algebra 1 unit 1 practice - williamsoncentral.org
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Name ______________________________ Period ________
Algebra 1
Unit 1 Practice:
Tools of Algebra:
Expressions, Equations
and Inequalities
Lesson 1: Using the Graphing Calculator to Explore Functions pg. 3
Lesson 2: Dimensional Analysis pg. 5
Lesson 3: Multiplying and Dividing Monomials pg. 6
Lesson 4: Multiplying and Dividing Polynomials pg. 7
Lesson 5: Adding and Subtracting Polynomials pg. 9
Lesson 6 & 7: The Distributive Property pg. 11
Lesson 8: The Commutative and Associative Properties pg. 13
Lesson 9: Sets of Numbers pg. 15
Lesson 10: Solving Equations Algebraically pg. 17
Lesson 11: Recognizing Properties of Equality in Solving Equations pg. 19
Lesson 12: Solving Equations with Fractions pg. 21
Lesson 13: Solving Equations for a Specific Variable pg. 23
Lesson 14: Solving Linear Inequalities Algebraically pg. 25
Lesson 15: Interpreting Two or More Inequalities Joined by βANDβ or βORβ pg. 27
Lesson 16: Solving and Graphing Inequalities Joined by βANDβ or βORβ pg. 29
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Lesson 1: Using the Graphing Calculator to Explore Functions
Look at the GRAPH of each function first. Then use the graph to determine an
appropriate table of values to use to plot the function.
1. π¦ = 2π₯ β 7
2. π¦ = |2π₯ + 1| β 3
π₯ (input) π¦ (output)
π₯ (input) π¦ (output)
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Complete the table of values below. Then graph the function.
3. π¦ = β3π₯ + 4
4. π¦ = 3π₯
π₯ (input) π¦ (output)
-4
-3
-2
-1
0
4
7
π₯ (input) π¦ (output)
-2
-1
0
1
2
3
4
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Lesson2: Dimensional Analysis
Convert each measurement to the given units.
1. 261 g kg
2. 3 days seconds
3. 9,474 mm cm
4. 0.73 kL L
5. 5.93 cm3 m3
6. 498.82 cg mg
7. 1 ft3 m3 (Note: 3.28 ft = 1 m) 8. 1 year minutes
9. 175 lbs kg (Note: 2.2 lb = 1 kg) 10. 4.65 km m
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Lesson 3: Multiplying and Dividing Monomials
Multiplying Monomials
1. xxxxx 2. yyyxx 3. 53 xx 4. yyxx 42 5. 23525 nnmnm
6. xx 52 7. zzyy 2946 8. 24 43 xx 9. 422 25 yxx 10. 23 354 xxx
Dividing Monomials
1. x
x3
2. 42
65
yx
yx 3.
3
3
x
x 4.
zyx
zyx64
6810
5. 52
623
cab
cba
6. x
x
2
2 2
7. 2
5
7
14
p
p 8.
2
6
20
10
d
d 9.
nm
nm8
108
2
12 10.
26
327
15
5
zx
zyx
Power to a Power
1. 32 )(x 2. 233 )( yx 3. 642 )( zxy 4. 35)2( x 5. 3)4( y
6. 47)6( h 7. 49)5( p 8. 24 )3( d 9. 810)( a 10. 572 )3( zyx
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Lesson 4: Multiplying and Dividing Polynomials
Classify each as monomial, binomial, trinomial, or polynomial.
1. 2π₯ + 1 2. 17π₯2 + 11 3. 8π₯3 + 2π₯2 + 3π₯ β 7
4. β130 5. 4π2 + 7π β 10 6. 10π₯3 β 2π₯ + 1
One of the expressions above is referred to as a constant. Can you identify the
expression that is a constant?
Simplify each expression. Combine like terms if possible.
7. 3π₯2(4π₯2 + 5) 8. β 7π₯(π₯ β 4π) 9. 9π₯4β27π₯6
3π₯3
10. π(ππ + ππ) 11. (8π2 β 12π2) Γ· (β4) 12. 12π₯3β6π₯2+2π₯
2π₯
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Simplify each expression. Combine like terms if possible. Leave answers in
standard form.
13. 6(π₯2 + 2π₯ + 7) 14. 4π₯(1 β π₯) 15. βπ₯2(π₯ + 5)
16. 3π₯2(4π₯3 β 5π₯ + 10) 17. 3π₯(βπ₯2 + 2π₯ β 12) 18. β18π₯2+21π₯
β3
19. 20π₯4β15π₯2
5π₯2 20. π₯4+3π₯3+7π₯
π₯
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Lesson 5: Adding and Subtracting Polynomials
Find each sum or difference by combining the parts that are alike.
