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每日一句

伤害我们的并非事情本身,而是我们对事情的看法。

任何事情,不管看起来多么可怕,也不能阻止我们探

寻其中隐藏的机遇。但在各种情形中寻找机遇,这需要很

大的勇气,因为你周围的大多数人总是用最粗俗的词语去

解释事情:成功或失败,好或坏,对或错。这些简单化、

极端化的分类,遮蔽了哪些对事情更有创造性,也更有用

的解释,他们恰恰比那些粗俗的解释要有益和有趣得多。

Epictetus:《The meditations》中央编译出版社,北京,2015

Chapter 7 Electrochemistry

§7.9 Electrode potential and electromotive forces

7.9.4 pH-dependence of : Pourbaix diagram

For electrode reaction with H+ or OH- participating in, the

electrode potential will depend on pH.

O2 + 4H+ + 4e- 2H2O

= ⊖ + 0.05916 lgaH+

= 1.229 - 0.05916 pH

= ⊖ + 0.05916 lgaH+

= 0.000 - 0.05916 pH

2H+ + 2e- H2

pH-potential diagram/Pourbaix diagram

§7.9 Electrode potential and electromotive forces

Marcel Pourbaix, (1904–1998), a

Russian-born, Belgian chemist,

“Atlas of electrochemical equilibria

in aqueous solutions”, National

Association of Corrosion Engineers,

1974.

7.9.4 pH-dependence of : Pourbaix diagram

§7.9 Electrode potential and electromotive forces

By 1938, he had devised the potential-

pH diagrams for which he became

famous. In 1939, he presented to the

Faculty his doctoral dissertation,

accompanied by a thesis entitled

"Thermodynamics of Dilute Aqueous

Solutions. Graphical Representation of

the Role of pH and Potential."

Pourbaix (left) and Evans (right)

图形化方法(Graphic method, visualization)

7.9.4 pH-dependence of : Pourbaix diagram

§7.9 Electrode potential and electromotive forces

Construction of Pourbaix diagram

Cu2+Cu(OH)2

Cu

pH

/ V

2 4 6 8 10 12 140

CuO22

Cu2O

7.9.4 pH-dependence of : Pourbaix diagram

§7.9 Electrode potential and electromotive forces

(1) When we plate Cu,

why do we use acidic

copper sulfate solution?

(2) When we anodize

copper in neural solution,

what phenomenon can we

observed?

§7.10 Application of EMF and electrode potential

Levine

pp. 431--443

14.8 Concentration cell

14.9 Liquid-junction potential

14.10 Applications of EMF measurements

14.12 ion-selective membrane electrodes

7.10.1 Computation of emf

For cell with single solution:

Cd(s)|CdSO4(a±) |Hg2SO4(s)|Hg(l)

2 24SO Cd

2

ln ln

( ) ln

E

RT RTa a

nF nF

RTa

nF

Because a is a measurable quantity, E of the cell with

single electrolyte can be calculated exactly.

E

§7.10 Application of EMF and electrode potential

For cell with two electrolytic solutions:

Zn(s)|ZnSO4(m1) ||CuSO4(m1) |Cu(s)

2

2

Cu

Zn

lnaRT

E EnF a

1 ,1

2 ,2

lnmRT

E EnF m

we have to use mean activity coefficient () which is

measurable in stead of the activity coefficient of individual

ion (+ or -) which is unmeasurable.

7.10.1 Computation of emf

§7.10 Application of EMF and electrode potential

7.10.2. Judge the strength of the oxidizing and reducing agents

⊖ (Fe3+/Fe2+) = 0.771 V

⊖ (I2/I) = 0.5362 V

Oxidative form: Fe3+, I2

Reductive form: Fe2+, I-

The oxidative form with higher (standard) electrode

potential is stronger oxidizing species, while the reductive

form with lower (standard) electrode potential is stronger

reducing agent. Why? E > 0 criterion

§7.10 Application of EMF and electrode potential

(Ox)1 + (Red)2 = (Red)1+ (Ox)2

7.10.3 Determination of the reaction direction

When concentration differs far from the standard

concentration, should be used in stead of ⊖.

