4 effect of acceleration on static fluid(1)

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    ACCELERATION EFFECTON STATIC FLUID

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    OBJECTIVES

    This chapter is designed to help students achieve the following :- Understanding the effect of the acceleration of the staticfluid.

    - Proving that the inclination of the plane surface.

    - Shows how the analysis of acceleration effect can assist insolve problems in the field of engineering.

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    LEARNING OUTCOMES

    At the end of this chapter, students will be able to use

    knowledge and skills to :

    - Define the effect of acceleration on the static fluid.

    - State the basic equations related effects of acceleration on astatic fluid.

    - Solve simple problems related effect of acceleration on staticfluid.

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    ACCELERATION EFFECT OF STATIC

    FLUID

    Consider a fluid-filled tank below :

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    When subjected to a horizontal directionacceleration, fluid surface will be inclined.

    This will affect the pressure on the bottom of the

    tank surface Indirectly it will affect the strength of the tank

    structure

    CONT..

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    Consider a small fluid molecules below :

    CONT..

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    If the molecule is accelerated with the accelerationof the fluid x, ax :

    Fx= max

    p1A1

    p2A2= max(p1p2)A = Vax

    (p1p2)yz = xyzax

    (p1

    p2) = xaxp/x = ax (1)

    CONT..

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    If the molecule is accelerated with the accelerationof the fluid y, ay :

    Fy= may

    p1A1

    p2A2 - mg = may(p1p2)A = V(ay+g)

    (p1p2)xz = xyz(ay+g)

    (p1

    p2) = y(ay+g)p/y = (ay+g) (2)

    CONT..

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    If the molecule is accelerated with the accelerationof the fluid z, az :

    Fz= maz

    p1A1

    p2A2= maz(p1p2)A = Vaz

    (p1p2)xy = xyzaz

    (p1

    p2) = zazp/z = az (3)

    CONT..

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    If the molecules is accelerated to the surface of theinclined fluid to the s axis (the angle will be fromthe x axis to s axis)

    p/s = (p/x)(x/s) + (p/y)(y/s)

    y

    x

    s

    CONT..

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    And is known on the surface of the fluid, thepressure is equal to atmospheric pressure.

    So,p/s = 0

    0 = (p/x)(x/s) + (p/y)(y/s)

    CONT..

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    (p/x)(x/s) = - (p/y)(y/s)

    (p/x)/(p/y) = -(y/s) )/(x/s)

    (y/x) = -(y/s) )/(x/s)

    As we know,

    (y/x) = tan

    So,

    tan = -ax/(g +ay)

    CONT..

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    Conclusion

    - Angle of inclination of the water surface when

    acceleration can be known with using the above

    formula.- When subjected to positive acceleration, angle

    inclination of the water surface will be

    within the limits of 90 to 180.

    CONT..

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    EXAMPLE

    Example 1

    Example 2

    Example 3

    http://d/KINGSTON%20(G)/BDA1052/LECTURE%20NOTE/TOPIK%204/contoh%201a.dochttp://d/KINGSTON%20(G)/BDA1052/LECTURE%20NOTE/TOPIK%204/contoh%202a.dochttp://d/KINGSTON%20(G)/BDA1052/LECTURE%20NOTE/TOPIK%204/contoh%203a.dochttp://d/KINGSTON%20(G)/BDA1052/LECTURE%20NOTE/TOPIK%204/contoh%203a.dochttp://d/KINGSTON%20(G)/BDA1052/LECTURE%20NOTE/TOPIK%204/contoh%202a.dochttp://d/KINGSTON%20(G)/BDA1052/LECTURE%20NOTE/TOPIK%204/contoh%201a.doc
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    THANK YOU