ball a ball b ball a is moving toward ball b. ball b is stationary ball a and ball b have the same...
TRANSCRIPT
Ball “A” Ball “B”
Ball “A” is moving toward Ball “B”. Ball “B” isstationary
Ball “A” and Ball “B” have the same mass!
When “A” strikes “B”, Ball “B” moves upward and Ball “A” moves downward.
Whatever momentum “A” has before the collision A’ and B’share after they collide
vA
vB’
vA’
KE = KE’
v12 + v2
2 = v1’2 + v2’2
If v2 = 0 then, v1 = v1’2 + v2’2
vA
vB’
vA’
vA
vB’
vA’
vA
vB’ vA’
vB’ = Cos1 vA
vA’ = Sin1 vA
vA
vB’
vA’
vBx’
vBy’
vAx’
vAy’
vBx’ = Cos vB’
vBy’ = Sin vB’
vAx’ = Cos vA’
vAy’ = Sin vA’
vA = vBx’ + vAx’
0 = vBy’ + vAy’
vA
vB’
vA’
vBx’
vBy’
vAx’
vAy’
p = p’ mvA = mvA’Cos2 + mvB’Cos1
m1 = m2 vA = vA’Cos2 + vB’Cos1
12
vA
vB’
p = p’
On ‘y’ axis0 = Sin1 vB’ + Sin2 vA’
Sin2 = -Sin1 vB’/vA’
va’
vA
vB’
vA’
vBx’
vBy’
vAx’
vAy
’
Two balls of equal mass strike each other. Ball A moves at 5.20 m/sand strikes ball B, which is stationary. After the collision ball Atravels above the original path at an angle of 21.00. What is the “p” “v”s of each ball after the collision?
1. vA’ = Cos1 vA vA’ = Cos 21.00 x 5.20 m/s vA’ = 4.85 m/s
2. vA = vA’2 + vB’2 vB’ = vA2 - vB’2 vB’ = 1.88 m/s
3. Sin2 = -Sin1 vA’/vB’ 2 = -Sin210 x 4.85m/s 1.88m/s
= 680