iii. unit conversions - 1.cdn.edl.io · pdf filea. derived units! combination of base units.!...

J. Flesock

II. Unit Conversions

MEASUREMENT

A. SI Units

Quantity Base Unit Abbrev.

Length

Mass

Time

Temp

Amount

Symbol

A. SI Units

Quantity Base Unit Abbrev.

Length

Mass

Time

Temp

meter m

Amount

Symbol

l

A. SI Units

Quantity Base Unit Abbrev.

Length

Mass

Time

Temp

meter

kilogram

m

kg

Amount

Symbol

l

m

A. SI Units

Quantity Base Unit Abbrev.

Length

Mass

Time

Temp

meter

kilogram

second

m

kg

s

Amount

Symbol

l

m

t

A. SI Units

Quantity Base Unit Abbrev.

Length

Mass

Time

Temp

meter

kilogram

second

kelvin

m

kg

s

K

Amount

Symbol

l

m

tT

A. SI Units

Quantity Base Unit Abbrev.

Length

Mass

Time

Temp

meter

kilogram

second

kelvin

m

kg

s

K

Amount mole mol

Symbol

l

m

tTn

A. Derived Units

A. Derived Units

n Combination of base units.

A. Derived Units

n Combination of base units.

n Volume (m3 or cm3)

A. Derived Units

n Combination of base units.

n Volume (m3 or cm3) n length × length × length

1 cm3 = 1 mL1 dm3 = 1 L

A. Derived Units

n Combination of base units.

n Volume (m3 or cm3) n length × length × length

1 cm3 = 1 mL1 dm3 = 1 L

Ø Density (kg/m3 or g/cm3)

A. Derived Units

n Combination of base units.

n Volume (m3 or cm3) n length × length × length

D = MV

1 cm3 = 1 mL1 dm3 = 1 L

Ø Density (kg/m3 or g/cm3)wmass per volume

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A. SI Prefix Conversions

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A. SI Prefix Conversions

1. Find the difference between the exponents of the two prefixes.

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A. SI Prefix Conversions

1. Find the difference between the exponents of the two prefixes.

2. Move the decimal that many places.

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A. SI Prefix Conversions

1. Find the difference between the exponents of the two prefixes.

2. Move the decimal that many places.

To the leftor right?

