adad thuan thuan.do luong.docthanh
TRANSCRIPT
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Bi tp ln o Lng TTCN Khoa in t
TRNG I HC K THUT CNG NGHIP
KHOA IN T
B mn: O LNG IU KHIN
BI TP LN
MN HC
O LNG V THNG TIN CNG NGHIP
Sinh vin :. .. . NGUYN TH THUN
Lp . . . .
K44KMT. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
Gio vin hng dn . PHM VN THIM. . . . . . . . . . . . . . . . . . . . . . . .
. . .
GVHD: Phm Vn Thim - 1 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in t
Thi Nguyn 2011
TRNG HKTCN CNG HO X HI CH NGHA VIT NAM
KHOA IN T c lp - T do - Hnh phc
BI TP LN
MN HC: O LNG V THNG TIN CNG NGHIP
B MN : O LNG IU KHIN.............................
Sinh vin: ..... NGUYN TH THUN..................... Lp: K44KMT.................
Ngnh: K THUT MY TNH
..........................................................................................................................................
.................................
Gio vin hng dn: PHM VN THIM............
Ngy giao : 30/10/2011........................ Ngy hon thnh: 5/12/2011......................
Tn ti.........................................................................................................................
.........................................................................................................................................
Yu cu............................................................................................................................
.........................................................................................................................................
.........................................................................................................................................
GVHD: Phm Vn Thim - 2 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in t.........................................................................................................................................
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GVHD: Phm Vn Thim - 3 - SVTH: Nguyn ThThun
GIO VIN HNG DN
(K v ghi r h tn)
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Bi tp ln o Lng TTCN Khoa in t .I A(
.
U BC)
.I B(.
U CA)
.I C( .U AB)
Chng minh:
Cng t o nng lng tc dngXt cng sut tc thi trong mch ba pha l:
P3f= uAiA + uBiB + uCiC.
i vi mnh ba pha ba dy,v khng c dy trung tnh ln dng in
trung tnh bng khng ngha l:iA+ iB+ iC=0 => iC= -(iA+ iB).
Vy:
P3pha= uAiA + uBiB- uC(iA+ iB)
= uAiA + uBiB- uCiA uCiB
=iA (uA - uC) + iB (uB - uC)
=iAuAC + iBuBC
Vy cng sut tc dng ca ba pha l:
P3pha = UACIA cos(.
U AC,.
I A)+ UBCIBcos(.
U BC,.
I B)
Cng t o nng lng phn khngim o m thng l u ngun nn ta coi mch ba pha c ngun i
xng, ph ti mang tnh cht cm.
Ta c mmen quay tng ca cng t l:
Mq=K(IAUBCcos 1 + IBUCA cos 2+ ICUAB cos 3)
= K [IAUAcos(900-A) + IBUB cos(900-B) + ICUCcos(900-C)]
GVHD: Phm Vn Thim - 5 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in t= K (IAUAsinA + IBUB sin B + ICUC sin C)
= K Q3pha.
Ta thy mmen quay t l vi cng sut phn khng trong
mch ba pha cho nn s ch ca cng t s t l vi nng lngphn khng tiu th trong mch ba pha.
Hnh 1.1
Cu 2:chn thang o cho cc thit b o trn s
1, Chn thang o bin dng in .
Dng in nh mc pha s cp l:
GVHD: Phm Vn Thim - 6 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in t ( )A
U
SI
dm
dm
dm 735.5710.3
1000
.3===
Vy ta chn bin dng in c h s bin dng : Iscm 735.57 (A)
Itcm= 5 (A)
Vy chn BI c : KI =5
75
2, Chn thang o cho bin in p.
