5 - pelton turbine
Embed Size (px)
TRANSCRIPT
-
8/6/2019 5 - Pelton Turbine
1/28
Design of Peltonturbines
-
8/6/2019 5 - Pelton Turbine
2/28
When to use a Peltonturbine
-
8/6/2019 5 - Pelton Turbine
3/28
Energy conversion in aPelton turbine
Outlet Outlet of
the runner
Inlet of
the runner
Outlet of
the needle
Inlet of
the needle
2
2c
-
8/6/2019 5 - Pelton Turbine
4/28
Main dimensions for thePelton runner
-
8/6/2019 5 - Pelton Turbine
5/28
-
8/6/2019 5 - Pelton Turbine
6/28
The ideal Pelton runnerAbsolute velocity from nozzle:
n1 Hg2c = 1Hg2
cc
n
11 =
=
Circumferential speed:
nu1
1 Hg2
2
1
2
cu == 5.0u1 =
Euler`s turbine equation:
)cucu(2 u22u11h =
1)05,00.15,0(2)(2 2211 === uuh cucu
1c u1 = 0c 2u =
-
8/6/2019 5 - Pelton Turbine
7/28
The real Pelton runner For a real Pelton runner there will always be losWe will therefore set the hydraulic efficiency to:
96.0h =
The absolute velocity from the nozzle will be:
995.0c99.0 u1
-
8/6/2019 5 - Pelton Turbine
8/28
From continuity equation:
u1
2
s c4
dzQ
=
u1
scz
Q4d
=
Where:
Z = number of nozzles
Q = flow rate
C1u = nHg2
-
8/6/2019 5 - Pelton Turbine
9/28
The size of the bucket
and number of nozzles
4.3
d
B1.3
s
>
Rules of thumb:
B = 3,1 ds 1 nozzle
B = 3,2 ds 2 nozzles
B = 3,3 ds
4-5 nozzles
B > 3,3 ds 6 nozzles
-
8/6/2019 5 - Pelton Turbine
10/28
Number of buckets
17z empirical
-
8/6/2019 5 - Pelton Turbine
11/28
Number of buckets
-
8/6/2019 5 - Pelton Turbine
12/28
Runner diameterRules of thumb:
D = 10 ds
Hn
< 500 m
D = 15 ds Hn = 1300 m
D < 9,5 ds must be avoided because water
will be lost
D > 15 ds is for very high head Pelton
-
8/6/2019 5 - Pelton Turbine
13/28
Speed number
zQ =
5,0u
0,1c
1
u1
=
=
4
dc
4
dQ
2
su1
2
s =
=
D
1
Hg2D
Hg2
Hg2D
u2
Hg2 n
n
n
1
n=
=
=
=
4
z
D
ds =
4
zd
D
1zQ
2
s ==
-
8/6/2019 5 - Pelton Turbine
14/28
For the diameter: D = 10 dsand one nozzle: z = 1
09,0
4
1
10
1
4
z
D
ds =
=
=
For the diameter: D = 10 dsand six nozzle: z = 6
22,04
6
10
1
4
z
D
ds =
=
=
The maximum speed number for a Pelton
turbine today is = 0,22
The maximum speed number for a Pelton
turbine with one nozzle is = 0,09
-
8/6/2019 5 - Pelton Turbine
15/28
Dimensioning of a
Pelton turbine
1. The flow rate and head are given*H = 1130 m
*Q = 28,5 m3/s
*P = 288 MW
2. Choose reduced values
c1u = 1 c1u = 149 m/su1 = 0,48 u1 = 71 m/s
3. Choose the number of nozzlesz = 5
4. Calculate ds from continuity for one nozzle
m22,0
cz
Q4d
u1
s =
=
-
8/6/2019 5 - Pelton Turbine
16/28
5. Choose the bucket width
B = 3,3 ds= 0,73 m
-
8/6/2019 5 - Pelton Turbine
17/28
6. Find the diameter by interpolation
D/ds
Hn [m]
10
15
400 1400
m0,3d65,13D
65,138H005,0d
D
s
n
s
==
=+=
-
8/6/2019 5 - Pelton Turbine
18/28
7. Calculate the speed:
8. Choose the number of poles on the generator:
The speed of the runner is given by the generator andthe net frequency:
where Zp=number of poles on the generator
The number of poles will be:
rpm452D
60un
2
D
60
n2
2
Du
1
1
==
==
]rpm[Z
3000n
p
=
764,6n
3000Zp ===
-
8/6/2019 5 - Pelton Turbine
19/28
]rpm[6,428Z
3000n
p
==
m16,3n
60uD
2
D
60
n2
2
Du 11 =
=
==
9. Recalculate the speed:
10. Recalculate the diameter:
11. Choose the number of buckets
z = 22
-
8/6/2019 5 - Pelton Turbine
20/28
12. Diameter of the turbine housing (for vertical turbines)
13. Calculate the height from the runner to the water levelat the outlet (for vertical turbines)
m4,9BKDD gsinHou =+=
K
z
8
9
1 64
m1,3DB5.3Height =
-
8/6/2019 5 - Pelton Turbine
21/28
Given values:
*Q =28,5 m3/s
*H =1130m
Chosen values:
c1u = 1
u1 = 0,48
z = 5
B= 0,73 m
z = 22
Zp = 7
Calculated values:
ds = 0,22 m
n =428,6 rpm
D=3, 16 m
Height= 3,1 m
Dhousing= 9,4 m
*P= 288MW
-
8/6/2019 5 - Pelton Turbine
22/28
GE Hydro
*Q=28,5 m3/s
*H = 1130m
*P =288MW
Jostedal, Sogn og Fjordane
-
8/6/2019 5 - Pelton Turbine
23/28
Jostedal, Sogn og Fjordane
GE Hydro
*Q=28,5 m3/s
*H =1130m
*P =288MW
-
8/6/2019 5 - Pelton Turbine
24/28
ExampleKhimti Power Plant
1. The flow rate and head are given*H = 660 m
*Q = 2,15 m3/s
*P = 12 MW
2. Choose reduced values
c1u = 1 c1u = 114 m/su1 = 0,48 u1 = 54,6 m/s
3. Choose the number of nozzles
z = 1
-
8/6/2019 5 - Pelton Turbine
25/28
ExampleKhimti Power Plant
4. Calculate ds from continuity forone nozzle
5. Choose the bucket widthB = 3,2 ds= 0, 5 m
mcz
Qd
u
s 15,04
1
=
=
-
8/6/2019 5 - Pelton Turbine
26/28
6. Find the diameter by interpolation
D/ds
Hn [m]
10
15
400 1400
mdD
Hd
D
s
n
s
7,13,11
3,118005,0
==
=+=
-
8/6/2019 5 - Pelton Turbine
27/28
7. Calculate the speed:
8. Choose the number of poles on thegenerator:
The speed of the runner is given by
the generator and the net frequency:
where Zp=number of poles on the
generator
The number of poles will be:
rpmD
un
DnDu
61360
260
2
2
1
1
=
=
==
]rpm[Z
3000n
p
=
59,43000
=== nZp
-
8/6/2019 5 - Pelton Turbine
28/28
][6003000
rpmZ
np
==
mn
uD
DnDu 74,1
60
260
2
2
11 =
=
==
9. Recalculate the speed:
10. Recalculate the diameter:
11. Choose the number of buckets
z = 22