aisc seismic design-module3-concentrically braced frames
TRANSCRIPT
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Design of Seismic-Design of Seismic-Resistant Steel Resistant Steel
Building StructuresBuilding Structures
with the support of theAmerican Institute of Steel Construction.
3. Concentrically Braced Frames
Version 1 - March 2007
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Design of Seismic-Resistant Design of Seismic-Resistant Steel Building StructuresSteel Building Structures
1 - Introduction and Basic Principles
2 - Moment Resisting Frames
3 - Concentrically Braced Frames
4 - Eccentrically Braced Frames
5 - Buckling Restrained Braced Frames
6 - Special Plate Shear Walls
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3 - Concentrically Braced Frames3 - Concentrically Braced Frames
• Description and Types of Concentrically Braced
Frames
• Basic Behavior of Concentrically Braced Frames
• AISC Seismic Provisions for Special Concentrically
Braced Frames
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Concentrically Braced FramesConcentrically Braced Frames
• Description and Types of Concentrically Braced
Frames
• Basic Behavior of Concentrically Braced Frames
• AISC Seismic Provisions for Special Concentrically
Braced Frames
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Concentrically Braced Frames (CBFs)Concentrically Braced Frames (CBFs)
Beams, columns and braces arranged to form a vertical truss. Resist lateral earthquake forces by truss action.
Develop ductility through inelastic action in braces.
- braces yield in tension- braces buckle in compression
Advantages
- high elastic stiffness
Disadvantages
- less ductile than other systems (SMFs, EBFs, BRBFs)
- reduced architectural versatility
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Types of CBFsTypes of CBFs
Single Diagonal Inverted V- Bracing V- Bracing
X- Bracing Two Story X- Bracing
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Concentrically Braced FramesConcentrically Braced Frames
• Description and Types of Concentrically Braced
Frames
• Basic Behavior of Concentrically Braced Frames
• AISC Seismic Provisions for Special Concentrically
Braced Frames
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Inelastic Response of CBFs under Earthquake LoadingInelastic Response of CBFs under Earthquake Loading
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Inelastic Response of CBFs under Earthquake LoadingInelastic Response of CBFs under Earthquake Loading
Tension Brace: Yields(ductile)
Compression Brace: Buckles(nonductile)
Columns and beams: remain essentially elastic
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Inelastic Response of CBFs under Earthquake LoadingInelastic Response of CBFs under Earthquake Loading
Compression Brace (previously in tension): Buckles(nonductile)
Tension Brace (previously in compression): Yields (ductile)
Columns and beams: remain essentially elastic
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Brace Behavior Under Cyclic Axial LoadingBrace Behavior Under Cyclic Axial Loading
P
Tension
Compression
ElongationShortening
P
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Brace Behavior Under Cyclic Axial LoadingBrace Behavior Under Cyclic Axial Loading
P
P
PCR1
1. Brace loaded in compression to peak compression capacity (buckling).
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Brace Behavior Under Cyclic Axial LoadingBrace Behavior Under Cyclic Axial Loading
P
P
1. Brace loaded in compression to peak compression capacity (buckling).
2. Continue loading in compression. Compressive resistance drops rapidly. Flexural plastic hinge forms at mid-length (due to P-Δ moment in member).
plastic hinge
2
Δ
PCR1
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Brace Behavior Under Cyclic Axial LoadingBrace Behavior Under Cyclic Axial Loading
P
1. Brace loaded in compression to peak compression capacity (buckling).
2. Continue loading in compression. Compressive resistance drops rapidly. Flexural plastic hinge forms at mid-length (due to P-Δ moment in member).
3. Remove load from member (P=0). Member has permanent out-of-plane deformation.
3
2
PCR1
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Brace Behavior Under Cyclic Axial LoadingBrace Behavior Under Cyclic Axial Loading
P
4. Brace loaded in tension to yield.
3
2
PCR1
4
P
Py
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Brace Behavior Under Cyclic Axial LoadingBrace Behavior Under Cyclic Axial Loading
P
4. Brace loaded in tension to yield.
5. Remove load from member (P=0).Member still has permanent out-of-plane deformation.
3
2
PCR1
4Py
5
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Brace Behavior Under Cyclic Axial LoadingBrace Behavior Under Cyclic Axial Loading
P
4. Brace loaded in tension to yield.
5. Remove load from member (P=0).Member still has permanent out-of-plane deformation.
6. Brace loaded in compression to peak compression capacity (buckling). Peak compression capacity reduced from previous cycle.
