analisa dan perencanaan balok tampang t.pptx

7/24/2019 ANALISA DAN PERENCANAAN BALOK TAMPANG T.pptx

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TUJUAN:Mahasiswa dapat melakukanperhitungan Analisa dan desain tampangBalok T

dgn metode Kekuatan (Strength method)

sesuai SNI !"#$%&"##

ANALISA DAN PERENCANAAN BALOKTAMPANG T

Analisa Tampang Balok T '


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UMUM

Balok T (dan L) merupakan en!uk !ampan" alok #an"pal$n" %er$n" d$"unakan %ela$n en!uk !ampan" per%e"$

Balok T !eren!uk karena alok dan pela! d$&or %e&aramonol$!' maka %ea"$an lear pela! dapa! d$an""apmen*ad$ a"$an dar$ alok+

Kekakuan alok !ampan" per%e"$ men*ad$ le$, e%ar karenaadan#a kon!r$u%$ dar$ %ea"$an pela!

Lear pela! #" dp! d$an""ap men*ad$ a"$an alok d$%eu!LEBAR E-EKTI- edan d$a!ur ole, SNI p%l ./+./

Pr$n%$p0

#" d$"unakan dlm anal$%a lk per%e"$ !e!ap erlakupd alok !ampan" T (dan *u"a L)

Analisa Tampang Balok T #


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PELAT LANTAI' BALOK T1L

%n0

e

Balok L

Pela!

lan!a$

e

Balok T

%n.

Analisa Tampang Balok T !


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LEBAR E-EKTI2 e

Pera!uran Lear ealok T Lear ealok

L

SNI3/43056730//0

e8L e9:.;.0L

e9:.


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MOMEN DE-ORMASI DAN LETAK TUL+ TARIK

S$%$ a!a% lkmener$ma !e"+ !ar$k

Mma

Mm$n

(:) (:)

(3)(3)

S$%$ 9, lkmener$ma !e"+ !ar$k

Tul+ Ba*a u!kmem$kulM(:)

Tul+ Ba*a u!kmem$kul M(3)

Analisa Tampang Balok T


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LETAK GRS NETRAL #Momen (:)

Pada daera, momen po%$!$@ (%ek$!ar !", en!an") umumn#aen% men"alam$ !e"+ Tekan+ Dlm ,al $n$ "r% ne!ral # $%a!erle!ak (.) pada -len% (0) pada B$dan" per!emuan an!araen% d"n dn alok a!au (4) erada pada Badan alok (9e)

Kond$%$ . #,= Kond$%$ 0 #F,= Kond$%$ 4 #,=

e

,=

A%

9

e

9

e

A%

9

Gr%

ne!ral

Daera,!ekan

"n

Analisa Tampang Balok T *


7/35

LETAK GRS NETRAL #Momen (3)

Pada daera, M(3) maka pela!;en% men"alam$ !e"+ Tar$k+ Dlmkond$%$ $n$ "r% ne!ral # !erle!ak erada pada adan alok

(9e)+ Keadaan $n$ %eenarn#a adala, %ama d"n alok T!eral$k d"n -len%3n#a !erle!ak d$ a9a,

Pd daera, M(3) lk T dp! d$perlakukan %" lk per%e"$ %,"anal$%a %ama d"n !eor$0%lm3n#a+

9

e

#

"n

Daera,!ekan

,=

fs/5H=&

=%fs

/5H=&

=%

Analisa Tampang Balok T &


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ANALISA PENAMPANG BALOK T(GRS NETRAL J?

-

)

=%

e

,= "+n

d ,

C&

Ts

e&uF///4 0,85fc

a

A%

9 Re"an"an Te"an"an Re%ul!anGa#a

Ke%e!$man"an "a#a CFT

ysec fAabf0,85 = (6+.)