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A. SI Prefix Conversions

532 m = _______ km

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=

A. SI Prefix Conversions

532 m = _______ km

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=

A. SI Prefix Conversions

NUMBERUNIT

532 m = _______ km

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=

A. SI Prefix Conversions

NUMBERUNIT UNIT

532 m = _______ km

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=

A. SI Prefix Conversions

NUMBERUNIT

NUMBER

UNIT

532 m = _______ km

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=

A. SI Prefix Conversions

NUMBERUNIT

NUMBER

UNIT

532 m = _______ km0.532

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A. SI Prefix Conversions

mega- M 106

deci- d 10-1

centi- c 10-2

milli- m 10-3

Prefix Symbol Factor

micro- µ 10-6

nano- n 10-9

pico- p 10-12

kilo- k 103

BASE UNIT --- 100

J. Flesock

A. SI Prefix Conversions

mega- M 106

deci- d 10-1

centi- c 10-2

milli- m 10-3

Prefix Symbol Factor

micro- µ 10-6

nano- n 10-9

pico- p 10-12

kilo- k 103

BASE UNIT --- 100

J. Flesock

A. SI Prefix Conversions

mega- M 106

deci- d 10-1

centi- c 10-2

milli- m 10-3

Prefix Symbol Factor

micro- µ 10-6

nano- n 10-9

pico- p 10-12

kilo- k 103

mov

e le

ft

BASE UNIT --- 100

J. Flesock

A. SI Prefix Conversions

mega- M 106

deci- d 10-1

centi- c 10-2

milli- m 10-3

Prefix Symbol Factor

micro- µ 10-6

nano- n 10-9

pico- p 10-12

kilo- k 103

mov

e le

ft

BASE UNIT --- 100

J. Flesock

A. SI Prefix Conversions

mega- M 106

deci- d 10-1

centi- c 10-2

milli- m 10-3

Prefix Symbol Factor

micro- µ 10-6

nano- n 10-9

pico- p 10-12

kilo- k 103

mov

e le

ft

mov

e rig

ht

BASE UNIT --- 100

J. Flesock

A. SI Prefix Conversions

1) 20 cm = ______________ m

2) 0.032 L = ______________ mL

3) 45 µm = ______________ nm

4) 805 dm = ______________ km

J. Flesock

A. SI Prefix Conversions

1) 20 cm = ______________ m

2) 0.032 L = ______________ mL

3) 45 µm = ______________ nm

4) 805 dm = ______________ km

0.2

J. Flesock

A. SI Prefix Conversions

1) 20 cm = ______________ m

2) 0.032 L = ______________ mL

3) 45 µm = ______________ nm

4) 805 dm = ______________ km

0.2

32

J. Flesock

A. SI Prefix Conversions

1) 20 cm = ______________ m

2) 0.032 L = ______________ mL

3) 45 µm = ______________ nm

4) 805 dm = ______________ km

0.2

45,000

32

J. Flesock

A. SI Prefix Conversions

1) 20 cm = ______________ m

2) 0.032 L = ______________ mL

3) 45 µm = ______________ nm

4) 805 dm = ______________ km

0.2

0.0805

45,000

32

J. Flesock

B. Dimensional Analysis

n The “Factor-Label” Methodn Units, or “labels” are canceled, or “factored” out

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B. Dimensional Analysis

n The “Factor-Label” Methodn Units, or “labels” are canceled, or “factored” out

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B. Dimensional Analysis

n The “Factor-Label” Methodn Units, or “labels” are canceled, or “factored” out

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B. Dimensional Analysis

n The “Factor-Label” Methodn Units, or “labels” are canceled, or “factored” out

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B. Dimensional Analysis

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B. Dimensional Analysis

n Steps:1. Identify starting & ending units.

2. Line up conversion factors so units cancel.

3. Multiply all top numbers & divide by each bottom number.

4. Check units & answer.

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B. Dimensional Analysis

n Lining up conversion factors:

1 in = 2.54 cm

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B. Dimensional Analysis

n Lining up conversion factors:

1 in = 2.54 cm2.54 cm 2.54 cm

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B. Dimensional Analysis

n Lining up conversion factors:

1 in = 2.54 cm2.54 cm 2.54 cm

= 1

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B. Dimensional Analysis

n Lining up conversion factors:

1 in = 2.54 cm2.54 cm 2.54 cm

1 in = 2.54 cm

= 1

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B. Dimensional Analysis

n Lining up conversion factors:

1 in = 2.54 cm2.54 cm 2.54 cm

1 in = 2.54 cm 1 in 1 in

= 1

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B. Dimensional Analysis

n Lining up conversion factors:

1 in = 2.54 cm2.54 cm 2.54 cm

1 in = 2.54 cm 1 in 1 in

= 1

1 =

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B. Dimensional Analysis

n How many milliliters are in 1.00 quart of milk?

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B. Dimensional Analysis

n How many milliliters are in 1.00 quart of milk?

qt mL

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B. Dimensional Analysis

n How many milliliters are in 1.00 quart of milk?

1.00 qt

qt mL

×

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B. Dimensional Analysis

n How many milliliters are in 1.00 quart of milk?

1.00 qt 1 L1.057 qt

qt mL

×

J. Flesock

B. Dimensional Analysis

n How many milliliters are in 1.00 quart of milk?

1.00 qt 1 L1.057 qt

qt mL

×

J. Flesock

B. Dimensional Analysis

n How many milliliters are in 1.00 quart of milk?

1.00 qt 1 L1.057 qt

qt mL

1000 mL1 L

×

J. Flesock

B. Dimensional Analysis

n How many milliliters are in 1.00 quart of milk?

1.00 qt 1 L1.057 qt

qt mL

1000 mL1 L

×

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B. Dimensional Analysis

n How many milliliters are in 1.00 quart of milk?