3
2
PCR1
4Py
5
P
6
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Brace Behavior Under Cyclic Axial LoadingBrace Behavior Under Cyclic Axial Loading
P
4. Brace loaded in tension to yield.
5. Remove load from member (P=0).Member still has permanent out-of-plane deformation.
6. Brace loaded in compression to peak compression capacity (buckling). Peak compression capacity reduced from previous cycle.
7. Continue loading in compression. Flexural plastic hinge forms at mid-length (due to P-Δ moment in member).
3
2
PCR1
4Py
5
P
67
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Experimental Behavior of Brace Under Cyclic Axial LoadingExperimental Behavior of Brace Under Cyclic Axial Loading
P
W6x20 Kl/r = 80
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Experimental Behavior of Brace Under Cyclic Axial LoadingExperimental Behavior of Brace Under Cyclic Axial Loading
P
W6x16 Kl/r = 120
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Experimental Behavior of Braced Frame Under Cyclic LoadingExperimental Behavior of Braced Frame Under Cyclic Loading
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Developing Ductile Behavior in CBFsDeveloping Ductile Behavior in CBFs
• Design frame so that inelastic behavior is restricted to braces.
Braces are "fuse" elements of frame.
Braces are weakest element of frame. All other frame elements (columns, beams, connections) are stronger than braces.
• Choose brace members with good energy dissipation capacity and fracture life (limit kL/r and b/t).
General ApproachGeneral Approach
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Developing Ductile Behavior in CBFsDeveloping Ductile Behavior in CBFs
• Design brace connections for maximum forces and deformations imposed by brace during cyclic yielding/buckling
General ApproachGeneral Approach
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Developing Ductile Behavior in CBFsDeveloping Ductile Behavior in CBFs
• Design beams and columns (and column splices and column bases) for maximum forces imposed by braces
General ApproachGeneral Approach
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Developing Ductile Behavior in CBFsDeveloping Ductile Behavior in CBFs
General ApproachGeneral Approach
• Design braces based on code specified earthquake forces.
• Design all other frame elements for maximum forces that can be developed by braces.
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Maximum Forces Developed by BracesMaximum Forces Developed by Braces
Braces in Tension - Axial Force:Braces in Tension - Axial Force:
P
P
Pmax = Py
For design:
Take Pmax = Ry Fy Ag
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Maximum Forces Developed by BracesMaximum Forces Developed by BracesBraces in Compression - Axial ForceBraces in Compression - Axial Force
P
P
Pmax
For design:
Take Pmax = 1.1 Ry Pn
( Pn = Ag Fcr )
Take Presidual = 0.3 Pn
Presidual 0.3 Pcr
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Maximum Forces Developed by BracesMaximum Forces Developed by Braces
Braces in Compression - Bending Moment:Braces in Compression - Bending Moment:
PP
MM
For "fixed" end braces: flexural plastic hinges will form at mid-length and at brace ends. Brace will impose bending moment on connections and adjoining members.
Plastic Hinges
For design:
Take Mmax = 1.1 Ry Fy Zbrace (for critical buckling direction)
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Maximum Forces Developed by BracesMaximum Forces Developed by Braces
Braces in Compression - Bending Moment:Braces in Compression - Bending Moment:
For "pinned" end braces: flexural plastic hinge will form at mid-length only. Brace will impose no bending moment on connections and adjoining members.
Must design brace connection to behave like a "pin"
PP
PP
Plastic Hinge
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Maximum Forces in Columns and BeamsMaximum Forces in Columns and Beams
To estimate maximum axial forces imposed by braces on columns and beams:
Braces in tension:Braces in tension:
Take P = Ry Fy Ag
Braces in compression:Braces in compression:
Take P = 1.1 Ry Pn or P = 0.3 Pn
whichever produces critical design case
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ExampleExample
Find maximum axial compression in column.
Tension Braces: Take P = Ry Fy Ag
Compression Braces: Take P = 0.3 Pn
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ExampleExample
Ry Fy Ag
Ry Fy Ag
Ry Fy Ag
0.3 Pn
0.3 Pn
Column Axial Compression =
[ (Ry Fy Ag ) cos + (0.3 Pn) cos ] + Pgravity
(sum brace forces for all levels above column)
0.3 Pn
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ExampleExample
Find maximum axial tension in column.
Tension Braces: Take P = Ry Fy Ag
Compression Braces: Take P = 0.3 Pn
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ExampleExample
Ry Fy Ag
0.3 Pn
Ry Fy Ag
Ry Fy Ag
0.3 Pn
0.3 Pn
Column Axial Tension =
[ (Ry Fy Ag ) cos + (0.3 Pn) cos ] - Pgravity
(sum brace forces for all levels above column)
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ExampleExample
Find maximum axial compression in column.
