geometry ch. 5 test review. 5-1 midsegment solve for x x=10x=9 x=7
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Geometry Ch. 5 Test Review
5-1 MidsegmentSolve for x
X=10
X=9 X=7
5-2 Perpendicular Bisector / Angle BisectorSolve for x
X=5X=5/2
5-3 IncenterSolve for x.
Radii of c
ircle
congru
ent X= -1
5-3 Graph the points. Find Circumcenter. Find Orthocenter.
(0,0)(4,-3)
Perp bisectors
altitudes
5-3 & 5-4 Point of ConcurrencyName it!
Altitude
Median Perpendiculuar Bisector
5-3 Draw an angle bisector!
5-3-5-4 Point of ConcurrencyName it!
Angle Bisectors Form _________________Perpendicular Bisectors Form
_____________Medians Form __________________Altitudes Form _________________
incenter circumcente
rcentroidorthocenter
5-3-5-4 Point of ConcurrencyName the line!
5-4 Centroid
5 10
12 36
5-6 List the SIDES in order.Smallest to largest.
54
5-6 Determine the SHORTEST side?
67
47S
M
L
S
M L
Not EG
X
Look for next small
O DG
5-6 Write sides in order from smallest to largest
67
47S
M
L
S
M LXO
DG, ED, EG/ EG, FG, EF
5-6 Longest side of triangle?In triangle ABC,
m<A = 2x + 20, m<B = 4x – 30, m<C = x + 50.Solve for x. Find LONGEST side of triangle ABC.
2x + 20 + 4x – 30 + x + 50 = 180 7x + 40 = 180
7x = 140x = 20
Continuation… Longest side.. In triangle ABC,
m<A = 2x + 20, m<B = 4x – 30, m<C = x + 50.Solve for x. Find LONGEST side of triangle ABC.
m<A = 2(20)+20 = 60m<B = 4(20) – 30 = 50m<C = 20 + 50 = 70
A
C
B60
50
70
AB
5-6 Which lengths could be SIDES of a triangle?
2.5, 8.5, 5.5
6, 5, 11
5x, 8x, 12x
No, 2.5+5.5>8.5 No, 6+5>11
Yes, 5x+8x>12x
5-6 Triangle InequalityFind range of values.
If lengths of sides of a triangle are 2k+3
and 6k, then the third side must be greater than ________ and less than _________
Small side + small side > 3rd side
Small side + small side > 3rd side
2k+3 + 6k > x
8k+3 > x OR2k+3 + x > 6k
-2k -3 -2k -3 x > 4k-3 x < 8k+3
8k+34k-3
Greater thanLess than
5-7 Hinge Theorem & Converse of Hinge TheoremFill in with <, >, or =. By which theorem?
AEB > BDC
so
By Hinge Theorem
Big
Big
5-7 Hinge Theorem & Converse of Hinge TheoremFill in with <, >, or =. By which theorem?
AB<EDsoBy Converse of Hinge Theorem
Big
Big
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