in p nh mc pha s cp ca my bin p l: UdmBA=10 (KV)
Cho nn chn BU c h s bin in p: KU= 1,010
3, Chn thang o cho ampek
V dng in pha th cp ca BI nh mc l 5(A) nn chn ampeke c thang o
l: DA=5(A)Dng ampe k in t:
Ampe k in t c ch to da trn c cu ch th in t.Ampe k ny
o c c dng mt chiu v dng xoay chiu
B phn chnh l mt cun dy dn, c th quay quanh mt trc, nm trong t
trng ca mt nam chm vnh cu. Cun dy c gn vi mt kim ch gc quay
trn mt thc hnh cung. Mt l xo xon ko cun v kim v v tr s khng khi
khng c dng in
Nguyn l hot ng
Khi dng in mt chiu chy qua cun dy, dng in chu lc tc ng ca t
trng (do cc in tch chuyn ng bn trong dy dn chu lc Lorentz) v b
GVHD: Phm Vn Thim - 7 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in tko quay v mt pha, xon l xo, v quay kim. V tr ca u kim trn thc o
tng ng vi cng dng in qua cun dy
y l mt thit b thc t o dng in c bn ngoi th trng
=> DA=5(A)
2, Chn thang o cho volk.
V in p pha th cp ca BU nh mc l 100(V) nn chn volke c thang ol: DV=100(V)GVHD: Phm Vn Thim - 8 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in t. Mch t gm li t bng tn silic c c tnh t tt v cun dy cch in cao.C cu chnh Kim v 0 bng c kh. Cn du n nh kim bng nam chm vnhcu, bng nha baklit c cch in cao. V bng nha ABS. Ca s bngnha PC trong sut (hn ch chy). 2 ci v d cho vic lp t Vn mt vo
bng in.
=>DV=100(V)
GVHD: Phm Vn Thim - 9 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in t3, Chn thang o cho cosk .
Do gc lch pha gia in p v dng in khng ph thuc vo h s bin i
ca BU v BI nn ta chn thang o cho Cos vi Cos [-11]
Nguyn l hot ng
Gc quay ca c cu l:
GVHD: Phm Vn Thim - 10 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in t
4,o tn s
Do tn s gia in p v dng in khng ph thuc vo h s bin i ca BUv BI nn ta chn thang o cho thit b o tn s c thang o 0 f 60 (Hz)
Nh Cung Cp Munhean c nhp t Singapre.
CngDng
ng h o tn s
GVHD: Phm Vn Thim - 11 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in tPhotoHnh nh
Cat.NoM s
TypePhn loi
RangeThang o
NG H O TN S - HIU MUNHEAN SINGAPORE Mt 96 x96 mm
CP-96FQP
Kim 220V ; 45 55Hz
ng h o tn s met cng hng
Nguyn l hot ng:
Tn s mt cng hng gm mt nam chm in,to ra bi cun
dy qun trn li st t hnh ch U,mt ming thp nm trong t trng ca nam
GVHD: Phm Vn Thim - 12 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in tchm in,gn cht vo thanh l co l thp rung c tn s dao ng ring khc
nhau. Tn s dao ng ring ca hai l thp k nhau hn km nhau l 0,25 hoc
0,5Hz.in p ca tn hiu cn do tn s s c a vo cun dy ca nam
chm in s to ra s dao ng ca tt c cc l thp.Tuy nhin l thp no c
tn s dao ng ring bng tn s f th s dao ng cc i do cng hng
ring,cn cc thanh khc khng cng hng th khng dao ng cc i.Nh vy
ta s c kt qu ti tr s tng ng vi thanh rung cc i.