Stronger oxidizing species oxidizes stronger reducing species

to produce weaker reducing and weaker oxidizing species.

⊖ (Fe3+/Fe2+) = 0.771 V; ⊖ (I2/I) = 0.5362 V

Fe3+ + I = Fe2+ + 1/2I2

§7.10 Application of EMF and electrode potential

Application of Pourbaix diagram

Cu2+Cu(OH)2

Cu

pH

/ V

2 4 6 8 10 12 140

CuO22

Cu2O

0.0

0.5

1.0

1.5

7.10.3 Determination of the reaction direction

§7.10 Application of EMF and electrode potential

Corrosion with hydrogen

evolution

Corrosion with oxygen

absorption

+Au 1e Au =1.7 V

2 2O +2H O+4e 4OH =0.401

Example

In order to make Au in mine dissolve in alkaline solution

with the aid of oxygen, people usually add some coordinating

agent into the solution. Which coordination agent is favorable?

Please answer this question based on simple calculation.

7.10.3 Determination of the reaction direction

§7.10 Application of EMF and electrode potential

Divergent /Disproportionation reaction

Cl2 + 2NaCl = NaCl + NaClO + H2O

Divergent reaction occur when R > L

HIO IO3 + I2

R 2

L 3

(HIO/I ) 1.45V

(IO /HIO) 1.13V

-1+7 +5 +1 01.7 1.13 1.45 0.534- -

25 6 3H I O I O H I O I I

which species can undergo divergent reaction?

7.10.3 Determination of the reaction direction

§7.10 Application of EMF and electrode potential

Exercise

Can what species undergo divergent reaction?

7.10.3 Determination of the reaction direction

§7.10 Application of EMF and electrode potential

元素电势图(Latimer diagram)

7.10.4. Advance of reaction (equilibrium constants)

1 mol dm-3 iodine

solution + Fe2+ (2

mol dm-3)

32

2

22

3

I3 2 Fe2

I Fe

IFe

Fe I

(Fe / Fe ) (I / I ) ln ln

ln ln a

a aRT RT

nF a nF a

a aRT RTE K

nF a a nF

3

2

3 2 3 2 Fe

Fe

(Fe / Fe ) (Fe / Fe ) lnaRT

nF a

2I

2 2

I

(I / I ) (I / I ) lnaRT

nF a

3 2

2(Fe / Fe ) (I / I )

Fe3+ + I¯ Fe2+ + ½ I2

At equilibrium

§7.10 Application of EMF and electrode potential

Standard emf and standard equilibrium constant

lnr mG nFE RT K lnRT

E KnF

For any reaction that can be designed to take place in an

electrochemical cell, its equilibrium constant can be measured

electrochemically.

Four equilibria in solution

1) Dissolution equilibrium

2) Reaction equilibrium

3) Dissociation equilibrium

4) Coordination equilibrium

7.10.4. Advance of reaction (equilibrium constants)

§7.10 Application of EMF and electrode potential

Example

Determine the solubility products of AgCl(s).

AgCl(s) Ag+ + Cl¯

The designed cell is

Ag(s)|AgNO3(a1)||KCl(a2)|AgCl(s)|Ag(s)

lnRT

E KnF

7.10.4. Advance of reaction (equilibrium constants)

§7.10 Application of EMF and electrode potential

7.10.5 Potentiometric titrations

GEH+(mx)SCE

automatic potential titrator

§7.10 Application of EMF and electrode potential

7.10.6 Determination of mean ion activity coefficients

Pt(s), H2 (g, p⊖)|HCl(m)|AgCl(s)-Ag(s)

1/2 H2 (g, p⊖) + AgCl(s) = Ag(s) + H+(m) + Cl(m)

H Cl

2 2ln ln ln

RT RT RTE E a a E m

nF nF nF

For combined concentration cell

1,1

2,2ln

2

m

m

F

RTE

Using one electrolytic solution with known mean activity

coefficient, the mean activity coefficient of another unknown

solution can be determined.

