stpm trial 2009 phy q&a terengganu
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JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
Instructions to candidates :
DO NOT OPEN THIS BOOKLET UNTIL YOU ARE TOLD TO DO SO.
There are fifty questions in this paper. For each question four suggested answers are given.Choose one correct answer and indicate it on the multiple choice answer sheet provided.
Read the instructions on the multiple choices answer sheet very carefully.
Answerall questions. Marks will not be deducted for wrong answers. The total score for this
paper is the number of correctly answered questions.
This question paper consists of 18 printed pages .
PHYSICS
PAPER 1
14
3 hours
JABATAN PELAJARAN
NEGERI TERENGGANU
960/1 TRIAL
2009
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2
Physics 960
Constants value
speed of light in vacuumpermeability of vacuum
permittivity of vacuum
magnitude of electron charge
Planck constant
atomic mass unit constant
electron rest mass
proton rest mass
molar gas constant
Avogadro constant
Boltzmann constant
gravitational constant
free fall acceleration
co
o
e
h
u
me
mp
R
L, NA
k
G
g
==
=
=
=
=
=
=
=
=
=
=
=
=
3.00 x 10
8
m s
-1
4 x 10-7 H m-1
8.85 x 10-12 F m-1
[1/(36 )] x 10-9 F m-1
1.60 x 10-19 C
6.63 x 10-34 J s
1.66 x 10-27 kg
9.11 x 10-31 kg
1.67 x 10-27
kg
8.31 J K-1 mol-1
6.02 x 1023
mol-1
1.38 x 10-23 J K-1
6.67 x 10-11
N m2
kg-2
9.81 m s-2
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3 Two block,Xand Yof masses m and 2m respevticely are accelerated along a smooth horizontal
surface by a force Fapplied to blockXas shown in the diagram
What is the magnitude of the force exerted by block Y on block X during this acceleration?
A3
F B
3
2F C
2
F D 0
4 A small mass metal sphere of mass m is moving trough a viscous liquid. When it reaches a constant
downward velocity , which of the following describes the change with time in the kinetic energy andgravitational potential energy of the sphere?
Kinetic energy Gravitational potential energy
A Constant and equal to2
2
1mv Decrease at a rate of ( 2
2
1mvmgv )
B Constant and equal to2
2
1mv Decrease at a rate of mgv
C Increases at a rate of mgv Decrease at a rate of mgv
D Increases at a rate of mgv Decrease at a rate of ( mgvmv 2
2
1 )
5 A particle moves with constant speed in a horizontal circle. Which of the following quantities is
zero?
A Resultant force
B Angular acceleration
C Angular velocity
D Centripetal acceleration
YX
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5
6 A mass of 0.05 kg is attached to one end of a piece of elastic of unstreched length 0.50 m. The
force constant of the elastic is1
40
Nm . The mass is rotated steadily on a smooth table in a horizontalcircle of radius 0.70 m as shown below
What is the approximate speed of the mass?
A1
20
ms 2 B1
24
ms C1
11
ms D1
15
ms
7 A small ball of weight W is suspended by a light thread. When a strong wind blows horizontally,
exerting a constant force F on the ball, the thread makes an angle to the vertical as shown
F
W
Which equation correctly relates , Fand W?
AW
F=cos
BW
F=sin
CWF=tan
DF
W=tan
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6
8 The diagram below shows a piece of inextensible string which passes trough a pulley. The pulley
has a radius of 0.05 m and moments of inertia24
100.6 kgm
. The end Q is held such that an object P
of mass 0.2 kg is stationary at a height of 0.2 m from the floor.
P Q
0.2 m
If end Q is released and the pulley is rough enough to prevent the string from slipping, find the speed ofP when it touches the floor.
A1
35.1ms B 123.1
ms C 101.1ms D 148.1
ms
9 The gravitational potential energy PE of a body varies with its distance r from the centre of a planet
as shown in the diagram below
PE
0 r
What does the gradient at any point on the curve present?
A the gravitational potential at that value ofr
B the gravitational field strength at that value ofrC the acceleration of the body towards the planet
D the force pulling the body towards the planet
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7
10 On the ground, the gravitational force on a satellite is W. What is the gravitational force on thesatellite when at a height R/50, where R is the radius of the earth A
A 1.02 W B 1.04 W C 0.96 W D 0.98 W
11 A particle of mass m performs simple harmonic motion with an amplitude a and a frequency f. Thetotal energy of this simple harmonic motion is
A222
2 fma B 222 fma C 22
2
1fma D 222 fma
12 Which of the following statements is true for a damped system of oscillation ?
A The oscillating amplitude is maximum when forced frequency is almost the same as the natural
frequency
B The system does not oscillate at its natural frequency
C When resonance takes place, the system does not lose energy
D Damping causes the oscillating frequency to become gradually smaller
13 Which of the following correctly summarizes what happens when light waves of frequency f and
wavelength move from air to glass ?
f
A increases decreases
B remains the same remains the same
C remains the same decreases
D decreases remains the same
14 To recieve FM waves of frequency 100 MHz, the total length of a bipolar half-wave aerial most
suitable for use is
A 0.75 m B 1.00 m C 1.50 m D 2.25 m
15 The fact that light waves are transverse wave can be shown by
A diffraction
B polarization
C interference
D Doppler effect
E photoelectric effect
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16 A wire under increasing tension, undergoes extension as shown in the graph.