5,Cng t o nng lng
A, Cng t o nng lng tc dng
V cho thi gian lm vic trong mt thng t=720h
Ta c Wtd = .Utcdm.Itcdm.Cos.t
Vi dng in p th cp cu BU l:
Utcdm =0,1 (KV) = 100 (V)
Dng in th cp ca BI l :5 (A)
Nu Wtdmax Cosmax = 1
=>Wtdmax = .0,1.5.1.720=623,54 (KWh)
Vy chn cng t o nng lng tc dng c thang o l 650 (KWh)
B, Cng t o nng lng phn khng
GVHD: Phm Vn Thim - 13 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in tTng t ta c t=720h
Wpk= .Utcdm.Itcdm.Sin.t
Vi dng in p th cp cu BU l:
Utcdm =0,1 (KV) = 100 (V)
Dng in th cp ca BI l :5 (A)
Nu Wpkmax Sinmax = 1
=>Wpkmax = .0,1.5.1.720=623,54 (KVArh)
Vy chn cng t o nng lng phn khng c thang o l 650 (KVArh)
GVHD: Phm Vn Thim - 14 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in t
GVHD: Phm Vn Thim - 15 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in t
GVHD: Phm Vn Thim - 16 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in t
GVHD: Phm Vn Thim - 17 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in t
GVHD: Phm Vn Thim - 19 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in t
8 Thit b o tn s
III-Tnh s ch ca mi cng t trong thi gian mt thng, bit rng c 80% thigian my bin p lm vic ch nh mc , 20% thi gian my bin p lm
vic ch non ti. Xc nh cos tb ca ph ti.
1, Tnh s ch ca cng t o nng lng tc dng.mc 3pha 2 phn t
a, S ch ca cng t tc dng trong ch nh mc.
Thi gian nh mc:
Tdm = 0,8.24.30 = 576(h)
Idm = IAdm = IBdm = ICdm = 735.57 (A)
Udm= 10(KV)
cos dm = 0,9 dm = 25.84o
Ta c:
dmBdmBC
I
Bdm
U
BCAdmAC
I
Adm
U
AC TIU
K
I
K
UIU
K
I
K
U.,cos..cos..W
...
,
.
cttddm
+
=
= dmBdmBCAdmACI
dm
U
dm TIUIUK
I
K
U.,cos,cos..
....
+
GVHD: Phm Vn Thim - 20 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in t
= ( ) ( )[ ] 576.84,2530cos84,2530cos.75
5.735.57.
10
1,0.10 0000 ++
= ( )KWh605,345
I
UA
A
UAC
UBC
UBUCIB
GVHD: Phm Vn Thim - 21 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in t
Hnh 1.1
b, S ch ca cng t tc dng trong ch non ti.
Thi gian non ti:
Tnt = 0,2.24.30 = 144(h)
Int = IAnt = IBnt = ICnt = 0,7.Idm =0,7.57,735 = 40,41(A)
Unt = Udm = 10(KV)
cos nt = 0,75 nt = 41,4o
Ta c:
ntBntBC
I
Bnt
U
BCAntAC
I
Ant
U
AC TIUK
I
K
UIU
K
I
K
U.,cos..,cos..W
....
cttdnt
+
=
= ntBntBCAntACI
nt
U
dm TIUIUK
I
K
U.,cos,cos..
....
+
= ( ) ( )[ ] 144.4.4130cos4.4130cos.75
5.41,40.
10
1,0.10 0000 ++
= ( )KWh4,50
GVHD: Phm Vn Thim - 22 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in t
I
UA
A
UAC
UBC
UBUCIB
Hnh 1.2
c, S ch ca cng t tc dng trong mt thng.
( )Wh005,3964,50605,345WWW cttdntcttddmcttd K=+=+=
GVHD: Phm Vn Thim - 23 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in t2, Tnh s ch ca cng t o nng lng phn khng.
a, S ch ca cng t phn khng trong ch nh mc.
Thi gian nh mc:
Tdm = 0,8.24.30 = 576(h)
Idm = IAdm = IBdm = ICdm = 57,735(A)
Udm= 10(KV)
cos dm = 0,9 sindm= sin(arccos dm) = 0,436
Ta c:
( KVArhhTKI
KU
dmdm
I
dm
U
dm 424,167576.436,0.75
5.735,57.10
1,0.10.3.sin...3Wctpkdm ===
b,S ch ca cng t phn khng trong ch non ti.
