6035 functions defined by the definite integral ab calculus

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6035 Functions Defined by the Definite Integral AB Calculus

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Page 1: 6035 Functions Defined by the Definite Integral AB Calculus

6035 Functions Defined by the Definite Integral

AB Calculus

Page 2: 6035 Functions Defined by the Definite Integral AB Calculus

Accumulation Functions

Given

Then A (x) is the Accumulation function. The points on A(x) reflects the amount under the curve f (t).

2

bA x f t dt

Net Area: Net Distance Net Money:

BIG PICTURE:

Page 3: 6035 Functions Defined by the Definite Integral AB Calculus

Functions Defined by the Definite Integral

f (t)

2( ) 1f t t

2

0

( ) ( 1)x

A x t dt Also can work with negative accumulation.

A (-1) =

A (-2) =

Page 4: 6035 Functions Defined by the Definite Integral AB Calculus

Functions Defined by the Definite Integral

f (t)

2( ) 1f t t 2

0

( ) ( 1)x

A x t dt A (0) =

A (1) =

A (2) =

A(3) =

TI-89 Graph then F-5 Math #7

TI-83 2nd Calc #7

x

y

x

y

x

y

0

12

4

3

14

3

x

y

Page 5: 6035 Functions Defined by the Definite Integral AB Calculus

Functions Defined by the Definite Integral

f (t)2( ) 1f t t 2

0

( ) ( 1)x

A x t dt Also can work with negative accumulation.

A (-1) =

A (-2) =

x

y

x

y

x

y

4

3

14

3

Page 6: 6035 Functions Defined by the Definite Integral AB Calculus

Functions Defined by the Definite Integralf (t) A (x)

2( ) 1f t t

2

0

( ) ( 1)x

A x t dt

A (x) points indicate the quantity of accumulation under f (t).

x

y

Page 7: 6035 Functions Defined by the Definite Integral AB Calculus

Verify: Write the equation A(x)

2

0

( ) ( 1)x

A x t dt

A (0) = , A (1) = , A (2) = ,

A(3) = , A (-1)= , A (-2) =

=

3

( ) 03

xA x x

=

Page 8: 6035 Functions Defined by the Definite Integral AB Calculus

Writing the Equations: Initial Values = Particular Solutions

2

0

( ) ( 1)x

A x t dt

2

2

( ) ( 1)x

A x t dt

2

1

( ) ( 1)x

A x t dt

What do -2, 0, and 1 represent?

REM: The Antiderivative finds…

Page 9: 6035 Functions Defined by the Definite Integral AB Calculus

Writing the Equations: Initial Values = Particular Solutions

Example:3

3

( 4 )x

t t dt

2

cos 2

x

t dt

20 (3 1)

x tdt

t

Page 10: 6035 Functions Defined by the Definite Integral AB Calculus

Initial Value Problems : 1st Fundamental Theorem

Think: I have $200.00 and deposit $20.00 a week for 4 weeks.

My brother has $350.00 and deposits $20.00 a week for 4 weeks.

( ) ( ) ( )

( ) ( ) ( )

( ) ( ) ( )

b

a

b

a

b

a

f t dt F b F a

F b F a f t dt

F b F a f t dt

Words:

or

Page 11: 6035 Functions Defined by the Definite Integral AB Calculus

Initial Value Problems (concept)

If A (0) = 4 , Find A (7)

b

0

A(x)= f(t)dtIf

7

0

7

0

7

0

A(7) - A(0) = f(t)dt

(7) A(0) + f(t)dt

(7) 4 + f(t)dt

A

A

7

0

f(t)dt

7

0

f(t)dt4 +

4

Page 12: 6035 Functions Defined by the Definite Integral AB Calculus

Initial Value Problems

If A (5) = 6 , Find A (8)

82

5

A(x)= (t +1)dtIf

Page 13: 6035 Functions Defined by the Definite Integral AB Calculus

Accumulation Functions

Suppose f (1) = 10. Find f (3)

Suppose f (0) = 0. Find f (1), f (2), f (3)

The graph the derivative, f / ,is given.

Page 14: 6035 Functions Defined by the Definite Integral AB Calculus

Accumulation Functions

The graph of a function, f , is shown.

a. Evaluate

b. Determine the average value

of the function on the

interval [ 1 , 7 ].

c. If F( 1) = -2 find F ( 7).

7

1( )f x dx

d. Determine the answers to parts a, b and c if the graph is translated two units up.

Page 15: 6035 Functions Defined by the Definite Integral AB Calculus

AP type

Page 16: 6035 Functions Defined by the Definite Integral AB Calculus

Last Update:

• 01/30/10

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