2b soal soal titrasi redoks
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Soal-soal Titrasi Redoks
sample mass= 04185g
KMnO4 titration= 0025M 4127mL
Fe2O3=
mol Fe2O3=12mol Fe=125mol KMNO4
=52(VM)KMnO4
25794mmol
massa Fe2O3= 4127mg
9861
sample= 04185 g= 4185 mg
Titration Fe2+
KMnO4 Vol= 4127 mLM= 0025 M
Mol KMnO4= (MV)= 103175 mmol
Reaction 5 Fe2+ + KMnO4 === 5 Fe3+ + Mn2+
mol Fe2+ = 5 mol KMnO4= 515875 mmol
Reaction 2 Fe2+ === 2 Fe3+ ===== Fe2O3
mol Fe2O3 = 05mol Fe2+ = 2579375 mmol
mass Fe2O3= molMr Fe2O3= 4127 mg
Fe2O3= mass Fe2O3mass sample100= 9861
Walden reductor UO22+ --gt U4+
Addition of Fe3+ U4++ 2Fe3+ ---gt U6+ + 2Fe2+
Titration 6 Fe2+ + K2Cr2O7 --gt 6 Fe3+ + 2 Cr3+
sample= 0315 g= 315 mgTitration
Vol= 1052 mLM= 000987 M
mmol K2Cr2O7= (VM)= 0103832 mmol
mmol Fe2+ =6 mmol K2Cr2O7= 0622994 mmol
mmol U4+ =05 mmol Fe2+ = 0311497 mmolmass U= mmol U4+ Ar (U)= 7414534 mgU= mass Umass sample 100= 2354
Ar U= 2380289
Cr= 519961 Fe 558Area= 30 cm2 density Cr= 72 gcm3
oxidizing 2Cr3+ === Cr2O72-
Addition of Fe(NH4)2(SO4)26H2O= 5000 mg
Reaction Cr2O72- + 6Fe2+ === 2Cr3+ + 6Fe3+
Backtitration
Reaction Cr2O72- + 6Fe2+ === 2Cr3+ + 6Fe3+
vol= 1829 mLM= 000389 M
mmol back titration = Fe2+ excess= (VM) backtitration== 0071148 mmol
mmol Fe total = mmol Fe-amm-sulfat=massMr Fe-amm-sulfat= 1276015 mmol
mmol Fe2+ bereaksi dengan Cr2O72- sampel= 120487 mmol
mmol Cr2O72-= 16 mmol Fe2+= 020081 mmol
mmol Cr3+ = 2 x mmol Cr2O72-= 040162 mmol
mass Cr3+= 209 mg= 002088 g
vol Cr3+= massdensity= 00029 cm3thickness=volumearea= 97E-05 cm
= 09668 μmMr Fe-amm-sulfat= 39185 gmol
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sample mass= 04185g
KMnO4 titration= 0025M 4127mL
Fe2O3=
mol Fe2O3=12mol Fe=125mol KMNO4
=52(VM)KMnO4
25794mmol
massa Fe2O3= 4127mg
9861
sample= 04185 g= 4185 mg
Titration Fe2+
KMnO4 Vol= 4127 mLM= 0025 M
Mol KMnO4= (MV)= 103175 mmol
Reaction 5 Fe2+ + KMnO4 === 5 Fe3+ + Mn2+
mol Fe2+ = 5 mol KMnO4= 515875 mmol
Reaction 2 Fe2+ === 2 Fe3+ ===== Fe2O3
mol Fe2O3 = 05mol Fe2+ = 2579375 mmol
mass Fe2O3= molMr Fe2O3= 4127 mg
Fe2O3= mass Fe2O3mass sample100= 9861
Walden reductor UO22+ --gt U4+
Addition of Fe3+ U4++ 2Fe3+ ---gt U6+ + 2Fe2+
Titration 6 Fe2+ + K2Cr2O7 --gt 6 Fe3+ + 2 Cr3+
sample= 0315 g= 315 mgTitration
Vol= 1052 mLM= 000987 M
mmol K2Cr2O7= (VM)= 0103832 mmol
mmol Fe2+ =6 mmol K2Cr2O7= 0622994 mmol
mmol U4+ =05 mmol Fe2+ = 0311497 mmolmass U= mmol U4+ Ar (U)= 7414534 mgU= mass Umass sample 100= 2354
Ar U= 2380289
Cr= 519961 Fe 558Area= 30 cm2 density Cr= 72 gcm3
oxidizing 2Cr3+ === Cr2O72-
Addition of Fe(NH4)2(SO4)26H2O= 5000 mg
Reaction Cr2O72- + 6Fe2+ === 2Cr3+ + 6Fe3+
Backtitration
Reaction Cr2O72- + 6Fe2+ === 2Cr3+ + 6Fe3+
vol= 1829 mLM= 000389 M
mmol back titration = Fe2+ excess= (VM) backtitration== 0071148 mmol
mmol Fe total = mmol Fe-amm-sulfat=massMr Fe-amm-sulfat= 1276015 mmol
mmol Fe2+ bereaksi dengan Cr2O72- sampel= 120487 mmol
mmol Cr2O72-= 16 mmol Fe2+= 020081 mmol
mmol Cr3+ = 2 x mmol Cr2O72-= 040162 mmol
mass Cr3+= 209 mg= 002088 g
vol Cr3+= massdensity= 00029 cm3thickness=volumearea= 97E-05 cm
= 09668 μmMr Fe-amm-sulfat= 39185 gmol
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sample= 04185 g= 4185 mg