Thi gian non ti:
Tnt = 0,2.24.30 = 144h
Int = 0,7Idm = 0,7.57,735 = 40,41(A)
Unt = Udm = 10(KV)
Cosnt = 0,75 sindm= sin(arccos dm) = 0,661
Ta c:
( )KVarhhT
K
I
K
Untnt
I
nt
U
nt 41,44144.661,0.75
5.41,40.
10
1,0.10.3.sin...3Wctpknt ===
c,S ch ca cng t pkn khng trong mt thng.
GVHD: Phm Vn Thim - 24 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in t
( )KVarhWW ctpkntctpkdm 834,21141,44424,167Wctpk =+=+=
3, Xc nh costb ca ph ti.
Ta c :
( )9,0
)424,167(605,345
605,345cos
2222=
+=
+=
ctpkdmcttddm
cttddmtbdm
WW
W
( )
75,0)41,44(4,50
4,50cos
2222=
+=
+=
ctpkntcttdnt
cttdnttbnt
WW
W
IV-Tnh sai s tuyt i v sai s tng i ca cc php o trong hai trnghp ph ti.
Cha sa
1, Sai s ca cc php o ch nh mc.
**C s l thuyt tnh sai s tng i , tuyt i
chnh xc l l tiu chun quan trong nht ca thit b o
xx dii =
Trong :xi l kt qu o ca ln o th i
xd l gi tr ng ca i lng o
i l sai lch ca ln o th i
GVHD: Phm Vn Thim - 25 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in tSai s php o l sai lch gia gi tr thc v gi tr o c , sai s
php o ch c th xc nh 1 cch tng i v ta khng th bit c gi tr
thc ca i lng cn o
Sai s ca php c th biu din lm 2 dng
+Sai s tuyt i
+Sai s tng i
Sai s tuyt i ca mt thit b o c nh ngha l gi tr ln nht ca sai
lch gy nn bi thit b trong khi o.
]max[ i=
Tuy nhin sai s tuyt i cha nh gi c chnh xc v yu cu ca cng
ngh thit b o.Thng thng chnh xc ca mt php o hoc mt thit b
o c nh gi bng sai s tng i
Sai s tng i c tnh vi mt php o
= vi x l gi tr i lng o
Sai s tng i c tnh vi mt thit b o
D=
vi D l khong gi tr nh nht ti gi tr ln nht
Gi tr % gi l sai s tng i quy i dng xp xp cc thit b o thnh
cp chnh xc
Theo quy nh hin hnh ca nh nc, cc dng c o c in c cp chnh
xc :0,05;0,1;0,2;0,5;1;1,5;2;2,5 v 4
Thit b o s c cp chnh xc: 0,005;0,01;0,02;0,05;0,1;0,2;0,5;1
GVHD: Phm Vn Thim - 26 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in tVy khi bit cp chnh xc ca mt thit b o ta c th xc nh c sai s
tng i quy i v suy ra sai s tng i ca thit b trong php o c th
X
D =
*Tnh ton sai s ca php o gin tip:
Gi s c 1 php o gin tip i lng y thng cc php o trc tip 1x , 2x ,..
nx . y=f( 1x , 2x ,.. nx ).
Ta c:
dy= 1 2. . ... . ny y ydx dx dxx x x + + +
- Sai s tuyt i ca php o gin tip c nh gi:
y= 2 2 2 21 211 2
( . ) ( . ) ... ( . ) ( . )n
n k
kn k
y y y yx x x x
x x x x=
+ + + =
1x , 2x ,.. nx : Sai s tuyt i ca php o cc i lng trc tip 1x , 2x ,.. nx .
- Sai s tng i ca php o gin tip c nh gi:
y =y
y
= 2 2 2 2 2 2 2 2 21 2 1 2
1 2
( ) .( ) ( ) .( ) ... ( ) .( ) ...n nn
xx xy y yx x x
y x y x y x
+ + + = + + +
1x , 2x ,.. nx : Sai s tng i ca php o trc tip cc i lng 1x , 2x
,.. nx .