How much work is done on the wire to cause an extension of 9 mm ?
A 0.72 J B 0.43 J C 0.36 J D 0.29 J
17 A steel wire has an original length of l , cross-sectional area of A, and Young modulus of E. The
force constant can be expressed as
Al
AE B
E
Al C
Al
E D
AE
l
18 Equation W = p (V2 V1) represents the work done by a gas during
A free expansionB isothermal expansion
C adiabatic expansion
D expansion at constant pressure
19 Find the work done when 3 moles of an ideal gas is expanded from 4 dm3
to 6 dm3
at 400 K
A 8 kJ B -4kJ C 4kJ D 6kJ
20 The specific heat capacity at constant volume for an ideal gas is 2.4 x 102 J kg-1 K-1. The change in
the internal energy of 5.0 x 10-3
kg of the gas when the temperature of the gas is increase from 27o
C to327oC is
A 32 J B 49 J C 180 J D 360 J
0
20 -
40 -
60 -
20 -
80 -
Tension/ N
Extension / mm105
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21 A ln p (pressure) against ln V (volume) graph is sketched as shown.
What is the quantity represented by the gradient of the straight line ?
A - B
C Change in internal energy
D Change in heat energy
22 An ideal gas is expanded at constant pressure, then cooled at constant volume, and finally
compressed adiabatically until it is returned to its original state. Which graph shows the changes which
occur to the gas?
A B
C D
ln p
ln V0
P
V
V
P
P
V
V
P
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23 A composite rod consists of a rod P and a rod Q where P is a better thermal conductor. The ends Mand N are maintained at constant temperatures TM and TN respectively where TM > TN. If the composite
rod is well insulated, which of the following graphs shows the variation of temperature, along thecomposite rod?
A B
C D
24 Which of the following statements is true about electrically equipotentials surfaces?
A The charge density is uniform
B No work is done to move a charge along an equipotential surface
C The electric field at any point on the equipotentials surface is zero
D There is no electric potential difference between 2 nearby electrically equipotential surfaces.
P Q
M
T N
T NM
TN
TM
T NM
TN
TM
T NM
TN
TM
T NM
TN
TM
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11
C1
C2
+ -
+ -
Drift velocity
Potential difference
Drift velocity
Potential difference
Drift velocity
Potential difference
Drift velocity
Potential difference
A B
DC
25 Figure shows two capacitors are connected as shown. A capacitor 1C with a capacitance of F4 is
charged to C200 and another capacitor 2C with a capacitance of F3 is charged to .300 C The total
energy lost in the two capacitor are
A 0 B J3100.2 C J2108.1 D J2100.2
26 Which graph best represent the variation in the drift velocity of the electrons in a uniform copper
wire as the potential difference across the wire changed? (Assume temperature of the wire remains
constant)
27 The resistance of a piece of pure silicon decreases rapidly with increasing temperature because
A the charge carriers move rapidly
B the number of charge carriers increases
C the ratio of negative charge carriers to positive charge carriers increases
D the ratio of positive charge carriers to negative charge carriers increases
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28 Kirchhoffs two laws for electric circuits can be derived by using certain conservation laws. Onwhich conservation laws do Kirchhoffs law depend?
Kirchhoffs first law Kirchhoffs second law
A charge current
B charge energy
C current mass
D energy current
29 The diagram below shows a model of an atom in which two electrons move around a nucleus in a
circular orbit. The electrons complete one full orbit in s15100.1
.
What is the current caused by the motion of the electrons in the orbit?
A A34
106.1
B A34
102.3
C A4
106.1
D A4
102.3
30 An electron moving with uniform velocity enters a magnetic field which is perpendicular to its
direction. The electron will then move
A in a straight line as before
B in a straight line parallel to the magnetic field
C in a circle at a plane normal to the magnetic field
D in a parabola at a plane normal to the magnetic field
31 Three straight conductors X, Y and Z are carrying currents of the same magnitude as shown. Which
of the following represents the resultants force acting on the conductor X?
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13
reactance
frequency
P
Q
32 The e.m.f induced in a coil of wire, which is rotating in a magnetic field, does not depend on
A the area of the coil
B the resistance of the coil
C the angular speed of rotation
D the number of turns on the coil
33 When the speed of an electric motor is increased due to a decreasing load, the current flowing
through it decreases. Which of the following is the best explanation of this?
