warm up - 2/15 on page 50

Warm Up - Warm Up - 2/15 on page 2/15 on page 5050 What is kept constant in BoyleWhat is kept constant in Boyle’’s s

Law?Law?

Solve for the unknown:Solve for the unknown: PP11 = 0.456 atm = 0.456 atm VV11 = 289 mL = 289 mL PP22 = 0.287 atm = 0.287 atm VV22 = ??? = ???

Gay-LussacGay-Lussac’’s Laws Law

Gay-LussacGay-Lussac’’s Laws Law

Created by Joseph Gay-LussacCreated by Joseph Gay-Lussac Deals with changes in pressure Deals with changes in pressure

and temperature (volume kept and temperature (volume kept constant)constant)

As one increases, the other As one increases, the other increases as well (direct increases as well (direct relationship)relationship)

FormulaFormula

PP11 = = PP22

TT11 T T22

ExampleExample

At 120At 120°C, the pressure of a sample °C, the pressure of a sample of nitrogen is 1.07 atm. What will of nitrogen is 1.07 atm. What will the pressure be at 205°C?the pressure be at 205°C?

PP11 = 1.07 atm = 1.07 atm TT11 = 120°C = 120°C PP22 = ??? = ??? TT22 = 205°C = 205°C

ExampleExample

(1.07 atm)(1.07 atm) = = P P22 (120(120°C) (205°C)°C) (205°C)

(1.07 atm)*(205°C)(1.07 atm)*(205°C) = P = P22

(120°C)(120°C)

PP22 = 1.80 atm = 1.80 atm

CharlesCharles’’ Law Law

CharlesCharles’’ Law Law

Created by Jacques CharlesCreated by Jacques Charles Deals with changes in Deals with changes in volumevolume

and and temperaturetemperature (pressure (pressure kept constant)kept constant)

As one increases, the other As one increases, the other increases as well (direct increases as well (direct relationship)relationship)

FormulaFormula

VV11 = = VV22

TT11 T T22

ExampleExample

A gas at 65A gas at 65°C occupies 4.22 L. °C occupies 4.22 L. At what Celsius temperature will At what Celsius temperature will the volume be 3.87 L?the volume be 3.87 L?

VV11 = 4.22 L = 4.22 L TT11 = 65°C = 65°C VV22 = 3.87 L = 3.87 L TT22 = ??? = ???

ExampleExample

(4.22 L)(4.22 L) = = (3.87 L)(3.87 L) (65(65°C) T°C) T22

(4.22 L)*T(4.22 L)*T22 = (3.87 L)*(65°C) = (3.87 L)*(65°C)

TT22 = = (3.87 L)*(65°C)(3.87 L)*(65°C) = 59.6°C = 59.6°C (4.22 L)(4.22 L)