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RDBMS Unit: Introduction To RDBMS and SQLModule 9: Union-Intersect-Minus

Exercise 01 Union/Intersect/Minusfunctions against the table

Estimated Completion Time: 45 minutes

OverviewThis exercise will require participants to query on the tables in Oracle SQL PLUSusing the SQL language.

InstructionsQuerying records in tables should be done in Oracle SQL PLUS.

1. In order to proceed with querying records in the tables, login using youruser name created in Exercise 01 and then proceed to use the SEToperators.

Hints1. Ensure the following while creating the queries on the table:

Execute the query in SQL PLUS

After each successful command save the command in the file

To save the file - C:\RDBMS\Day3\UnIntMin.sql append

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RDBMS Unit: Introduction To RDBMS and SQLModule 9: Union-Intersect-Minus

Union/Intersect and Minus

1) Display the first name and last name of both the instructor and student in 1 result set.

Solution:

SELECT FIRST_NAME, LAST_NAME FROM INSTRUCTOR_INFO

UNION

SELECT FIRST_NAME, LAST_NAME FROM STUDENT_INFO

2) Modify the above query to display duplicate names also.

Solution:

SELECT FIRST_NAME, LAST_NAME FROM INSTRUCTOR_INFO

UNION ALL

SELECT FIRST_NAME, LAST_NAME FROM STUDENT_INFO

3) Modify the above query to add a column Name to display text as 'Instructor' or 'Student'in each row.

Solution:

SELECT FIRST_NAME, LAST_NAME, INSTRCUTOR NAME' FROMINSTRUCTOR_INFO UNION

SELECT FIRST_NAME, LAST_NAME, 'STUDENT NAME' FROM STUDENT_INFO

4) Display the instructor id not having any section

Solution:

SELECT INSTRUCTOR_ID FROM INSTRUCTOR_INFO

MINUS

SELECT INSTRUCTOR_ID FROM SECTION_INFO

5) Display the course no having section.

Solution:

SELECT COURSE_NO FROM COURSE_INFO

INTERSECT

SELECT COURSE_NO FROM SECTION_INFO

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RDBMS Unit: Introduction To RDBMS and SQLModule 9: Union-Intersect-Minus

6) Display a list of courses and section having no students enrolled. Add a new columncalled as status that displays text as 'No Student Enrolled'

Solution:

SELECT COURSE_NO, SECTION_NO, 'NO ENROLLMENTS ' AS STATUS FROMSECTION_INFO MINUS

SELECT COURSE_NO, SECTION_NO, ' NO ENROLLMENTS ' FROMSECTION_INFO

WHERE SECTION_ID IN

(SELECT SECTION_ID FROM SECTION_INFO

INTERSECT

SELECT SECTION_ID FROM ENROLLMENT_INFO)

7) Display all the zip codes that are present in both the instructor and the student tables.

Solution:

SELECT 'INSTRCUTOR ZIP' ZIP, ZIP FROM INSTRUCTOR_INFO

INTERSECT

SELECT 'INSTRCUTOR ZIP' ZIP, ZIP FROM STUDENT_INFO

8) Display the student ids who are enrolled.

Solution:

SELECT STUDENT_ID FROM STUDENT

INTERSECT

SELECT STUDENT_ID FROM ENROLLMENT

RDBMS 3 52354326.doc 2007 Accenture. All Rights Reserved.