A The induced back e.m.f increases
B The resistance of the coil changes
C Frictional forces increased as the speed increases
D At high speeds it is more difficult to feed current into the motor
34 Graph shows the variation of reactance and frequency of an alternating current flowing through two
electrical components P and Q. What are the components P and Q ?
Component P Component Q
A capacitor resistor
B inductor resistor
C inductor capacitor
D resistor capacitor
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14
iV
time
0V
time
0V
time
A
0V
time
0V
time
B
C D
35 Figure shows an op-amp acting as an integrator with negative feedback. Choose 0V for the shown
iV .
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15
36 Which of the following is true about the difference between an electromagnetic wave and amechanical wave?
Electromagnetic wave Mechanical wave
A Cannot produce stationary waves Can produce stationary waves
B Longitudinal waves only Longitudinal or transverse waves
C Cannot propagate in vacuum Propagates in vacuumD Travel with a speed almost the same Travel with a speed less than that
or the same as speed of light of light
37 An object is placed 5 cm from a convex mirror with a radius of curvature of 20 cm. The image
formed is
A 3.3 cm in front of the mirror and is diminished
B 3.3 cm behind the mirror and is enlarged
C 4 cm in front of the mirror and is diminished
D 4 cm behind the mirror and is enlarged
38 Two waves are said to be coherent if both the waves have
A the same phase
B the same amplitude
C the same frequency
D the same wavelength
39 In a Youngs double slit experiment, when the distance between the slits and screen is increased
A the fringe separation decreases the maximum intensity of bridge fringes decreasesB the fringe separation decreases the maximum intensity of bridge fringes increases
C the fringe separation increases the maximum intensity of bridge fringes decreases
D the fringe separation increases the maximum intensity of bridge fringes increases
40 Which of the following is true based on the photoelectric effect?
A The emission of electrons will not occur for very low light intensity.
B The number of electrons produced per second does not depend on the intensity of light.
C The maximum velocity of the electrons increases when the wavelength of light decreases.
D The average kinetic energy of the electrons decreases when the frequency of light increases.
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16
41 When light of wavelength 350 nm is incidented on a metal surface, photoelectrons with maximumkinetic energy 2.0 eV are emitted from the surface. What is the maximum wavelength of light that can
emit photoelectrons from the metal?
A 200 nm B 580 nm C 620 nm D 802 nm
42 What is the maximum possible number of emission spectral lines produced by an atom which has
five distinct energy levels only?
A 4 B 6 C 10 D 12
43 From Bohrs theory for hydrogen atom, the n-th energy level in eV is given by
...,3,2,1,6.13
2== n
nEn
What is the wavelength of a photon which is absorbed to excite an electron from ground state to the level
n = 4?
A 1.36 x 10-9 m
B 9.15 x 10-8
m
C 9.54 x 10-8
m
D 1.46 x 10-6
m
44 When the potential difference of an X-ray tube increases, the intensity of the K characteristic line
increases because
A more electrons cause the transition which produces the K characteristic line
B the frequency corresponding to the K characteristic line has increasedC the number of electrons escapes from the filament has increased
D anode temperature in the X-ray tube has increased
45 Which of the following is not true of the charge of an electron ?
A It is measured in Coulombs
B Its has the same magnitude as the charge of a proton
C It has the same magnitude as the charge of a beta particle
D It can only be determined by experiment when its mass is given
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17
46 In the mass spectrometer shown in the figure above, the ions which follow paths P1 and P2 always
have
A the same charge
B the same speed
C the same mass
D the same acceleration
47 The table below shows the count rate of a radioactive source at different times at a location.
Time(hours)Count rate (count per second )
With source Without source
10 60 20
20 30 20
30 20 20
Determine the half-life of the source based on the data given in the table.
A 5 hours B 10 hours
C 12 hours D 18 hours
48 At time t = 0 minute, 16 mg of a radioactive element X of half life 4.0 minutes is inserted into a
closed container. At time t = 8.0 minute, 8 mg of the radioactive element X is added into the container.What is the mass of the radioactive element X left in the container at time t = 12.0 minutes ?
A 2 mg B 3 mg
C 6 mg D 8 mg
49 The energy of the sun is acquired through
A the liberation of energy from unstable nuclei
B the liberation of helium nuclei to form hydrogen nuclei
C the fission of uranium nuclei by neutrons
D the fusion of hydrogen nuclei to form helium nuclei
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18
50 A strong nuclear force
A abides by the inverse square law
B is short range
C is repulsive if the charge of the particles are of the same type
D is an electrostatic force
END OF QUESTION PAPER.
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Name : NRIC :
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
Instructions to candidates :
This question paper consists of 15 printed pages
Answerallthe questions in Section A in thespaces provided.Answer any four questions from section B.
For this section, write your answers on theanswer s heets pr ovided. B egin eachanswer on a f resh sheet of paper. Answers
should be i llustrated by l arge, c learly
labeled diagrams wherever suitable.
