x=[17.88 , 28.92, 33.00, 41.52, 42.12, 45.60, 48.48, 51.84, 51.96, 54.12, 55.56, 67.80];
Post on 30-Dec-2015
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Example: lifetimes for ball bearings in millions of resolutions : 17.88, 28.92, 33.00, 41.52, 42.12, 45.60, 48.48, 51.84, 51.96, 54.12, 55.56, 67.80, 68.64, 68.88, 84.12, 93.12, 98.64, 105.12, 105.84, 127.92, 128.04, 173.40. Evaluate the empirical cdf Choose class of cdf to model the data - PowerPoint PPT Presentation
TRANSCRIPT
x=[17.88 , 28.92, 33.00, 41.52, 42.12, 45.60, 48.48, 51.84, 51.96, 54.12, 55.56, 67.80]; x=[x 68.64, 68.88, 84.12, 93.12, 98.64, 105.12, 105.84, 127.92, 128.04, 173.40];cd F:\wafo_new initwafo wweibplot(x)wnormplot(x)wweibfit(x)
Example: lifetimes for ball bearings in millions of resolutions:
17.88, 28.92, 33.00, 41.52, 42.12, 45.60, 48.48, 51.84, 51.96, 54.12, 55.56, 67.80, 68.64, 68.88, 84.12, 93.12, 98.64, 105.12, 105.84, 127.92, 128.04, 173.40.
1) Evaluate the empirical cdf2) Choose class of cdf to model the data3) Find a member in the class that fits best the data (ECDF)
Matlab code:
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