bao cao tn_ dang
TRANSCRIPT
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LI GII THIU
Ngy nay vi s pht trin ca cng nghip vi in t,k thut s th cc h thng
iu khin dn dn c t ng ha. Vi nhng k thut tin tin nh vi x l,vi mch
s th cc h thng iu khin bng c kh th s vi tc x l chm chp t chnh xc
s c thay th bng cc h thng iu khin t ng vi cc chng trnh c thit
lp trc
Trong nhiu lnh vc sn xut cng nghip hin nay,nht l ngnh cng nghip
luyn kim,ch bin thc phm. vn o v khng ch nhit c bit c ch trng
n v n l mt t quyt nh cht lng sn phm. p ng c yu cu o v khng
ch nhit th c nhiu phng php thc hin. Vi nhng g c hc,nghin cu
v kho st v vi iu khin th nhm ng dng n vo vic o v khng ch nhit l
phng php ti u nht. c s hng dn ca thy,nhm thc hin ti Thit k
mch iu khin nhit ng dng trong l nhit
Vi nhng kin thc c hc cng vi s hng dn ca thy gio v s gip
ca bn b,nhm c gng hon thnh ti ng thi hn. Do vy khng trnh khithiu st,nhm em mong nhn c kin t thy c ti ca nhm c pht trin
tt hn.
Nng,ngy ,thng ,nm2010
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THIT K MCH IU KHIN NHIT
NG DNG TRONG L NHIT
1.Nhim v thit k:
Nhim v cn thc hin l thit k mt b iu khin nhit vi di nhit t 30 0C n
1200C. Vy yu cu t ra l:
+Thit k b cm bin nhit .+Thit k b chuyn i tng t sang s ( khi ADC)
+Thit k khi x l trung tm
+Thit k khi bn phm
+Thit k khi cng sut
+Thit k khi hin th
+Thit k khi giao tip
+Vit thut ton.+Vit chng trnh iu khin
2.S khi:
CMU 8051
Khi hin th
L nhit
Khi cm bin
Khi ADC
Khi giao tip
Khi cng sut
Khi bn phm
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3. Chc nng tng khi:
+ Khi cm bin nhit :dng o nhit trong l nhit
+ Khi x l trung tm: dng x l cc tn hiu vo v xut tn hiu ra,iu khin mi
hot ng ca h thng.
+ Khi ADC: c nhim v s ha tn hiu ra ca cm bin nhit a vo VDK.
+ Khi cng sut: c nhim v iu khin,cp ngun cho l nhit,qua lm thay i nhit
trong l nhit.
+ Khi hin th: hin th nhit l nhit.
+ Khi giao tip: trao i vi my tnh v cc thng s ca qu trnh iu khin.
+ Khi bn phm: nhp d liu.
GII THIEU VE VI IEU KHIEN 8951
1. Tong quan ve ky thuat vi ieu khien
1.1. Khai quat chung ve vi ieu khien
Bo vi ieu khien viet tat la Micro-controller, la mach tch
hp tren mot chip co the lap trnh c, dung e ieu khien
hoat ong cua mot he thong. Theo chng trnh ieu khien a
nap san ben trong chip, bo vi ieu khien tien hanh oc, lutr thong tin, x ly thong tin, sau o da vao ket qua cua
qua trnh x ly e a ra cac thong bao, tn hieu ieu khien
tien hanh ieu khien qua trnh hoat ong cua cac thiet b
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ben ngoai. Vi ieu khien c ng dung trong rat nhieu san
pham cong nghiep va tieu dung.
Trong cac thiet b ien va ien t dan dung, cac bo viieu khien ieu khien hoat ong cua TV, may giat, au oc
laser, ien thoai, lo vi-ba ... Trong he thong san xuat t ong,
bo vi ieu khien c s dung trong Robot, day chuyen t
ong. Cac he thong cang thong minh th vai tro cua he vi
ieu khien cang quan trong.
1.2. Lch s phat trien cua vi ieu khien
Bo vi ieu khien thc ra la mot loai vi x l trong tap hp
cac bo vi x ly noi chung. Bo vi ieu khien c phat trien
t bo vi x l, t nhng nam 1970 do s phat trien va hoan
thien ve cong nghe vi ien t da tren ky thuat MOS (Metal-
Oxide-Semiconductor), mc o tch hp cua cac linh kien ban
dan trong mot chip ngay cang cao.
Nam 1971 xuat hien bo vi x l 4 bit loai TMS1000 do cong
ty texas Instruments va la ni phat minh va la nha san xuat.
Nhn tong the th bo vi x ly ch co cha tren mot chip
nhng chc nang can thiet e x ly chng trnh theo mot
trnh t, con tat ca bo phan phu tr khac can thiet nh: bo
nh d lieu, bo nh chng trnh, bo chuyen oi AD, khoi
ieu khien, khoi hien th, ieu khien may in, noi ong ho
va lch la nhng linh kien nam ben ngoai c noi vaobo vi x ly.
Mai en nam 1976 cong ty INTEL (Intelligen-Elictronics) mi
cho ra i bo vi ieu khien n chip au tien tren the gii
vi ten goi 8048. Ben canh bo x ly trung tam, 8048 con
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cha bo nh d lieu, bo nh chng trnh, bo em va phat
thi gian, cac cong vao ra digital tren mot chip. Cac cong ty
khac cung lan lc cho ra i cac bo vi ieu khien 8 bit tngt nh 8048 va hnh thanh ho vi ieu khien MCS-48.
en nam 1980 cong ty INTEL cho ra i the he th hai
cua bo vi ieu khien n chip vi ten goi 8951. Va sau o
hang loat cac vi ieu khien cung loai vi 8951 ra i va
hnh thanh ho vi ieu khien MCS-51 .
en nay ho vi ieu khien 8 bit MCS51 a co en 250thanh vien va hau het cac cong ty hang dan au the
gii che tao. ng au la cong ty INTEL va rat nhieu
cong ty khac nh : AMD, SIEMENS, PHILIPS, DALLAS, OKI
1.3. S o khoi cua mot bo vi ieu khien
S o khoi chung cua hau het cac bo vi ieu khien bao gom
CPU, bo nh ROM hay EPROM va RAM, mach giao tiep, mach giao
tiep song song, bo nh thi gian, he thong ngat va cac BUS
c tch hp tren cung mot chip.
2. Kien truc cua vi ieu khien 8951
IC vi ieu khien 8951 thuoc ho MCS51 co cac ac iem sau
:
+ 4 kbyte ROM
+ 128 byte RAM
+ 4 port I/0 8 bit
+ Hai bo nh thi 16 bits
+ Giao tiep noi tiep
+ 64KB khong gian bo nh chng trnh ngoai
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+ 64 KB khong gian bo nh d lieu ngoai
+ 210 bit c a ch hoa
+Bo nhan / chia 4 s
2.1. Cau truc ben trong cua 8951
INT\1
INT\0
TIMER2
TIMER1PORT noitiep
TXD* RXD*
T1*
T2*
P0
P1
P2
P3EA\ RST PSEN ALE
Cacthanh
ghikhac
128byteRam
Rom
4K-8951
OK-8031
Timer1
Timer2
ieukhienngat
ieukhienbus
CPU
Portnoitiep
Cc port I/O
Todaong
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S o Khoi 8951
Phan chnh cua vi ieu khien 8951 la bo x l trung
tam (CPU: central processing unit) bao gom :
+ Thanh ghi tch luy A
+ Thanh ghi tch luy phu B, dung cho phep nhan va phep
chia
+ n v logic hoc (ALU : Arithmetic Logical Unit )
+ T trang thai chng trnh (PSW : Prorgam Status Word)+ Bon bang thanh ghi
+ Con tro ngan xep
+ Ngoai ra con co bo nh chng trnh, bo giai ma lenh,
bo ieu khien thi gian va logic.
n v x l trung tam nhan trc tiep xung t bo dao ong,
ngoai ra con co kha nang a mot tn hieu gi nhp t ben
ngoai.Chng trnh ang chay co the cho dng lai nh mot
khoi ieu khien ngat ben trong. Cac nguon ngat co
the la: cac bien co ben ngoai, s tran bo em nh
thi hoac cung co the la giao dien noi tiep.
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Hai bo nh thi 16 bit hoat ong nh mot bo em.