Answers may be written in either Malay orEnglish.
Arrange y our ans wer i n num erical or der
and tie the answer sheets to this booklet.
For examiners use
Section Marks Marks
Obtained
A
1 5
2 5
3 54 5
5 5
6 5
7 5
8 5
B
9 15
10 15
11 15
12 15
13 15
14 15
TOTAL 100
TRIAL
2009
JABATAN PELAJARAN
NEGERI TERENGGANU
960/2
PHYSICS
PAPER 2
2 hours
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2
Physics 960
Constants value
speed of light in vacuumpermeability of vacuum
permittivity of vacuum
magnitude of electron charge
Planck constant
atomic mass unit constant
electron rest mass
proton rest mass
molar gas constant
Avogadro constant
Boltzmann constant
gravitational constant
free fall acceleration
co
o
e
h
u
me
mp
R
L, NA
k
G
g
==
=
=
=
=
=
=
=
=
=
=
=
=
3.00 x 10
8
m s
-1
4 x 10-7 H m-1
8.85 x 10-12 F m-1
[1/(36 )] x 10-9 F m-1
1.60 x 10-19 C
6.63 x 10-34 J s
1.66 x 10-27 kg
9.11 x 10-31 kg
1.67 x 10-27
kg
8.31 J K-1 mol-1
6.02 x 1023
mol-1
1.38 x 10-23 J K-1
6.67 x 10-11
N m2
kg-2
9.81 m s-2
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3
1. A water wheel has eight bucket equally spaced around its circumference as shown in diagrambelow.
045
1.8 m
The wheel makes six revolution per minute. Calculate
(a) the total change in potential energy of the water in the buckets in one revolution of the wheel.
[2]
(b) the average input power to the wheel
[2]
(c) Suggest why a larger number of small bucket is preferred to a smaller number of large bucketcontaining the same total mass of water
[1]
Water
46
2
1
8
73
Water
Full bucketEm t bucket
Direction of rotation
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4
2. The figure below illustrates a mass which can be made to vibrate vertically between two springs.
The vibrator itself has constant amplitude. As the frequency is varied, the amplitude of vibration of
the mass is seen to change as shown in Fig 3A
Fig 3A
(a) Name the phenomenon which is illustrated in Fig 3A.
[1](b) For the mass vibrating at maximum amplitude, calculate the angular frequency.
[2]
(c) A light piece of card is fixed to the mass with its plane horizontal. On Fig 3A, draw a curve toshow the new variation with frequency of the amplitude of vibration of the mass.
[1](d) State one situation in which the phenomenon illustrated in Fig 3A is used to advantage.
[1]
variable frequency
vibrator
mass
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5
3 A uniform copper rod with thermal conductivity 380 W m-1 K-1 which is perfectly insulated has a
cross-sectional area of 2.50 cm2 and length 20.0 cm. Heat is conducted by the copper rod. When the
steady state is achieved, the temperatures at the ends of the rod are 130 oC and 20 oC.
Calculate
(a) the rate of heat flow in the rod.
[3]
(b) the temperature 15.0 cm from the hot end.
[2]
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6
4 (a) Electrical conduction in a metal can be explained in terms of motion of free electrons. State the
estimated values at room temperature for mean random velocity of the free electrons.
[1]
(b) A 5.0 A current flows through a wire of length 1.50 m and crass sectional area of 1.2 mm2
where the potential difference across the wire is 0.24 V.
(i) Calculate the power dissipated from the wire
[2]
(ii) Explain what will happen to the drift velocity of the free electrons if the power produced in
the wire is increased.
[2]
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7
V2
V1
330 k
33 k
10 k
+15 V
-15 V
V0
+
5.
(a) State the name of the amplifier circuit which is connected to various input as shown in the
diagram above.
[1]
(b) Calculate the output voltage V0 if V1 is 0.50 V and V2 is 0.20 V.
[3]
(c) What happen to the output voltage if the supply 15 is replaced with V9 ?.
[1]
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9
7 Monochromatic light with wavelength 365 nm illuminates a metallic surface with work function 2.30
eV.
(a) Calculate the maximum speed of the photoelectrons emitted.
[3]
(b) Estimate the de Broglie wavelength of the photoelectrons.
[2]
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10
8
The graph above represents the decay of a sample of a specific radioactive element. Find the half-life
of the element.
Hint :
[5]
t
t
eNrateCount
eNN
=
=
0
0
dt
dN
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11
Section B [60 marks]
Answer any four questions in this section
9 (a) Define the terms moment of a force and draw a sketch to illustrate the meaning. [2]
(b) State the condition for a body to be in equilibrium [1]
(c) During the construction of many modern bridges, section are added from both banks until thetwo halves meet at the centre. Figure 1 below shows a new section S, of weight N5100.3 ,after it has been attached to an existing part B of a bridge
The support cable which keeps section S in equilibrium is at an angle of0
25 to the horizontal.
