the

maximum amount of solute that can dissolve.

• Have undissolved solute at the bottom

of the container.



Supersaturated Solutions

http://www.stevespanglerscience.com/content/science-video/super-saturated-solution


Soluble and Insoluble Salts

Ionic compounds that• Dissolve in water

are soluble salts.• Do not dissolve in

water are insoluble salts.



Solubility Rules

Soluble salts • Typically contain at least one ion from

Groups 1A(1) or • NO3

−, or C2H3O2− (acetate).


Table 12.3


Using the Solubility Rules

The solubility rules predict if a salt• Is soluble or• Insoluble in water.

Table 12.4



Formation of a Solid

When solutions of salts are mixed, • A solid forms if ions of an insoluble salt

are present.



Equations for Forming Solids

A molecular equation shows the formulas of the

compounds.

Pb(NO3)(aq) + 2NaCl(aq) PbCl2(s) + 2NaNO3(aq)

An ionic equation shows the ions of the compounds.

Pb2+(aq) + 2NO3−(aq) + 2Na+(aq) + 2Cl−(aq)

PbCl2(s) + 2Na+(aq) + 2NO3−(aq)

A net ionic equation shows only the ions that form asolid. Ions remaining in solution are spectator ions.Pb2+(aq) + 2Cl−(aq) PbCl2(s)


Equations for the Insoluble SaltSTEP 1 Observe the ions in the reactants.

Pb2+(aq) + 2NO3−(aq)

2Na+(aq) + 2Cl−(aq) STEP 2 Determine if any new ion combinations are insoluble salts. Yes. PbCl2(s)

STEP 3 Ionic equation with insoluble salt product.

Pb2+(aq) + 2NO3−(aq) + 2Na+(aq) + 2Cl−(aq)

PbCl2(s) + 2Na+(aq) + 2NO3−(aq)

STEP 4 Net ionic equation.

Pb2+(aq) + 2Cl−(aq) PbCl2(s)


Molarity and Dilution




Molarity (M)Molarity (M) is

• A concentration term for solutions.

• The moles of solute in 1 L solution.

• moles of soluteliter of solution


Preparing a 1.0 Molar Solution

A 1.00 M NaCl solution is prepared• By weighing out 58.5 g NaCl (1.00 mol) and• Adding water to make 1.00 liter of solution.



What is the molarity of 0.500 L NaOH solution if itcontains 6.00 g NaOH?STEP 1 Given 6.00 g NaOH in 0.500 L solution

Need molarity (mol/L)

STEP 2 Plan g NaOH mol NaOH molarity

STEP 3 Conversion factors 1 mol NaOH = 40.00 g

1 mol NaOH and 40.00 g NaOH 40.00 g NaOH 1 mol NaOH

Calculation of Molarity


STEP 4 Calculate molarity.6.00 g NaOH x 1 mol NaOH = 0.150 mol

40.00 g NaOH

0.150 mol = 0.300 mol = 0.300 M NaOH 0.500 L 1 L

Calculation of Molarity (cont.)


Molarity Conversion Factors

The units of molarity are used as conversion factors in calculations with solutions.

Table 2.6



Molarity in Calculations

How many grams of KCl are needed to prepare

125 mL of a 0.720 M KCl solution?

STEP 1 Given 125 mL (0.125 L) of 0.720 M KCl

Need Grams of KCl

STEP 2 Plan L KCl mol KCl g KCl


Molarity in Calculations (cont.)

STEP 3 Conversion factors 1 mol KCl = 74.55 g

1 mol KCl and 74.55 g KCl 74.55 g KCl 1 mol KCl

1 L KCl = 0.720 mol KCl 1 L and 0.720 mol KCl

0.720 mol KCl 1 L

STEP 4 Calculate grams.0.125 L x 0.720 mol KCl x 74.55 g KCl = 6.71 g KCl 1 L 1 mol KCl


DilutionIn a dilution

• Water is added.

• Volume increases.

• Concentration decreases.



Comparing Initial and Diluted Solutions

In the initial and diluted solution

• The moles of solute are the same.

• The concentrations and volumes are related by the equation

M1V1 = M2V2

initial diluted


Dilution Calculations

What is the molarity if 0.180 L of 0.600 M KOH isdiluted to a final volume of 0.540 L?STEP 1 Prepare a table:

M1= 0.600 MV1 = 0.180 L

M2= ? V2 = 0.540 L

STEP 2 Solve dilution equation for unknown.

M1V1 = M2V2 M1V1/ V2 = M2

STEP 3 Set up and enter values:

M2 = M1V1 = (0.600 M)(0.180 L) = 0.200 M

V2 0.540 L

chapter 12 solutions copyright © 2008 by pearson education, inc. publishing as benjamin cummings

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