B$la # ,=maka lk T d$perlakukan %" lk per%e"$ d"n Fe+

Analisa Tampang Balok T $


9/35

TINGGI GRS NETRAL #

Dar$ per% (6+.) !ad$

ec

ys

bf0,85

fAa

=

$la db

A

e

s

=

(0+0.)

c

y

f

f

Maka !$n""$ lok !e" per%e"$ ek$@alen a

0,85

da =

(6+0)

(0+0/)dan

(6+4)

Maka !$n""$ "r% ne!ral #

11 0,85

d

ay (0+;6+6)

1l$,a! SNI p%l .0+0+7

a!au Sl$de no .0

Anal$%a penampan"Blk per%e"$ TulTun""al

Sama d"n per% (0+.7)d"n Fe

Analisa Tampang Balok T +


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MOMEN NOMINAL Mn

Per$k%a re"+ a*a %

ycus y

y-d (0+.0) per% (6+.)3(6+4) adl d"n

a%um%$ Ba*a Lele,

$la %# maka a*a !ar$k men&apa$ !e"+ lele,' %," Mn dp!

d$,$!un" d"n per% (0+.5)

2

adfAM ysn

(0+.5)a!au

2

a

dabf0,85M ecn(6+6a)

Dp! d$%$mpulkan $la "r%ne!ral # !erle!ak pd -len%maka lk dp! d$anal$%a %p!lk per%e"$ d"n lear Fe

$la re"+ a*a % #!ul+ Ba*a !dk men&apa$ !e"+ Lele, %,"

(6+6)

2

adfAM ssn d"n =%dar$ per% (0+4.)



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RASIO TUL+ BALANCE b

Un!uk alok T d"n #,=maka ra%$o !ulan"an bdp! d$!en!ukan

%ama %p! alok per%e"$ $a%a per%+ (0+0)

yy

1c

b f600

600

f

f0,85

=

(0+0)

Ca!a!an UMUM3n#a un!uk alok penampan" T dan L "r% ne!ral

erada d$ -len% dan Tul+ a*a !ar$k men&apa$ !e"an"an

Lele, =# B$la !$n""$ lok !e" ek$@ a,=maka alok T adala, alok T

!dk murn$ dan dapa! d$perlakukan %eper!$ alok per%e"$$a%a d"n lear Fe

Analisa Tampang Balok T ''


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ANALISA PENAMPANG BALOK T(GRS NETRAL J?-)

e

,=

"+nd ,

C&

Ts

ecu=0,003 0,85fc

a

A%

9=%

Re"+ Te"+

Un!uk Blk T d"n #,= ada 0 kemun"k$nan !$n""$ lok !e"+

ek$@+ a #a$!u a,=a!au $%a *u"a a,=B$la #,=!ap$ a,=maka d$perlakukan %" lk+ per%e"$

Analisa Tampang Balok T '#


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PENAMPANG EKI2ALEN UTK #,=

Penampan" alok T $n$ (a,=) dp! d$anal$%a d"n &ara

%p!;%eola,3ola, anal$%a penampan" lk per%e"$ !ulan"an

ran"kap (Per,a!$kan Gr d$a!a%Q) Kon!r$u%$ dar$ %a#ap;-len% C= d$an""ap dp! d$ GANTI3kan;d$3

AKIL3kan d"n %ua!u lua%an !ul+ a*a IMAINER A%= #"

mempun#a$ e%ar "a#a dan !$!$k !an"kap %ama d"n !!k !an"kapC=

Re%+ Ga#a

e

,=

"+nd ,

s

A

%

9 D$a"ram Re"+

C1

/5H=&

T9

C=

T= d-hf

d-a

cu=0,003

Tampan"Per%e"$ek$@alen

Penampan"alok T

(:)As

As

f

fy

Analisa Tampang Balok T '!