Tension Brace: Take P = Ry Fy Ag
Compression Brace: Take P = 0.3 Pn
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ExampleExample
Ry Fy Ag
0.3 PnColumn Axial Compression =
(Ry Fy Ag ) cos + (0.3 Pn) cos + Pgravity
Note
Based on elastic frame analysis:
Column Axial Force = Pgravity
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ExampleExample
Find maximum bending moment in beam.
Tension Brace: Take P = Ry Fy Ag
Compression Brace: Take P = 0.3 Pn
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ExampleExample
Ry Fy Ag
0.3 Pn
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ExampleExample
( Ry Fy Ag - 0.3 Pn ) sin
Compute moment in beam resulting from application of concentrated load at midspan of ( Ry Fy Ag + 0.3 Pn ) sin
and add moment due to gravity load
Note
Based on elastic frame analysis:
Moment in beam 0
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ExampleExample
Find maximum axial tension and compression that will be applied to gusset plate.
Tension Brace: Take P = Ry Fy Ag
Compression Brace: Take P = 1.1 Ry Pn
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ExampleExample
1.1 Ry Pn
Ry Fy Ag
Check gusset buckling, beam web crippling, etc.
Check gusset yield, gusset net section fracture, gusset block shear fracture, local beam web yielding, etc.
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Concentrically Braced FramesConcentrically Braced Frames
• Description and Types of Concentrically Braced
Frames
• Basic Behavior of Concentrically Braced Frames
• AISC Seismic Provisions for Special Concentrically
Braced Frames
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2005 AISC Seismic Provisions2005 AISC Seismic Provisions
Section 13 Special Concentrically Braced Frames (SCBF)
Section 14 Ordinary Concentrically Braced Frames (OCBF)
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Section 13Special Concentrically Braced Frames (SCBF)
13.1 Scope
13.2 Members
13.3 Required Strength of Bracing Connections
13.4 Special Bracing Configuration Requirements
13.5 Column Splices
13.6 Protected Zone
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AISC Seismic Provisions - SCBF13.1 Scope
Special concentrically braced frames (SCBF) are expected to withstand significant inelastic deformations when subjected to the forces resulting from the motions of the design earthquake.
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AISC Seismic Provisions - SCBF13.2 Members 13.2a Slenderness
Bracing members shall have:yF
E4
r
KL
Fy = 36 ksi: KL/r ≤ 114
Fy = 42 ksi: KL/r ≤ 105
Fy = 46 ksi: KL/r ≤ 100
Fy = 50 ksi: KL/r ≤ 96
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13.2a Slenderness
Bracing members shall have:yF
E4
r
KL
Exception:
Braces with: 200r
KL
F
E4
y
are permitted in frames in which the available strength of the columns is at least equal to the maximum load transferred to the column considering Ry times the nominal strengths of the brace elements.
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ExampleExample
Find required axial compression strength of column.
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ExampleExample
Ry Fy Ag
Ry Fy Ag
Ry Fy Ag
0.3 Pn
0.3 Pn
Required column axial compression strength =
[ (Ry Fy Ag ) cos + (0.3 Pn) cos ] + [(1.2 + 0.2SDS) D + 0.5L]
0.3 Pn
OR
Ω0 QE + [(1.2 + 0.2SDS) D + 0.5L]
yF
E4
r
KLAll bracing members:
Note: Ω0 = 2 for SCBF and OCBF
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ExampleExample
Ry Fy Ag
Ry Fy Ag
Ry Fy Ag
0.3 Pn
0.3 Pn
Required column axial compression strength =
[ (Ry Fy Ag ) cos - (0.3 Pn) cos ] + [(1.2 + 0.2SDS) D + 0.5L]
0.3 Pn
Ω0 QE + [(1.2 + 0.2SDS) D + 0.5L]
Bracing members with: 200r
KL
F
E4
y
NOT PERMITTED
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13.2 Members 13.2b Required Strength
Where the effective net area of bracing members is less than the gross area, the required tensile strength of the brace, based on a limit state of fracture of the net section shall be at least Ry Fy Ag of the bracing member.
