bmayer@chabotcollege.edu mth15_lec-23_sec_5-2_integration_substitution.pptx 1 bruce mayer, pe chabot...
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BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 1
Bruce Mayer, PE Chabot College Mathematics
Bruce Mayer, PELicensed Electrical & Mechanical Engineer
BMayer@ChabotCollege.edu
Chabot Mathematics
§5.2 Integration
By Substitution
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 2
Bruce Mayer, PE Chabot College Mathematics
Review §
Any QUESTIONS About• §5.1 → AntiDerivatives
Any QUESTIONS About HomeWork• §5.1 → HW-22
5.1
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 3
Bruce Mayer, PE Chabot College Mathematics
§5.2 Learning Goals
Use the method of substitution to find indefinite integrals
Solve initial-value and boundary-value problems using substitution
Explore a price-adjustment model in economics
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 4
Bruce Mayer, PE Chabot College Mathematics
Recall: Fcn Integration Rules
1. Constant Rule: for any constant, k
2. Power Rule:for any n≠−1
3. Logarithmic Rule:for any x≠0
4. Exponential Rule:for any constant, k
Cxkdxk
Cn
xdxx
nn
1
1
Cxdxx
ln 1
Cek
dxe kxkx 1
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 5
Bruce Mayer, PE Chabot College Mathematics
Recall: Integration Algebra Rules
1. Constant Multiple Rule: For any constant, a
2. The Sum or Difference Rule:
• This often called the Term-by-Term Rule
dxxuudxxua
dxxvdxxudxxvxu
dxxqdxxpdxxqxp
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 6
Bruce Mayer, PE Chabot College Mathematics
Integration by Substitution
Sometimes it is MUCH EASIER to find an AntiDerivative by allowing a new variable, say u, to stand for an entire expression in the original variable, x
In the AntiDerivative expression ∫f(x)dx substitutions must be made:• Within the Integrand• For dx
Along Lines →
dxxgdu
xgdx
du
xGdx
du
dx
dxGu
Let
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 7
Bruce Mayer, PE Chabot College Mathematics
Investigate Substitution
Compute the family of AntiDerivatives given by
a. by expanding (multiplying out) and using rules of integration from Section 5.1
b. by writing the integrand in the form u2and guessing at an antiderivative.
dxx 13 2
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 8
Bruce Mayer, PE Chabot College Mathematics
Investigate Substitution
SOLUTION a: “Expand the BiNomial” by “FOIL”
Multiplication
SOLUTION b: Let: Sub u into Expression →
dxxxxdxxxdxx 1339 1313 13 22
C 33 169 23Rules Sum &Power
2 xxxdxxx
13 xu
dxu 2
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 9
Bruce Mayer, PE Chabot College Mathematics
Investigate Substitution
Examine the “substituted” expression to find the• Integrand stated in terms of u• Integrating factor (dx) stated in terms of x
The Integrand↔IntegratingFactor MisMatch does Not Permit the AntiDerivation to move forward.• Let’s persevere, with the understanding is
something missing by flagging that with a (well-placed) question mark.
dxudxu 22
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 10
Bruce Mayer, PE Chabot College Mathematics
Investigate Substitution
Continuing
)31?()399(? 123 Cxxx
123 31?&)399(? CCCxxx
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 11
Bruce Mayer, PE Chabot College Mathematics
Investigate Substitution
The integral in part (b) (which is speculative) agrees with the integral calculated in part (a) (using established techniques) when
By Correspondence observe that ?=⅓• This Begs the Question: is there some
systematic, a-priori, method to determine the value of the question-mark?