1.00 qt 1 L1.057 qt

= 946 mL

qt mL

1000 mL1 L

×

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B. Dimensional Analysis

n You have 1.5 pounds of gold. Find its volume in cm3 if the density of gold is 19.3 g/cm3.

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B. Dimensional Analysis

n You have 1.5 pounds of gold. Find its volume in cm3 if the density of gold is 19.3 g/cm3.

lb cm3

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B. Dimensional Analysis

n You have 1.5 pounds of gold. Find its volume in cm3 if the density of gold is 19.3 g/cm3.

lb cm3

1.5 lb

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B. Dimensional Analysis

n You have 1.5 pounds of gold. Find its volume in cm3 if the density of gold is 19.3 g/cm3.

lb cm3

1.5 lb 1 kg2.2 lb

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B. Dimensional Analysis

n You have 1.5 pounds of gold. Find its volume in cm3 if the density of gold is 19.3 g/cm3.

lb cm3

1.5 lb 1 kg2.2 lb

J. Flesock

B. Dimensional Analysis

n You have 1.5 pounds of gold. Find its volume in cm3 if the density of gold is 19.3 g/cm3.

lb cm3

1.5 lb 1 kg2.2 lb

1000 g1 kg

J. Flesock

B. Dimensional Analysis

n You have 1.5 pounds of gold. Find its volume in cm3 if the density of gold is 19.3 g/cm3.

lb cm3

1.5 lb 1 kg2.2 lb

1000 g1 kg

J. Flesock

B. Dimensional Analysis

n You have 1.5 pounds of gold. Find its volume in cm3 if the density of gold is 19.3 g/cm3.

lb cm3

1.5 lb 1 kg2.2 lb

1000 g1 kg

1 cm3

19.3 g

J. Flesock

B. Dimensional Analysis

n You have 1.5 pounds of gold. Find its volume in cm3 if the density of gold is 19.3 g/cm3.

lb cm3

1.5 lb 1 kg2.2 lb

1000 g1 kg

1 cm3

19.3 g

J. Flesock

B. Dimensional Analysis

n You have 1.5 pounds of gold. Find its volume in cm3 if the density of gold is 19.3 g/cm3.

lb cm3

1.5 lb 1 kg2.2 lb

= 35 cm31000 g1 kg

1 cm3

19.3 g

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B. Dimensional Analysis

n How many liters of water would fill a container that measures 75.0 in3?

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B. Dimensional Analysis

n How many liters of water would fill a container that measures 75.0 in3?

in3 L

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B. Dimensional Analysis

n How many liters of water would fill a container that measures 75.0 in3?

75.0 in3

in3 L

J. Flesock

B. Dimensional Analysis

n How many liters of water would fill a container that measures 75.0 in3?

75.0 in3 (2.54 cm)3

(1 in)3

in3 L

J. Flesock

B. Dimensional Analysis

n How many liters of water would fill a container that measures 75.0 in3?

75.0 in3 (2.54 cm)3

(1 in)3

in3 L

J. Flesock

B. Dimensional Analysis

n How many liters of water would fill a container that measures 75.0 in3?

75.0 in3 (2.54 cm)3

(1 in)3

in3 L

1 L1000 cm3

J. Flesock

B. Dimensional Analysis

n How many liters of water would fill a container that measures 75.0 in3?

75.0 in3 (2.54 cm)3

(1 in)3

in3 L

1 L1000 cm3

J. Flesock

B. Dimensional Analysis

n How many liters of water would fill a container that measures 75.0 in3?

75.0 in3 (2.54 cm)3

(1 in)3 = 1.23 L

in3 L

1 L1000 cm3

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B. Dimensional Analysis

5) Your European hairdresser wants to cut your hair 8.0 cm shorter. How many inches will he be cutting off ?

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B. Dimensional Analysis

5) Your European hairdresser wants to cut your hair 8.0 cm shorter. How many inches will he be cutting off ?

cm in

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B. Dimensional Analysis

5) Your European hairdresser wants to cut your hair 8.0 cm shorter. How many inches will he be cutting off ?