1. (2π + 4) + 5(π β 1) β (π + 7) 2. (7π₯4 + 9π₯) β 2(π₯4 + 13)
3. (5 β π‘2) + 6(π‘2 β 8) β (π‘2 + 12) 4. (8π₯3 + 5π₯) β 3(π₯3 + 2)
5. (12π₯ + 1) + 2(π₯ β 4) β (π₯ β 15) 6. (9 β π‘ β π‘2) β3
2(8π‘ + 2π‘2)
7. (4π + 6) β 12(π β 3) + (π + 2) 8. (15π₯4 + 10π₯) β 12(π₯4 + 4π₯)
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9. The expression (π₯2 β 5π₯ β 2) β (β6π₯2 β 7π₯ β 3) is equivalent to
10. The expression (2π₯2 + 6π₯ + 5) β (6π₯2 + 3π₯ + 5) multiplied by 12
π₯3 is
equivalent to
11. When 3π₯2 β 8π₯ is subtracted from 2π₯2 + 3π₯, the difference is
12. When 3π2 β 4π + 2 is subtracted from 7π2 + 5π β 1, the difference is
13. When 4π₯2 + 7π₯ β 5 is subtracted from 9π₯2 β 2π₯ + 3, the result is
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Lesson 6 & 7: The Distributive Property
Simplify each expression using the distributive property.
1. (π₯ + 7)(π₯ β 5) 2. (2 β π)(4 β π) 3. (π β 4)(π + 16)
4. (3
7π +
8
3π)
2 5. (π₯ +
3
4) (π₯ β
5
4) 6. (3π₯ β 4)2
7. (π + π)(π + π + π) 8. (π₯ + π¦ + π§)(π₯ + 1)
9. (π₯ + π¦ β 3)(π₯ + π¦ + 2)
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10. Given the expression: (π₯ + 3)(π¦ + 1)(π₯ + 2)
Write an equivalent expression by applying the Distributive Property.
11. Use the distributive property to show that the equation below is true.
(π₯ + 2π)2 = π₯2 + 2ππ₯ + 2π(π₯ + 2π).
12. Use the distributive property to show that the equation below is true.
(π₯ + 2π)2 = π₯2 + 4π(π₯ + 2π) β 4π2
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Lesson 8: The Commutative and Associative Properties Select the property that represents the equation.
1. β3 + 6 = 6 + β3
(1) Associative Property of Addition
(2) Commutative Property of Addition
2. 3 + (5 + 7) = 3 + (7 + 5)
(1) Associative Property of Addition
(2) Commutative Property of Addition
3. 7 β’ 3 = 3 β’ 7
(1) Associative Property of Multiplication
(2) Commutative Property of Multiplication
4. (7 β’ 5) β’ 2 = 7 β’ (5 β’ 2)
(1) Associative Property of Multiplication
(2) Commutative Property of Multiplication
5. Which of the following is an illustration of the associative property?
(1) π(π + π) = ππ + ππ (3) π + (π + π) = (π + π) + π
(2) ππ + 0 = ππ (4) π + π = π + π
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6. Prove (π₯ + π¦) + π§=(π§ + π¦) + π₯is true for all real numbers π₯, π¦ and π§.
7. Write a mathematical proof to show that (π₯ + π)(π₯ + π) is equivalent to π₯2 + ππ₯ + ππ₯ + ππ.
8. The steps in finding the product of (3π₯2π¦5) and (7π₯5π¦2) are shown below. Fill in
either the associative property or the commutative property to justify each step.
(3π₯2π¦5)(7π₯5π¦2)
(3π₯2)(π¦4 β 7)(π₯5π¦2) _______________________________________
(3π₯2)(7π¦4)(π₯5π¦2) _______________________________________
3(π₯2 β 7)(π¦4π₯5π¦2) _______________________________________
3(7π₯2)(π₯5π¦4π¦2) _______________________________________
(3 β 7)(π₯2π₯5)(π¦4π¦2) _______________________________________
21π₯7π¦6
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Lesson 9: Sets of Numbers
Name all the classifications for each real number.
1. β34
2. β121
3. β3
11
4. 2. 6Μ
5. 3.14
6. π
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True or False: If the answer is false, provide an example to support your
reasoning.
7. The sum of two rational numbers is rational.
8. The product of two irrational numbers is rational.
9. The sum of a rational number and an irrational number is irrational.
10. The product of a nonzero rational number and an irrational number is irrational.
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Lesson 10: Solving Equations Algebraically
Solve each equation. Check your solution(s).
1. 4π¦ β 3 = 5π¦ β 8 2. β7 β 6π + 5π = 3π β 5π
3. 7 β 2π₯ = 1 β 5π₯ + 2π₯ 4. 4(π₯ β 2) = 8(π₯ β 3) β 12
5. π2 β 4n + 8 = (n β 4)(n + 3) 6. β21 β 8π = β5(π + 6)
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7. β11 β 2π = 6π + 5(π + 3) 8. 2(6π + 8) = 4 + 6π
9. 3
2π=
1
4 10.