Cac cong (port0,1,2,3), s dung vao muc ch ieu khien.
cong 3 co them cac ng dan ieu khien dung e traooi vi mot bo nh ben ngoai, hoac e au noi giao dien
noi tiep, cung nh cac ng ngat dan ben ngoai. Giao dien
noi tiep co cha mot bo truyen va mot bo nhan khong
ong bo, lam viec oc lap vi nhau.Toc o truyen qua cong
noi tiep co the at trong dai rong va c an nh bang
mot bo nh thi.
Trong vi ieu khien 8951 co hai thanh phan quan trong
khac o la bo nh va cac thanh ghi :
+ Bo nh gom co bo nh RAM va bo nh ROM dung
e lu tr d lieu va ma lenh.
+ Cac thanh ghi s dung e lu tr thong tin trong qua
trnh x l. Khi CPU lam viec no lam thay oi noi dung cua cac
thanh ghi.
2.2.Chc nang cac chan cua vi ieu khien 8951
C 1 3 0 p
C 2 3 0 p
U 2
8 0 5 1
3 1
1 9
1 8
9
1 21 31 41 5
1234567
8
3 93 83 73 63 53 43 3
3 2
2 12 22 32 42 52 62 72 8
1 71 62 93 01 1
1 0
E A / V P
X 1
X 2
R E S E T
I N T 0I N T 1T 0T 1
P 1 . 0P 1 . 1P 1 . 2P 1 . 3P 1 . 4P 1 . 5P 1 . 6
P 1 . 7
P 0 . 0P 0 . 1P 0 . 2P 0 . 3P 0 . 4P 0 . 5P 0 . 6P 0 . 7
P 2 . 0P 2 . 1P 2 . 2P 2 . 3P 2 . 4P 2 . 5P 2 . 6P 2 . 7
R DW R
P S E NA L E / P
T X D
R X D
R S T
1 2 M H z
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Hnh 2.3 :S o chan 8951
Vi ieu khien 8951 co 32 trong 40 chan co chc nang
nh la cac cong I/O, trong o 24 chan c s dung vi
hai muc ch. Ngha la ngoai chc nang cong I/O, moi
chan co cong dung kep nay co the la mot ng ieu
khien cua Bus a ch hay Bus d lieu hoac la moi chan
hoat ong mot cach oc lap e giao tiep vi cac thiet
n bit nh la cong tac, LED, transistor
a.Port0: la port co 2 chc nang, tren chan t 32
en 39 cua MC 8951. Trong cac thiet ke c nho khong
dung bo nh ngoai, P0 c s dung nh la nhng cong
I/O. Con trong cac thiet ke ln co yeu cau mot so
lng ang ke bo nh ngoai th P0 tr thanh cac ng
truyen d lieu va 8 bit thap cua bus a ch.b. Port1: la mot port I/O chuyen dung, tren cac chan 1-
8 cua MC8951. Chung c s dung vi mot muc ch duy
nhat la giao tiep vi cac thiet b ngoai khi can thiet.
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c. Port2: la mot cong co cong dung kep tren cac
chan 21 28 cua MC 8951. Ngoai chc nang I/O, cac chan
nay dung lam 8 bit cao cua bus a ch cho nhng mo
hnh thiet ke co bo nh chng trnh ROM ngoai hoac bo
nh d lieu RAM co dung lng ln hn 256 byte.
d. Port3: la mot cong co cong dung kep tren cac chan 10
17 cua MC 8951. Ngoai chc nang la cong I/O, nhng chan
nay kiem luon nhieu chc nang khac na lien quan en
nhieu tnh nang ac biet cua MC 8951, c mo ta trong bangsau:
Bit Ten Chc nang chuyen oiP3.
0
P3.
1P3.
2
P3.
3
P3.
4P3.
5
P3.
6
RxD
TxD
0INT
1INT
T0
T1
WR
RD
Ngo vao d lieu noi tiep.
Ngo xuat d lieu noi
tiep.
Ngat ngoai 0.Ngat ngoai 1.
Ngo vao TIMER 0.
Ngo vao cua TIMER 1.
ieu khien ghi d lieu len
bo nh ngoai.
ieu khien oc bo nh dlieu ngoai.
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P3.
7
Chc nang cua cac chan tren port3e. PSEN (Program Store Enable): 8951 co 4 tn hieu ieu khien,
PSEN la tn hieu ra tren chan 29. No la tn hieu ieu
khien e cho phep truy xuat bo nh
chng trnh m rong va thng c noi en chan OE
(Output Enable) cua mot EPROM e cho phep oc cac byte
ma lenh cua chng trnh. Tn hieu PSEN mc thap trongsuot pham vi qua trnh cua mot lenh. Cac ma nh phan
cua chng trnh c oc t EPROM qua bus va c chot
vao thanh ghi lenh cua 8951 e giai ma lenh. Khi thi hanh
chng trnh trong ROM noi PSEN se mc cao.
f. ALE (Address Latch Enable ): Tn hieu ra ALE tren chan 30
tng hp vi cac thiet b lam viec vi cac x ly 8585,
8088. 8951 dung ALE e giai a hp bus a ch va d
lieu, khi port 0 c dung lam bus a ch/d lieu a hp:
va la bus d lieu va la byte thap cua a ch 16 bit .
ALE la tn hieu e chot a ch vao mot thanh ghi ben
ngoai trong na au cua chu ky bo nh. Sau o, cac
ng Port 0 dung e xuat hoac nhap d lieu trong na
sau chu ky cua chu ky bo nh.
Cac xung tn hieu ALE co toc o bang 1/6 lan tan so
dao ong tren chip va co the c dung la nguon xung
nhp cho cac he thong. Neu xung tren 8951 la 12MHz th
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ALE co tan so 2MHz. Chan nay cung c lam ngo vao
cho xung lap trnh cho EPROM trong 8951.
g. EA (External Access): Tn hieu vao EA tren chan 31
thng c noi len mc cao (+5V) hoac mc thap (GND).
Neu mc cao, 8951 thi hanh chng trnh t ROM noi
trong khoang a ch thap (4K). Neu mc thap, chng
trnh ch c thi hanh t bo nh m rong. Ngi ta
con dung chan EA lam chan cap ien ap 21V khi lap
trnh cho EPROM trong 8951.h. RST (Reset): Ngo vao RST tren chan 9 la ngo reset
cua 8951. Khi tn hieu nay c a len mc cao (trong t
nhat 2 chu ky may), cac thanh ghi trong 8951 c a vao
nhng gia tr thch hp e khi ong he thong.
i.OSC: 8951 co mot bo dao ong tren chip, no thng
c noi vi thach anh gia hai chan 18 va 19. Tan sothach anh thong thng la 12MHz.
j. POWER: 8951 van hanh vi nguon n +5V. Vcc c
noi vao chan 40 va Vss (GND) c noi vao chan 20.
THIT K MCH CM BIN V ADC
1. GII THIU :
1.1.CHUYN I A/D :
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1.1.1. NGUYN TC CHUYN I:Mch chuyn i tn hiu tng t sang s,chuyn mt tn hiu ng vo tng t
(dng in hay in p) thnh dng m s nh phn c gi tr tng ng.
Chuyn i ADC c rt nhiu phng php.Tuy nhin,mi phng php iu c nhngthng s c bn khc nhau:
+ chnh xc ca chuyn i AD.+ Tc chuyn i .+ Di bin i ca tn hiu tng t ng vo
Hnh S khi tng qut ca mch ADC Hot ng
-u tin kch xung start b ADC hot ng
--Ti mt tn s c xc nh bng xung clock b iu khin lm thay i thnh snh phn c lu tr trong thanh ghi(Register).-S nh phn trong thanh ghi c chuynthnh dng in p Va bng b chuyn i DA.
-B so snh,so snh Va vi in p ng vo Va .Nu Va < Va th ng ra ca b sosnh vn gi mc cao. Khi Va > Va ng ra ca b so snh xung mc thp v qu trnhthay i s ca thanh ghi ngng. Lc ny V a gn bng Va , nhng s trong thanh ghi lnhng s cn chuyn i .1.1.2.ADC0804 :-CS (Chip select)Chn s 1, l chn chn Chip, u vo tch cc mc thp c s dng kch hot ChipADC0804. truy cp ADC0804 th chn ny phi mc thp.- RD (Read)Chn s 2, l mt tn hiu vo, tch cc mc thp. Cc b chuyn i u vo tng t thnh snh phn v gi n mt thanh ghi trong. RD c s dng c d liu c chyn i tiu ra ca ADC0804.
