organic chemistry: carbonyl compounds and nitrogen compounds

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Organic Chemistry: Carbonyl Compounds and Nitrogen Compounds Discussing nucleophilic addition on carbonyl discussion and reactions on carboxylic acid and its derivates. Also a brief description about amino acids and protein structures

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Organic Chemistry III

Carbonyl compounds and

Nitrogen Compounds

Indra Yudhipratama

Outline Carbonyl Compounds

(Aldehydes and Ketones) Reduction-oxidation

reactions Addition reaction Identification Reaction

Carboxylic Acid and Derivatives The Acidity of Carboxylic

acid The Formation Reaction to form salts, esters,

and acyl chloride Nitrogen Compounds

The basicity of amines Amino acids and Proteins

Aldehydes and Ketones The Formation and the redox of Aldehydes and Ketones

R

R

O

R

O

H

N a B H 4

N a B H 4

C r 2 O 72 -

H +

C r 2 O 72 -

H +

C r 2 O 72 -

H +

C r 2 O 72 -

H +

CH3

O

OH

butanoic acid

No Reaction

CH3 OH CH3 O

CH3

CH3

OH

CH3

CH3

O

Aldehydes and Ketones The Nucleophilic Addition

Nucleophile is a chemical that can donate a pair of electron with the subsequent formation of a covalent bond

Nucloephilic Addition is addition reaction in which the first step is the attack by a nucleophile on the electron-deficient part of molecule

R

O

R

Aldehydes and Ketones E.g. Reaction between NaCN in water with butanal

via:

Draw the product of this reaction:

H

ONaCN, HCN

H

NC OH

cyanohydrin

H

O

CN

H

O CN H CN

H

HO CN

O

NaCN, HCN

NH

NO2

NO2

R

O

R'

H2N

NH

NO2

NO2

N

R

R'

Aldehydes and Ketones Reaction with 2,4-DNPH (2,4-dinitrophenylhydrazine) – Identification.

Gives the yellow precipitate of hydrazone. To identify the carbonyl groups

2,4-DNPH Hydrazone

Aldehydes and Ketones

Another identification test Fehling’s Reagent (an alkaline solution of Cu2+ ions

complex) Aldehydes: Red precipitate and carboxylic acid forms. Ketones: No changing

Tollen’s Reagent (an aqueous solution of AgNO3 in excess ammonia) Aldehydes: Silver mirror and carboxylic acid forms. Ketones: No changing

Aldehydes and Ketones

Another identification test Acidified Cr2O7

2-

Aldehydes: The solution turns green (Cr3+) Ketones: No changing (solution still yellow-orange)

An alkaline solution of iodine To identify CH3CO- FG

OI2

NaOH(aq)I3C

OI2

NaOH(aq)O

O

+ CHI3

Aldehydes and Ketones(Summary of Identification)

Type of Test Aldehydes Ketones

2,4-DNPH (+) yellow ppt. (+) yellow ppt.

Tollen’s Reagent (+) silver mirror (-) no changing

Fehling’s Reagent (+) red ppt. (-) no changing

Oxidation acidified Cr2O7

2-

(+) solution turns into green

(-) no changing

An aqueos alkaline of iodine to identify CH3CO – gives yellow ppt.

Carboxylic Acids Main features: Behaves as an acid and has the highest b.p. along all

the functional group. The formation of Carboxylic acid

Oxidation of alcohol

R

OH

O

CH3

O

OH

butanoic acid

CH3 OH

CH3 O

C r 2 O 72 -

H +

C r 2 O 72 -

H +

Carboxylic acids

Hydrolysis cyanohidrin or nitriles

Via:Ph

NH

OH2 Ph

NH

H2O

Ph

OH

NH

H

- H++ H+

Ph

OH

NH2Ph

O

NH2

H

Ph

O

NH2H3O+

Ph

O

OH

Hydrolysis amide (see later)

Ph CN

H2O, H2SO4

Ph

OH

O

Carboxylic AcidsThe Acidity of Carboxylic Acids Acidity How strong the acid is. The easiness to release H+ (proton) Measures as Ka or pKa [pKa = -log(Ka)]. Higher pKa, weaker the acid

FG substituted carboxylic acid e- withdrawing FG (e.g. Cl) stabilise the ion by inductive effects. More e- with drawing FG more stable the ion. Further the FG, decrease the acidity. e- donating FG un-stabilise the ion, so the acidity is decreasing.

CH3

OH

O

+ OH2 O+

H

H

H

+CH3

O

O

-

Carboxylic Acids

(pKa = 4.76) (pKa = 2.86) (pKa = 1.48) (pKa = 0.70)

(pKa = 4.81) (pKa = 2.85) (pKa = 4.05) (pKa = 4.50)

CH3

OH

O

OH

OCl

OH

OCl

Cl OH

OCl

Cl Cl

OH

O

CH3

Cl

OH

O

CH3

Cl

OH

O

ClOH

O

CH3

Carboxylic AcidsQuick Review:

Predict the order of acidity from the strongest to the weakest from those acids below. Give your reason.

(1) (2) (3) (4)

Ans:

(1) > (2) > (3) > (4)

F has the highest electronegativity, so it has the biggest inductive effect/the electrons more attracts toward FG. Thus, the resonance is more stabilised compare to the others.

OH

O

ClOH

O

FOH

O

BrOH

O

I

fluoroacetic acid chloroacetic acid bromoacetic acid iodoacetic acid

Carboxylic Acids The Reactions

Formation of Salts Reacts with an alkaline solution to give salts.

