470086412_guc_elk_dev_vize_2012
TRANSCRIPT
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22.11.2012U.ArifoluZMLER
Cevap 1) a) Yke ilikin ilikin ortalama gerilim deeri (gerekli ekilleri izerek).
V9.385dwt)wtsin(32*2202
3V
3/piLort
b) "a" faz akm sigorta akm deeri.
A17.34dwt)10
wtsin32220(
2
2I
3/pi
2aetkin
c) Tristr olarak BStN 35 kullanldna gre, tristrn iletim kayplarn watt olarak bulunuz.
" bir tristr akm deiimi"
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22.11.2012U.Arifolu
V86.12dwt)wtsin(32222
1I
3/piTort
A16.24dwt)10
wtsin32220(
2
1I
3/pi
2Tetkin
W22.1316.24*10*84.086.12*99.0I*rI*UP 232
TiTortsT
Cevap 2)Yk geriliminin deiimi
A ve B alanlar birbirlerine eit olmak zorundadr (bobinin ortalama gerilimi daima sfr volt tur).
a) 0dwt*)wtsin(322206/2
1V
6/
alfa3
Lort
b) dwt
)t(diwL)wt(vL Cdwt*)wtsin(32220
wL
1)wt(i ; (i(wt=/3+alfa)=0)
i(wt)=-17.15*cos(wt)+C ; C=-14.852 bulunur.i(wt)=-17.15*cos(wt)-14.852 Amper bulunur.
Yk akmnn deiimi
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22.11.2012U.Arifolu
A525.1dwt*)852.14)wtcos(15.17(6/2
1I
6/
alfa3
Lort
3)
Kaynak akm (is(t))deiimi
A78.77dwt)2
wtsin2220(
1I
2/pi
2setkin
; A35.65I etkin1
35.65
)35.6578.77(
I
)II(DF
5.022
etkin1
5.02etkin1
2setkin
= 0.6454 ;