+StartcommandV
A
VA
Control Unit
Register
D/Aconverter
Comparator
clock
Digital output
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Khi CS = 0 nu c mt xung cao xung thp p n chn RD th d liu ra dng s 8 bit c ati cc chn d liu (DB0 DB7).- WR (Write)Chn s 3, y l chn vo tch cc mc thp c dng bo cho ADC bit bt u qu trnhchuyn i. Nu CS = 0 khi WR to ra xung cao xung thp th b ADC0804 bt u qu trnhchuyn i gi tr u vo tng t Vin v s nh phn 8 bit. Khi vic chuyn i hon tt th chnINTR c ADC h xung thp.
- Ngt INTR (Interupt)Chn s 5, l chn ra tch cc mc thp. Bnh thng chn ny trng thi cao v khi vic chuyni hon tt th n xung thp bo cho CPU bit l d liu chuyn i sn sng ly i. Saukhi INTR xung thp, cn t CS = 0 v gi mt xung cao xung thp ti chn RD a d liura.
Vin (+) v Vin (-)
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Chn s 6 v chn s 7, y l 2 u vo tng t vi sai, trong Vin = Vin(+) Vin (-). Thngthng Vin (-) c ni ti t v Vin (+) c dng lm u vo tng t v s c chuyn iv dng s.
- VccChn s 20, l chn ngun nui +5V. Chn ny cn c dng lm in p tham chiu khi u voVref/2 h.
- Vref/2Chn s 9, l chn in p u vo c dng lm in p tham chiu. Nu chn ny h th inp u vo tng t cho ADC0804 nm trong di 0 - +5V. Tuy nhin, c nhiu ng dng m uvo tng t p n Vin khc vi di 0 - +5V. Chn Vref/2 c dng thc hin cc in pu ra khc 0 - +5V.Bng quan h in p Vref/2 vi Vin
D0 - D7D0 - D7, chn s 18 11, l cc chn ra d liu s (D7 l bit cao nht MSB v D0 l bit thp nhtLSB). Cc chn ny c m ba trng thi v d liu c chuyn i ch c truy cp khichn CS = 0 v chn RD a xung mc thp. tnh in p u ra ta tnh theo cng thc sau
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- Mch to xung clock cho ADC 0804 :
Tuy nhin ADC0804 cng c mt b to xung ng h ring. dng ng h ring th cc chnCLK IN (chn s 4) v CLK R (chn s 19) c ni vi mt t in v mt in tr (nh hnhv). Khi y tn s c xc nh bng biu thc:
Vi R=10 k , C=150pF v tn s f=606 kHz v thi gian chuyn i l 110 ms.
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Hnh Biu thi gian ca ADC 0804
1.2.O NHIT BNG IC:
1.2.1.Gii thiu:
K thut vi in t cho php ch to c nhng mch kt ni gm nhng transistorging nhau c s dng lm cm bin hon ho o nhit da vo vic o s khc
bit in p VBE di tc ng ca nhit .Cc cm bin ny to ra cc dng in hcin p t l vi nhit tuyt i,vi tuyn tnh cao; n c iu li l vn hnh ngin, tuy nhin phm vi hot ng gii hn ch trong khong 550C n 1500C.
1.2.2.Nguyn l chung ca IC o nhit :L mch tch hp nhn tn hiu nhit chuyn thnh tn hiu di dng in p
hoc tn hiu dng in. Da vo c tnh rt nhy ca cc bn dn vi nhit , to ra inp hoc dng in t l thun vi nhit tuyt i. o tn hiu in, ta bit c gi trca nhit cn o.
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S tch cc ca nhit to ra in tch t do v cc l trng trong cht bn dnbng s ph v cc phn t, bt cc electron thnh dng t do di chuyn qua cc vng cutrc mng tinh th, to s xut hin cc l trng nhit lm cho t l in t t do v cc ltrng tng ln theo quy lut hm m vi nhit . Kt qu ca hin tng ny l di mcin p thun, dng thun ca mi ni p-n (trong diode hay transistor) s tng theo hm mtheo nhit .
2.MCH CM BIN NHIT :
P 1 .P 1 .P 1 .P 1 .P 1 .P 1 .P 1 .P 1 .P 3 .P 3 .P 3 .
U 4
L M 3 5
V S +1
V O U T2
G
N
D
3
U 5
A D C 0 8 0 4
+ I N6
- I N7
A
G
N
D
8
V R E F / 29
G
N
D
1
0
D B 71 1D B 61 2D B 51 3D B 41 4D B 31 5D B 21 6D B 11 7D B 01 8
C L K R1 9
V
C
C
/V
R
E
F
2
0
C L K I N4
I N T R5
C
S
1
R D2
W R3
V C C
U 6L M 3 3 6
-
+
U 7 A
L M 3 5 8
3
21
8
4
V C CR 9
1 0 k
C 4
1 u F
R 78 k 2
V C C
C 5
1 5 0 p
C 6
1 u F
R 8
1 0 k
V C C
R 1 02 k 2
o nhit c chnh xc, tt nhin cn c mt u d thch hp. u d l mtcm bin nhit c nhim v vn chuyn t nhit qua tn hiu in. C rt nhiu loicm bin nh gii thiu chng I.Da vo l thuyt v thc t ca mch cn thit k tadng phng php o bng IC cm bin nhit . Cc IC cm bin nhit c chnh
xc cao, d tm v gi thnh r. Mt trong s l IC LM35, l loi thng dng trn thtrng hin nay, ng thi n c nhng c tnh lm vic ph hp vi thit k chi tit camch.
-Mt s tnh cht c bn ca LM35:
- LM35 c bin thin theo nhit : 10mV / 1oC.
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- chnh xc cao, tnh nng cm bin nhit rt nhy, nhit 25oC n c sai skhng qu 1%. Vi tm o t -55oC 150oC, tn hiu ng ra tuyn tnh lin tc vi nhngthay i ca tn hiu ng vo.
- Thng s k thut:Tiu tn cng sut thp.
Dng lm vic t 450 A 5mA.
Dng ngc 15mA.
Dng thun 10mA.
- c tnh in:Theo thng s ca nh sn xut LM35, quan h gia nhit v in p ng ra nh
sau:
Vout = 0,01 ToC
Vy ng vi tm hot ng t 0oC 150oC ta c s bin thin in p ng ra l:
0oC th in p ng ra Vout = 0 (V).
150oC th in p ng ra Vout = 1,5(V).
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Thc tp cng nhnGVHD: L Hng Nam
KHI HIN TH V BN PHM
1Kh i hin th:
1 .1.S nguyn l:
U 2
7 4 4 7
D 07
D 11
D 22
D 36
B I / R B O4
R B I5
L T3
A1 3
B1 2
C1 1
D1 0
E9
F1 5
G1 4
V
C
C
1
6
G
N
D
8
v c c
R 1 71 K 2
R 1 8
1 K 2
R 1 9
1 K 2
D 8
L E D
D 9
L E D
D 1 0
L E D
J 2
H E A D E R 8
1
2
3
4
5
6
7
8
5 V5 V 5 V
R 33 3 0
R 53 3 0
R 63 3 0
R 73 3 0
R 83 3 0
R 93 3 0
R 1 03 3 0
A
B
D
C
G
F
E
0
O 6
O 5
O 4
0
0
8
U 7
L E D 7 . 1
B6
E1
D2
T
3
C4
D P5
A7
L
8
F9
G1 0
8
U 8
L E D 7 . 2
B6
E1
D2
T
3
C4
D P5
A7
L
8
F9
G1 0
8
U 9
L E D
B6
E1
D2
T
3
C4
D P5
A7
L
8
F9
G1 0
A
C
B
F
E
D
B
A
G
D
C
G
F
E
C
B
A
E
D
G
F
R 2 0
3 3 0
R 1 11 K 2 R 1 21 K 2 R 1 31 K 2
O 5 O 6O 4
D 1 1
L E D
J 4
H E A D E R 2
1
2
J 5
H E A D E R 2
1
2
0
5 V
V c c
V C C
0
Q 7A 1 0 1 5
Q 8A 1 0 1 5
Q 9A 1
0Q 1 0A 1 0 1 5
Q 1 1
A 1 0 1 5
Q 1 2
A 1 0 1 5
R 1 4
3 3 0
R 1 5
3 3 0
R 1 6
3 3 0
V c cV c cV c c
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Thc tp cng nhnGVHD: L Hng Nam
Nguyn l hot ng :
Trong h thng vi x l, b hin th ng vai tr rt quan trng: dng giao tip vi my
tnh v ngi s dng, cho php ngi s dng quan st, cm nhn qu trnh lm vic ca
h thng. y b hin th ch c chc nng l hin th nhit ngoi ra khng c chc
nng khc. .. n gin c phn cng th ch cho php nhit hin th t 00C 999C
t port 1 ca vi iu khin. B hin th hng Led 7 on l loi c s dng ph bin.