§7.10 Application of EMF and electrode potential

Answer: = 0.9946

Example:

Pt(s), H2 (g, p) |HBr(m) | AgBr(s)-Ag(s)

Given E = 0.0714 V, m = 1.262 10-4 mol·kg-1, E = 0.5330 V,

calculate .

2lnRT

E E mF

7.10.6 Determination of mean ion activity coefficients

§7.10 Application of EMF and electrode potential

7.10.7 Determination of transference number

Zn|ZnSO4(a,1) |ZnSO4(a,2) |Zn

Zn(s)|ZnSO4(a,1)|Hg2SO4(s)-Hg(l)-Hg2SO4(s)|ZnSO4(a,2)|Zn(s)

2,

1,

2,

1,ln)12(ln)(

a

a

F

RTt

a

a

F

RTttE j

The relationship between transference number and liquid

junction potential can be made use of to determine the

transference number of ions.

Electromotive forces of cell with and without liquid junction

potential gives liquid junction potential.

§7.10 Application of EMF and electrode potential

7.10.8 Measurement of pH

1909, Sorensen defined: pH = log [H+]

present definition: H

H logp a Non-operational

definition

1) Hydrogen electrode

Pt(s), H2 (g, p⊖)|H +(x) |SCE

+ +2

SCE H /H H

SCE

lg

0.05916pH

RTE a

nF

poison of platinized platinum

The way to determine pH

§7.10 Application of EMF and electrode potential

2) Quinhydrone electrode

supramolecule

1:1 quinone: hydroquinone

1) Equal concentrations of both

species in the solution.

2) Being nonelectrolytes, activity

coefficients of dilute Q and

H2Q is unity.

Q + 2H + + 2e- H2Q

Pt(s)|Q, H2Q, H+(mx) |SCE

2

2

2

SCE Q/H Q

H Q

SCE Q/H Q 2

Q H

SCE

ln2

0.6995 0.05916pH

E

aRT

F a a

O

O H

H O

O

O

O

2e-2H+

OH

OH

+ +

7.10.8 Measurement of pH

§7.10 Application of EMF and electrode potential

3) Glass electrode

0.1 molkg-1 HCl 内充液 离子选择性膜

7.10.8 Measurement of pH

§7.10 Application of EMF and electrode potential

membrane potential

GE = ⊖ GE - 0.05915 pH

Linear relation of GE and pH exists

within pH range from 0 to 14.

GE H+(mx)(SCE)Test cell:

Ag(s) AgCl(s) HCl(as) GM H+(ax)(SCE)

Reference-1Reference-2

7.10.8 Measurement of pH

§7.10 Application of EMF and electrode potential

4) Operational definition of pH

s x( )pH(x) pH(s)

2.303

E E F

RT

Buffer A B C D E

pH 3.557 4.008 6.865 7.413 9.180

pH meter with standard buffer

solution

pH of standard buffer solutions at 25 oC

Es = ⊖SCE –(⊖GE - 0.05915 pHs )

Ex = ⊖SCE –(⊖GE - 0.05915 pHx )

Calibration

Measurement

7.10.8 Measurement of pH

§7.10 Application of EMF and electrode potential

What is the concentration of

hydrogen ion in this solution?

Composite electrode:

with reference electrode,

usually AgCl/Ag electrode

embedded on the side of glass

electrode.

7.10.8 Measurement of pH

§7.10 Application of EMF and electrode potential

7.10.9. Determination of ion concentration

Ion-selective electrode

Cutaway view of an ion

selective electrode

For F- electrode, thin film of LaF3 single

crystal is used as ion selective membrane.

For S2- electrode, compressed thin film of

AgCl-Ag2S mixture is used as ion-selective

membrane.

§7.10 Application of EMF and electrode potential

7.10.9. Determination of ion concentration

§7.10 Application of EMF and electrode potential

antigen antibody

electrochemical sensor

of potential type

7.10.10 Electrochemical sensor

electrochemical sensor of current type

Electrochemical nose

Electroanalytical chip

§7.10 Application of EMF and electrode potential

7.10.10 Electrochemical sensor

§7.10 Application of EMF and electrode potential

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