The existing part B of the bridge provides a horizontal force on S.
(i) Draw a labeled vector diagram and show the three forces on S [2]
(ii) Use your diagram to determine the tension in the cable and the horizontal force which B
exerts on S [2]
(d) In the sport of clay pigeon shooting, a clay disc is launched into the air by a spring, and thecontestant fires a shot at the moving disc. A launching device has been modified to project the
disc vertically upwards. The spring in the launching device has a spring constant of1
2000Nm
and the clay disc has mass 80g. In use the spring obeys Hookes law and the extension decreases
from 13 cm to 7.0 cm.
(i) Sketch a graph of force against extension for the spring and shade the area which represent
the loss of energy stored by the spring when launching the clay disc. [2]
(ii) Calculate
(a) the loss of elastic potential energy of the spring [2](b) the initial speed of the clay disc, assuming all the energy lost by the spring becomes
kinetic energy of the disc [2]
(c) the height to which the disc will rise, assuming that air resistance is negligible. [2]
S B
Support cable
N5100.3
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12
10 (a) State three differences between a progressive wave and a stationary wave. [3]
(b) In large auditoriums, the walls are covered with thick curtains. State the effect of thick curtains
on the sound waves and hence explain the advantage of this practice. [2]
(c) Two sound waves have frequencies 890 Hz and 894 Hz respectively. The intensity of the sound
waves at a given point is 6.3 x 10-9 W m-2.
(i) What are the conditions required for beats to be heard from two separate sound
sources? [2]
(ii) What is the frequency of the resultant wave and what is the beat frequency? [2]
(iii) Determine the maximum intensity level of the beats heard at the point concerned.
[The minimum intensity of audible sound is 1.0 x 10-12
W m-2
] [2]
(iv) Another sound sources with intensity level 98.0 dB is located at the point. What is the ratio
of the intensity of the first sound to that of the second sound? [2]
(d) A high-speed train is travelling at a speed of 47.4 m s-1
when the engineer sounds the 418 Hz
warning horn. The speed of the sound is 343 m s-1
. What is the frequency of the sound as
perceived by a person standing at a crossing when the train is approaching? [2]
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13
11 (a) StateHookes Law [2]
(b) Explain the main difference between elastic deformation andplastic deformation [3]
(c) The graph shows a simplified version of the variation of the load applied against
the extension of the material. The original length of the wire is 1.0 m and itsdiameter is 1.5 mm.
(i) The material is brittle or ductile ? [1]
(ii) What is the Youngs Modulus of the material ? [3]
(iii) If the wire snaps when the load reaches the value atP, how much energy is
required to snap the wire ? [3]
(iv) Assume that the cross-section of the wire remains constant throughout the
extension. What is the stress in the wire when the load reaches the value at P?
[3]
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1
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN ERENGGANUJABATANPELAJARAN TERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR
JABATAN PELAJARAN ERENGGANUJABATANPELAJARAN TERENGGANU JABATANPELAJAR
MARK SCHEME
PAPER 1 AND 2
PHYSICS
960
JABATAN PELAJARAN
TERENGGANU
960/1/2 TRIAL
2009
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2
ANSWER PAPER 1
Question Answer Explanation
1 AStrain=
0/le is dimensionless
[stress] = F/A= [pressure]
2 B
During the time from 0 to T, the body slides along the horizontal surface with
zero resultant vertical force since its weight is balanced by the reaction force
from the surface. After time T, the resultant force acting on the ball is its own
weight W under free fall situation.
3 B
m
F
mm
Fa
32=
+=
To block X alone, )3
)(2(m
FmmaFF Y ==
Hence, YF = force exerted by block Y on block X= 3
2F
4 B
Kinetic energy of sphere =2
2
1mv = constant since v is constant.
Potential energy of sphere = mgvdt
dxmg =
v x
5 Br
vw = is constant because v and r are constant. Hence angular acceleration = 0
6 C
The force constant of the elastic string is140
Nm . Hence, the force exerted bythe string on the mass to keep it in circular motion is
NkxF 8)50.070.0(40 === If v is the linear velocity of the mass, it is related to this centripetal force by
r
vmF
2
=
7.0)05.0(8
2v
= 1
1158.10
== msv
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3
7 C
T
F
W
If T is the tension in the light thread, then
FT =sin
WT =cos W
F=tan
8 A
22
2
1
2
1Imvmgh += rwv =
2
22
+= rvImvmgh
=21 v
rm
+
2
2
4
05.0
100.62.0)2.0)(10)(2.0(2 v
+=
135.1
= msv
9 D
From
r
MmGUEP ==
PE is the gravitational potential energy of a body of mass m at distance rfrom
the centre of a planet of mass M
Force of attraction =2r
MmG
dr
dU+=
Thus, the gradient at any point on the gravitational potential energy curve
represent the force pulling the body towards the planet.