Objective: yield of gross section of brace prior to fracture of net section
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ExampleExample
double angle bracing membergusset plate
Check double angle bracing member for limit state of net section fracture
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Pu= Ry Fy Ag
Required axial tension strength of brace for limit state of fracture of the net section
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Pu= Ry Fy Ag
Critical Net Section
Ae = U An
Ae < Ag due to:
bolt hole (An < Ag ), and
shear lag (U < 1)
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Pu= Ry Fy Ag
Limit state: fracture of net section
Pn = (0.75) Ae (Rt Fu)
Per Section 6.2: use expected tensile strength Rt FU when checking net section fracture of bracing member, since Ry Fy of the same member is used to computed the required strength
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Pu= Ry Fy Ag
Limit state: fracture of net section
(0.75) Ae (Rt Fu) ≥ Ry Fy Ag
ut
yy
g
e
FR75.0
FR
A
AOR:
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Pu= Ry Fy Ag
Limit state: fracture of net section
ut
yy
g
e
FR75.0
FR
A
A
For A36 Angles:
03.1ksi582.175.0
ksi365.1
A
A
g
e
For A572 Gr. 50 Angles:
03.1ksi651.175.0
ksi501.1
A
A
g
e
Need to Reinforce Net Section (Ae need not exceed Ag )
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Pu= Ry Fy Ag
Also check block shear rupture of bracing member....
Pn = (0.75) Ubs Ant Rt Fu + lesser of 0.6 Anv Rt Fu
0.6 Agv Ry Fy
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Reinforcing net section of bracing member....
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ExampleExample gusset plate
rectangular HSS bracing member
Check HSS bracing member for limit state of net section fracture
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Pu= Ry Fy Ag
Required axial tension strength of brace for limit state of fracture of the net section
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Pu= Ry Fy Ag
Critical Net Section
Ae = U An
Ae < Ag due to:
slot (An < Ag ), and
shear lag (U < 1)
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Pu= Ry Fy Ag
Limit state: fracture of net section
(0.75) Ae (Rt Fu) ≥ Ry Fy Ag
ut
yy
g
e
FR75.0
FR
A
AOR:
For A500 Gr B rectangular HSS:
14.1ksi583.175.0
ksi464.1
A
A
g
e
Need to Reinforce Net Section (Ae need not exceed Ag )
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Pu= Ry Fy Ag
Also check block shear rupture of bracing member....
Pn = (0.75) Ubs Ant Rt Fu + lesser of 0.6 Anv Rt Fu
0.6 Agv Ry Fy
Ant 0
L t = design wall thickness of HSS
Ant = Agv = 4 L t
For A500 Gr B rectangular HSS: Rt Fu = 1.3 x 58 ksi = 75.4 ksi
Ry Fy = 1.4 x 46 ksi = 64.2 ksi
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Pu= Ry Fy Ag
Also check block shear rupture of bracing member....
L t = design wall thickness of HSS
Pn = (0.75) ( 4 L t x 0.6 x 64.2 ksi) ≥ 1.4 x 46 ksi x Ag
t
A557.0L g
= minimum length of welded overlap needed based on block shear rupture in HSS bracing member
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Reinforcing net section of bracing member....
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13.2 Members 13.2c Lateral Force Distribution
Along any line of bracing, braces shall be deployed in opposite directions such that, for either direction of force parallel to the bracing, at least 30 percent but not more than 70% of the total horizontal force along that line is resisted by braces in tension..
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13.2 Members 13.2c Lateral Force Distribution
Deploy braces so that about half are in tension (and the other half in compression)
All braces in tension (or compression) NG
OK
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13.2 Members 13.2d Width-Thickness Limitations
Columns and braces shall meet requirements of Section 8.2b.
i.e. columns and braces must be seismically compact : ≤ ps
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13.2d Width-Thickness Limitations
Columns: ≤ ps
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13.2d Width-Thickness Limitations
Braces: form plastic hinge during buckling
P
plastic hinge
Δ
With high b/t's - local buckling and possibly fracture may occur at plastic hinge region
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13.2d Width-Thickness Limitations
Bracing Members: ≤ ps
For rectangular HSS (A500 Gr B steel):
1.16ksi46
ksi2900064.0
F
E64.0
t
b
y
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AISC Seismic Provisions - SCBF13.3 Required Strength of Bracing Connections 13.3a Required Tensile Strength
The required tensile strength of bracing connections (including beam-to-column connections if part of the bracing system) shall be the lesser of the following:
1. Ry Fy Ag of the bracing member.
2. The maximum load effect, indicated by analysis that can be transferred to the brace by the system.
Few practical applications of Item 2.
Note that ΩoQE is NOT an acceptable method to establish "maximum load effect"
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Ry Fy Ag
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Pu = Ry Fy Ag
Pu cos
Pu sin
Consider load path through connection region
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Pu = Ry Fy Ag
Pu cos
Pu sin
Consider load path through connection region:
Uniform Force Method - Vertical Component of Pu transferred to column.
