warm–up #9. solve by factoring 2 #s that mult to 56 –15 & add to –8 –7 set each factor =...
Post on 19-Jan-2016
214 Views
Preview:
TRANSCRIPT
Warm–up #91. Solve by Factoring
2. Solve by Completing the Square
Solve by Factoring1.
x(2x(x – 4) – 7(x – 4)) = 0
x(2x – 7)(x – 4) = 0
x = 0 2x – 7 = 0 x – 4 = 0
{0, 4, }
2 #s that mult to56
–15 & add to
–8 –7
set each factor = 0
Common factor first
Make = 0!!!
=
Solve by Completing the Square
2.
2 2 2
+
√¿¿
❑¿
√¿¿
❑¿
Homework LogWed
10/14
Lesson 2 – 4
Learning Objective: To solve quadratic forms
Hw: #210 Pg. 128 #12, 24, 36, 37 – 51 odd, WS # 8 – 10
10/14/15 Lesson 2 – 4 Quadratic Form Day 2
Advanced Math/Trig
Learning Objective
To solve quadratic equations in quadratic form
Solve by Factoring1.
4u(u – 1) – 9(u – 1) = 0
(4u – 9)(u – 1) = 0
Make = 0 first
It has quadratic form
Let 2 #s that mult to3
6
–13& add to
–4 –9
Solve by Factoring1. (4u – 9)(u – 1) = 0
(2x – 3)(2x + 3)(x + 1)(x – 1) = 0
2x – 3 = 0 2x + 3 = 0 x + 1 = 0 x – 1 = 0
Now replace u with
4 Answers!!
Highest Power is 4!!
Solve by Factoring2.
u(u + 8) – 1(u + 8) = 0
(u – 1)(u + 8) = 0
Let
2 #s that mult to–8
7& add to
8 –1
Solve by Factoring2. (u – 1)(u + 8) = 0
1
Now replace u with
Solve by completing the square!
Diff & Sum of Cubes!
1 11
Solve by Factoring2.
x – 1 =
x = x = 6 Answers!!
√¿¿
❑¿√¿
¿❑¿ √¿
¿❑¿√¿
¿❑¿
Solve by Factoring3.
2u(u + 3) + 1(u + 3) = 0
(2u + 1)(u + 3) = 0
Let
2 #s that mult to6
7& add to
6 1
Solve by Factoring3. (2u + 1)(u + 3) = 0
2 = –x 1 = –3x
Now replace u with
2 Answers!!
Solve by Factoring4.
u(u – 7) + 9(u – 7) = 0
(u – 7)(u + 9) = 0
Let
2 #s that mult to–63
2& add to
–7 9
Solve by Factoring4. (u – 7)(u + 9) = 0
((x – 4) – 7)((x – 4) + 9) = 0
(x – 11)(x + 5) = 0
x – 11 = 0 x + 5 = 0
{– 5, 11}
Now replace u with
2 Answers!!
Highest Power is 2!!
Solve by Factoring5.
(u – 4) (u + 4) = 0
(
(x – 2)(x + 2)() = 0
Let
Diff of Squares
Replace u with
x =
Solve by Factoring6.
2u(2u + 7) + 5(2u + 7) = 0
(2u + 7)(2u + 5) = 0
Let
2 #s that mult to14
0
24& add to
14
10
Solve by Factoring6. (2u + 7)(2u + 5) = 0
(2(3x – 2) + 7)(2(3x – 2) + 5) = 0
(6x – 4 + 7)(6x – 4 + 5) = 0
(6x + 3)(6x + 1) = 0
6x + 3 = 0 6x + 1 = 0
Replace u with
Solve by Factoring7.
3(5u(4u – 9) – 1(4u – 9) = 0
3(4u – 9)(5u – 1) = 0
Make = 0 first
Factor out GCF!
Let
2 #s that mult to180
–49& add to
–45 –4
Solve by Factoring7. 3(4u – 9)(5u – 1) = 0
3(2x – 3)(2x + 3)(5) = 0
2x – 3 = 0 2x + 3 = 0 5
Now replace u with
5
=
=
x =
Ticket Out the Door
Solve
Homework
#210 Pg. 128 #12, 24, 36, 37 – 51 odd, WS # 8 – 10
top related