bài giảng môn tín hiệu và mạch - ths ngô hán chiêu [tuần 1]
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GV: ThS Ng Hn ChiuEmail: [email protected]
HP: 0908.978.988
TN HIU V MCH
I HC CNG NGH THNG TIN
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TNG QUAN
H thng my ch:
S tn ch: 03
S tit hc: 45 tit
Tiu chun nh gi:
Thi gia k: 20%
Thi cui k: 80%.
Thang im: 10
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GIO TRNH & TI LIU THAM KHO
H thng my ch:
1. Phng Xun Nhn, L thuyt mch v h thng, i hc BckKhoa H Ni, 2001.
2. Nguyn Vn Chuyt, C s l thuyt truyn tin, NXB KHKT, 2004.3. Phm Th C, Mch in (tp 1,2), NXB HQG TP. HCM, 2007.4. L Phi Yn, K thut in t, NXB HQG TP. HCM, 2007.5. Nguyn Kim nh, K thut in, NXB HQG TP. HCM, 2007.6. Nguyn Quc Dinh, L thuyt mch, Hc vin CNBCVT, 2006.7. William Stalling, Introduction to Electronics design, Prentice Hall,
1995.8. Charles Belove, Circuit design and Analyse, McGraw Hill
Company, 1996.
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TNG QUAN
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TNG QUAN (tt)
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TNG QUAN (TT)
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TNG QUAN (TT)
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KHI NIM
Mch in l m hnh vt l thc, baogm cc in tr, t in, transitor,...cghp ni vi nhau bng cc on dy dnhay board mch in.
S mch in l m hnh l tng, ccphn t thc ca mch in c thay thbng cc phn t l tng
PHN TCH MCH V TNG HP MCH U THC HINTRN M HNH L TNG
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CC PHN T C BN CA MCH IN
IN TR
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CC PHN T C BN CA MCH IN
IN TR (TT)
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CC PHN T C BN CA MCH IN
GI TR IN TR
vd1 vd2
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CC PHN T C BN CA MCH IN
PHN LOI IN TR
in tr thng : in tr thng l cc in tr c cng sut nht0,125W n 0,5W
in trcng sut : L cc in tr c cng sut ln hn t1W,2W, 5W, 10W.
in tr s, in tr nhit : L cch gi khc ca cc in trcng sut , in tr ny c v bc s, khi hot ng chng tonhit.
Cc in tr : 2W 1W 0,5W 0,25Win tr s hay tr nhit
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CC PHN T C BN CA MCH IN
CNG SUT IN TR
Khi mc in tr vo mt on mch, bn thn in tr tiu thmt cng sut P tnh c theo cng thc
P = U . I = U2 / R = I2.R
Cng sut tiu th ca in tr ph thuc vo dng in iqua in tr hoc ph thuc vo in p trn hai u intr.
Cng sut tiu th ca in tr l hon ton tnh c trckhi lp in tr vo mch.
Nu em mt in tr c cng sut danh nh nh hn cngsut n s tiu th th in tr s b chy. Thng thng ngi ta lp in tr vo mch c cng sut
danh nh > = 2 ln cng sut m n s tiu th
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CC PHN T C BN CA MCH IN
VD: CNG SUT IN TR
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CC PHN T C BN CA MCH IN
BIN TR
Bin trL in tr c th chnh thay i gitr, c k hiu l VR chng c hnh dng nh sau :
Bin tr thng rp trong my phc v cho qu trnh sa cha,cn chnh ca k thut vin, bin tr c cu to nh hnh bndi.
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CC PHN T C BN CA MCH IN
T INT in : T in l linh kin in t th ng c s dng rt rngri trong cc mch in t, chng c s dng trong cc mch lcngun, lc nhiu, mch truyn tn hiu xoay chiu, mch to daong,...
Cu to ca t in
Cu to ca t in gm hai bncc t song song, gia c mtlp cch in gi l in mi.Ngi ta thng dng giy, gm ,mica, giy tm ho cht lm cht
in mi v t in cng cphn loi theo tn gi ca cc chtin mi ny nh T giy, T gm,T ho.