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KONTRIBUSI DARI GAJA TEKAN Cn

fwecf hbbf0,85C

Ga#a !ekan C= era%al dar$ -len% %elear (e39)+ Ga#a C=

d$%amakan d"n %ua!u "a#a $ma*$ner T= #" mempun#a$

kapa%$!a% "a#a #" %e!ara ;ek$@alen d"n kapa%$!a% "a#a dar$o@er,an" C=

(6+H)

fysff CfA = (6+


15/35

MOMEN Mndar$ -LENS

D"n meru*uk "r d$a!a% 1 men$n*au Momen !,d p%! era! !ul!ar$k A%maka Mn=%" kon!r$u%$ dar$ -len% adala,

2

h

dbbhf0,85!CM f

wefcffnf (6+a)' a!au

e

"+n

A%

9

F C1

/5H=&

T9

C=

T= d-hf

d-a (:)

As"

Asf

2

hdfAM fysfnf (6+)

*ad$ Mn#" d$er$kan ole, -len% dp! d$,$!un" d"n Per% (6+)



16/35

MOMEN Mndar$ EB (BADAN)

ysfs"w fAA

Dar$ "r %lm3n#a

2

adfAA

2

adabf0,85M ysfs"wcnw

wc

ysfs"

bf0,85

fA-Aa

abf0,85C wcw

(6+..)

(6+.0)

(6+.6)

Dan' Mn9%" kon!r$u%$ dar$ 9e;dn alok dp! d$,$!un" d"n

per% (6+.6)

sfs"sw AAA (6+./)

Dar$ per% (4+..) dan (4+.0) d$perole, a

(6+.4)

Analisa Tampang Balok T '*


17/35

MOMEN NOMINAL TOTAL Mn!

(6+.Ha)

(6+.H)

D"n dem$k$an Momen nom$nal To!al dar$ alok T adala, Mn!

nfnwn" MMM

2

hdbbhf0,85

2

adabf0,85M fwefcwcn"

a!au

2

hdfA#

2

adfA-A=M fysfysfs"n" -- (6+.H&)

D$manaa d$,$!un" d"n per% (6+.4)

A%=d$,$!un" d"n per% (6+7)

A%!adl lua% !ul+ Tar$k !o!al

2

h

2

a

fA2

a

dfAM f

ysfys"n"(6+.Hd)

a!au

Analisa Tampang Balok T '&


18/35

SJARAT BLK T MURNI

Sua!u alok T dp! d$ka!akan %" lk T murn$ (Real3T Beam)$la !erpenu,$ %ala, %a!u dar$ rumu% er$ku! $n$

fec

ys"

hbf0,85

fA

a >(6+0) a!au

0,85

dhf

(6+.


19/35

PEMBATASAN TULANGAN

Ra%$o !ulan"an alan&e u!k alok T (d"n a,=) adala, %

fbe

wb" b

b

yy

1c

b f600

600

f

f0,85

=

(6+.7)

db

hbb

f

f0,85

w

fwe

y

1c

f=

(0+0)

(6+.5)

Un!uk men*am$n per$laku alok #" dak!a$l maka *umla, !ul

d$a!a%$ %ea"a$ er$ku!

be

s 0,$5db

A (6+.)a!a% !ul+ Mak%

yw

s

f

1,%

db

A (6+0/)a!a% !ul+ M$n

Analisa Tampang Balok T '+


20/35

CONTO? ANALISA TAMPANG

CONTO? .

D$ke!a,u$ alok !ampan" T d"n da!a !ekn$%

=&F05MPa

=#F6./MPa

eF.///mm

,=F


21/35

PENJELESAIANRa%$o !ul+

Per$k%a !ampan" alok !er,adap makdan m$n

0,003%10

1,%&'n =

(6+0/)0,0030,021%3$,5250

2281 &'nw =

0,00$50,0010,02(1000250b" =

0,02(1010

600

%10

0,85280,85b ==

(6+.7)

0,001%3$,5250%10

652501000

%10

0,85280,85f =

=

(0+0)

(6+.5)

0,00560,00$50,$50,$5 b"&a) =

0,00560,0052%3$,51000

2281

analisa dan perencanaan balok tampang t.pptx

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