Hnh 7.4.d . a: B hin th Led 7 on, b: Loi anode chung, c: Loi Cathod chung.
BCD inputs Segment outputsDisplay
A B C D a b c d e f g0 0 0 0 0 0 0 0 0 0 1 00 0 0 1 1 0 0 1 1 1 1 10 0 1 0 0 0 1 0 0 1 0 20 0 1 1 0 0 0 0 1 1 0 30 1 0 0 1 0 0 1 1 1 1 40 1 0 1 0 0 1 0 0 1 0 5
ff
g g
ccVcc
e e
d d
aa
b b
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Thc tp cng nhnGVHD: L Hng Nam
Khi hin th gm 3 led 7 on v 2 led n.Khi led n vng sng th ta nhp gi tr nhit
cn khng ch vo.Gi tr nhit ny s hin th trn led 7 on.Khi led xanh sng th
led 7 on s hin th nhit hin ti ca l.Nhit ny s ly t cm bin nhit .
*Kim tra khi hin th:
-Kim tra in p cung cp cho IC cm bin LM35,IC 89C52 v IC chuyn i m c ng
v c khng,o in p ra trn mi IC xem c t yu cu khng.
-Kim tra cc in tr ni t b chuyn i n cc led 7 on c ng khng,kim tra cc
in tr ko t ngun xung c ng khng.
-Kim tra cc led 7 on c ng loi khng( y dng loi anod chung)
*Nu led 7 on khng sng th phi kim tra:
-Kim tra led c ng loi khng(anod chung)
-Kch cho ng cung cp ngun(kim tra con bjt c dn khng)
-Kim tra con gii m c hot ng khng.
*Nu hin th khng ng th phi kim tra:
0 1 1 0 1 1 0 0 0 0 0 60 1 1 1 0 0 0 1 1 1 1 71 0 0 0 0 0 0 0 0 0 0 81 0 0 1 0 0 0 1 1 0 0 9
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Thc tp cng nhnGVHD: L Hng Nam
-Cho qut chm,qut ht ct ny n ct kia(cho delay ln)
-Kim tra in p kch cho ct,hng c ng khng(xut gi tr ra ri phi tt led)
Cc linh kin s dng trong mch:
a.IC74LS47: dng chuyn tn hiu dng s nh phn ng vo sang m 7 on. IC ny
hot ng tch cc mc thp. Do ta c bng chn thc sau:
IC hot ng ta kt ni chn 16 (Vcc) vi ngun 5 V, chn s 8 vi t. Ng vo c 4
chn l 7,1,2,6 tng ng vi A,B,C,D trong mc ngha gim dn t A n D. Kt ni
cc ng ra A,B,C,D ca iC vi cc cng tc m mi cng tc n gin l nm gia 2 mc
cao hoc thp. Cc chn LT, BI/RBO, RBI khng cn kt ni. Nu ta dng Led 7 on kiu
cathod chung th mi ng ra ca IC 7447 cn kt ni vi cc cng o trc khi n cc
chn ca Led.
1.2.Tnh gi tr n tr hn dng Rhd ni vi 74LS47 :
Ngun cung cp Vcc = 5V. Cc thng s ng ra ca IC7447 l :
Vol = 0.4V
Iol = 40mA .
- Gi s , ta mun cc led sng vi mt dng nh mc Iledm =10mA vy:
Ihd =T
T0 .Iledm
Vi T0 l thi gian 1 led sngT l thi gian led khng sng
Chn thi gian sng cho 1 led l 100s
Thi gian khng c dng chy qua led l 600 s
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Thc tp cng nhnGVHD: L Hng Nam
- Mi on ca led cn dng khong 10mA sng , n gin ta xem led 7 on
gm 7 led n.
Vy dng qua led l ihd = 10.7 = 70 (mA)
Ihd =600
100 .70 = 28,5(mA)
Chn BJT 2SA1015 c = 70
Dng IBmin = 28,5/70 =0,41(mA)
Chn IB=(23)IBmin =2.0.41 =0.82(mA)
Rhd= (Vcc V LED Vol)/ILED => Rhd = (5V-1.8V 0.4V )/0.82mA
=> Rhd = 3,4K
Rhd =3,9K.
Lc ILED = (5V - 1,8V - 0,4V)/3,9k = 0,7(mA)
1.3 .Tnh gi tr in tr Rb ni vi BJT:
- Xt iu kin transistor bo ho l :Ic Ib
Vi led 7 on, 1 led sng cn dng 10mA, sng ht 7 led cn dng Ic = 7.10 = 70
(mA)Chn BJT A1015 c min = 70 .Ti ng ra ca IC8051 c cc thng s sau :
Iol = 3.2mA
Vol =0.4 V
Vy dng Ib nm trong gii hn sau :
c
IIbIol hay
c
I
b
b
R
UIol
T ta suy ra R:
Rbol
b
I
U=
ol
olcc
I
VVV =
0032,0
4,08,05 VVV =
0032,0
8,31187,5
Chn RB =1.2K
Lc vi led 7 on ta c:
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Thc tp cng nhnGVHD: L Hng Nam
Ib =b
b
R
U=1200
8,3= 3,16 (mA)
70
70=1(mA)
Vi led n ta c:
Ib = 3,16 (mA) 70
10=0,14(mA)
2.Bn phm
Nguyn l:
thc hin ma trn bn phm ta dng phng php qut phm. Qut ct v c dliu ti hng hoc ngc li. Theo hnh v th cc ct cch nhau 1 n v, cc hng cchnhau 4 n vi.
Vy gi tr ca bn phm c tnh theo cng thc sau
Bp= C+h.4
Trong : Bp: Gi tr ca phm c nhn.
C: Ct c qut.H: Hng c phm nhn.
Khi mch cn nhiu phm th ta mi t chc ma trn phm gim s lng cng s
dng cho bn phm.
Ban u cc nt bm c set mc cao,khi nhn nt th chuyn sang mc thp(mc 0)
1 4
2 3
1 4
2 3
1 4
2 3C 3
1 4
2 3
71 4
2 3
P 1 .3
1
H 2
2
C
3
F1 4
2 3
H 0
P 1 .1
1 4
2 3
5
P 1 .0
1 4
2 3
1 4
2 3
P 1 .5
E
P 1 .4
1 4
2 3
D
1 4
2 3
64
1 4
2 3
98
0
1 4
2 3
C 0
H 1
1 4
2 3
P 1 .6
J 1
C O N 8
12345678
C 1
P 1 .7
1 4
2 3
H 3
A
C 2
1 4
2 3
P 1 .2
B
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Thc tp cng nhnGVHD: L Hng Nam
*Kim tra bn phm :
-Trc ht phi kim tra gn cc chan ca nt bm ng cha:c 1 cp chn ca nt
bm mc cao,khi bm th xung mc thp,dng ng h kim tra khi nhn nt c thngmch khng.
-Kim tra v tr cc nt bm chnh xc cha(tng ng vi hng v ct nh hnh v trn)
*Nu nhn phm v hin th khng m khng hin th s bm th phi kim tranh sau:
-Kim tra phn cng xem c ng vi chng trnh vit khng.
-Kim tra xem cc nt c b dnh vi nhau khng.
KHI GIAO TIP
1.C u tr c c n g ni tip:
Cngnitipcsdngtruyndliuhaichiugiamytnhvngoivi,cccuimsau:
- Khongcchtruynxahntruynsongsong.- Sdyktnit.
- Cthtruynkhngdydnghngngoi.