-Bng tnh sai s ca hm y= 1x . 2x
GVHD: Phm Vn Thim - 27 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in t
Hm y Sai s tuyt i y Sai s tng i y = y/y
1x . 2x
2 2 2 2
1 2 2 1( ) ( )x x x x +
2 21 2
1 2( ) ( )
x x
x x
+
a, Sai s ca php o dng in.
Dng in qua cc pha A,B,C ( ba pha nh nhau ) c xc nh.
Idm = KI.IAdmVi IAm l dng m ampek o c ch nh mc.
( )AK
II
I
dmAdm 849,35.
75
735,57 ===
Ta c:
Sai s tuyt i ca ampek l:
( )ADI AAAdm 075,05.100
5,1. ===
Sai s tuyt i ca bin dng in l:
( )AKK IKII 225,05
75.
100
5,1. ===
Vy sai s tuyt i ca php o dng in ch nh mc l :
( ) ( ) 22 .. AdmIAdmIdm IKIKI +=
GVHD: Phm Vn Thim - 28 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in t
( ) ( )
( )A37,1
075,0.15849,3.225,022
=+=
Sai s tng i ca php o dng in ch nh mc l:
%37,2%100.735,57
37,1%100.% =
=
=
dm
dmI
I
Idm
b, Sai s ca php o in p.
Sai s tuyt i ca bin in p:
( )VKK UKUU 11,0
10.
100
1. ===
Sai s tuyt i ca volk :
( )VDU VVV 2100.100
2. ===
Kt qu o in p dy :
GVHD: Phm Vn Thim - 29 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in t ( )KVUKU VUd 10. ==
Vi UVddm l dng m volke o c ch nh mc.
VU =ddV m
U
U
K = ( )V1001,010
10000=
Vy sai s tuyt i ca php o in p dy l:
( ) ( )2 2dd. .d U V m U V U K U K U = +
( ) ( )
( )V84,142
2.100100.122
=+=
Sai s tng i ca php o in p dy:
142,84
.100% .100% 1, 43%% 10000
ddm
ddm d
U
U U
= = =
Sai s tuyt i ca php o in p pha:
( ) ( )2 2
. .fdm U fdm U V
U K U K U = +
( )2
2. .
3
Vddmfdm U U V
UU K K U
= +
GVHD: Phm Vn Thim - 30 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in t
( )
( )
2
21001. 100.2
3
208,17 V
= +
=
Sai s tng i ca php o in p pha :
%
208,17.100% .100% 2, 0817%
10000
f
Ufdmf
U
U
= = =
c, Sai s ca php o nng lng tc dng.
Nng lng tc dng ca ph ti ch nh mc l:
( )Wh5,548407605,365.
5
75.
1,0
10W..W cttddmtddm KKK IU ===
Sai s tuyt i ca cng t tc dng ch nh mc trong vng mt thng
cttddmcttd D.Wcttddm =
chn cng t o nng lng tc dng c thang o l 650 (KWh)
Ta c : =cttddmD ( )Wh650 KDcttdnt =
( )KWh75,9650.100
5,1Wcttddm ==
GVHD: Phm Vn Thim - 31 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in tVy sai s tuyt i ca php o nng lng tc dng ch nh mc l :
( ) ( ) ( ) 222tddm ......W cttddmIUcttddmIUcttddmIU WKKWKKWKK ++=
( ) ( ) ( ) 222 75,9.15.100605,365.225,0.100605,365.15.1 ++=
( )KWh18,17653=
Sai s tng i ca php o nng lng tc dng l :
%22.3%100.5,548407
18,17653%100.
tddmW=
=
=
tddm
tddm
W
W
d, Sai s ca php o nng lng phn khng .