Reacts with alcohols to form esters

Reaction with SOCl2 or PCl3 or PCl5 to form acyl chlorides

R

OH

O

+ NaOH R

O-

O

+ OH2

Na+

R

O

OH

R' OH+H3O+

R

O

O

R'

R

O

OH R

O

Cl

SOCl2 or

PCl3 orPCl5

Carboxylic Acid Derivatives Ester Formation under acidic condition

Via:

Esters can also be synthesised by reacting acyl chlorides with alcohol. Why can’t we make esters under alkaline condition?

O

OH

Et OH+H3O+ O

O

Et

O

OH

Et OH

OH2H

O

OH

H

O

O OH

Et

H

OH2H

O

O HO

Et

H

H

O

O HO

Et

H

HO

O

Et

H H2O

O

O

Et

Carboxylic Acid Derivates Quick Quiz

Predict the results of the reaction below. All reactions are in acidic condition.

H OH

On-BuOH

H3O+

OH

O

OH

MeOH

H3O+

H O

O

O

O

OH

Carboxylic Acid Derivates

Ester hydrolysis with acid catalyst

Via:

O

OH

Et OH+H3O+

O

O

Et

O

O

Et

H OH2 O

O

Et

H

H2O

O

HO OH

H

H2O

O

HO OH

EtEt

H OH2

O

OH

Et OH+

O

Et

HO OH

H

HH2O

O

OH

+ OH3

Carboxylic Acid Derivates

Ester hydrolysis in alkaline condition

Via:

This process is also called saponification (making soap)

O

O

Et OH+O

O

Et

NaOH(aq)

Na

O

O

Et

OH

O

O OH

EtO

O

HO Et

O

O

Et OH+

Carboxylic acid Derivates Mainly, Polyesters can be formed by reacting dicarboxylic acids and

diols

OH

OO

OH

OH

OH

+

benzene-1,4-dicarboxylic acid

ethane-1,2-diol PET

Carboxylic Acid Derivates Acyl Chloride

The hydrolysis would give carboxylic acids. Reacts readily with water

R

OH

O R

Cl

OS O C l2 o r P C l3 o r

P C l5

R

Cl

O H 2 OR

OH

O

O H -/H2 O

R

O-

O

Carboxylic Acid Derivates The reactions of acyl chloride

Reacts with alcohols to give esters Reacts with primary amines to give amides

Via:

O

Cl

HNMe2

O

N

O

Cl

HN

N

O Cl

HHN N

O Cl

N

O

+ Me2NCl

Carboxylic acid derivates

Reacts with phenol to give esters

Via:

O

Cl

PhOHO

OPhbase

O

Cl

OH

O

O

O

H

O Cl

BO

O Cl

OPh

PhOH

Nitrogen Compounds Main Features

Relatively high b.p. for organic compounds High solubility in water and polar solvent Act as basic compounds

NH3 NH2 RNH R

R1N R

R1

R2ammonia

NH3 NH2 CH3 NH CH3

CH3 N CH3

CH3

CH3ammonia methanamine N-methylmethanamine N,N-dimethylmethanamine

The Classification

1o 2o 3o

e.g.

Nitrogen Compounds The formations

Substitution reaction

Reduction of nitrile

CH3

Br

N H 3 CH3

NH2

CH3

N

L iA lH 4

D ry e th e r

CH3

NH2

Nitrogen Compounds The reactions

The formation of Amides from amines and acyl chlorides

Why amides can’t be formed from reaction of carboxylic acids and amines?

O

Cl

HNMe2

O

N

OH

O

+HN

N

O

Nitrogen Compounds The Hydrolysis in aqueous alkaline solution

Via:

Requires stronger (more extreme) condition than hydrolysis of ester

NH

Oconc. NaOH

O

O

Na+ H2N

NH

O

HN

OH

NH

O OH

O

O

HO

O

H2N

Nitrogen Compounds The Hydrolysis in aqueous acidic solution

Via:NH

Oconc. H2SO4

3 hrs, 100 oC OH

O

+ H3N

NH

O

H

NH

O

H

H2O

NH

HO OH

H

NH

HO OHH

HN

HO OH

H

OH

O

HO

OH

H2N H3N

H

Nitrogen Compounds The formation of Polyamides

It is formed from diacyl chlorides and diamines

Cl

OO

Cl

NH2NH2+

28-4 Proteins

Zwitterion

Copyright © 2011 Pearson Canada Inc.

General Chemistry: Chapter 28Slide 33 of 59

Peptides

The peptide-bond structures

The character of double bond at peptide bond create atoms C, N, H, O almost co-planar.

Protein 20 different amino acids

polymerise to build protein. Protein has unique sequence. The sequence of amino acids

that build the protein is called primary structure.

Different sequences, provide different function of protein

Primary structure of myoglobin

From Gene to Protein (Protein Synthesis in vivo)

The Genetic Code

Translasi

Secondary Structure

Stabilise by hydrogen bonding

Tertiary Structure

Two Main structure:

Fibrous and Globular

Linkages contributing to tertiary structure of proteins

FIGURE 28-15

The four levels of protein structureFIGURE 28-16

Copyright © 2011 Pearson Canada Inc.

General Chemistry: Chapter 28Slide 43 of 59

Another example of quaternary structure:

Nucleosome

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