10 C
22
1
RW
R
GMmW =
Gravitational force on the satellite when at the highest R/50
50
RR + from the centre of the earth = W
RR
R2
2
50
+
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4
= W
R
R2
2
2
50
11
+
= 0.96 W
11 A 2222222 2)2(2
1
2
1fmafmamaE ===
12 D
13 C
The frequencyis determined by the source and not the medium through which it
flows. In a denser medium, the velocity will decrease and as a result the
wavelength will decrease.
14 CV = f
(100 x 106) = 3 x 108
= 3 m
l= / 2 = 2/3= 1.5 m
15 B
16 B
Work = area under the graph
=310)]59)(8060(
2
1)560(
2
1[ ++
= [(150) + (704) x310 ]
= 430 x310
= 0.43 J
17 A
k =e
F
E = eA
Fl
k =l
EA
18 D
19 C =2
1
V
VW Vp
l
Dipole aerial
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5
= 2
1
V
VV
V
nRT )( nRTpV =
= nRT1
2lnV
V
=4
6ln)400)(31.8(3 = 4043.30 J = 4kJ
20 D
Since V = 0,W = p V = 0,
Q = U + W
U = Q = mcvV= 5.0 x 10-3 x 2.4 x 102 x (600 300) J
= 360 J
21 A
pV = k
p = kV
ln p = ln k ln V
= - lnV + ln k
(gradient = - )
22 C
23 A
24 BVqw =
since 00 == wV
25 B
Initial energy
( ) ( )J
CQ
CQ
02.0103
10300
104
10200
2
1
21
21
6
26
6
26
2
2
2
1
2
1
=
+
=
+
Equivalent capacitance
( ) ( ) FCCC
666
21
107103104 =+=
+=
Final energy
JC
Q018.0
107
10500
2
1
2
16
62
=
=
Energy lost,
J3100.2018.002.0 =
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6
26 B
The resistance of a copper wire remains unchanged at constant temperature and
is given byA
lR =
Potential difference, V
( ) venvAeAl
IRV ln =
==
Since I is directly proportional to drift velocity of electrons in the wire, thus
directly proportional to potential difference.
27 AWhen temperature increases, electrons are freed from covalent bonds. Hence the
number of electron-holes increases.
28 B
Kirchhoffs first law is related to current and depends on the conservation of
charge
Kirchhoffs second law is related to electric potentials and depends on the
conservation of energy.
29 D( )( )
A
t
QI
ItQ
4
15
19
102.3
100.1
106.12
=
==
=
30 C
31 A
32 B
Induced e.m.f is given by BAN= where
N number of turns
A area
B flux density
angular velocity
33 A
34 BP is inductor, wLXL =
Q is resistor
35 A
36D
37B r = 20cm, f = -10 cm, u = +5 cm
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7
cmv
v
vuf
3.3
5
1
10
11
111
=
=
+=
38 A
39C From the formula of fringe separation
a
Dy
= , Dy
40
C
From Einsteins equation,
cf
WhfmvK
=
== 2maxmax2
1
Iffincreases or decreases,Kmax or vmax increases
41
D
mf
c
h
Kcf
hfKhf
oo
o
o
7
15
34
19
9
8max
max
1002.8
10374.01063.6
106.10.2
10350
100.3
==
=
==
+=
42
C
43
D
mE
hc
hcE
JEEE
6
19
834
1919
2214
1046.11036.1
100.31063.6
1036.1)106.1(1
1
4
1)6.13(
=
==
=
=
==
44
A
The K characteristic line is produced by electronic transition in the target atom.
The intensity is determined by the number of electrons hitting the target and the
number of collisions determines the number of electronic transition.
45 D The charge of an electron can still be determined if its mass is not given
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8
46 BM.massandqcharge
ondependnotdoesitbecauseconstantB
Ev,
1
1
alwaysspeed
qEqvB
=
=
47 B
hours
e
eNN t
100693.0
2ln2lnlifehalf
0693.0
204ln
4010)1030(
0
===
=
=
=
=
48 C
0 min 4.0 min 8.0 min 12.0 min
16 mg 8 mg 4 mg+ 8 mg6 mg
49 DNuclear fission :
nHeHH 103
2
2
1
2
1 ++
50 BA strong nuclear force is experienced by nucleons such as protons and neutrons
in the nucleus and are of very short range such as 1.7 x 10-15
m
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9
Paper 2
Question Answer Mark
Structure 1
(a)
Total change in potential energy of water in the buckets in one revolution of the wheel
= hmg8 = )26.1(81.9408
= J4100.1
1
1
(b)
Average input power to wheel = number of revolutions made per unit time X change inpotential energy of the water in the buckets per revolution of the wheel
=4
100.160
6
= W3100.1
=1kW
1
1
(c)A large number of a small buckets is preferred because the rotation of the wheel would
be smoother than the case would be when a smaller number of large buckets is used. 1
Structure 2
2(a) resonance 1
2(b) From graph, fresonance = 12.5Hz
= 2f= 2 (12.5)
=78.5 rads-1
1
1
2(c)
1
2(d) Microwave oven/
radio signal receiver1
Structure 3
(a) dx
dkA
dt
dQ =
1
1
mass
with card
mass without
card
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10
= (380)(2.5 x10-4)2
1020
)20130(
= 52.25 W
1
(b)
The temperature at 15.0 cm = ( )1020
20130)(1015
2
2
= 82.5 oC
The temperature 15.0 cm from the hot end = 130 oC 82.5 oC
= 47.5 oC
1
1
Structure 4
(a)velocity is a vector quantity. The velocities cancel out each other in any directions,
since the number of free electrons is very large. So mean random velocity is zero.1
(b-i)
Power,P
W
IVP
2.1
)0.5)(24.0(
=
==
1
1
(b-ii)Power,
22
IPRIP =
Since, nevI= , therefore 2vP
Hence, when power increases drift velocity increases.