Nng lng phn khng ca ph ti ch nh mc l :
( )KVarhKK IU 251136424,167.15.100W..W ctpkdmpkdm ===
Sai s tuyt i ca cng t phn khng :
ctpkdmctpk D.Wctpkdm =
chn cng t o nng lng phn khng c thang o l 650 (KVArh)
Ta c:
( )KVarhDD ctpkmtctpkdm 650==
( )KVarhWctpkdm 75,9650.100
5,1==
Vy sai s tuyt i ca php o nng lng phn khng l :
GVHD: Phm Vn Thim - 32 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in t ( ) ( ) ( )222pkdm ......W ctpkdmIUctpkdmIUctpkdmIU WKKWKKWKK ++=
( ) ( ) ( ) 222 75,9.15.100424,167.225,0.100424,167.15.1 ++=
( )KVarh74,15309=
Sai s tng i ca php o nng lng phn khng l:
%1,6%100.
251136
74,15309%100.
pkdmW =
=
= pkdm
pkdm
W
W
2, Sai s ca cc php o ch non ti.
a, Sai s ca php o dng in
Dng in ch non ti c xc nh :
Int = KI.IAnt
C : IAnt = 0,7.IAdm = 0,7.3,849 = 2,694(A)
Int = 15.2,694 = 40,41(A)
Sai s tuyt i ca ampek :
( )AII AdmAnt 1,0==
Vy sai s tuyt i ca php o dng in ch non ti l :
GVHD: Phm Vn Thim - 33 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in t ( ) ( ) 22 .. AntIAntInt IKIKI +=
( ) ( )
( )A28,1
075,0.15649,2.225,022
=
+=
Sai s tng i ca php o dng in ch non ti l :
%17,3%100.41,40
28,1%100.% =
=
=nt
ntI
I
Int
b, Sai s ca php o nng lng tc dng .Nng lng tc dng ca ph ti ch non ti l:
( )Wh756004,50.5
75.
1,0
10W..W cttdnttdnt KKK IU ===
Sai s tuyt i ca cng t tc dng ch non ti :
cttdntcttd D.Wcttdnt =
Ta c :
( )KWhDcttdnt 650=
( )KWh75.9650.100
5,1Wcttdnt ==
Vy sai s tuyt i ca php o nng lng tc dng ch non ti l
GVHD: Phm Vn Thim - 34 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in t( ) ( ) ( ) 222tdnt ......W cttdntIUcttdntIUcttdntIU WKKWKKWKK ++=
( ) ( ) ( ) 222 75,9.15.1004,50.225,0.1004,50.15.1 ++=
( )KWh37,14688=
Sai s tng i ca php o nng lng tc dng ch non ti:
%42,19%100.75600
37,14688%100.
tdnt
W =
=
=tdnt
tdnt
W
W
c, Sai s ca php o nng lng phn khng.
Nng lng phn khng ca ph ti ch non ti l :
( )KVarhKK IU 615,6641,44.15.100W..W ctpkntpknt ===
Sai s tuyt i ca cng t phn khng ch non ti :
ctpkdmctpk D.Wctpkdm =
Ta c :
( )KVarhDD cttdntctpknt 650==
( )KVarhWctpknt 75,9650.100
5,1 ==
Vy sai s tuyt i ca php o nng lng phn khng ch non ti l :
GVHD: Phm Vn Thim - 35 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in t ( ) ( ) ( )222
pknt ......W ctpkntIUctpkntIUctpkntIU WKKWKKWKK ++=
( ) ( ) ( ) 222 75,9.15.10041,44.225,0.10041,44.15.1 ++=
( )KVarh22,14674=
Sai s tng i ca php o nng lng phn khng ch non ti l:
%03,22%100.66615
22,14674%100.
pkntW=
=
=
pknt
pknt
W
W
Phn II:
Thu thp tn hiu truyn dn cho trm bin p.Vi s lng knh thu thp12.
S dng m hnh ni tip song song thu thp tn hiu.
*S lng knh 12 tng ng:S1,S2,..S12.