- CthghpniviviiukhinhayPLC(ProgrammableLogicDevice).
- Chophpnimng.
- Cththolpthitbtronglcmytnhanglmvic.
- Cthcungcpngunchoccmchinngin
Cc thit b ghp ni chia thnh 2 loi: DTE (Data Terminal Equipment) v
DCE (DataCommunicationEquipment).DCE lcc thitb trunggiannhMODEMcnDTEl ccthitbtipnhnhaytruyndliunhmytnh,PLC,viiukhin,Victraoitnhiuthngthngqua2chnRxD(nhn)vTxD(truyn).Cctnhiucnlicchc nng h tr thit lp v iu khin qu trnh truyn, c gi l cc tnhiu bt tay (handshake). u im ca qu trnh truyn dng tn hiubt tay l c thkimsotng truyn.
Tn hiu truyn theo chun RS-232 ca EIA (Electronics IndustryAssociations). Chun RS-232 quy nh mc logic 1 ng vi in p t -3V n -25V
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Thc tp cng nhnGVHD: L Hng Nam
(mark),mc logic0 ngviinpt3Vn25V(space)vckhnngcungcpdngt10mAn20mA. Ngoira,ttcccngraucctnhchngchpmch.
Chun RS-232 chophp truyn tn hiu vi tc n 20.000bps nhng nu cp
truynngncthlnn115.200bps.CcphngthcnigiaDTEvDCE:
-ncng(simplexconnection):dliuchctruyntheo1hng.
- Bn song cng ( half-duplex): d liu truyn theo 2 hng, nhng mi thi imchctruyntheo1hng.
-Songcng(full-duplex):sliuctruynngthitheo2hng.
nhdngcakhungtruyndliutheochunRS-232nhsau:
Start D0 D1 D2 D3 D4 D5 D6 D7 P Stop0 1
Khikhngtruyndliu,ngtruynstrngthimark(inp-10V).Khibtutruyn, DTE s a ra xung Start (space: 10V) v sau ln lt truyn t D0 n D7 vParity,cuicnglxungStop(mark:-10V)khiphctrngthingtruyn.
CcctnhkthutcachunRS-232nhsau:
Chiudicablecci 15mTcdliucci 20Kbpsinpngracci 25V
inpngracti 5Vn 15VTrkhngti 3K n7Kinpngvo 15Vnhyngvo 3VTrkhngngvo 3K n7K
Cc tc truyn d liu thng dng trong cng ni tip l: 1200bps, 4800bps,9600bpsv19200bps
Schncngnitip
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Thc tp cng nhnGVHD: L Hng Nam
M t S chn1 Da ta carrier detect
(DCD)Trnh tn hiu mng d liu
2 Received data (RxD) D liu c nhn3 Transmitted data (TxD) D liu c gi4 Data terminal ready
(DTR)u d liu sn sng
5 Signal ground (GND) t ca tn hiu6 Request to send (RTS) D li u sn sng7 Request to send (RTS) Yu cu d liu8 Clear to send (CTS) Xo gi9 Ring indicator (RL) Bo chung
2.Giao tip vi vi iu khin
Khithchingiaotipviviiukhin,taphidngthmmchchuynmclogict TTL 232 v ngc li. Cc vi mch thng s dng l MAX232 ca Maxim hayDS275caDallas.Mchchuynmclogicmtnhsau:
P 1
D B 9
594837261
U 1
M A X 2 3 2
C 1 +1
C 1 -3
C 2 +4
C 2 -5
V
C
C
1
6
G
N
D
1
5
V +2
V -6
R 1 O U T1 2
R 2 O U T9
T 1 I N1 1
T 2 I N1 0
R 1 I N1 3
R 2 I N8
T 1 O U T1 4
T 2 O U T7
C 1
1 0 u
J 1
C O
1234
V C C
C 2
1 0 u
V C CC 3
1 0 uC 4
1 0 uC 5
1 0 u
MchchuynmclogicTTLRS232.
Tuynhin,khisdngmchchuynmc logicdngccvimch thihiphidngchungGNDgiamytnhvvimchckhnnglmhngcngnitipkhixyrahin tngchpmchmchngoi.Do, tac thdng thmopto4N35cch lyv
in.
*Kim tra Max232:
-o ngun,o cc t xem c t yu cu khng
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Thc tp cng nhnGVHD: L Hng Nam
-Kim tra cc chn ca t,ca Max232 ng cha,cc iu kin c khng
-u chn (2) v chn (3) gi d liu xung => nhn c l c.
-Chp ng ra ca Max232,ni vi chn ra ca IC89C52 xem c giao tip c khng(xem c thupht d liu c khng)
-u tin cng COM trc.
KHI CNG SUT V NG B
1.S nguyn l:
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Thc tp cng nhnGVHD: L Hng Nam
R 1 8
1 0 0 k
V C C
R 2 05 k 6
-
+
U 9 A
L M 3 9 3
3
21
8
4
R 1 7
1 0 0 kJ 5
X O A Y C H I E U
12
R 2 6
1 2 k
V C C
R 2 48 k 2
U 8M O C 3 0 2 1
1
2
6
4
C 7
1 u F
Q 1T R I A C
Q 2
A 1 0 1 5
R 1 13 3 0
R 1 2
3 , 3 k
R 1 3
1 8 0
R 2 5
2 k 4
C 8
1 u F
J 4
T A I + N G
12
D 2
D I O D E
P 3 . 4
R 1 4
2 . 2 M
V C C
R 1 94 7 k
P 3 . 2
Q 6C 1 8 1 5
2.Nguyn l hot ng:-Mch ng b to ra xung iu khin tn hiu kch v p xoay chiu t ln triac,tora s ng b v tn hiu kch v p xoay chiu t vo triac
+Triac kch ch I+,III+
+Tn hiu xoay chiu qua b opamp so snh va BJT C1815 lt tin hiu.Tn hiu ra aqua VK nhn c v kt hp vi tn hiu t cm bin s iu khin tn hiu chn P3.4 iu khin BJT A1015 v to ra dng kch cho triac.
Nu mc ra t cm bin l Tmin th P3.4=0,BJT A1015 dn bo ho v to ra dngkch vo cng G ca triac,lm triac hot ng ,t nung nhit nng ln. Tn hiu kch tnti t nht phi 2us th triac mi bt u dn. Gc kch c iu chnh qua VK bngcch delay mt khong thi gian so vi tn hiu nhn v chn P3.2 theo sn ln haysn xung,v tn hiu ny phi nhn c sau khi c tn hiu t ADC l Tmin
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Thc tp cng nhnGVHD: L Hng Nam
Nu mc ra t cm bin l Tmax th P3.4=1,BJT A1015 ngt v lm triac ngng hot ng,t nhit gim dn
- iu khin ti AC: Ta dng phng php iu khin gc pha l phng php thayi gc kch ca Triac lm bin i in p t ln ti, khi gc kch = 0 th coi nhton b in p li t ln ti nu nh ta b qua st p trn Triac. u im ca phng
php ny l iu khin lin tc v chnh xc hn.
*Kim tra khi iu khin cng sut:
-Trc tin kim tra con triac gn ng cha(dng ng h xc nh chnh xc cc chnca triac)
-Kim tra cc thnh phn iu khin
-Kim tra ngun cung cp c khng
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Thc tp cng nhnGVHD: L Hng Nam
-Kim tra kch c hot ng c khng
*Nu ng mch m ng c khng chy th kim tra:
-Kim tra cc thnh phn iu khin (kim tra con triac,kch c hot ng c khng)
*Nhit khng n nh c th kim tra g?
Nu nhit hin th khng n nh c th kim tra:
-iu khin theo phng php gc pha:
+o xung kch mt nhit no ,y ra 1 xung kch xem nhit thay i nh thno?
* Phng php thc hin mch i n
Sau khi v hon chnh s mch in trn giy, chng ta bc sang giai on
thc hin mch in. Trnh t thc hin tin hnh theo cc bc sau:
Bc 1: Dng giy nhm nhuyn nh sch lp oxit ha ang bm trn tm mch in (phac trng lp ng), trc khi v cc ng mch.
Bc 2: To ng mch in trn mt ng c cc phng php sau:
- In mch in v ra giy in la hoc p nhit to mch in trn mt ng.
- Dng vit lng c dung mi acetone v ni cc ng mch trn mt ng (datheo cc im pointou va nh v v s mch v trc trn giy).