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 12
Bruce Mayer, PE Chabot College Mathematics
SubOut Integrating Factor, dx
Let the single value, u, represent an algebraic expression in x, say:
Then take thederivative of bothsides
Then Isolate dx
xGu
orxGudx
d
xGdx
du
dx
d
xgdx
du xg
dxxg
dx
du
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 13
Bruce Mayer, PE Chabot College Mathematics
SubOut Integrating Factor, dx
Then the Isolated dx:
Thus the SubStitution Components
Consider the previous example
Let: Then after subbing:
dxxg
du
dxxdG
du
xg
dudxxGu and
dxx 13 2
13 xxGu
dxu 2
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 14
Bruce Mayer, PE Chabot College Mathematics
SubOut Integrating Factor, dx
Now Use Derivation to Find dx in terms of du →
Multiply both sides by dx/3 to isolate dx
Now SubOut Integrating Factor, dx
Now can easily AntiDerivate (Integrate)
13 xdx
du
dx
d
dxdu
dx
dudx
dx
du
33
303
duudu
uduudxu 2
222
3
1
33
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 15
Bruce Mayer, PE Chabot College Mathematics
SubOut Integrating Factor, dx
Integrating
Recall: BackSub u=3x+1 into integration result
Expanding the BiNomial find
3
&93933
1
3
1 32 K
CCuKu
Ku
duu
13 xu
C
xC
uduudxx
9
13
33
3
1 13
3322
CxxxC
xxxC
x
9
133
9
192727
9
13 23233
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 16
Bruce Mayer, PE Chabot College Mathematics
SubOut Integrating Factor, dx
Then
The Same Result as Expanding First then Integrating Term-by-Term Using the Sum Rule
023232 33
9
13313 CxxxCxxxdxx
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 17
Bruce Mayer, PE Chabot College Mathematics
GamePlan: Integ by Substitution
1. Choose a (clever) substitution, u = u(x), that “simplifies” the Integrand, f(x)
2. Find the Integrating Factor, dx, in terms of x and du by:
duuhduxu
dxd
dxxudx
d
dx
duxuu
1
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 18
Bruce Mayer, PE Chabot College Mathematics
GamePlan: Integ by Substitution
3. After finding dx = r(h(u), du) Sub Out the Integrand and Integrating Factor to arrive at an equivalent Integral of the form:
4. Evaluate the transformed integral by finding the AntiDerivative H(u) for h(u)
5. BackSub u = u(x) into H(u) to eliminate u in favor of x to obtain the x-Result:
duuhdxxf
CxuHdxxf
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 19
Bruce Mayer, PE Chabot College Mathematics
Example: Substitution with e
Find SOLUTION: First, note that none of the rules from the
Previous lecture on §5.1 will immediately resolve this integral
Need to choose a substitution that yields a simpler integrand with which to work• Perhaps if the radicand were simpler, the
§5.1 rules might apply
dxeexZ xx 7
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 20
Bruce Mayer, PE Chabot College Mathematics
Example: Substitution with e
Try Letting: Take d/dx of Both Sides
Solving for dx: Now from u-Definition:
Thendx →
xxx eeedx
d
dx
duu
dx
d 017
dxdue
edx
du
e
dxx
xx
1
77 ueeu xx
duu
due
dxx 7
11
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 21
Bruce Mayer, PE Chabot College Mathematics
Example: Substitution with e
Now Sub Out in original AntiDerivative:
This process yields
This works out VERY Well
Now can BackSub for u(x)
7 ue x ue x 7 duu
dx7
1
duu
uudxeexZ xx 7
17 7
Ku
duuuRxZ
23
2321
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 22
Bruce Mayer, PE Chabot College Mathematics
Example: Substitution with e
Using u(x) = e−x+7:
Thus the Final Result:
• This Result can be verified by taking the derivative dZ/dx which should yield the original integrand
K
eK
uuRxZ
x
3
72
3
223
23
KedxeexZ xxx 23
73
2 7
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 23
Bruce Mayer, PE Chabot College Mathematics
Example: Sub Rational Expression
Find
SOLUTION: Try: Taking du/dx
find This produces
dx
xx
xxZ
122
243 2
3123 2 122122 xxxxu
dux
udu
uxdx
24
3
24
3 2
2
duudu
x
u
u
xxZ
324
324 2
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 24
Bruce Mayer, PE Chabot College Mathematics
Example: Sub Rational Expression
Solving
Thus the Answer
An Alternative u:
CxxCu
duuxZ 2312
2
1222
3
2
33
Cxxdxxx
xxZ
322
3 2122
2
3
122
24
24122 2 xdx
duxxu
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 25
Bruce Mayer, PE Chabot College Mathematics
Example: Sub Rational Expression
SubOut x using:
Find
Then
• The Same Result as before
24&122 2
x
dudxxxu
duudu
xu
xdx
xx
xxZ
31
33 2 24
124
122
24
Cxxuu
duuxZ 1222
3
2
3
32232
3231
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 26
Bruce Mayer, PE Chabot College Mathematics
Example DE Model for Annuities
Li Mei is a Government Worker who has an annuity referred to as a 403b. She deposits money continuously into the 403b at a rate of $40,000 per year, and it earns 2.6% annual interest.
