algebra ii 8 - andrews universityrwright/algebra2/powerpoints/08 rational... · (3(2x))/x –2x/2 =...
TRANSCRIPT
(-3x(9x2-1))/((3x+1)(x-1)) * ((3x-1)(x-1)) (-3x(3x-1)(3x+1)(3x-1)(x-1))/(3x(3x+1)(x-1)) -(3x-1)2
(x+2)/((3x+2)(9x2-6x+4)) * (9x2-6x+4)/1 (x+2)/(3x+2)
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4
3𝑥2+
𝑥
3𝑥2 2𝑥 + 1→
4 2𝑥 + 1
3𝑥2 2𝑥 + 1+
𝑥
3𝑥2 2𝑥 + 1→
9𝑥 + 4
3𝑥2 2𝑥 + 1
𝑥 + 1
𝑥 + 3 𝑥 + 3–
1
𝑥 + 3 𝑥 − 3→
𝑥 + 1 𝑥 − 3
𝑥 + 3 2 𝑥 − 3−
𝑥 + 3
𝑥 + 3 2 𝑥 − 3
→𝑥2 – 2𝑥 – 3
𝑥 + 3 2 𝑥 − 3–
𝑥 + 3
𝑥 + 3 2 𝑥 − 3→
𝑥2 − 3𝑥 − 6
𝑥 + 3 2 𝑥 − 3
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3𝑥 − 4
1𝑥 − 4 +
3𝑥 + 1
→
3𝑥 − 4
1 𝑥 + 1𝑥 − 4 𝑥 + 1
+3 𝑥 − 4
𝑥 − 4 𝑥 + 1
→
3𝑥 − 4
𝑥 + 1𝑥 − 4 𝑥 + 1
+3𝑥 − 12
𝑥 − 4 𝑥 + 1
→
3𝑥 − 44𝑥 − 11
𝑥 − 4 𝑥 + 1
→3
𝑥 − 4⋅𝑥 − 4 𝑥 + 1
4𝑥 − 11
→3 𝑥 + 1
4𝑥 − 11
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(3(2x))/x – 2x/2 = (12(2x))/x 6 – x = 24 -x = 18 x = -18
5x = 4(x+1) – 5 5x = 4x + 4 – 5 x = -1Check answer: can’t divide by -1 so NO SOLUTION
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(3x-2)/(x-2) = 6/((x-2)(x+2)) + 1 (3x-2)(x+2) = 6 + (x-2)(x+2) 3x2 + 4x – 4 = 6 + x2 –4 2x2 + 4x – 6 = 0 x2 + 2x – 3 = 0 (x – 1)(x + 3) = 0 x = 1, -3
3/(x(x+4)) = 1/(x+4) 3 = x
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