8.0 cm

cm in

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B. Dimensional Analysis

5) Your European hairdresser wants to cut your hair 8.0 cm shorter. How many inches will he be cutting off ?

8.0 cm 1 in2.54 cm

cm in

J. Flesock

B. Dimensional Analysis

5) Your European hairdresser wants to cut your hair 8.0 cm shorter. How many inches will he be cutting off ?

8.0 cm 1 in2.54 cm

cm in

J. Flesock

B. Dimensional Analysis

5) Your European hairdresser wants to cut your hair 8.0 cm shorter. How many inches will he be cutting off ?

8.0 cm 1 in2.54 cm

= 3.2 in

cm in

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B. Dimensional Analysis

6) Taft football needs 550 cm for a 1st down. How many yards is this?

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B. Dimensional Analysis

6) Taft football needs 550 cm for a 1st down. How many yards is this?

cm yd

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B. Dimensional Analysis

6) Taft football needs 550 cm for a 1st down. How many yards is this?

550 cm

cm yd

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B. Dimensional Analysis

6) Taft football needs 550 cm for a 1st down. How many yards is this?

550 cm 1 in2.54 cm

cm yd

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B. Dimensional Analysis

6) Taft football needs 550 cm for a 1st down. How many yards is this?

550 cm 1 in2.54 cm

cm yd

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B. Dimensional Analysis

6) Taft football needs 550 cm for a 1st down. How many yards is this?

550 cm 1 in2.54 cm

cm yd

1 ft12 in

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B. Dimensional Analysis

6) Taft football needs 550 cm for a 1st down. How many yards is this?

550 cm 1 in2.54 cm

cm yd

1 ft12 in

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B. Dimensional Analysis

6) Taft football needs 550 cm for a 1st down. How many yards is this?

550 cm 1 in2.54 cm

cm yd

1 ft12 in

1 yd3 ft

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B. Dimensional Analysis

6) Taft football needs 550 cm for a 1st down. How many yards is this?

550 cm 1 in2.54 cm

cm yd

1 ft12 in

1 yd3 ft

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B. Dimensional Analysis

6) Taft football needs 550 cm for a 1st down. How many yards is this?

550 cm 1 in2.54 cm

= 6.0 yd

cm yd

1 ft12 in

1 yd3 ft

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B. Dimensional Analysis

7) A piece of wire is 1.3 m long. How many 1.5-cm pieces can be cut from this wire?

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B. Dimensional Analysis

7) A piece of wire is 1.3 m long. How many 1.5-cm pieces can be cut from this wire?

cm pieces

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B. Dimensional Analysis

7) A piece of wire is 1.3 m long. How many 1.5-cm pieces can be cut from this wire?

1.3 m

cm pieces

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B. Dimensional Analysis

7) A piece of wire is 1.3 m long. How many 1.5-cm pieces can be cut from this wire?

1.3 m 100 cm1 m

cm pieces

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B. Dimensional Analysis

7) A piece of wire is 1.3 m long. How many 1.5-cm pieces can be cut from this wire?

1.3 m 100 cm1 m

cm pieces

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B. Dimensional Analysis

7) A piece of wire is 1.3 m long. How many 1.5-cm pieces can be cut from this wire?

1.3 m 100 cm1 m

cm pieces

1 piece1.5 cm

J. Flesock

B. Dimensional Analysis

7) A piece of wire is 1.3 m long. How many 1.5-cm pieces can be cut from this wire?

1.3 m 100 cm1 m

cm pieces

1 piece1.5 cm

J. Flesock

B. Dimensional Analysis

7) A piece of wire is 1.3 m long. How many 1.5-cm pieces can be cut from this wire?

1.3 m 100 cm1 m

= 86 pieces

cm pieces

1 piece1.5 cm

C. Temperature

Used to measure the heat energy of a substance or reaction

n Celsius - 25°C

n Fahrenheit =

n Kelvin =

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