*Chn cc Mux: Chn Mux CD4051B.
Thit k b Mux chn tn hiu dng in trn cc pha
+ S1=D0 : Dng in qua pha A
S2=D1: Dng in qua pha B
S3=D2: Dng in qua pha C
S dng b Mux 1 c 2 chn a ch m ha 3 chn d liu vo
GVHD: Phm Vn Thim - 36 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in t
Bng trng thi
A1 C1 Q1
O O 1 D0
O 1 1 D1
1 O 1 D2
u ra:
1 1 0 1 0 0 1 1 0 1 2Q C [A .A .D A .A .D A .A .D= + +
Thit k b Mux chn tn hiu in p
in p pha A S4=D4
in p pha B S5=D5
in p pha C S6=D6
in p pha AB S7=D7
in p pha BC S8=D8
in p pha CA S9=D9
GVHD: Phm Vn Thim - 37 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in tChn b mux c 3 chn a ch m ha 6 chn d liu
Bng trng thi
A3 A4 C2 Q1
0 0 0 1 D3
0 0 1 1 D4
0 1 0 1 D5
0 1 1 1 D6
1 0 0 1 D7
1 0 1 1 D8
u ra:
2 2 2 3 4 3 2 3 4 4 2 3 4 5 2 3 4 6Q C [A .A .A .D A .A .A .D A .A .A .D A .A .A .D= + + + +
. . . . . ]2 3 4 7 2 3 4 8A A A D A A A D+
Thit k b mux chn tn hiu cos, tn s, cng t do nng lng
+1 tn hiu cos do nng lng mt pha: S10=D9
+ 1 tn hiu tn s 3 pha: S11=D10
GVHD: Phm Vn Thim - 38 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in t+ 1 cng t do nng lng: S12=D11
S dng b mux c 2 chn a ch m ha 3 chn d liu
Q1=D12
Q2=D13
Q3=D14
Bng trng thi
A6 C3 Q1
0 0 1 D9
0 1 1 D10
1 0 1 D11
u ra:
3 3 5 6 9 5 6 10 5 6 11Q C [A .A .D A .A .D A .A .D= + +
Thit k b MUX chn 3 tn hiu t 3 b mux1,mux2,mux3
GVHD: Phm Vn Thim - 39 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in t
A8 C Q
0 0 1 D12
0 1 1 D131 0 1 D14
u ra:
7 8 12 7 8 13 7 8 14[A .A .D A .A .D A .A .DQ C = + +
GVHD: Phm Vn Thim - 40 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in t
*Lp bng trng thi tng th
Tn hiu vo Chn clock Tn hiu ra
A0 A1 A2 A3 A4 A5 A6 A7 A8 C1 C2 C3 CQ1 Q2 Q3 Q
S1 0 0 X X X X X 0 0 1 0 0 1 D0 X X D12
S2 0 1 X X X X X 0 0 1 0 0 1 D1 X X D12
S3 1 0 X X X X X 0 0 1 0 0 1 D2 X X D12
S4 X X 0 0 0 X X 0 1 0 1 0 1 X D3 X D13
S5 X X 0 0 1 X X 0 1 0 1 0 1 X D4 X D13
S6 X X 0 1 0 X X 0 1 0 1 0 1 X D5 X D13
S7 X X 0 1 1 X X 0 1 0 1 0 1 X D6 X D13
S8 X X 1 0 0 X X 0 1 0 1 0 1 X D7 X D13
S9 X X 1 0 1 X X 0 1 0 1 0 1 X D8 X D13
S10 X X X X X 0 0 1 0 0 0 1 1 X X D9 D14
S11 X X X X X 0 0 1 0 0 0 1 1 X X D10 D14
S12 X X X X X 0 1 1 0 0 0 1 1 X X D11 D14
GVHD: Phm Vn Thim - 41 - SVTH: Nguyn ThThun
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Bi tp ln o Lng TTCN Khoa in t