Trong khi v ta ch , c hai phng php v im pad hn trn mch in. im pad hnc th v theo hnh trn hoc hnh vung. Thng thng im pad trn d thc hin nhngli km tnh m thut hn im pad vung.Mun thc hin im pad vung, ta c th dngvit t rng (quanh v tr cnto im pad vung), sau dng u mi dao nhn v thc
k ta bt mc duy tr mt vng mc bm hnh vung cho im pad cn thc hin. Cngvic ny i hi nhiu thi gian v s t m khi thc hin.
- Sau khi to cc ng mch trn mt ng ca mch in, ta quan st xem c vtr no b v khng lin nt, m ca cc ng phi u nhau, ng thi khng b stng mch no c. Trong trng hp cn thit, sinh vin phi ch cho mc kh hn ri li mt ln na.
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Thc tp cng nhnGVHD: L Hng Nam
Bc 3: Sau khi v hon chnh, sinh vin ch kh mi mang mch in nhng vo thuc ty.Ha cht ty s n mn lp ng ti cc v tr khng bm mc v s nguyn lp ng ticc v tr c bao ph bng cc ng v mc. Khi nhng mch in trong thuc ty, mun
phn ng ha hc xy ra nhanh, cn thc hin cc thao tc sau tng tc phn ng:
- Lc tm mch trong chu thuc.
- Nn t chu thuc ty ni c nh sng mt tri tng cng tc phn
ng nh hiu ng quang.
- Nu thuc ty c nung nng khong 50oC th thi gian ty s nhanh hn
khi thuc ty c nhit thp (bng nhit mi trng).
Bc 4: Sau khi ty xong cc phn ng khng cn thit, nn ngm mch vo
trong nc l v dng giy nhm nhuyn ch sch cc ng mc v. Cng vic
s chm dt khi cc ng mch c nh bng v sng.
Trc khi dng nha thng lng ph bo v lp ng, ta dng khoan (ng
knh li khoan khong 0,8 -1mm) khoan cc l ghim linh kin. Trong mt vi
trng hp, ta c th dng my dp bm l thay v khoan. Tuy nhin, l dp khng
trn v khi dp d lm m lp bakelite nhng tc thi cng nhanh hn, v d
thao tc hn phng php khoan.
Bc 5: Sau khi khoan (hay dp) l xong, cn nh s li mt ln mch in (pha c ccng ng) bng giy nhm nhuyn, lm sch lp oxit ha ln cui ri mi nhng tmmch vo dung dch nha thng pha vi xng v du la. Khi nhng xong mch, ro v
phi kh lp sn ph ri mi hn linh kin ln mch.
3.Tnh ton mch:
3.1Tnh mch cng sut:
Dng in tr dy t : Rs4=50()
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Thc tp cng nhnGVHD: L Hng Nam
Khi dng qua mch:
I= = =4,4(A)
Chn triac :BT138 c VDRM=600(V) IT=12(A)VGM=5(V)
dIT/dt =45A/s IGM=2(A) PG(tb)=0,5(w) ton=2us
Tra datasheet chn dng kch cho triac IG=10mA
Chn p t vo triac khi kch l 14(V)
Khi : VGT2=0,7(V) (80oC)
Vtriacopto=1,4(v)
VR25+13=14- 0,7 - 1,4=11,9(v)
RR25+13= =1,19(k )
Chn R25=1(k) R13=180(ohm)
Dng kch cho triac l 10mAPtriacopto=10.1,4=14(mW)
Chonj opto_triac MOC3021:Input: Vm=1,5(V) Im=50mA Pm=100mV
Output: Vm=400(V) Im=100mA Pm=300mV
Chn dng qua Input ca opto triac :I=10mA ; Vdiode=1,2(v)
Chn BJT Qs1 l A1015
Khi opto hot ng th BJT A1015 dn bo ho
VCEs=0,1(v) P=10.0,1=1(mW) tho mn iu kin ca BJT
p ri trn: R11= = =330()
Chn R11=330()
Tnh chn R12
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Thc tp cng nhnGVHD: L Hng Nam
QS1 A1015 dn bo ho th:
VEB=VEBs=0,8(v)
IB =0,15(mA)
Mc khc dng VK I=3,2(mA) Vmax=0,8(v) mc 0
IB.R12+0,8+0,8=5(v)
Chn IB=1(mA)
R12= =3,3(k)
Chn R12=3,3(k)
3.2Tnh mch ng b:
Chn p vo so snh VI=4v
=VI=4(v)
=3
Chn R26=12(k ) R20=5,6(k )
Chn R17=R20=100k hn dng vo opamp v hn ch dng lch khng.
Opamp co VO=3,5(V) IO=1(uA)
Khi C1815 bo ha VBES=0,7(V)
R14= =2,8(M )
R14=2,2(M )
R19= =49(k )
R19=47(k )
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Thc tp cng nhnGVHD: L Hng Nam
*CHNG TRNH DELPHI
I/Gim st
- Nhit cm bin- Cc ci t t bn phm nh nhit n nh v tt m ngun ca l nhit v cnh bobng m thanh cng nh mu sc
II/iu khin- Ci t nhit n nh- Tt /m ngun ti
unit Unit1;
interface
usesWindows, Messages, SysUtils, Variants, Classes, Graphics, Controls, Forms,Dialogs, StdCtrls, CPort, ExtCtrls, Menus;
typeTForm1 = class(TForm)
ComPort: TComPort;Memo1Tcambien: TMemo;Edit1Send: TEdit;ButtonOpen: TButton;ButtonSetting: TButton;ButtonSend: TButton;
ButtonClear: TButton;ButtonExit: TButton;Label1: TLabel;Label2: TLabel;Timer1: TTimer;NGAY: TLabel;GIO: TLabel;Button1: TButton;Button2: TButton;Label3: TLabel;Memo3TrangThai: TMemo;Label4: TLabel;
Edit2Tnhap: TEdit;Label5: TLabel;Label6: TLabel;Label7: TLabel;Label8: TLabel;Label9COM: TLabel;Edit3LedPower: TEdit;ButtonPower: TButton;Edit1PHIM4X4: TEdit;
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Label9PHIM4X4: TLabel;Edit1COM: TEdit;procedure ButtonExitClick(Sender: TObject);procedure ButtonOpenClick(Sender: TObject);procedure ButtonSettingClick(Sender: TObject);procedure ButtonSendClick(Sender: TObject);procedure ButtonClearClick(Sender: TObject);procedure ComportRxChar(Sender: TObject; Count: Integer);procedure Timer1Timer(Sender: TObject);procedure Button1Click(Sender: TObject);procedure Button2Click(Sender: TObject);procedure ButtonPowerClick(Sender: TObject);
private{ Private declarations }
public{ Public declarations }end;
varForm1: TForm1;
implementation
{$R *.dfm}//-----------thoat COM v chuong trinh---------------------------------procedure TForm1.ButtonExitClick(Sender: TObject);begin
ComPort.Close;Close;
end;//-----------turn on ---turn off---cong COM------------procedure TForm1.ButtonOpenClick(Sender: TObject);beginif ComPort.Connected then // Kiem tra cong COM co mo khong
beginComport.Close; // neu mo thi dong laiButtonOpen.Caption:='Close';
Memo3TrangThai.Color:=clwhite;Edit1COM.Color:=clwhite;Edit1PHIM4X4.Color:=clwhite;Edit3LedPower.Color:=clwhite;
Memo3TrangThai.Text :='' ;Memo1Tcambien.Text :='' ;Edit2Tnhap.Text :='' ;
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Edit1PHIM4X4.Text :='' ;Edit3LedPower.Text :='' ;
Label9COM.Caption :='Cong COM da dong';endelsebeginComport.Open;ButtonOpen.Caption:='Open';Edit1COM.Color:=clRED;Label9COM.Caption :='Cong COM da ket noi...';end;