Vuc
Vub
Vuc + Vub = Pu sin
Vuc is transferred directly to column
Vub is transferred indirectly to column through beam and beam to column connectionVub
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Pu = Ry Fy Ag
Pu cos
Pu sin
Huc
Hub
Huc + Hub = Pu cos
Hub is transferred directly to beam
Huc is transferred indirectly to beam through column and beam to column connection
Huc
Consider load path through connection region:
Uniform Force Method - Horizontal Component of Pu transferred to beam.
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Pu = Ry Fy Ag
Pu cos
Pu sin
Consider load path through connection region:
Use caution in use of bolts and welds.
Section 7.2:"Bolts and welds shall not be designed to share force in a joint or the same force component in a connection."
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Pu = Ry Fy Ag
Pu cos
Pu sin
If designed by uniform force method - this connection violates Section 7.2
Bolts and welds must transfer same force components.
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AISC Seismic Provisions - SCBF13.3 Required Strength of Bracing Connections 13.3b Required Flexural Strength
The required flexural strength of bracing connections is1.1 Ry Mp of bracing member.
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P
MM
For "fixed" end braces: flexural plastic hinges will form at mid-length and at brace ends. Brace will impose bending moment on connections and adjoining members.
Plastic Hinges
Mu = 1.1 Ry Mp = 1.1 Ry Fy Zbrace
(for critical buckling direction)
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1.1 Ry Mp-brace
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AISC Seismic Provisions - SCBF13.3 Required Strength of Bracing Connections 13.3b Required Flexural Strength
The required flexural strength of bracing connections is1.1 Ry Mp of bracing member.
Exception:
Brace connections that can accommodate the inelastic rotations associated with brace post-buckling deformations need not meet this requirement.
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For "pinned" end braces: flexural plastic hinge will form at mid-length only. Brace will impose no bending moment on connections and adjoining members.
Must design brace connection to behave like a "pin"
PP
PP
Plastic Hinge
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Buckling perpendicular to gusset plate
Line of rotation ("fold line") when the brace buckles out-of-plane (thin direction of plate)
To accommodate brace end rotation: provide "fold line"
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2t
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2t
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Concrete floor slab
2t
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Concrete floor slab
Styrofoam
2t
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>2t
> 2t
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>2t
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> 2t
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AISC Seismic Provisions - SCBF13.3 Required Strength of Bracing Connections 13.3c Required Compressive Strength
The required compressive strength of bracing connections shall be at least 1.1 Ry Pn
Pn = Ag Fcr of bracing member (per Chapter E of AISC Main Specification)
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1.1 Ry Pn
Check: - buckling of gusset plate
- web crippling for beam and column
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AISC Seismic Provisions - SCBF13.4 Special Bracing Configuration Requirements 13.4a V-Type and Inverted V-Type Bracing
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AISC Seismic Provisions - SCBF13.4 Special Bracing Configuration Requirements 13.4a V-Type and Inverted V-Type Bracing
(1) Design beams for unbalanced load that will occur when compression brace buckles and tension brace yields.
Take force in tension brace: Ry Fy Ag
Take force in compression brace: 0.3 Pn
Assume beam has no vertical support between columns.
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Ry Fy Ag
0.3 Pn
wgravity = (1.2 + 0.2 SDS) D + 0.5L
ExampleL
Beam-to-column connections: simple framing
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wgravity = (1.2 + 0.2 SDS) D + 0.5L
Example
L
( Ry Fy Ag - 0.3 Pn ) sin ( Ry Fy Ag + 0.3 Pn ) cos
Forces acting on beam:
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AISC Seismic Provisions - SCBF13.4 Special Bracing Configuration Requirements 13.4a V-Type and Inverted V-Type Bracing
(2) Both flanges of beams must be provided with lateral braces with a maximum spacing of Lpd
and
Both flanges of the beam must be braced at the point of intersection of the braces.
Per Main AISC Specification (Appendix 1):
yy2
1pd r
F
E
M
M076.012.0L
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AISC Seismic Provisions - SCBF13.4 Special Bracing Configuration Requirements 13.4b K-Type Bracing
K-Type Braces are not Permitted for SCBF
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Section 13Special Concentrically Braced Frames (SCBF)
13.1 Scope
13.2 Members
13.3 Required Strength of Bracing Connections
13.4 Special Bracing Configuration Requirements
13.5 Column Splices
13.6 Protected Zone