algebra 2 10.7 day 1 solve quadratic systems · 10/10/2019 · 2. solve using substitution. y = x...
TRANSCRIPT
![Page 1: Algebra 2 10.7 day 1 Solve Quadratic Systems · 10/10/2019 · 2. Solve using substitution. y = x + 1 4x + 5y = 23 3. Solve using elimination. 3x + 2y = 6 6x + 3y = 6 What if we](https://reader030.vdocuments.mx/reader030/viewer/2022040606/5eb61de1abb578730c63f08e/html5/thumbnails/1.jpg)
Algebra 210.7 day 1Solve Quadratic Systems
Learning Target:I can solve linear & quadratic systems of equations. [A.REI.7]
We've learned how to solve a linear system of equations using 3 methods:1. Graphing2. Substitution3. Elimination (Linear Combinations)
Let's Review:
1. Solve by graphing.y = x + 2y = -2x - 1
![Page 2: Algebra 2 10.7 day 1 Solve Quadratic Systems · 10/10/2019 · 2. Solve using substitution. y = x + 1 4x + 5y = 23 3. Solve using elimination. 3x + 2y = 6 6x + 3y = 6 What if we](https://reader030.vdocuments.mx/reader030/viewer/2022040606/5eb61de1abb578730c63f08e/html5/thumbnails/2.jpg)
2. Solve using substitution.y = x + 14x + 5y = 23
3. Solve using elimination.3x + 2y = 66x + 3y = 6
What if we want to solve a linear-quadratic system?
4. -3x2 + y2 = 9 y = 2x
![Page 3: Algebra 2 10.7 day 1 Solve Quadratic Systems · 10/10/2019 · 2. Solve using substitution. y = x + 1 4x + 5y = 23 3. Solve using elimination. 3x + 2y = 6 6x + 3y = 6 What if we](https://reader030.vdocuments.mx/reader030/viewer/2022040606/5eb61de1abb578730c63f08e/html5/thumbnails/3.jpg)
5. x2 + y2 = 10y = -3x + 10
6. y2 - 2x - 10 = 0x + y = -1
![Page 4: Algebra 2 10.7 day 1 Solve Quadratic Systems · 10/10/2019 · 2. Solve using substitution. y = x + 1 4x + 5y = 23 3. Solve using elimination. 3x + 2y = 6 6x + 3y = 6 What if we](https://reader030.vdocuments.mx/reader030/viewer/2022040606/5eb61de1abb578730c63f08e/html5/thumbnails/4.jpg)
7. y = -2x - 5y = x2 + 6x + 7
Exit Problem: Solve the system. x2 + y2 = 17 y = x + 3
Assignment: 10.7 day 1 Worksheet
![Page 5: Algebra 2 10.7 day 1 Solve Quadratic Systems · 10/10/2019 · 2. Solve using substitution. y = x + 1 4x + 5y = 23 3. Solve using elimination. 3x + 2y = 6 6x + 3y = 6 What if we](https://reader030.vdocuments.mx/reader030/viewer/2022040606/5eb61de1abb578730c63f08e/html5/thumbnails/5.jpg)
1. (2, 4), (-2, -4)
2. (2, -1), (1, -4)
3. (4, -5), (-5, 4)
4. (3, 2), (0, -1)
5. (7, 15), (3, 3)
6. (4, -6), (-1, 9)
7. (6, 5), (-2, -3)
Answers to 10.7 D1