end;
// ---------cai dat con COM-----------------------------procedure TForm1.ButtonSettingClick(Sender: TObject);beginComport.ShowSetupDialog;
Comport.Open;
end;
// ---------cai dat nhiet do on dinh---------------------------procedure TForm1.ButtonSendClick(Sender: TObject);
var s1,s2,s3,nguon:string;
var a,b,c,tg,nhietdodat:integer;begintg:=strtoint(Edit3LedPower.Text);nguon:=chr(tg) ;
if Comport.Connected thenbeginif(Edit1Send.Text='') thenShowMessage('Can nhap nhiet do vao')else
if(strtoint(Edit1Send.Text)>120)or(strtoint(Edit1Send.Text)
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tg:=nhietdodat mod 100;b:=tg div 10;s2:=chr(b);
c:=tg mod 10;s3:=chr(c);
ComPort.WriteStr(s1); //tram-phimComPort.WriteStr(s2); //chuc-phimComPort.WriteStr(s3) ; //donvi-phimComPort.WriteStr(nguon) ; //gui data dieu khien nguon
ShowMessage('Nhiet do on dinh da duoc cai dat') ;Edit2Tnhap.Text:=Edit1Send.Text;Edit1Send.Text:='';
endendelse ShowMessage('Cong com dang dong')
end;
// -------------------xoa o nhap nhiet do on dinh-------procedure TForm1.ButtonClearClick(Sender: TObject);beginbeep;Edit1Send.Text:='';end;
//----------doan code nhan data tu vdk phat len----------procedure TForm1.ComportRxChar(Sender: TObject; Count: Integer);var str:string;
beginif comport.Connected thenbegin
comport.ReadStr(str,Count) ;
Memo1Tcambien.Text := inttostr(ord(str[1]));
Edit2Tnhap.Text := inttostr(ord(str[2]));Edit3LedPower.Text := inttostr(ord(str[3]));Edit1PHIM4X4.Text := inttostr(ord(str[4]));
// kiem tra NGUON duoc ON or OFF de bat LedPowerif(strtoint(Edit3LedPower.Text)=1) then
beginEdit3LedPower.Color:=clred;ButtonPower.Caption:='TURN OFF';
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endelse
beginEdit3LedPower.Color:=clwhite;ButtonPower.Caption:='TURN ON';end;
//kiem tra co suu dung ban phim hay khongif(strtoint(Edit1PHIM4X4.Text)=1) then
beginLabel9PHIM4X4.CAPTION:='Dang nhap ban phim....hihi' ;Edit1PHIM4X4.Color:=clred;beep;end
else
beginLabel9PHIM4X4.CAPTION:='4X4 no use.hic' ;Edit1PHIM4X4.Color:=clgreen;end ;
// xem nhiet do cam bien voi nhiet do datif (Edit2Tnhap.Text='') then Memo3TrangThai.Text :='chua cai dat nhiet do on
dinh'else
beginif(strtoint(Edit2Tnhap.Text)>=strtoint(Memo1Tcambien.Text)) then
begin
Memo3TrangThai.Text :='binh thuong..hihi' ;Memo3TrangThai.Color:=clgreen;end
else beginbeep; //qua nhiet thi canh bao bang am thanhMemo3TrangThai.Text :='Oi qua nhiet sep oi..hic hic' ;Memo3TrangThai.Color:=clred;end
end
endend;
// --------thoi gian-------------------------------------procedure TForm1.Timer1Timer(Sender: TObject);beginGIO.Caption:=timetostr(now());NGAY.Caption:=datetostr(now());end;
//-------------about-------------------------------
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procedure TForm1.Button1Click(Sender: TObject);beginshowmessage('chuong trinh GIAM SAT VA ON DINH NHIET DO '+#13#10+'giao vien huong dan:Le Hong Nam'+#13#10+'sinh vien thuc hien:'+#13#10+'NGUYEN MANH HO'+#13#10+'NGUYEN TUAN THANH'+#13#10+'LUONG DUY NINH'+#13#10+'TRAN LE NHAT BINH'+#13#10+'PHAM VAN DANG'+#13#10+'NGO THI VAN DAT'+#13#10+'LE DAO ANH THU');end;// ------------help----------------------------procedure TForm1.Button2Click(Sender: TObject);
beginshowmessage('hotline:01268558797');end;
//----------dieu khien ON--OFF --nguon--------------procedure TForm1.ButtonPowerClick(Sender: TObject);var s1,s2,s3,nguon:string;var a,b,c,tg,nhietdodat:integer;
beginif(strtoint(Edit3LedPower.Text)=1) then
begin //TAT NGUONButtonPower.Caption:='TURN ON';nguon:=chr($0);
nhietdodat:=strtoint( Edit2Tnhap.Text);a:=nhietdodat div 100;s1:=chr(a) ;
tg:=nhietdodat mod 100;b:=tg div 10;s2:=chr(b);
c:=tg mod 10;s3:=chr(c);
ComPort.WriteStr(s1); //tram-phimComPort.WriteStr(s2); //chuc-phimComPort.WriteStr(s3) ; //donvi-phimComPort.WriteStr(nguon) ; //gui data dieu khien nguon
Edit3LedPower.Text:=inttostr(0);
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ShowMessage('Da tat nguon') ;end //HET MO NGUON
elsebegin //MO NGUON
ButtonPower.Caption:='TURN OFF';nguon:=chr($1);
nhietdodat:=strtoint( Edit2Tnhap.Text);a:=nhietdodat div 100;s1:=chr(a) ;
tg:=nhietdodat mod 100;b:=tg div 10;s2:=chr(b);
c:=tg mod 10;s3:=chr(c);
ComPort.WriteStr(s1); //tram-phimComPort.WriteStr(s2); //chuc-phimComPort.WriteStr(s3) ; //donvi-phimComPort.WriteStr(nguon) ; //gui data dieu khien nguonEdit3LedPower.Text:=inttostr(1);ShowMessage('Da mo nguon') ;
end //HET MO NGUONend;end.
Chng trnh chnh
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DONVI EQU 30H
CHUC EQU 31H
TRAM EQU 32H
DONVI_PHIM EQU 33H
CHUC_PHIM EQU 34H
TRAM_PHIM EQU 35H
T_NHAP EQU 36H
T_CAMBIEN EQU 37H ;nhiet doc tu cam bien
NGUON EQU 38H ;REG de phoi hop voi phanmem ON or OFF nguon,khong phai de dk goc pha
;NGUON=1 mo lo,NGUON=0 tat
lo
BANPHIM EQU 39H ;gui tin hieu lenchuong trinh giam sat biet co dang nhap ban phim 4x4 hay khong
;BANPHIM=1 la co su dungban phim 4x4,BANPHIM=0 la khong dung
;-----Dinh nghia cac Bit-----
RDCB BIT P3.7
WRCB BIT P3.6
INTR BIT P3.5
CONGSUAT BIT P3.4 ;BIT DIEU KHIEN CONG SUAT
LED_CONGSUAT BIT P3.3 ;DEN LED BAO QUA NHIET HAY KHONG
LEDPOWER BIT P2.7 ;DEN BAO ON-OFF NGUON
;CAC THANH GHI DA DUNG: R1 LA REG DEM DE NHAP BAN PHIM
; R2 LA DE CHUA GIA TRI TAM THOI CUA T_NHAP
;----------Chuong trinh----------------
ORG 0H
LJMP MAINMAIN
ORG 03H
LJMP XULYCONGSUAT
ORG 23H
LJMP TRUYENDULIEU
ORG 100H
MAINMAIN:
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MOV DONVI,#0H
MOV CHUC,#0H
MOV TRAM,#0H
MOV CHUC_PHIM,#1