1
1
Structure 5
(a) Adder operational amplifier 1
(b)
V
VR
RV
R
RV
f
i
f
60.11
2.010
3305.0
33
330
22
10
=
+
=
+
=
1+1
1
(c) Output voltage will become V9 only as saturation occurs. 1
Structure 6
(a)( )
=
21
111
1
rrn
f
where
f = focal length,
n = refractive index of the material of the lens,r1 = radius of curvature of the front surface receiving the incoming rays,
r2 = radius of curvature of the hind surface where the outgoing rays emerges.
[Rubric: Formula 1 mark; Defining symbols 1 mark]
1
1
(b)In water applying the formula
=
211
2 1111
rrn
n
f
mf
cmf
f
25.1
125
20
1
60
11
33.1
65.11
=
=
+
+
=
1(formula)
1(sign of
r)
1(answer)
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11
Structure 7
(a) Using Einsteins equation, maximum kinetic energy is
15
31
19
max
19
199
834
2max
1023.6
1011.9
)1077.1(2
1077.1
)106.1(30.210365
)1000.3)(1063.6(
2
1
=
=
=
=
=
sm
v
J
Whc
mv
1
1
1
(b)Momentum of the photoelectrons,
hmv =
m
mv
h
9
531
34
1017.1
)1023.6)(1011.9(
1063.6
=
=
=
1
1
Structure 8
8
min4.240.0284
2ln2lnTlifeHalf
0.0284
182810-3
5ln
e
e
12000
20000:
)........(12000).......(20000
dt
dN
21
28-
10-
)28(
0
)10(
0
0
0
===
=
=+=
=
==
=
=
ii
i
iieNieN
eNrateCount
eNN
t
t
11
1
1
1
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Essay
Essay 9
(a) The moment of a force, F is the force multiplied by the perpendicular distance, d from
the point about which the moment is being measured example the axis of rotation
d
F
1
1
(b) For a body to be in a equilibrium, there must be no resultant force and no resultanttorque
1
(c)(i)
S
F
BF 0
25
Weight of section S, W= N5100.3
All
correct2
or
Two
correct1
(c)(ii) Resolving forces vertically
=0
25sinSF W for equilibrium
NW
Fs5
0
5
01010.7
25sin
100.3
25sin=
==
Resolving forces horizontally,050
25cos1010.725cos == SB FF
= N51043.6
1
1
(d)(i)F/N
e/cm
7 13
Draw
graphcorrect
1
Area
shaded
1
(d)(ii)(a)Loss of elastic potential energy of the spring =
2
1
2
22
1
2
1kxkx
1
Axis of rotation
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= )07.013.0(20002
1 22
= 12 J
1
(d)(ii)(b) Kinetic energy of the disc = Energy lost by the spring
1221 2 =mv
080.0
212=v
Initial speed =1
3.17ms
1
1
(d)(iii)(c) Gain in gravitational potential energy of the disc = lose in kinetic energy
2
2
1mvmgh =
81.9080.0
12
=h
=15.3 m
1
1
Essay 10
(a)
Progressive wave Stationary wave
1. Wave profile moves
2. Adjacent particles of amedium vibrate in a different
phases
3. The amplitude in constant forall particles of the medium
- Wave profiles does not move
- Particles between two adjacentnodes of a medium vibrate in the
same phase
- Particles between two adjacentnodes vibrate with different
amplitudes
1
1
1
(b)Thick curtains will absorb the sound.This will reduce echo and interference of sound waves in the hall and hence the
audience will be able to hear a performance clearly.