Titration Fe2+
KMnO4 Vol= 4127 mLM= 0025 M
Mol KMnO4= (MV)= 103175 mmol
Reaction 5 Fe2+ + KMnO4 === 5 Fe3+ + Mn2+
mol Fe2+ = 5 mol KMnO4= 515875 mmol
Reaction 2 Fe2+ === 2 Fe3+ ===== Fe2O3
mol Fe2O3 = 05mol Fe2+ = 2579375 mmol
mass Fe2O3= molMr Fe2O3= 4127 mg
Fe2O3= mass Fe2O3mass sample100= 9861
Walden reductor UO22+ --gt U4+
Addition of Fe3+ U4++ 2Fe3+ ---gt U6+ + 2Fe2+
Titration 6 Fe2+ + K2Cr2O7 --gt 6 Fe3+ + 2 Cr3+
sample= 0315 g= 315 mgTitration
Vol= 1052 mLM= 000987 M
mmol K2Cr2O7= (VM)= 0103832 mmol
mmol Fe2+ =6 mmol K2Cr2O7= 0622994 mmol
mmol U4+ =05 mmol Fe2+ = 0311497 mmolmass U= mmol U4+ Ar (U)= 7414534 mgU= mass Umass sample 100= 2354
Ar U= 2380289
Cr= 519961 Fe 558Area= 30 cm2 density Cr= 72 gcm3
oxidizing 2Cr3+ === Cr2O72-
Addition of Fe(NH4)2(SO4)26H2O= 5000 mg
Reaction Cr2O72- + 6Fe2+ === 2Cr3+ + 6Fe3+
Backtitration
Reaction Cr2O72- + 6Fe2+ === 2Cr3+ + 6Fe3+
vol= 1829 mLM= 000389 M
mmol back titration = Fe2+ excess= (VM) backtitration== 0071148 mmol
mmol Fe total = mmol Fe-amm-sulfat=massMr Fe-amm-sulfat= 1276015 mmol
mmol Fe2+ bereaksi dengan Cr2O72- sampel= 120487 mmol
mmol Cr2O72-= 16 mmol Fe2+= 020081 mmol
mmol Cr3+ = 2 x mmol Cr2O72-= 040162 mmol
mass Cr3+= 209 mg= 002088 g
vol Cr3+= massdensity= 00029 cm3thickness=volumearea= 97E-05 cm
= 09668 μmMr Fe-amm-sulfat= 39185 gmol
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Walden reductor UO22+ --gt U4+
Addition of Fe3+ U4++ 2Fe3+ ---gt U6+ + 2Fe2+
Titration 6 Fe2+ + K2Cr2O7 --gt 6 Fe3+ + 2 Cr3+
sample= 0315 g= 315 mgTitration
Vol= 1052 mLM= 000987 M
mmol K2Cr2O7= (VM)= 0103832 mmol
mmol Fe2+ =6 mmol K2Cr2O7= 0622994 mmol
mmol U4+ =05 mmol Fe2+ = 0311497 mmolmass U= mmol U4+ Ar (U)= 7414534 mgU= mass Umass sample 100= 2354
Ar U= 2380289
Cr= 519961 Fe 558Area= 30 cm2 density Cr= 72 gcm3
oxidizing 2Cr3+ === Cr2O72-
Addition of Fe(NH4)2(SO4)26H2O= 5000 mg
Reaction Cr2O72- + 6Fe2+ === 2Cr3+ + 6Fe3+
Backtitration
Reaction Cr2O72- + 6Fe2+ === 2Cr3+ + 6Fe3+
vol= 1829 mLM= 000389 M
mmol back titration = Fe2+ excess= (VM) backtitration== 0071148 mmol
mmol Fe total = mmol Fe-amm-sulfat=massMr Fe-amm-sulfat= 1276015 mmol
mmol Fe2+ bereaksi dengan Cr2O72- sampel= 120487 mmol
mmol Cr2O72-= 16 mmol Fe2+= 020081 mmol
mmol Cr3+ = 2 x mmol Cr2O72-= 040162 mmol
mass Cr3+= 209 mg= 002088 g
vol Cr3+= massdensity= 00029 cm3thickness=volumearea= 97E-05 cm
= 09668 μmMr Fe-amm-sulfat= 39185 gmol
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Cr= 519961 Fe 558Area= 30 cm2 density Cr= 72 gcm3
oxidizing 2Cr3+ === Cr2O72-
Addition of Fe(NH4)2(SO4)26H2O= 5000 mg
Reaction Cr2O72- + 6Fe2+ === 2Cr3+ + 6Fe3+
Backtitration
Reaction Cr2O72- + 6Fe2+ === 2Cr3+ + 6Fe3+
vol= 1829 mLM= 000389 M
mmol back titration = Fe2+ excess= (VM) backtitration== 0071148 mmol
mmol Fe total = mmol Fe-amm-sulfat=massMr Fe-amm-sulfat= 1276015 mmol
mmol Fe2+ bereaksi dengan Cr2O72- sampel= 120487 mmol
mmol Cr2O72-= 16 mmol Fe2+= 020081 mmol
mmol Cr3+ = 2 x mmol Cr2O72-= 040162 mmol
mass Cr3+= 209 mg= 002088 g
vol Cr3+= massdensity= 00029 cm3thickness=volumearea= 97E-05 cm
= 09668 μmMr Fe-amm-sulfat= 39185 gmol
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