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CC PHN T C BN CA MCH IN
CC DNG T IN
T gm T ho
T mng nha T xoay s dng trong Radio
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CC PHN T C BN CA MCH IN
in dung, n v v k hiu ca t inin dung : L i lng ni ln kh nng tch in trn hai bn cc cat in, in dung ca t in ph thuc vo din tch bn cc, vt liulm cht in mi v khong cch gi hai bn cc theo cng thc
C = . S / dTrong C : l in dung t in , n v l Fara (F)
: L hng s in mi ca lp cch in.d : l chiu dy ca lp cch in.S : l din tch bn cc ca t in.* n v in dung ca t : n v l Fara (F) , 1Fara l rt ln do trong thc t thng dng cc n v nh hn nh MicroFara (F) ,NanoFara (nF), PicoFara (pF).1 Fara = 1.000.000 Fara = 1.000.000.000 n F = 1.000.000.000.000 p F1 Fara = 1.000 n Fara1 n Fara = 1.000 p Fara
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CC PHN T C BN CA MCH IN
T IN (TT)
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CC PHN T C BN CA MCH IN
T IN (TT)
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CC PHN T C BN CA MCH IN
T IN (TT)
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CC PHN T C BN CA MCH IN
CUN DY
Cun cm gm mt s vng dy qun li thnh nhiu vng, dy qunc sn emay cch in, li cun dy c th l khng kh, hoc l vtliu dn t nh Ferrite hay li thp k thut
Li khng kh Li Ferit
L1 l cun dy li khng kh, L2 l cun dy li ferit, L3 l cun dy c li chnh, L4 l cun dy li thp k thut
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CC PHN T C BN CA MCH IN
CUN DY (tt)
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CC PHN T C BN CA MCH IN
CUN DY (tt)
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CC PHN T C BN CA MCH IN
CUN DY (tt)
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CC PHN T C BN CA MCH IN
CC THNG S CUN DY (tt)
H s t cm (nh lut Faraday)
H s t cm l i lng c trng cho sc in ng cm ng
ca cun dy khi c dng in bin thin chy qua.L = 4.3,14.10-7 n2.S.l
L : l h s t cm ca cun dy, n v l Henrry (H)
n : l s vng dy ca cun dy.
l : l chiu di ca cun dy tnh bng mt (m)S : l tit din ca li, tnh bng m2
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CC PHN T C BN CA MCH IN
CC THNG S CUN DY (tt)
Cm khng
Cm khng ca cun dy l i lng c trng cho s cn
tr dng in ca cun dy i vi dng in xoay chiu .
ZL = 2.3,14.f.L
Trong : ZL l cm khng, n v l
f : l tn s n v l Hz
L : l h s t cm , n v l Henry
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CC PHN T C BN CA MCH IN
ng dng ca cun dy
R le
Bin p
U1 / U2 = n1 / n2
U1 / U2 = I2 / I1Loa
Micro
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CC PHN T C BN CA MCH IN
NGUN P
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CC PHN T C BN CA MCH IN
NGUN P (TT)
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CC PHN T C BN CA MCH IN
NGUN DNG
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GV: ThS Ng Hn ChiuEmail: [email protected]
HP: 0908.978.988
MCH 1 CHIU
I HC CNG NGH THNG TIN
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MCH 1 CHIUTNG QUAN
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CC NH LUT C BN
NH LUT OHM
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NH (NT), NHNH V VNG
Nhnh l phn t hai cc bt k, hoc gmcc phn t hai cc ni tip vi nhau trn c cng dng in chy qua.
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NH (NT), NHNH V VNG (tt)
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NH (NT), NHNH V VNG (tt)
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V D
Nhnh 1: e1, R1 ni tip.
Nhnh 2: e2, R2 ni tipNhnh 3: R3.Nhnh 4: R4Nhnh 5: R5Nhnh 6: R6n= 6
4 nh A,B,C v D
d= 4
V = n d + 1 = 6-4+1 = 303 mt li
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V D
Vng 1: nhnh 1,6 v 4.
Vng 2: nhnh 2,5 v 6Vng 3: 4,5 v 3Vng 4: 1,2 v 3
Vng 5: 1,6,5,3
Vng 6: 1,2,5,4Vng 7: 2,3,4,6
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NH LUT KIRCHOFF 1 (K1)
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NH LUT KIRCHOFF 1 (K1)
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V D
Nt A: i1 - i2 i6 = 0Nt B: i2 - i3 - i5 = 0Nt C: - i1 + i3 - i4 = 0Nt D: i4 + i5 + i6 = 0
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NH LUT KIRCHOFF 2 (K2)
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NH LUT KIRCHOFF 2 (K2) (tt)
Du ca in p c xc nh da trn chiudng ca in p chn so vi chiu ca vng.
Chiu ca vng c chn tu (thng chncng nhnhau: cng chiu hoc ngc chiu kimng h).
Trong mi vng, nu chiu vng i t cc (+)
sang cc ( - ) ca mt in p, th in p mangdu (+), ngc li in p y mang du ( - ).
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V D
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BI TP 1
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BI TP 1
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BI TP 1
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BI TP 2
Tm dng in chytrong cc nhnh
Tm dng in chytrong cc nhnh
Tnh tng cng sutpht ca cc ngunv tng cng suttiu tn ca cc R
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BI TP 3
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BI TP 2
K hiu cc dng nhnh
Chn i1 = variable
C : i = -10 AKCL : i2 = i1 + 5i = i1 - 50KCL : i3 = i2 + 20 = i1 - 30KCL : i4 = i - i1 = - 10 - i1Th vo pt KVL duy nht vit cho vng kn bao 2 ml pha trn :10*i1 + 20*i2 - 200 + 40*i3 - 30*i4 = 100
10*i1 + 20*[i1 - 50] - 200 + 40*[i1 - 30] - 30*[- i1 - 10] = 100100*i1 - 2100 = 100Suy ra i1 = 22 A
Bi gii 1A
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HOMEWORK
Homework1:1.2; 1.8; 1.11; 1.16; 1.17; 1.20; 1.23; 1.24; 1.29; 1.32;Sch Bi tp mch in 1 - Phm Th C NXB HQG TP. HCM - 2002