solutions - rensselaer polytechnic instituteengr-2300 quiz 2 fall 2019 vout vin ui ou rc 3....
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SOLUTIONS
VA VB
Vin = VA - VB ( after removing load resistor)Va = Vin (p?¥) = 4 V
vis = Vin (¥⇒ = 2V
Vin = VA - VB =⑦
To find Rta ,switch Vin off ⇒ Vin = 0
( Replace by shfrrtu.at)
F÷÷÷i÷=t¥÷÷Rin = RAB -
- (Rill Rz)t( 13311124)= 2k⑦
2Kr
2V Ifk}RI due I Rhoad = 62¥
g=
bad = 7%71%7 Va#
R,t R2iRLoadRz -1 Road
= 8.83 mV <<75mV
④
VB -- FITR VA Thad ( voltage follower)"
YA,
damn:""
tf! %Ymv hoax amplitude -- 8-8mV
Diaper.
but = 1¥ ( vz - Y ) = 7¥ ( vz - V , )
Vz = [5 - C -5)) RI - 5 = OV
Rit R2
650mV = 10¥ ( o - Vi )Vi = - 65mV = [5 - C - 5)] R4_ - 5
Rz -1124
⇒ V,= to RI - SV = - 65mV
Rz -1124
⇒ p,!÷ = 0.4935 ⇒ 123=513526
Multiple options① 1352 resistor in series with 124
.
OR
② 1352 resistor in series with RI.
OR
③ 19.73 Kr resistor in parallel with 123.
As the beam bends,one
of the strain gauges increases
in resistance while the
Other decreases at the
same rate .
i÷÷÷÷r÷
Va Vb
Zero current throughammeter ⇒ Va = Vb
Va -- 9 (2*23) = 9 (') = 6 V
Vb = 9 (i) = ?s!÷q = GV
⇒ 9 Rq = 9 K t 6124 ⇒ Rq=3l
O
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