Basic Algebraic Applications

Day 2

Steps for Solving Basic Algebraic Applications

1. Read the Problem2. What are they asking? Define Unknowns

and variables3. What operations do you have? Key

concepts and operations4. Set up the problem5. Solve the equation6. Verify that you answered the question

correctly. (Does your answer make sense?)7. Check your answer

Procedures Application

Solving Algebraic Applications Is about …

Solving word problems with unknown values.

1. Read the problemRead the problem

2. What are they asking? Define Unknowns and variables

3. What operations do you have? Key concepts and operations

4. Set up the problem.Draw figure if necessary..

1. Find two consecutive integers whosesum is 45

2. Two consecutive integers are needed.1st integer (a) and 2nd integer (a +1).

3. two consecutive integers, sum (+), is(=), 45

4.1st integer + 2nd integer = 45

two consecutive integerssum 45is

two consecutive integers sumis 45

a + (a + 1) = 45

Two consecutive integers

5. Solve the equation

7. Check your answerCheck your answer

6. Verify that you answered the question Verify that you answered the question correctly. correctly.

(Does your answer make sense?)(Does your answer make sense?)

5.

7. 1st integer + 2nd integer = 45

4512 a11

442 a22 22a

6. Solving for two consecutive integers so one Solving for two consecutive integers so one more integer is needed.more integer is needed.a = 22a = 22 2nd integer = a + 1

2nd integer = 22 + 12nd integer = 23

1st integer = 22 & 2nd integer = 23

45 = 45

☺

22 + 23 ? 45

a + (a + 1) = 45

Procedures Application

Solving Algebraic Applications Is about …

Solving word problems with unknown values.

1. Read the problemRead the problem

2. What are they asking? Define Unknowns and variables

3. What operations do you have? Key concepts and operations

4.

Set up the problem.Draw figure if necessary..

1. Find three consecutive even integerswhose sum is 72

2. three consecutive even integers are needed.1st even integer (a), 2nd even integer (a +2), 3rd integer (a + 4)

3. three consecutive even integers,sum (+), is(=), 72

4. 1st even integer + 2nd even integer + 3rd even integer = 72

three consecutive even integerssum 72is

three consecutive even integerssum is 72

a + (a + 2) + (a + 4) = 72

three consecutive even integers

5. Solve the equation

7 Check your answerCheck your answer

6 Verify that you answered theVerify that you answered thequestion correctly. question correctly. (Does your answer make(Does your answer makesense?)sense?)

5.

7. 1st even integer + 2nd even integer + 3rd even integer = 72

7263 a66

663 a3322a

6. Solving for two consecutive integers so one Solving for two consecutive integers so one more integer is needed.more integer is needed.a = 22a = 22 2nd even integer = a + 2

2nd even integer = 22 + 22nd even integer = 24

1st even integer = 22, 2nd even integer = 24, 3rd even integer = 26

72 = 72

☺

22 + 24 + 26 ? 72

a + (a + 2) + (a + 4) = 72

3rd even integer = a + 43rd even integer = 22 + 43rd even integer = 26

Procedures Application

Solving Algebraic Applications Is about …

Solving word problems with unknown values.

1. Read the problemRead the problem

2. What are they asking? Define Unknowns and variables

3. What operations do you have? Key concepts and operations

4. Set up the problem.Draw figure if necessary..

1. Find two consecutive odd integers whose sum is -88

2. Two consecutive odd integers areneeded.1st odd integer (a) and 2nd odd integer (a +1).

3. two consecutive odd integers, sum (+), is(=), -88

4.1st odd integer + 2nd odd integer = -88

two consecutive odd integerssum -88is

two consecutive odd integerssum is -88

a + (a + 2) = -88

Two consecutive odd integers

5. Solve the equation

7. Check your answerCheck your answer

6. Verify that you answered the question Verify that you answered the question correctly. correctly.

(Does your answer make sense?)(Does your answer make sense?)

5.

7. 1st odd integer + 2nd odd integer = -88

8822 a22

902 a22 45a

6. Solving for two consecutive odd integers soSolving for two consecutive odd integers soone more integer is needed.one more integer is needed.a = -45a = -45 2nd odd integer = a + 2

2nd odd integer = -45 + 22nd odd integer = -43

1st integer = -45 & 2nd integer = -43

-88 = -88

☺

-45 + -43 ? -88

a + (a + 2) = -88