1
1
c(i)
Conditions:
- the frequency of the two sound must be almost the same
- the amplitudes from the two sound sources must be the same or almost thesame
- waves from the two sound sources must be propagated in the same direction
1
1
or 1
c(ii)Frequency of beats = 894 890 = 2 Hz
Frequency of resultant wave = (894 + 890) 2 = 892 Hz1
1
c(iii)Intensity level = log10
10
0
I
I= 10 log10
12
9
100.1
103.6
= 38.0 dB
1
1
c(iv)
=
2
1
21 log10I
I 1
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14
=
2
1log100.980.38I
I
6log2
1 =
I
I
6
2
1 10=
I
I
1
d
=
=
4.47343
343418'
svv
vff
= 485 Hz
1
1
Essay 11
(a) Hookes Law : States that the extension is directly proportional to the stress
(force) applied in an object,if the elastic limit is not exceeded.
2
(b) Elastic Deformation Plastic Deformation
Wire can return to original shape &size when the stress has been
removed
Wire does not return to its originalshape and size when the stress has
been removed.
(Permanent deformation occurs)
3
(c) (i) Brittle
1
(ii) from graph : m10x1.0x -3= for N250F= ( )( )
( ) ( )Pa10x1.41
10x0.110x75.0
0.1250
Ax
FLE
11
323===
3
(iii) Energy = area under the curve
J26=
3
(iv) at P :( )
Pa10x1.9810x0.75
350
A
Fstress 8
23-===
3
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15
Essay 12
(a)
When charge, q is moving, there will be a current,Iwill produce. By using Fleming lefthand rule for charge, q moving in a uniform magnetic field, B a force, F will be exerted
on the charge, q.
B, I and F must perpendicular to each others. Thus q will move in a circular path.
An expression for the force,Fexerted on the charged particle is given by,).(sinBqvF=
where
F is the force exerted on the charge
B is the magnetic field
q for charge
v for velocity
angle between v and B
1
1
1
1
(b-i)
Centripetal force = Magnetic force
m
Bew
m
Berrwv
m
Berv
Bevr
mv
=
==
=
=2
1
1
(b-ii)
mBe
Tw == 2
The period,
s
meBe
m
BBe
mT
9
112
1078.1
1076.1
1
100.2
2
1222
=
=
=
==
1
1
(b-iii)
From equationBe
mT
2= , the period is independent of the velocity and thus independent
of the kinetic energy of the electron.
So the period is still same// equal to s91078.1
1
1
(c-i)
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16
2
(c-ii)
Electrostatic force = magnetic force
16
4
105.7
008.0
106
=
==
=
ms
B
Ev
BeveE
1
1
1
Essay 1313(a) - An electromagnetic radiation is given out when an electron makes a transition from
one state of higher energy level to another of lower energy level.
- The energy of a photon of the electromagnetic radiation is given by E = hf
1
1
13(b)(i) - The electron in the ground state gains energy that is exactly equal to the energy
difference between the initial energy level of the electron and the final energy level.
- Electron move up to the higher energy level than the ground state 1
1
13(b)(ii) Energy absorbed
eV
EE
8.12
)1
6.13(
4
6.1322
14
=
=
=
1
1
13(b)(iii) Photon energy
m
hcE
8
83419
1071.9
1000.31063.6)106.1(8.12
=
=
=
1
1
1
13(c)(i) Continuous X-rays:
- When an electron strikes a metal, it can lose any portion of its energy. This energy
loss of the incident electron is converted into energy of a X-ray photon. Hence, the
energies of X-ray photons are different. Since the wavelength of a photon is inversely
proportional to its energy, the wavelengths of the photons emitted are different.- If all the energy of the incident electron is lost as energy of a photon, X-ray photon
with the minimum wavelength is produced.
Line X-rays:
- The incident electrons may penetrate deep into the inner-most shell of the target
atoms, causing the electron from the inner K or L shells to be excited to higher energy
levels.
- When an electron from a higher energy level falls to fill up these vacancies, the
1
1
1
FE
FB
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17
difference in energy is emitted as energy of line X-rays
1
13c(ii) When all the energy of the incident electron is converted into energy of an X-ray
photon,
m
hceV
10min
min
834319
min
1049.2
)1000.3()1063.6()100.5()106.1(
=
=
=
1
1
Essay 14
14 a
(i)
(ii)
(iii)
Nuclides which have the same number of proton but different number of neutrons
The disintegration of a heavy nucleus to lighter nuclei with the release of a lot of
energy
The combination of lighter nuclei at very a high temperature to produce a heavy
nucleus with release a lot of energy
1
1
1
14b
(i)
(ii)
Mass number, AAtomic number , Z
Mass- energy
HCHeB 1113
6
4
2
10
5 ++
HeLi 427
3
1
1 2H +
HeLinB 427
3
1
0
10
5 ++
1
1
1
1
1
1
14c
(i)
(ii)
Energy released E
J
mcE
13-
827-
2
107.44103.00101.6627.97693]-[27.98191
=
=
=
The energy of -ray photon ,
hcE=
hcE=
1
1
1
1
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