Write a differential equation modeling the growth rate of the net worth of the annuity, solve it, and determine how much the annuity is worth at the end of 10 years.
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 27
Bruce Mayer, PE Chabot College Mathematics
Example DE Model for Annuities
SOLUTION: TRANSLATE: The 403b has two ways
in which it grows yearly: • The annual Deposit by Li Mei = $40k • The annual interest accrued = 0.026·A
– Where A is the current Amount in the 403b
Then the yearly Rate of Change for the Amount in the 403b account
k40$ $k/yrin 026.0 A
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 28
Bruce Mayer, PE Chabot College Mathematics
Example DE Model for Annuities
This DE is Variable Separable
Affecting the Separation and Integrating
Find the AntiDerivative by Substitution Let: Then:
dtdAA026.040
1
Au 026.040
dudAdA
du
026.0
1026.00
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 29
Bruce Mayer, PE Chabot College Mathematics
Example DE Model for Annuities
SubOut A in favor of u:
Integrating:1
1
026.0
1Ctdu
u
21026.0&026.0ln CCCCtu
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 30
Bruce Mayer, PE Chabot College Mathematics
Example DE Model for Annuities
Note that u = $40k + 0.026A is always positive, so the ABS-bars can be dispensed with
Now BackSub Solve for A(t) by
raising e to the power of both sidesFind the General(Includes C) solution:
CtAu 026.0026.040lnln
CtA ee 026.0026.040ln
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 31
Bruce Mayer, PE Chabot College Mathematics
Example DE Model for Annuities
Use the KNOWN data that at year-Zero there is NO money in the 403b; i.e.; (t0,A0) = (0,A(0)) = (0,0)
Sub (0,0) into the General Soln to find C
Or Thus the
particular soln
40ln40
026.0
400
0026.0
CCC
eee
689.340lnln CeC
026.0
40
026.0
40 689.3026.040ln026.0
tt eeA
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 32
Bruce Mayer, PE Chabot College Mathematics
Example DE Model for Annuities
Using the Log property Find
Factoring Out the 40
Then at 10 years the 403b Amount
vuvu aaa
026.0
4040
026.0
40
026.0
40 026.0026.040ln40ln026.0
ttt eeeeA
026.0
140
026.0
teA
k816.456$
026.0
2969.0k40$
026.0
140
10026.0
e
A
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 33
Bruce Mayer, PE Chabot College Mathematics
WhiteBoard Work
Problems From §5.2• P61 → Retirement Income vs. Outcome• P66 → Price Sensitivity to Supply &
Demand
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 34
Bruce Mayer, PE Chabot College Mathematics
All Done for Today
SubstitutionCity
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 35
Bruce Mayer, PE Chabot College Mathematics
Bruce Mayer, PELicensed Electrical & Mechanical Engineer
BMayer@ChabotCollege.edu
Chabot Mathematics
Appendix
–
srsrsr 22
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 36
Bruce Mayer, PE Chabot College Mathematics
ConCavity Sign Chart
a b c
−−−−−−++++++ −−−−−− ++++++
x
ConCavityForm
d2f/dx2 Sign
Critical (Break)Points Inflection NO
InflectionInflection
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 37
Bruce Mayer, PE Chabot College Mathematics
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 38
Bruce Mayer, PE Chabot College Mathematics
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 39
Bruce Mayer, PE Chabot College Mathematics
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 40
Bruce Mayer, PE Chabot College Mathematics
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 41
Bruce Mayer, PE Chabot College Mathematics
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 42
Bruce Mayer, PE Chabot College Mathematics
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 43
Bruce Mayer, PE Chabot College Mathematics
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 44
Bruce Mayer, PE Chabot College Mathematics
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 45
Bruce Mayer, PE Chabot College Mathematics
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 46
Bruce Mayer, PE Chabot College Mathematics
BMayer@ChabotCollege.edu • MTH15_Lec-23_sec_5-2_Integration_Substitution.pptx 47
Bruce Mayer, PE Chabot College Mathematics
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