MOV TRAM_PHIM,#1
MOV DONVI_PHIM,#9
MOV NGUON,#1 ;ban dau khoi dong NGUON=1 tuc la nguondc TURN ON
MOV BANPHIM,#0 ;ban dau khoi dong BANPHIM=0 =chua sudung
MOV TMOD,#21H
SETB EA ;CHO PHEP NGAT TOAN CUC
SETB EX0 ;CHO PHEP NGAT INT_CAMBIEN DE CHO PHAN DIEUKHIEN CONG SUAT
SETB IT0 ;NGAT THEO SUON XUONG
SETB ES ;CHO PHEP NGAT NOI TIEP
MOV TH1,#-3 ;toc do buad la 9600
MOV SCON,#50H ; set SMO/SM1 =0/1,set bit REN =1
SETB TR1 ;bo dinh thoi 1 hoat dong
MOV P1,#0FFH MOV P2,#0FFH
MOV P3,#0FFH
;--------------------------------------
;--------Chuong trinh chinh------------
;--------------------------------------
MAIN: MOV BANPHIM,#0 ;de bao maytinh rang khong su dung banphim4x4
CALL CHUYENMANGUOC ;chuyen ma nguoc de co T_NHAP,mac dinh luckhoi dong la 119 C
CALL DOC_CAM_BIEN ; Gia tri 8 bit--> A co dc gia tri tram,chuc, don vi
MOV T_CAMBIEN,A ;luu nhiet do cam bien vao regT_CAMBIEN
MOV SBUF,A
CALL CHUYENMA
CALL DISPLAY
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MOV P0,#0FEH
JNB P0.7,PHIM_MODE ;kiem tra xem co chon phim cai dat banphim
JMP MAIN
PHIM_MODE:
JNB P0.7,$
CALL NHAP_BAN_PHIM
JMP MAIN
;--------Chuong trinh con doc cam bien--
DOC_CAM_BIEN:
CLR WRCB ;bat dau cho phep chuyen doi
SETB WRCB
HERE:
JB INTR,HERE ;ket thuc chuyen doi
CLR RDCB ; gui data ra port 1
MOV A,P1
SETB RDCB ;ngat gui data
RET
*LU THUT TON CHNG TRNH QUT BN PHM VHIN TH
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;------chuong trinh con nhap ban phim--------------
NHAP_BAN_PHIM: MOV BANPHIM,#1 ;de bao cho may tinh biet dang sudung ban phim 4x4
CALL CHUYENMANGUOC
CALL CHUYENMA2
CALL DISPLAY
MOV SBUF,T_CAMBIEN
MOV P0,#0FEH
NOP
JNB P0.4,SO1
JMP NEXTX
SO1:
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CALL DELAY_MS
JNB P0.4,$
MOV R1,#1
JMP SOLVE_HIENTHI
SO4:
CALL DELAY_MS
JNB P0.5,$
MOV R1,#4
JMP SOLVE_HIENTHI
SO7:
JNB P0.6,$
MOV R1,#7 JMP SOLVE_HIENTHI
CANCEL: JNB P0.7,$
MOV R1,#0
MOV DONVI_PHIM,#0
MOV CHUC_PHIM,#0
MOV TRAM_PHIM,#0
JMP NHAP_BAN_PHIM
MODE:
JNB P0.7,$
CALL DELAY_MS
MOV R1,TRAM_PHIM
CJNE R1,#0,NEXTMODE ;KIEM TRA XEMNHIET NHIET DO DAT CO QUA120 DO HAY KHONG
JMP MAIN
NEXTMODE: CJNE R1,#1,NHAPLAI
MOV R1,CHUC_PHIM
CJNE R1,#0,NEXTMODE1
JMP MAIN
NHAPLAI:
JMP CANCEL
NEXTMODE1:
CJNE R1,#1,NEXTMODE2
JMP MAIN
NEXTMODE2:
CJNE R1,#2,NHAPLAI
MOV R1,DONVI_PHIM
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CJNE R1,#0,NHAPLAI
JMP MAIN
NEXTX:
MOV P0,#0FEH
JNB P0.4,SO1
JNB P0.5,SO4
JNB P0.6,SO7
JNB P0.7,MODE
MOV P0,#0FDH
JNB P0.4,SO2
JNB P0.5,SO5
JNB P0.6,SO8
JNB P0.7,SO0
MOV P0,#0FBH
JNB P0.4,SO3
JNB P0.5,SO6
JNB P0.6,SO9
JNB P0.7,CANCEL
MOV P0,#0F7H
JNB P0.7,KEY_ENTER
JMP NHAP_BAN_PHIM
KEY_ENTER: MOV R1,NGUON
CJNE R1,#0,TURN_OFF
MOV NGUON,#1
CLR LEDPOWER
JMP NHAP_BAN_PHIM
TURN_OFF: MOV NGUON,#0
SETB LEDPOWER
JMP NHAP_BAN_PHIM
SO0:
JNB P0.7,$
MOV R1,#0
JMP SOLVE_HIENTHI
SO2:
JNB P0.4,$
MOV R1,#2
JMP SOLVE_HIENTHI
SO3:
JNB P0.4,$
MOV R1,#3
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JMP SOLVE_HIENTHI
SO5:
JNB P0.5,$
MOV R1,#5
JMP SOLVE_HIENTHI
SO6:
JNB P0.5,$
MOV R1,#6
JMP SOLVE_HIENTHI
SO8:
JNB P0.6,$
MOV R1,#8
JMP SOLVE_HIENTHI SO9:
JNB P0.6,$
MOV R1,#9
JMP SOLVE_HIENTHI
SOLVE_HIENTHI: MOV A,CHUC_PHIM
MOV TRAM_PHIM,A
MOV A,DONVI_PHIM MOV CHUC_PHIM,A
MOV DONVI_PHIM,R1
JMP NHAP_BAN_PHIM
RET
;-----chuong trinh con chuyen ma --dung cho doc cambien---------------------------
CHUYENMA:
MOV B,#100
DIV AB
ADD A,#0E0H
MOV TRAM,A
MOV A,B
MOV B,#10
DIV AB
ADD A,#0D0H
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MOV CHUC,A
MOV A,B
ADD A,#0B0H
MOV DONVI,A
RET
;------chuong trinh chuyen ma 2--dung cho ban phim----------------
CHUYENMA2:
MOV A,TRAM_PHIM
ADD A,#0E0H
MOV TRAM,A
MOV A,CHUC_PHIM
ADD A,#0D0H
MOV CHUC,A MOV A,DONVI_PHIM
ADD A,#0B0H
MOV DONVI,A
RET
;****************chuyen ma nguoc**dung cho dk cong suat****************
CHUYENMANGUOC: MOV A,TRAM_PHIM
MOV B,#100
MUL AB
MOV T_NHAP,A
MOV A,CHUC_PHIM
MOV B,#10
MUL AB
MOV R0,#36H
ADD A,@R0
MOV T_NHAP,A
MOV A,DONVI_PHIM
ADD A,@R0
MOV T_NHAP,A
RET
;*---------------HIEN THI-----------------
DISPLAY:
MOV R0,#250
LOOPO: MOV P2,DONVI
CALL DELAY_MS
MOV P2,CHUC
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CALL DELAY_MS
MOV P2,TRAM
CALL DELAY_MS
DJNZ R3,LOOPO
RET
;***********************XU LY CONG SUAT**********************
XULYCONGSUAT: PUSH ACC
PUSH PSW
CALL CHUYENMANGUOC
MOV A,T_NHAP
CJNE A,T_CAMBIEN,KHONG_BANG ;T_NHAP-T_CAMBIEN
JMP BINHTHUONG
KHONG_BANG: JNC BINHTHUONG ;NEU BIT C =1 THI T_CAMBIEN
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CLR RI
JNB RI,$
MOV CHUC_PHIM,SBUF
CLR RI
JNB RI,$
MOV DONVI_PHIM,SBUF
CLR RI
JNB RI,$ ;nhan tin hieu dieu khien lam viec cualo la ON or OFF tu may tinh
MOV NGUON,SBUF
CLR RI
SJMP EXIT_TRUYENDULIEU
PHAT: MOV SBUF,T_CAMBIEN ;gui nhiet do cam bien
JNB TI,$
CLR TI
MOV SBUF,T_NHAP ;gui nhiet do nhap tu ban phim
JNB TI,$
CLR TI
MOV SBUF,NGUON ;gui TIN HIEU DIEU KHIEN NGUON
JNB TI,$
CLR TI
MOV SBUF,BANPHIM ;gui tin hieu co su dung ban phim4x4 hay khong
JNB TI,$
CLR TI
EXIT_TRUYENDULIEU: POP PSW
POP ACC
RETI
;-----Chuong trinh con tao tre 1ms------------
DELAY_MS:
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MOV TH0,#HIGH(-1000)
MOV TL0,#LOW(-1000)
SETB TR0
JNB TF0,$
CLR TF0
CLR TR0
RET
;--------delay--dung cho dk cong suat------------
DELAYX:
MOV TH0,#HIGH(-1000)
MOV TL0,#LOW(-1000)
SETB TR0
JNB TF0,$
CLR TF0
CLR TR0
DJNZ R7,DELAYX
RET
END
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*Nhim v ca mi c nhn
-Thnh+ng :hin th nhit & thi cng mch
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