torque and the vector product thus far: torque torque is the vector product between the force vector...

Torque and the vector product

Thus far:

Torque sinFr

Torque is the vector product between the force vector F and vector r

Fr

is perpendicular to r and p

has magnitude = r·F·sin

Torque and the vector product

Definition of vector product:

BAC

- The vector product of vectors A and B is the vector C.

- C is perpendicular to A and B

- The magnitude of is C = A·B·sin

Torque and the vector product

BAC

Use the right hand rule to figure out the direction of C.

- Thumb is C (or torque angular velosity , angular momentum L)

- Index finger is A (or radius r)

- Middle finger is B (or force F)

Torque and the vector product

BAC

Rules for the vector product.

ABBA

If A is parallel to B then . Thus, 0BA

0AA

If A is perpendicular to B then BABA

CABACBA

)(

1.

2.

3.

4.

5. Magnitude of C = A·B·sin is equal to area of parallelogram made by A and B

Torque and the vector product

BAC

Rules for the vector product (cont).

kBABAjBABAiBABABA xyyxxzzxyzzy

)()()( 6.

A force F = (2.00i + 3.00j) is applied to an object that is pivoted about a fixed axis aligned along the z-axis.

The force is applied at the point r = (4.00i + 5.00j).

Black board example 11.1

(a) Find the magnitude of the net torque about the z-axis

(b) Find the direction of the torque vector .

(c) Find the angle between r and F.

Angular momentum of a particle

prL

L… angular momentum

r… distance from the origin

p… momentum of particle

Definition:

L is perpendicular to r and p

L has magnitude L = r·p·sin

Angular momentum of a rotating rigid object

We’ll consider an object that is rotating about the z-axis.

The angular momentum of the object is given by:

ILz

Note that in this case L and are along the z axis.

Also note the analog formula for linear momentum p = m·v

Black board example 11.2

A light rigid rod, 1 m in length, joins two particles – with masses 3 kg and 4 kg at its end. The system rotates in the x-y plane about a pivot through the center of the rod.

Determine the angular momentum of the system about the origin when the speed of each particle is 5.00 m/s.

You may treat the particles as point particles.

The earth has a mass m = 6.0 ·1024 kg, and a radius R = 6400 km.

It rotates about its own axis and it orbits around the sun at a distance d = 1.5·1011 m

What is its total angular momentum?

Black board example 11.3

Angular momentum of the earth

Conservation of angular momentum

The total angular momentum of a system is constant in both magnitude and direction if the resultant external torque acting on the system is zero.

constantL

If the system undergoes an internal “rearrangement”, then

constant fi LL

If the object is rotating about a fixed axis (say z-axis), then:

constant ffii II

Conservation laws

system isolatedan For

LL

pp

UKUK

i

fi

ffii

Student on a turn table.

A student stands on a turn table holding two weights, each with a mass of 3.00 kg. When his arms are extended horizontally, the weights are 1.00 m from the axis of rotation and he rotates with an angular speed of 0.75 rad/s. Assume that the moment of inertia of the student and turn table (without weights) remains constant at 3.00 kg·m2. The student pulls the weights inward to a position 0.300 m from the rotation axis.

(a) What is the new angular speed of the student?

(b) Find the kinetic energy of the student before and after he pulls the weights inwards.

Black board example 11.4

Two Demos

A students stands still on a rotatable platform and holds a spinning wheel. The bicycle wheel is spinning in the clockwise direction when viewed from above.

He flips the wheel over.

What happens?

Next demo (why do helicopters need two rotors?) Now the student stands still on a rotatable platform, and the wheel is initially not rotating.

The students spins the wheel in one direction, what happens to the student?