5-2 medians and altitudes of triangles

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5-2 Medians and Altitudes of Triangles You identified and used perpendicular and angle bisectors in triangles. Identify and use medians in triangles. Identify and use altitudes in triangles.

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You identified and used perpendicular and angle bisectors in triangles. 5-2 Medians and Altitudes of Triangles. Identify and use medians in triangles. Identify and use altitudes in triangles. F. H. G. J. Median. - PowerPoint PPT Presentation

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Page 1: 5-2 Medians and Altitudes of Triangles

5-2 Medians and Altitudes of Triangles

You identified and used perpendicular and angle bisectors in triangles.

• Identify and use medians in triangles.

• Identify and use altitudes in triangles.

Page 2: 5-2 Medians and Altitudes of Triangles

MedianA median of a triangle is a segment

whose endpoints are a vertex and the midpoint of the opposite side.

(Goes from vertex to opposite side)

F

GH

J

Median

Page 3: 5-2 Medians and Altitudes of Triangles

Every triangle has three medians that are concurrent.

The point of concurrency of the medians of a triangle is called the centroid and is always inside the triangle.

Page 335

Page 4: 5-2 Medians and Altitudes of Triangles

Balancing Act

Balance your triangle on the eraser end of your pencil. Mark the point. This is the centroid of the triangle.

Fold your triangle to find the midpoint of each side of your triangle Connect each vertex to the midpoint of the opposite side.

Do all three line segments meet at one point?

Page 5: 5-2 Medians and Altitudes of Triangles

Centroid

The point of concurrency of the medians of any triangle is called the centroid.

The centroid is the center of balance (or center of gravity) of the triangle.

Centroid

Page 6: 5-2 Medians and Altitudes of Triangles

In ΔXYZ, P is the centroid and YV = 12. Find YP and PV.

Centroid Theorem

YV = 12

Simplify.

Answer: YP = 8; PV = 4

YP + PV = YV Segment Addition

8 + PV = 12 YP = 8

PV = 4 Subtract 8 from each side.

Page 7: 5-2 Medians and Altitudes of Triangles

A. LR = 15; RO = 15

B. LR = 20; RO = 10

C. LR = 17; RO = 13

D. LR = 18; RO = 12

In ΔLNP, R is the centroid and LO = 30. Find LR and RO.

Page 8: 5-2 Medians and Altitudes of Triangles

A. 4

B. 6

C. 16

D. 8

In ΔJLN, JP = 16. Find PM.

Page 9: 5-2 Medians and Altitudes of Triangles

Altitude (height)

An altitude of a triangle is a perpendicular segment drawn from a vertex to the line that contains the opposite side.

(Vertex to opposite side at a right angle.)

K

L

MN

K

L

MN

Altitude

Page 10: 5-2 Medians and Altitudes of Triangles

Every triangle has three altitudes. If extended, the latitudes of a triangle intersect in a common point called the orthocenter.

Page 337

Page 11: 5-2 Medians and Altitudes of Triangles

COORDINATE GEOMETRY The vertices of ΔHIJ are H(1, 2), I(–3, –3), and J(–5, 1). Find the coordinates of the orthocenter of ΔHIJ.

Find an equation of the altitude from The slope of

so the slope of an altitude is

Point-slope form

Distributive Property

Add 1 to each side.

Page 12: 5-2 Medians and Altitudes of Triangles

Point-slope form

Distributive Property

Subtract 3 from each side.

Next, find an equation of the altitude from I to The

slope of so the slope of an altitude is –6.

Page 13: 5-2 Medians and Altitudes of Triangles

Equation of altitude from J

Multiply each side by 5.

Add 105 to each side.

Add 4x to each side.

Divide each side by –26.

Substitution,

Then, solve a system of equations to find the point of intersection of the altitudes.

Page 14: 5-2 Medians and Altitudes of Triangles

Replace x with in one of the equations to find the y-coordinate.

Multiply and simplify.

Rename as improper fractions.

Answer: The coordinates of the orthocenter of ΔHIJ are

Page 15: 5-2 Medians and Altitudes of Triangles
Page 16: 5-2 Medians and Altitudes of Triangles

5-2 Assignment

Page 340, 5-11, 16-19, 27-30