β3
1+π=
β6
1βπ
11. A lawn-and-garden dealer wants to make a new blend of grass seed by using 200 pounds of $0.45 per pound seed and some $0.65 per pound seed. How much of the $0.65 seed does the dealer need to make a $0.55 per pound blend?
0.45(200) + 0.65(x) = 0.55(200+x)
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Lesson 11: Recognizing Properties of Equality in Solving Equations
Solve the equation for π. For each step, describe the property used to convert
the equation.
1. 3π₯ β [8 β 3(π₯ β 1)] = π₯ + 19
2. π₯β3
π₯β1=
π₯+1
π₯+2
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3. Complete the Justification column with the appropriate property used to
convert the equation.
Steps: Justification
3(π₯ β 2) + 5π₯ = 9π₯ β 24 Given
3π₯ β 6 + 5π₯ = 9π₯ β 24 a.
3π₯ + 5π₯ β 6 = 9π₯ β 24 b.
8π₯ β 6 = 9π₯ β 24 c.
8π₯ β 8π₯ β 6 = 9π₯ β 8π₯ β 24 d.
β6 = π₯ β 24 e.
β6 + 24 = π₯ β 24 + 24 f.
18 = π₯
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Lesson 12: Solving Equations with Fractions
Solve each equation. Check your solutions.
1. 3
4π₯ =
1
2 2.
β5
6π₯ =
3
4
3. β1
4π€ β 3 = π€ +
1
3 4.
1
2(5π₯ β 2) = 2π₯ + 4
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5. 2
3(3π₯ + 1) = 5 6.
1
2+
2
5π‘ β 1 =
1
5π‘ + π‘
7. π₯
2β
5π₯
6=
1
9 8. π¦ β
2
5= β
1
3
Bonus: Can figure this one out?
2
π₯β
3
8π₯=
1
4
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Lesson 13: Solving Equations for a Specific Variable
Solve each equation for π.
1. ππ₯ + 3π = 2π 2. π₯+π
4= π 3.
π₯
5β 7 = 2π
4. π₯
6β
π₯
7= ππ 5.
3ππ₯+2π
π= 4π 6. Solve for π :
π΄ = π 2
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Solve each equation for y. Then graph each equation on the graph provided.
Label each line with the appropriate equation.
7. β6π₯ β 3π¦ = 3 8. 10π₯ β 16 = 4π¦
9. 18 β 3π¦ = 1π₯ 10. 6π¦ β 4π₯ = 30
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Lesson 14: Solving Inequalities Algebraically
Find the solution set to each inequality. Then express the solution graphically
on the number line.
1. 2
3π₯ β
1
2+ 2 2. β5(π₯ β 1) β₯ 10 3. 13π₯ < 9(1 β π₯)
4. 8π¦ + 4 < 7π¦ β 2 5. 6 β π β€ 15 6. βπ₯
12β€
14
7. 3(2π₯+2)
6>
1
3π₯ + 2 8. 4(π₯ β 3) > 2(π₯ β 2)
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9. 8π₯ β 6(π₯ β 2) > 20 β 2π₯ 10. 8(π₯ β 2) β 3(2π₯ + 1) β₯ 7π₯ + 4 β 3(π₯ + 1)
11. Two siblings Edwin and Rhea are both going skiing but choose different
payment plans. Edwinβs plan charges $45 for rentals and $5.25 per lift up the
mountain. Rheaβs plan was a bundle where her entire day cost $108. (source: emathinstruction Kirk Weiler)
(a) Set up an inequality that models the number of trips, n, up the mountain for
which Edwin will pay more than Rhea. Solve the inequality.
(b) What is the greatest amount of trips that Edwin can take up the mountain
and still pay less than Rhea? Explain how you arrived at your answer.
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Lesson 15: Interpreting Two or More Inequalities Joined by βANDβ or βORβ
Graph the solution set to each compound inequality on a number line.
1. π < βπ or π > βπ 2. π < π β€ ππ 3. Graph each compound sentence on a number line.
a. π₯ = 2 or π₯ > 4 b. π₯ β€ β5 or π₯ β₯ 2
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4. The amount of money that Tucker carries in his wallet is at least 25 dollars but no more than 100 dollars. Create a scale on the number line below and then use it to show the amount of money that Tucker carries with him in his wallet.
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Lesson 16: Solving and Graphing Inequalities Joined by βANDβ or βORβ
Solve each inequality. Represent your solution on a number line.
1. β3π₯ > 12 or 5π₯ β₯ 10 2. β2π₯ + 8 < 14 and 3π₯ + 1 < 1
3. 3(6 β π¦) β€ 6 and 6 β π¦ β₯ 8 4. β1 < 9 + π < 17
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5. 3π₯ < 2π₯ β 3 or 7π₯ > 4π₯ β 9 6. 2π + 5 > 1 and 3π + 4 > 7
7. β€ k 8. v or v