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DUE 2/23 AP PHYSICS WEEK 24 HOMEWORK RUBRIC PAGE 240-243 AREA NET TORQUE POSSIBLE POINTS CORNEL NOTE FORMAT: Heading, Page Set Up, Legible, Organized, Color 5 Explain rotational equilibrium and how it is calculated. rotational equilibrium when the net torque on the object is zero about any point (center the sum of the torques is zero. 15 Give 2 example of rotational equilibrium. A see saw in a balanced position, a person balancing on the end of a diving board 15 If a 100 Kg adult sat on a see saw and a 30 kg child sat on the other side 3m from the fulcrum how close to the fulcrum would the adult need to sit to balance the see saw. Ϯ net = ϯ 1 - ϯ 2 0= (30 x 3) – (100 x r)= 100/90 =1 .11 m 15 Explain static equilibrium and how it is related to torque An object is holding its position by applying a net torque of zero on a fixed point. The general condition for static equilibrium has two parts, both of which must be satisfied: The sum of forces must be zero in all directions (ΣF = 0). The sum of torques must be zero around any choice of center (Στ = 0) 15 Answer questions 1,2,3 on page 243 15

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DUE 2/23 AP PHYSICS WEEK 24 HOMEWORK RUBRIC PAGE 240-243

AREA NET TORQUE POSSIBLEPOINTS

CORNEL NOTE FORMAT: Heading, Page Set Up, Legible, Organized, Color 5Explain rotational equilibrium and how it is calculated.rotational equilibrium when the net torque on the object is zero about any point (centerthe sum of the torques is zero.

15

Give 2 example of rotational equilibrium.A see saw in a balanced position, a person balancing on the end of a diving board

15

If a 100 Kg adult sat on a see saw and a 30 kg child sat on the other side 3m from the fulcrum how close to the fulcrum would the adult need to sit to balance the see saw.

Ϯnet = ϯ1- ϯ2 0= (30 x 3) – (100 x r)= 100/90 =1 .11 m

15

Explain static equilibrium and how it is related to torque

An object is holding its position by applying a net torque of zero on a fixed point.The general condition for static equilibrium has two parts, both of which must be satisfied:

The sum of forces must be zero in all directions (ΣF = 0). The sum of torques must be zero around any choice of center (Στ = 0)

15

Answer questions 1,2,3 on page 243 15

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TOTAL 105